Integrand size = 34, antiderivative size = 164 \[ \int \frac {(-3+x) (-2+x) \left (2-x+2 x^3\right )^{2/3}}{x^6 \left (-2+x+2 x^3\right )} \, dx=\frac {3 \left (2-x+2 x^3\right )^{2/3} \left (2-x+7 x^3\right )}{10 x^5}-2 \sqrt [3]{2} \sqrt {3} \arctan \left (\frac {\sqrt {3} x}{x+\sqrt [3]{2} \sqrt [3]{2-x+2 x^3}}\right )+2 \sqrt [3]{2} \log \left (-2 x+\sqrt [3]{2} \sqrt [3]{2-x+2 x^3}\right )-\sqrt [3]{2} \log \left (4 x^2+2 \sqrt [3]{2} x \sqrt [3]{2-x+2 x^3}+2^{2/3} \left (2-x+2 x^3\right )^{2/3}\right ) \]
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\[ \int \frac {(-3+x) (-2+x) \left (2-x+2 x^3\right )^{2/3}}{x^6 \left (-2+x+2 x^3\right )} \, dx=\int \frac {(-3+x) (-2+x) \left (2-x+2 x^3\right )^{2/3}}{x^6 \left (-2+x+2 x^3\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {3 \left (2-x+2 x^3\right )^{2/3}}{x^6}+\frac {\left (2-x+2 x^3\right )^{2/3}}{x^5}-\frac {3 \left (2-x+2 x^3\right )^{2/3}}{x^3}-\frac {\left (2-x+2 x^3\right )^{2/3}}{2 x^2}-\frac {\left (2-x+2 x^3\right )^{2/3}}{4 x}+\frac {\left (25+4 x+2 x^2\right ) \left (2-x+2 x^3\right )^{2/3}}{4 \left (-2+x+2 x^3\right )}\right ) \, dx \\ & = -\left (\frac {1}{4} \int \frac {\left (2-x+2 x^3\right )^{2/3}}{x} \, dx\right )+\frac {1}{4} \int \frac {\left (25+4 x+2 x^2\right ) \left (2-x+2 x^3\right )^{2/3}}{-2+x+2 x^3} \, dx-\frac {1}{2} \int \frac {\left (2-x+2 x^3\right )^{2/3}}{x^2} \, dx-3 \int \frac {\left (2-x+2 x^3\right )^{2/3}}{x^6} \, dx-3 \int \frac {\left (2-x+2 x^3\right )^{2/3}}{x^3} \, dx+\int \frac {\left (2-x+2 x^3\right )^{2/3}}{x^5} \, dx \\ & = \text {Too large to display} \\ \end{align*}
Time = 0.49 (sec) , antiderivative size = 141, normalized size of antiderivative = 0.86 \[ \int \frac {(-3+x) (-2+x) \left (2-x+2 x^3\right )^{2/3}}{x^6 \left (-2+x+2 x^3\right )} \, dx=\frac {3 \left (2-x+2 x^3\right )^{2/3} \left (2-x+7 x^3\right )}{10 x^5}-2 \sqrt [3]{2} \sqrt {3} \arctan \left (\frac {\sqrt {3} x}{x+\sqrt [3]{4-2 x+4 x^3}}\right )+2 \sqrt [3]{2} \log \left (-2 x+\sqrt [3]{4-2 x+4 x^3}\right )-\sqrt [3]{2} \log \left (4 x^2+2 x \sqrt [3]{4-2 x+4 x^3}+\left (4-2 x+4 x^3\right )^{2/3}\right ) \]
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Time = 15.89 (sec) , antiderivative size = 174, normalized size of antiderivative = 1.06
method | result | size |
pseudoelliptic | \(\frac {20 \sqrt {3}\, 2^{\frac {1}{3}} \arctan \left (\frac {\sqrt {3}\, \left (x +2^{\frac {1}{3}} \left (2 x^{3}-x +2\right )^{\frac {1}{3}}\right )}{3 x}\right ) x^{5}+20 \,2^{\frac {1}{3}} \ln \left (\frac {-2^{\frac {2}{3}} x +\left (2 x^{3}-x +2\right )^{\frac {1}{3}}}{x}\right ) x^{5}-10 \,2^{\frac {1}{3}} \ln \left (\frac {2^{\frac {2}{3}} \left (2 x^{3}-x +2\right )^{\frac {1}{3}} x +2 \,2^{\frac {1}{3}} x^{2}+\left (2 x^{3}-x +2\right )^{\frac {2}{3}}}{x^{2}}\right ) x^{5}+21 \left (2 x^{3}-x +2\right )^{\frac {2}{3}} x^{3}-3 \left (2 x^{3}-x +2\right )^{\frac {2}{3}} x +6 \left (2 x^{3}-x +2\right )^{\frac {2}{3}}}{10 x^{5}}\) | \(174\) |
risch | \(\text {Expression too large to display}\) | \(670\) |
trager | \(\text {Expression too large to display}\) | \(1014\) |
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Leaf count of result is larger than twice the leaf count of optimal. 424 vs. \(2 (134) = 268\).
Time = 6.59 (sec) , antiderivative size = 424, normalized size of antiderivative = 2.59 \[ \int \frac {(-3+x) (-2+x) \left (2-x+2 x^3\right )^{2/3}}{x^6 \left (-2+x+2 x^3\right )} \, dx=-\frac {20 \, \sqrt {3} 2^{\frac {1}{3}} x^{5} \arctan \left (\frac {6 \, \sqrt {3} 2^{\frac {2}{3}} {\left (20 \, x^{7} + 8 \, x^{5} - 16 \, x^{4} - x^{3} + 4 \, x^{2} - 4 \, x\right )} {\left (2 \, x^{3} - x + 2\right )}^{\frac {2}{3}} - 12 \, \sqrt {3} 2^{\frac {1}{3}} {\left (76 \, x^{8} - 32 \, x^{6} + 64 \, x^{5} + x^{4} - 4 \, x^{3} + 4 \, x^{2}\right )} {\left (2 \, x^{3} - x + 2\right )}^{\frac {1}{3}} - \sqrt {3} {\left (568 \, x^{9} - 444 \, x^{7} + 888 \, x^{6} + 66 \, x^{5} - 264 \, x^{4} + 263 \, x^{3} + 6 \, x^{2} - 12 \, x + 8\right )}}{3 \, {\left (872 \, x^{9} - 420 \, x^{7} + 840 \, x^{6} + 6 \, x^{5} - 24 \, x^{4} + 25 \, x^{3} - 6 \, x^{2} + 12 \, x - 8\right )}}\right ) - 20 \cdot 2^{\frac {1}{3}} x^{5} \log \left (-\frac {6 \cdot 2^{\frac {2}{3}} {\left (2 \, x^{3} - x + 2\right )}^{\frac {1}{3}} x^{2} - 6 \, {\left (2 \, x^{3} - x + 2\right )}^{\frac {2}{3}} x - 2^{\frac {1}{3}} {\left (2 \, x^{3} + x - 2\right )}}{2 \, x^{3} + x - 2}\right ) + 10 \cdot 2^{\frac {1}{3}} x^{5} \log \left (\frac {6 \cdot 2^{\frac {1}{3}} {\left (10 \, x^{4} - x^{2} + 2 \, x\right )} {\left (2 \, x^{3} - x + 2\right )}^{\frac {2}{3}} + 2^{\frac {2}{3}} {\left (76 \, x^{6} - 32 \, x^{4} + 64 \, x^{3} + x^{2} - 4 \, x + 4\right )} + 24 \, {\left (4 \, x^{5} - x^{3} + 2 \, x^{2}\right )} {\left (2 \, x^{3} - x + 2\right )}^{\frac {1}{3}}}{4 \, x^{6} + 4 \, x^{4} - 8 \, x^{3} + x^{2} - 4 \, x + 4}\right ) - 9 \, {\left (7 \, x^{3} - x + 2\right )} {\left (2 \, x^{3} - x + 2\right )}^{\frac {2}{3}}}{30 \, x^{5}} \]
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Timed out. \[ \int \frac {(-3+x) (-2+x) \left (2-x+2 x^3\right )^{2/3}}{x^6 \left (-2+x+2 x^3\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {(-3+x) (-2+x) \left (2-x+2 x^3\right )^{2/3}}{x^6 \left (-2+x+2 x^3\right )} \, dx=\int { \frac {{\left (2 \, x^{3} - x + 2\right )}^{\frac {2}{3}} {\left (x - 2\right )} {\left (x - 3\right )}}{{\left (2 \, x^{3} + x - 2\right )} x^{6}} \,d x } \]
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\[ \int \frac {(-3+x) (-2+x) \left (2-x+2 x^3\right )^{2/3}}{x^6 \left (-2+x+2 x^3\right )} \, dx=\int { \frac {{\left (2 \, x^{3} - x + 2\right )}^{\frac {2}{3}} {\left (x - 2\right )} {\left (x - 3\right )}}{{\left (2 \, x^{3} + x - 2\right )} x^{6}} \,d x } \]
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Timed out. \[ \int \frac {(-3+x) (-2+x) \left (2-x+2 x^3\right )^{2/3}}{x^6 \left (-2+x+2 x^3\right )} \, dx=\int \frac {\left (x-2\right )\,\left (x-3\right )\,{\left (2\,x^3-x+2\right )}^{2/3}}{x^6\,\left (2\,x^3+x-2\right )} \,d x \]
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