Integrand size = 34, antiderivative size = 165 \[ \int \frac {\left (-b+a x^4\right ) \left (b+a x^4\right )^{3/4}}{x^8 \left (b+2 a x^4\right )} \, dx=\frac {\left (b-6 a x^4\right ) \left (b+a x^4\right )^{3/4}}{7 b x^7}-\frac {3 a^{7/4} \arctan \left (\frac {\sqrt {2} \sqrt [4]{a} x \sqrt [4]{b+a x^4}}{-\sqrt {a} x^2+\sqrt {b+a x^4}}\right )}{2 \sqrt {2} b}-\frac {3 a^{7/4} \text {arctanh}\left (\frac {\frac {\sqrt [4]{a} x^2}{\sqrt {2}}+\frac {\sqrt {b+a x^4}}{\sqrt {2} \sqrt [4]{a}}}{x \sqrt [4]{b+a x^4}}\right )}{2 \sqrt {2} b} \]
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Time = 0.18 (sec) , antiderivative size = 255, normalized size of antiderivative = 1.55, number of steps used = 13, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.294, Rules used = {594, 597, 12, 385, 217, 1179, 642, 1176, 631, 210} \[ \int \frac {\left (-b+a x^4\right ) \left (b+a x^4\right )^{3/4}}{x^8 \left (b+2 a x^4\right )} \, dx=\frac {3 a^{7/4} \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{a x^4+b}}\right )}{2 \sqrt {2} b}-\frac {3 a^{7/4} \arctan \left (\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{a x^4+b}}+1\right )}{2 \sqrt {2} b}+\frac {3 a^{7/4} \log \left (-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{a x^4+b}}+\frac {\sqrt {a} x^2}{\sqrt {a x^4+b}}+1\right )}{4 \sqrt {2} b}-\frac {3 a^{7/4} \log \left (\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{a x^4+b}}+\frac {\sqrt {a} x^2}{\sqrt {a x^4+b}}+1\right )}{4 \sqrt {2} b}+\frac {\left (a x^4+b\right )^{3/4}}{7 x^7}-\frac {6 a \left (a x^4+b\right )^{3/4}}{7 b x^3} \]
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Rule 12
Rule 210
Rule 217
Rule 385
Rule 594
Rule 597
Rule 631
Rule 642
Rule 1176
Rule 1179
Rubi steps \begin{align*} \text {integral}& = \frac {\left (b+a x^4\right )^{3/4}}{7 x^7}+\frac {\int \frac {18 a b^2+15 a^2 b x^4}{x^4 \sqrt [4]{b+a x^4} \left (b+2 a x^4\right )} \, dx}{7 b} \\ & = \frac {\left (b+a x^4\right )^{3/4}}{7 x^7}-\frac {6 a \left (b+a x^4\right )^{3/4}}{7 b x^3}-\frac {\int \frac {63 a^2 b^3}{\sqrt [4]{b+a x^4} \left (b+2 a x^4\right )} \, dx}{21 b^3} \\ & = \frac {\left (b+a x^4\right )^{3/4}}{7 x^7}-\frac {6 a \left (b+a x^4\right )^{3/4}}{7 b x^3}-\left (3 a^2\right ) \int \frac {1}{\sqrt [4]{b+a x^4} \left (b+2 a x^4\right )} \, dx \\ & = \frac {\left (b+a x^4\right )^{3/4}}{7 x^7}-\frac {6 a \left (b+a x^4\right )^{3/4}}{7 b x^3}-\left (3 a^2\right ) \text {Subst}\left (\int \frac {1}{b+a b x^4} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right ) \\ & = \frac {\left (b+a x^4\right )^{3/4}}{7 x^7}-\frac {6 a \left (b+a x^4\right )^{3/4}}{7 b x^3}-\frac {1}{2} \left (3 a^2\right ) \text {Subst}\left (\int \frac {1-\sqrt {a} x^2}{b+a b x^4} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )-\frac {1}{2} \left (3 a^2\right ) \text {Subst}\left (\int \frac {1+\sqrt {a} x^2}{b+a b x^4} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right ) \\ & = \frac {\left (b+a x^4\right )^{3/4}}{7 x^7}-\frac {6 a \left (b+a x^4\right )^{3/4}}{7 b x^3}-\frac {\left (3 a^{3/2}\right ) \text {Subst}\left (\int \frac {1}{\frac {1}{\sqrt {a}}-\frac {\sqrt {2} x}{\sqrt [4]{a}}+x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{4 b}-\frac {\left (3 a^{3/2}\right ) \text {Subst}\left (\int \frac {1}{\frac {1}{\sqrt {a}}+\frac {\sqrt {2} x}{\sqrt [4]{a}}+x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{4 b}+\frac {\left (3 a^{7/4}\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2}}{\sqrt [4]{a}}+2 x}{-\frac {1}{\sqrt {a}}-\frac {\sqrt {2} x}{\sqrt [4]{a}}-x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{4 \sqrt {2} b}+\frac {\left (3 a^{7/4}\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2}}{\sqrt [4]{a}}-2 x}{-\frac {1}{\sqrt {a}}+\frac {\sqrt {2} x}{\sqrt [4]{a}}-x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{4 \sqrt {2} b} \\ & = \frac {\left (b+a x^4\right )^{3/4}}{7 x^7}-\frac {6 a \left (b+a x^4\right )^{3/4}}{7 b x^3}+\frac {3 a^{7/4} \log \left (1+\frac {\sqrt {a} x^2}{\sqrt {b+a x^4}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b+a x^4}}\right )}{4 \sqrt {2} b}-\frac {3 a^{7/4} \log \left (1+\frac {\sqrt {a} x^2}{\sqrt {b+a x^4}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b+a x^4}}\right )}{4 \sqrt {2} b}-\frac {\left (3 a^{7/4}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {2} b}+\frac {\left (3 a^{7/4}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {2} b} \\ & = \frac {\left (b+a x^4\right )^{3/4}}{7 x^7}-\frac {6 a \left (b+a x^4\right )^{3/4}}{7 b x^3}+\frac {3 a^{7/4} \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {2} b}-\frac {3 a^{7/4} \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {2} b}+\frac {3 a^{7/4} \log \left (1+\frac {\sqrt {a} x^2}{\sqrt {b+a x^4}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b+a x^4}}\right )}{4 \sqrt {2} b}-\frac {3 a^{7/4} \log \left (1+\frac {\sqrt {a} x^2}{\sqrt {b+a x^4}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b+a x^4}}\right )}{4 \sqrt {2} b} \\ \end{align*}
Time = 0.52 (sec) , antiderivative size = 158, normalized size of antiderivative = 0.96 \[ \int \frac {\left (-b+a x^4\right ) \left (b+a x^4\right )^{3/4}}{x^8 \left (b+2 a x^4\right )} \, dx=\frac {4 \left (b-6 a x^4\right ) \left (b+a x^4\right )^{3/4}+21 \sqrt {2} a^{7/4} x^7 \arctan \left (\frac {\sqrt {2} \sqrt [4]{a} x \sqrt [4]{b+a x^4}}{\sqrt {a} x^2-\sqrt {b+a x^4}}\right )-21 \sqrt {2} a^{7/4} x^7 \text {arctanh}\left (\frac {\sqrt {a} x^2+\sqrt {b+a x^4}}{\sqrt {2} \sqrt [4]{a} x \sqrt [4]{b+a x^4}}\right )}{28 b x^7} \]
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Time = 1.37 (sec) , antiderivative size = 198, normalized size of antiderivative = 1.20
method | result | size |
pseudoelliptic | \(\frac {21 \ln \left (\frac {-\left (a \,x^{4}+b \right )^{\frac {1}{4}} x \,a^{\frac {1}{4}} \sqrt {2}+\sqrt {a}\, x^{2}+\sqrt {a \,x^{4}+b}}{\left (a \,x^{4}+b \right )^{\frac {1}{4}} x \,a^{\frac {1}{4}} \sqrt {2}+\sqrt {a}\, x^{2}+\sqrt {a \,x^{4}+b}}\right ) a^{\frac {7}{4}} \sqrt {2}\, x^{7}+42 \arctan \left (\frac {a^{\frac {1}{4}} x +\sqrt {2}\, \left (a \,x^{4}+b \right )^{\frac {1}{4}}}{a^{\frac {1}{4}} x}\right ) a^{\frac {7}{4}} \sqrt {2}\, x^{7}-42 \arctan \left (\frac {a^{\frac {1}{4}} x -\sqrt {2}\, \left (a \,x^{4}+b \right )^{\frac {1}{4}}}{a^{\frac {1}{4}} x}\right ) a^{\frac {7}{4}} \sqrt {2}\, x^{7}-48 a \left (a \,x^{4}+b \right )^{\frac {3}{4}} x^{4}+8 b \left (a \,x^{4}+b \right )^{\frac {3}{4}}}{56 b \,x^{7}}\) | \(198\) |
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Result contains complex when optimal does not.
Time = 40.36 (sec) , antiderivative size = 488, normalized size of antiderivative = 2.96 \[ \int \frac {\left (-b+a x^4\right ) \left (b+a x^4\right )^{3/4}}{x^8 \left (b+2 a x^4\right )} \, dx=-\frac {21 \, \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {1}{4}} b x^{7} \log \left (-\frac {27 \, {\left (2 \, {\left (a x^{4} + b\right )}^{\frac {1}{4}} \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {1}{4}} a^{4} x^{3} + 2 \, \sqrt {a x^{4} + b} \sqrt {-\frac {a^{7}}{b^{4}}} a^{2} b x^{2} - a^{5} + 2 \, {\left (a x^{4} + b\right )}^{\frac {3}{4}} \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {3}{4}} b^{2} x\right )}}{2 \, a x^{4} + b}\right ) - 21 \, \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {1}{4}} b x^{7} \log \left (\frac {27 \, {\left (2 \, {\left (a x^{4} + b\right )}^{\frac {1}{4}} \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {1}{4}} a^{4} x^{3} - 2 \, \sqrt {a x^{4} + b} \sqrt {-\frac {a^{7}}{b^{4}}} a^{2} b x^{2} + a^{5} + 2 \, {\left (a x^{4} + b\right )}^{\frac {3}{4}} \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {3}{4}} b^{2} x\right )}}{2 \, a x^{4} + b}\right ) + 21 i \, \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {1}{4}} b x^{7} \log \left (-\frac {27 \, {\left (2 i \, {\left (a x^{4} + b\right )}^{\frac {1}{4}} \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {1}{4}} a^{4} x^{3} - 2 \, \sqrt {a x^{4} + b} \sqrt {-\frac {a^{7}}{b^{4}}} a^{2} b x^{2} - a^{5} - 2 i \, {\left (a x^{4} + b\right )}^{\frac {3}{4}} \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {3}{4}} b^{2} x\right )}}{2 \, a x^{4} + b}\right ) - 21 i \, \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {1}{4}} b x^{7} \log \left (-\frac {27 \, {\left (-2 i \, {\left (a x^{4} + b\right )}^{\frac {1}{4}} \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {1}{4}} a^{4} x^{3} - 2 \, \sqrt {a x^{4} + b} \sqrt {-\frac {a^{7}}{b^{4}}} a^{2} b x^{2} - a^{5} + 2 i \, {\left (a x^{4} + b\right )}^{\frac {3}{4}} \left (-\frac {a^{7}}{b^{4}}\right )^{\frac {3}{4}} b^{2} x\right )}}{2 \, a x^{4} + b}\right ) + 8 \, {\left (6 \, a x^{4} - b\right )} {\left (a x^{4} + b\right )}^{\frac {3}{4}}}{56 \, b x^{7}} \]
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\[ \int \frac {\left (-b+a x^4\right ) \left (b+a x^4\right )^{3/4}}{x^8 \left (b+2 a x^4\right )} \, dx=\int \frac {\left (a x^{4} - b\right ) \left (a x^{4} + b\right )^{\frac {3}{4}}}{x^{8} \cdot \left (2 a x^{4} + b\right )}\, dx \]
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\[ \int \frac {\left (-b+a x^4\right ) \left (b+a x^4\right )^{3/4}}{x^8 \left (b+2 a x^4\right )} \, dx=\int { \frac {{\left (a x^{4} + b\right )}^{\frac {3}{4}} {\left (a x^{4} - b\right )}}{{\left (2 \, a x^{4} + b\right )} x^{8}} \,d x } \]
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\[ \int \frac {\left (-b+a x^4\right ) \left (b+a x^4\right )^{3/4}}{x^8 \left (b+2 a x^4\right )} \, dx=\int { \frac {{\left (a x^{4} + b\right )}^{\frac {3}{4}} {\left (a x^{4} - b\right )}}{{\left (2 \, a x^{4} + b\right )} x^{8}} \,d x } \]
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Timed out. \[ \int \frac {\left (-b+a x^4\right ) \left (b+a x^4\right )^{3/4}}{x^8 \left (b+2 a x^4\right )} \, dx=\int -\frac {{\left (a\,x^4+b\right )}^{3/4}\,\left (b-a\,x^4\right )}{x^8\,\left (2\,a\,x^4+b\right )} \,d x \]
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