Integrand size = 42, antiderivative size = 152 \[ \int \frac {\left (-b+a x^5\right )^{3/4} \left (4 b+a x^5\right )}{x^4 \left (-b+c x^4+a x^5\right )} \, dx=\frac {4 \left (-b+a x^5\right )^{3/4}}{3 x^3}+\sqrt {2} c^{3/4} \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} x \sqrt [4]{-b+a x^5}}{-\sqrt {c} x^2+\sqrt {-b+a x^5}}\right )+\sqrt {2} c^{3/4} \text {arctanh}\left (\frac {\frac {\sqrt [4]{c} x^2}{\sqrt {2}}+\frac {\sqrt {-b+a x^5}}{\sqrt {2} \sqrt [4]{c}}}{x \sqrt [4]{-b+a x^5}}\right ) \]
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\[ \int \frac {\left (-b+a x^5\right )^{3/4} \left (4 b+a x^5\right )}{x^4 \left (-b+c x^4+a x^5\right )} \, dx=\int \frac {\left (-b+a x^5\right )^{3/4} \left (4 b+a x^5\right )}{x^4 \left (-b+c x^4+a x^5\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {4 \left (-b+a x^5\right )^{3/4}}{x^4}+\frac {(4 c+5 a x) \left (-b+a x^5\right )^{3/4}}{-b+c x^4+a x^5}\right ) \, dx \\ & = -\left (4 \int \frac {\left (-b+a x^5\right )^{3/4}}{x^4} \, dx\right )+\int \frac {(4 c+5 a x) \left (-b+a x^5\right )^{3/4}}{-b+c x^4+a x^5} \, dx \\ & = -\frac {\left (4 \left (-b+a x^5\right )^{3/4}\right ) \int \frac {\left (1-\frac {a x^5}{b}\right )^{3/4}}{x^4} \, dx}{\left (1-\frac {a x^5}{b}\right )^{3/4}}+\int \left (\frac {4 c \left (-b+a x^5\right )^{3/4}}{-b+c x^4+a x^5}+\frac {5 a x \left (-b+a x^5\right )^{3/4}}{-b+c x^4+a x^5}\right ) \, dx \\ & = \frac {4 \left (-b+a x^5\right )^{3/4} \operatorname {Hypergeometric2F1}\left (-\frac {3}{4},-\frac {3}{5},\frac {2}{5},\frac {a x^5}{b}\right )}{3 x^3 \left (1-\frac {a x^5}{b}\right )^{3/4}}+(5 a) \int \frac {x \left (-b+a x^5\right )^{3/4}}{-b+c x^4+a x^5} \, dx+(4 c) \int \frac {\left (-b+a x^5\right )^{3/4}}{-b+c x^4+a x^5} \, dx \\ \end{align*}
Time = 1.13 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.96 \[ \int \frac {\left (-b+a x^5\right )^{3/4} \left (4 b+a x^5\right )}{x^4 \left (-b+c x^4+a x^5\right )} \, dx=\frac {4 \left (-b+a x^5\right )^{3/4}}{3 x^3}+\sqrt {2} c^{3/4} \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} x \sqrt [4]{-b+a x^5}}{-\sqrt {c} x^2+\sqrt {-b+a x^5}}\right )+\sqrt {2} c^{3/4} \text {arctanh}\left (\frac {\sqrt {c} x^2+\sqrt {-b+a x^5}}{\sqrt {2} \sqrt [4]{c} x \sqrt [4]{-b+a x^5}}\right ) \]
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Time = 0.47 (sec) , antiderivative size = 193, normalized size of antiderivative = 1.27
method | result | size |
pseudoelliptic | \(\frac {-3 \ln \left (\frac {\sqrt {a \,x^{5}-b}-\left (a \,x^{5}-b \right )^{\frac {1}{4}} x \,c^{\frac {1}{4}} \sqrt {2}+\sqrt {c}\, x^{2}}{\left (a \,x^{5}-b \right )^{\frac {1}{4}} x \,c^{\frac {1}{4}} \sqrt {2}+\sqrt {c}\, x^{2}+\sqrt {a \,x^{5}-b}}\right ) c^{\frac {3}{4}} \sqrt {2}\, x^{3}-6 \arctan \left (\frac {\sqrt {2}\, \left (a \,x^{5}-b \right )^{\frac {1}{4}}+c^{\frac {1}{4}} x}{c^{\frac {1}{4}} x}\right ) c^{\frac {3}{4}} \sqrt {2}\, x^{3}-6 \arctan \left (\frac {\sqrt {2}\, \left (a \,x^{5}-b \right )^{\frac {1}{4}}-c^{\frac {1}{4}} x}{c^{\frac {1}{4}} x}\right ) c^{\frac {3}{4}} \sqrt {2}\, x^{3}+8 \left (a \,x^{5}-b \right )^{\frac {3}{4}}}{6 x^{3}}\) | \(193\) |
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Timed out. \[ \int \frac {\left (-b+a x^5\right )^{3/4} \left (4 b+a x^5\right )}{x^4 \left (-b+c x^4+a x^5\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (-b+a x^5\right )^{3/4} \left (4 b+a x^5\right )}{x^4 \left (-b+c x^4+a x^5\right )} \, dx=\int \frac {\left (a x^{5} - b\right )^{\frac {3}{4}} \left (a x^{5} + 4 b\right )}{x^{4} \left (a x^{5} - b + c x^{4}\right )}\, dx \]
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\[ \int \frac {\left (-b+a x^5\right )^{3/4} \left (4 b+a x^5\right )}{x^4 \left (-b+c x^4+a x^5\right )} \, dx=\int { \frac {{\left (a x^{5} + 4 \, b\right )} {\left (a x^{5} - b\right )}^{\frac {3}{4}}}{{\left (a x^{5} + c x^{4} - b\right )} x^{4}} \,d x } \]
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\[ \int \frac {\left (-b+a x^5\right )^{3/4} \left (4 b+a x^5\right )}{x^4 \left (-b+c x^4+a x^5\right )} \, dx=\int { \frac {{\left (a x^{5} + 4 \, b\right )} {\left (a x^{5} - b\right )}^{\frac {3}{4}}}{{\left (a x^{5} + c x^{4} - b\right )} x^{4}} \,d x } \]
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Timed out. \[ \int \frac {\left (-b+a x^5\right )^{3/4} \left (4 b+a x^5\right )}{x^4 \left (-b+c x^4+a x^5\right )} \, dx=\int \frac {{\left (a\,x^5-b\right )}^{3/4}\,\left (a\,x^5+4\,b\right )}{x^4\,\left (a\,x^5+c\,x^4-b\right )} \,d x \]
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