Integrand size = 41, antiderivative size = 167 \[ \int \frac {\sqrt {q+p x^5} \left (-2 q+3 p x^5\right )}{b x^4+a \left (q+p x^5\right )^2} \, dx=-\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x \sqrt {q+p x^5}}{\sqrt {a} q-\sqrt {b} x^2+\sqrt {a} p x^5}\right )}{\sqrt {2} a^{3/4} \sqrt [4]{b}}-\frac {\text {arctanh}\left (\frac {\frac {\sqrt [4]{a} q}{\sqrt {2} \sqrt [4]{b}}+\frac {\sqrt [4]{b} x^2}{\sqrt {2} \sqrt [4]{a}}+\frac {\sqrt [4]{a} p x^5}{\sqrt {2} \sqrt [4]{b}}}{x \sqrt {q+p x^5}}\right )}{\sqrt {2} a^{3/4} \sqrt [4]{b}} \]
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Time = 0.31 (sec) , antiderivative size = 242, normalized size of antiderivative = 1.45, number of steps used = 10, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.171, Rules used = {6844, 217, 1179, 642, 1176, 631, 210} \[ \int \frac {\sqrt {q+p x^5} \left (-2 q+3 p x^5\right )}{b x^4+a \left (q+p x^5\right )^2} \, dx=\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a} \sqrt {p x^5+q}}\right )}{\sqrt {2} a^{3/4} \sqrt [4]{b}}-\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a} \sqrt {p x^5+q}}+1\right )}{\sqrt {2} a^{3/4} \sqrt [4]{b}}+\frac {\log \left (-\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x}{\sqrt {p x^5+q}}+\sqrt {a}+\frac {\sqrt {b} x^2}{p x^5+q}\right )}{2 \sqrt {2} a^{3/4} \sqrt [4]{b}}-\frac {\log \left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x}{\sqrt {p x^5+q}}+\sqrt {a}+\frac {\sqrt {b} x^2}{p x^5+q}\right )}{2 \sqrt {2} a^{3/4} \sqrt [4]{b}} \]
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Rule 210
Rule 217
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 6844
Rubi steps \begin{align*} \text {integral}& = -\left (2 \text {Subst}\left (\int \frac {1}{a+b x^4} \, dx,x,\frac {x}{\sqrt {q+p x^5}}\right )\right ) \\ & = -\frac {\text {Subst}\left (\int \frac {\sqrt {a}-\sqrt {b} x^2}{a+b x^4} \, dx,x,\frac {x}{\sqrt {q+p x^5}}\right )}{\sqrt {a}}-\frac {\text {Subst}\left (\int \frac {\sqrt {a}+\sqrt {b} x^2}{a+b x^4} \, dx,x,\frac {x}{\sqrt {q+p x^5}}\right )}{\sqrt {a}} \\ & = -\frac {\text {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\frac {x}{\sqrt {q+p x^5}}\right )}{2 \sqrt {a} \sqrt {b}}-\frac {\text {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\frac {x}{\sqrt {q+p x^5}}\right )}{2 \sqrt {a} \sqrt {b}}+\frac {\text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}+2 x}{-\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\frac {x}{\sqrt {q+p x^5}}\right )}{2 \sqrt {2} a^{3/4} \sqrt [4]{b}}+\frac {\text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}-2 x}{-\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\frac {x}{\sqrt {q+p x^5}}\right )}{2 \sqrt {2} a^{3/4} \sqrt [4]{b}} \\ & = \frac {\log \left (\sqrt {a}+\frac {\sqrt {b} x^2}{q+p x^5}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x}{\sqrt {q+p x^5}}\right )}{2 \sqrt {2} a^{3/4} \sqrt [4]{b}}-\frac {\log \left (\sqrt {a}+\frac {\sqrt {b} x^2}{q+p x^5}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x}{\sqrt {q+p x^5}}\right )}{2 \sqrt {2} a^{3/4} \sqrt [4]{b}}-\frac {\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a} \sqrt {q+p x^5}}\right )}{\sqrt {2} a^{3/4} \sqrt [4]{b}}+\frac {\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a} \sqrt {q+p x^5}}\right )}{\sqrt {2} a^{3/4} \sqrt [4]{b}} \\ & = \frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a} \sqrt {q+p x^5}}\right )}{\sqrt {2} a^{3/4} \sqrt [4]{b}}-\frac {\arctan \left (1+\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a} \sqrt {q+p x^5}}\right )}{\sqrt {2} a^{3/4} \sqrt [4]{b}}+\frac {\log \left (\sqrt {a}+\frac {\sqrt {b} x^2}{q+p x^5}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x}{\sqrt {q+p x^5}}\right )}{2 \sqrt {2} a^{3/4} \sqrt [4]{b}}-\frac {\log \left (\sqrt {a}+\frac {\sqrt {b} x^2}{q+p x^5}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x}{\sqrt {q+p x^5}}\right )}{2 \sqrt {2} a^{3/4} \sqrt [4]{b}} \\ \end{align*}
Time = 1.73 (sec) , antiderivative size = 127, normalized size of antiderivative = 0.76 \[ \int \frac {\sqrt {q+p x^5} \left (-2 q+3 p x^5\right )}{b x^4+a \left (q+p x^5\right )^2} \, dx=-\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x \sqrt {q+p x^5}}{-\sqrt {b} x^2+\sqrt {a} \left (q+p x^5\right )}\right )+\text {arctanh}\left (\frac {\sqrt {b} x^2+\sqrt {a} \left (q+p x^5\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x \sqrt {q+p x^5}}\right )}{\sqrt {2} a^{3/4} \sqrt [4]{b}} \]
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Time = 1.36 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.05
method | result | size |
pseudoelliptic | \(\frac {\sqrt {2}\, \left (\ln \left (\frac {p \,x^{5}-\left (\frac {b}{a}\right )^{\frac {1}{4}} \sqrt {p \,x^{5}+q}\, \sqrt {2}\, x +\sqrt {\frac {b}{a}}\, x^{2}+q}{p \,x^{5}+\left (\frac {b}{a}\right )^{\frac {1}{4}} \sqrt {p \,x^{5}+q}\, \sqrt {2}\, x +\sqrt {\frac {b}{a}}\, x^{2}+q}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {p \,x^{5}+q}+\left (\frac {b}{a}\right )^{\frac {1}{4}} x}{\left (\frac {b}{a}\right )^{\frac {1}{4}} x}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {p \,x^{5}+q}-\left (\frac {b}{a}\right )^{\frac {1}{4}} x}{\left (\frac {b}{a}\right )^{\frac {1}{4}} x}\right )\right )}{4 \left (\frac {b}{a}\right )^{\frac {1}{4}} a}\) | \(175\) |
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Result contains complex when optimal does not.
Time = 0.91 (sec) , antiderivative size = 639, normalized size of antiderivative = 3.83 \[ \int \frac {\sqrt {q+p x^5} \left (-2 q+3 p x^5\right )}{b x^4+a \left (q+p x^5\right )^2} \, dx=\frac {1}{4} \, \left (-\frac {1}{a^{3} b}\right )^{\frac {1}{4}} \log \left (\frac {a p^{2} x^{10} + 2 \, a p q x^{5} - b x^{4} + a q^{2} + 2 \, \sqrt {p x^{5} + q} {\left (a b x^{3} \left (-\frac {1}{a^{3} b}\right )^{\frac {1}{4}} + {\left (a^{3} b p x^{6} + a^{3} b q x\right )} \left (-\frac {1}{a^{3} b}\right )^{\frac {3}{4}}\right )} - 2 \, {\left (a^{2} b p x^{7} + a^{2} b q x^{2}\right )} \sqrt {-\frac {1}{a^{3} b}}}{a p^{2} x^{10} + 2 \, a p q x^{5} + b x^{4} + a q^{2}}\right ) - \frac {1}{4} \, \left (-\frac {1}{a^{3} b}\right )^{\frac {1}{4}} \log \left (\frac {a p^{2} x^{10} + 2 \, a p q x^{5} - b x^{4} + a q^{2} - 2 \, \sqrt {p x^{5} + q} {\left (a b x^{3} \left (-\frac {1}{a^{3} b}\right )^{\frac {1}{4}} + {\left (a^{3} b p x^{6} + a^{3} b q x\right )} \left (-\frac {1}{a^{3} b}\right )^{\frac {3}{4}}\right )} - 2 \, {\left (a^{2} b p x^{7} + a^{2} b q x^{2}\right )} \sqrt {-\frac {1}{a^{3} b}}}{a p^{2} x^{10} + 2 \, a p q x^{5} + b x^{4} + a q^{2}}\right ) - \frac {1}{4} i \, \left (-\frac {1}{a^{3} b}\right )^{\frac {1}{4}} \log \left (\frac {a p^{2} x^{10} + 2 \, a p q x^{5} - b x^{4} + a q^{2} - 2 \, \sqrt {p x^{5} + q} {\left (i \, a b x^{3} \left (-\frac {1}{a^{3} b}\right )^{\frac {1}{4}} + {\left (-i \, a^{3} b p x^{6} - i \, a^{3} b q x\right )} \left (-\frac {1}{a^{3} b}\right )^{\frac {3}{4}}\right )} + 2 \, {\left (a^{2} b p x^{7} + a^{2} b q x^{2}\right )} \sqrt {-\frac {1}{a^{3} b}}}{a p^{2} x^{10} + 2 \, a p q x^{5} + b x^{4} + a q^{2}}\right ) + \frac {1}{4} i \, \left (-\frac {1}{a^{3} b}\right )^{\frac {1}{4}} \log \left (\frac {a p^{2} x^{10} + 2 \, a p q x^{5} - b x^{4} + a q^{2} - 2 \, \sqrt {p x^{5} + q} {\left (-i \, a b x^{3} \left (-\frac {1}{a^{3} b}\right )^{\frac {1}{4}} + {\left (i \, a^{3} b p x^{6} + i \, a^{3} b q x\right )} \left (-\frac {1}{a^{3} b}\right )^{\frac {3}{4}}\right )} + 2 \, {\left (a^{2} b p x^{7} + a^{2} b q x^{2}\right )} \sqrt {-\frac {1}{a^{3} b}}}{a p^{2} x^{10} + 2 \, a p q x^{5} + b x^{4} + a q^{2}}\right ) \]
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\[ \int \frac {\sqrt {q+p x^5} \left (-2 q+3 p x^5\right )}{b x^4+a \left (q+p x^5\right )^2} \, dx=\int \frac {\sqrt {p x^{5} + q} \left (3 p x^{5} - 2 q\right )}{a p^{2} x^{10} + 2 a p q x^{5} + a q^{2} + b x^{4}}\, dx \]
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\[ \int \frac {\sqrt {q+p x^5} \left (-2 q+3 p x^5\right )}{b x^4+a \left (q+p x^5\right )^2} \, dx=\int { \frac {{\left (3 \, p x^{5} - 2 \, q\right )} \sqrt {p x^{5} + q}}{b x^{4} + {\left (p x^{5} + q\right )}^{2} a} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {q+p x^5} \left (-2 q+3 p x^5\right )}{b x^4+a \left (q+p x^5\right )^2} \, dx=\text {Timed out} \]
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Time = 173.68 (sec) , antiderivative size = 498, normalized size of antiderivative = 2.98 \[ \int \frac {\sqrt {q+p x^5} \left (-2 q+3 p x^5\right )}{b x^4+a \left (q+p x^5\right )^2} \, dx=\frac {\ln \left (\frac {\left (2\,\sqrt {p\,x^5+q}\,{\left (-a^3\,b\right )}^{15/4}-a^{23/2}\,b^{7/2}\,p\,x^4+a^{19/2}\,b^{7/2}\,x\,\sqrt {-a^3\,b}\right )\,\left (2\,a^{27/2}\,b^{7/2}\,q\,\sqrt {p\,x^5+q}\,{\left (-a^3\,b\right )}^{15/4}-a^{24}\,b^8\,x^3+a^{25}\,b^7\,p\,x^4\,\left (p\,x^5+q\right )+a^{23}\,b^7\,q\,x\,\sqrt {-a^3\,b}+2\,a^{23}\,b^7\,x\,\left (p\,x^5+q\right )\,\sqrt {-a^3\,b}\right )}{\left (x^2\,\sqrt {-a^3\,b}+a^2\,q+a^2\,p\,x^5\right )\,\left (4\,q\,{\left (-a^3\,b\right )}^{15/2}+2\,p\,x^5\,{\left (-a^3\,b\right )}^{15/2}+a^{22}\,b^8\,x^2-a^{23}\,b^7\,p^2\,x^8\right )}\right )\,{\left (-a^3\,b\right )}^{1/4}}{2\,a^{3/2}\,\sqrt {b}}+\frac {\ln \left (\frac {\left (-2\,\sqrt {p\,x^5+q}\,{\left (-a^3\,b\right )}^{15/4}+a^{23/2}\,b^{7/2}\,p\,x^4\,1{}\mathrm {i}+a^{19/2}\,b^{7/2}\,x\,\sqrt {-a^3\,b}\,1{}\mathrm {i}\right )\,\left (a^{24}\,b^8\,x^3\,1{}\mathrm {i}-2\,a^{27/2}\,b^{7/2}\,q\,\sqrt {p\,x^5+q}\,{\left (-a^3\,b\right )}^{15/4}-a^{25}\,b^7\,p\,x^4\,\left (p\,x^5+q\right )\,1{}\mathrm {i}+a^{23}\,b^7\,q\,x\,\sqrt {-a^3\,b}\,1{}\mathrm {i}+a^{23}\,b^7\,x\,\left (p\,x^5+q\right )\,\sqrt {-a^3\,b}\,2{}\mathrm {i}\right )}{\left (a^2\,q-x^2\,\sqrt {-a^3\,b}+a^2\,p\,x^5\right )\,\left (4\,q\,{\left (-a^3\,b\right )}^{15/2}+2\,p\,x^5\,{\left (-a^3\,b\right )}^{15/2}-a^{22}\,b^8\,x^2+a^{23}\,b^7\,p^2\,x^8\right )}\right )\,{\left (-a^3\,b\right )}^{1/4}\,1{}\mathrm {i}}{2\,a^{3/2}\,\sqrt {b}} \]
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