Integrand size = 34, antiderivative size = 134 \[ \int \frac {b+a x^2}{\left (-b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx=\frac {\text {arctanh}\left (\frac {\sqrt {6-4 \sqrt {2}} \sqrt {a} \sqrt {b} x}{b+a x^2+\sqrt {b^2+a^2 x^4}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}-\frac {\text {arctanh}\left (\frac {\sqrt {6+4 \sqrt {2}} \sqrt {a} \sqrt {b} x}{b+a x^2+\sqrt {b^2+a^2 x^4}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}} \]
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Time = 0.05 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.37, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {1713, 214} \[ \int \frac {b+a x^2}{\left (-b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx=-\frac {\text {arctanh}\left (\frac {\sqrt {2} \sqrt {a} \sqrt {b} x}{\sqrt {a^2 x^4+b^2}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}} \]
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Rule 214
Rule 1713
Rubi steps \begin{align*} \text {integral}& = b \text {Subst}\left (\int \frac {1}{-b+2 a b^2 x^2} \, dx,x,\frac {x}{\sqrt {b^2+a^2 x^4}}\right ) \\ & = -\frac {\text {arctanh}\left (\frac {\sqrt {2} \sqrt {a} \sqrt {b} x}{\sqrt {b^2+a^2 x^4}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}} \\ \end{align*}
Time = 0.53 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.37 \[ \int \frac {b+a x^2}{\left (-b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx=-\frac {\text {arctanh}\left (\frac {\sqrt {2} \sqrt {a} \sqrt {b} x}{\sqrt {b^2+a^2 x^4}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}} \]
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Time = 2.36 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.28
method | result | size |
elliptic | \(-\frac {\operatorname {arctanh}\left (\frac {\sqrt {a^{2} x^{4}+b^{2}}\, \sqrt {2}}{2 x \sqrt {a b}}\right ) \sqrt {2}}{2 \sqrt {a b}}\) | \(38\) |
default | \(-\frac {\sqrt {2}\, \left (2 \ln \left (2\right )+\ln \left (-\frac {2 a \left (-\frac {\sqrt {2}\, \sqrt {a b}\, \sqrt {a^{2} x^{4}+b^{2}}}{2}+\left (a \,x^{2}+b \right ) \sqrt {a b}+a b x \right )}{a \,x^{2}+2 x \sqrt {a b}+b}\right )+\ln \left (-\frac {2 a \left (-\frac {\sqrt {2}\, \sqrt {a b}\, \sqrt {a^{2} x^{4}+b^{2}}}{2}+\left (-a \,x^{2}-b \right ) \sqrt {a b}+a b x \right )}{a \,x^{2}-2 x \sqrt {a b}+b}\right )\right )}{4 \sqrt {a b}}\) | \(143\) |
pseudoelliptic | \(-\frac {\sqrt {2}\, \left (2 \ln \left (2\right )+\ln \left (-\frac {2 a \left (-\frac {\sqrt {2}\, \sqrt {a b}\, \sqrt {a^{2} x^{4}+b^{2}}}{2}+\left (a \,x^{2}+b \right ) \sqrt {a b}+a b x \right )}{a \,x^{2}+2 x \sqrt {a b}+b}\right )+\ln \left (-\frac {2 a \left (-\frac {\sqrt {2}\, \sqrt {a b}\, \sqrt {a^{2} x^{4}+b^{2}}}{2}+\left (-a \,x^{2}-b \right ) \sqrt {a b}+a b x \right )}{a \,x^{2}-2 x \sqrt {a b}+b}\right )\right )}{4 \sqrt {a b}}\) | \(143\) |
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Time = 0.30 (sec) , antiderivative size = 132, normalized size of antiderivative = 0.99 \[ \int \frac {b+a x^2}{\left (-b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx=\left [\frac {1}{4} \, \sqrt {2} \sqrt {\frac {1}{a b}} \log \left (\frac {a^{2} x^{4} - 2 \, \sqrt {2} \sqrt {a^{2} x^{4} + b^{2}} a b x \sqrt {\frac {1}{a b}} + 2 \, a b x^{2} + b^{2}}{a^{2} x^{4} - 2 \, a b x^{2} + b^{2}}\right ), \frac {1}{2} \, \sqrt {2} \sqrt {-\frac {1}{a b}} \arctan \left (\frac {\sqrt {2} \sqrt {a^{2} x^{4} + b^{2}} \sqrt {-\frac {1}{a b}}}{2 \, x}\right )\right ] \]
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\[ \int \frac {b+a x^2}{\left (-b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx=\int \frac {a x^{2} + b}{\left (a x^{2} - b\right ) \sqrt {a^{2} x^{4} + b^{2}}}\, dx \]
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\[ \int \frac {b+a x^2}{\left (-b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx=\int { \frac {a x^{2} + b}{\sqrt {a^{2} x^{4} + b^{2}} {\left (a x^{2} - b\right )}} \,d x } \]
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\[ \int \frac {b+a x^2}{\left (-b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx=\int { \frac {a x^{2} + b}{\sqrt {a^{2} x^{4} + b^{2}} {\left (a x^{2} - b\right )}} \,d x } \]
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Timed out. \[ \int \frac {b+a x^2}{\left (-b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx=\int -\frac {a\,x^2+b}{\sqrt {a^2\,x^4+b^2}\,\left (b-a\,x^2\right )} \,d x \]
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