Integrand size = 30, antiderivative size = 173 \[ \int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx=\frac {i (-1+x) \sqrt {2+x+2 x^2} \left (\frac {i \left (-18-107 x+73 x^2+22 x^3\right )}{600 (-1+x)^2 \sqrt {2+x+2 x^2}}-\frac {i \text {arctanh}\left (\sqrt {\frac {2}{3}}+\sqrt {\frac {2}{3}} x-\frac {\sqrt {2+x+2 x^2}}{\sqrt {3}}\right )}{12 \sqrt {3}}-\frac {91 i \text {arctanh}\left (\sqrt {\frac {2}{5}}-\sqrt {\frac {2}{5}} x+\frac {\sqrt {2+x+2 x^2}}{\sqrt {5}}\right )}{200 \sqrt {5}}\right )}{\sqrt {-(-1+x)^2 \left (2+x+2 x^2\right )}} \]
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\[ \int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx=\int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx \\ \end{align*}
Time = 0.61 (sec) , antiderivative size = 164, normalized size of antiderivative = 0.95 \[ \int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx=\frac {819 \sqrt {5} (-1+x)^2 \sqrt {2+x+2 x^2} \text {arctanh}\left (\frac {\sqrt {2}-\sqrt {2} x+\sqrt {2+x+2 x^2}}{\sqrt {5}}\right )-5 \left (-54-321 x+219 x^2+66 x^3-50 \sqrt {3} (-1+x)^2 \sqrt {2+x+2 x^2} \text {arctanh}\left (\frac {1}{3} \left (\sqrt {6}+\sqrt {6} x-\sqrt {3} \sqrt {2+x+2 x^2}\right )\right )\right )}{9000 (-1+x) \sqrt {-(-1+x)^2 \left (2+x+2 x^2\right )}} \]
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Time = 1.36 (sec) , antiderivative size = 134, normalized size of antiderivative = 0.77
method | result | size |
risch | \(-\frac {22 x^{3}+73 x^{2}-107 x -18}{600 \left (-1+x \right ) \sqrt {-\left (-1+x \right )^{2} \left (2 x^{2}+x +2\right )}}-\frac {\left (-\frac {\sqrt {3}\, \arctan \left (\frac {\left (-3+3 x \right ) \sqrt {3}}{6 \sqrt {-2 \left (1+x \right )^{2}+3 x}}\right )}{72}+\frac {91 \sqrt {5}\, \arctan \left (\frac {\left (-5-5 x \right ) \sqrt {5}}{10 \sqrt {-2 \left (-1+x \right )^{2}-5 x}}\right )}{2000}\right ) \left (-1+x \right ) \sqrt {-2 x^{2}-x -2}}{\sqrt {-\left (-1+x \right )^{2} \left (2 x^{2}+x +2\right )}}\) | \(134\) |
trager | \(\frac {\left (22 x^{3}+73 x^{2}-107 x -18\right ) \sqrt {-2 x^{4}+3 x^{3}-2 x^{2}+3 x -2}}{600 \left (-1+x \right )^{3} \left (2 x^{2}+x +2\right )}+\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+3\right ) \ln \left (-\frac {-\operatorname {RootOf}\left (\textit {\_Z}^{2}+3\right ) x^{2}+2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+3\right ) x +2 \sqrt {-2 x^{4}+3 x^{3}-2 x^{2}+3 x -2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+3\right )}{\left (1+x \right ) \left (-1+x \right )}\right )}{72}-\frac {91 \operatorname {RootOf}\left (\textit {\_Z}^{2}+5\right ) \ln \left (\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+5\right ) x^{2}+2 \sqrt {-2 x^{4}+3 x^{3}-2 x^{2}+3 x -2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+5\right )}{\left (-1+x \right )^{2}}\right )}{2000}\) | \(188\) |
default | \(-\frac {\left (250 \sqrt {3}\, \sqrt {-2 x^{2}-x -2}\, \arctan \left (\frac {\left (-1+x \right ) \sqrt {3}}{2 \sqrt {-2 x^{2}-x -2}}\right ) x^{2}+819 \sqrt {5}\, \sqrt {-2 x^{2}-x -2}\, \arctan \left (\frac {\left (1+x \right ) \sqrt {5}}{2 \sqrt {-2 x^{2}-x -2}}\right ) x^{2}-500 \sqrt {3}\, \sqrt {-2 x^{2}-x -2}\, \arctan \left (\frac {\left (-1+x \right ) \sqrt {3}}{2 \sqrt {-2 x^{2}-x -2}}\right ) x -1638 \sqrt {5}\, \sqrt {-2 x^{2}-x -2}\, \arctan \left (\frac {\left (1+x \right ) \sqrt {5}}{2 \sqrt {-2 x^{2}-x -2}}\right ) x +250 \sqrt {3}\, \arctan \left (\frac {\left (-1+x \right ) \sqrt {3}}{2 \sqrt {-2 x^{2}-x -2}}\right ) \sqrt {-2 x^{2}-x -2}+819 \sqrt {5}\, \arctan \left (\frac {\left (1+x \right ) \sqrt {5}}{2 \sqrt {-2 x^{2}-x -2}}\right ) \sqrt {-2 x^{2}-x -2}-660 x^{3}-2190 x^{2}+3210 x +540\right ) \left (-1+x \right ) \left (2 x^{2}+x +2\right )}{18000 \left (-2 x^{4}+3 x^{3}-2 x^{2}+3 x -2\right )^{\frac {3}{2}}}\) | \(287\) |
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Time = 0.31 (sec) , antiderivative size = 213, normalized size of antiderivative = 1.23 \[ \int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx=-\frac {819 \, \sqrt {5} {\left (2 \, x^{5} - 5 \, x^{4} + 5 \, x^{3} - 5 \, x^{2} + 5 \, x - 2\right )} \arctan \left (\frac {\sqrt {5} \sqrt {-2 \, x^{4} + 3 \, x^{3} - 2 \, x^{2} + 3 \, x - 2} {\left (x + 1\right )}}{2 \, {\left (2 \, x^{3} - x^{2} + x - 2\right )}}\right ) + 250 \, \sqrt {3} {\left (2 \, x^{5} - 5 \, x^{4} + 5 \, x^{3} - 5 \, x^{2} + 5 \, x - 2\right )} \arctan \left (\frac {\sqrt {3} \sqrt {-2 \, x^{4} + 3 \, x^{3} - 2 \, x^{2} + 3 \, x - 2}}{2 \, {\left (2 \, x^{2} + x + 2\right )}}\right ) - 30 \, \sqrt {-2 \, x^{4} + 3 \, x^{3} - 2 \, x^{2} + 3 \, x - 2} {\left (22 \, x^{3} + 73 \, x^{2} - 107 \, x - 18\right )}}{18000 \, {\left (2 \, x^{5} - 5 \, x^{4} + 5 \, x^{3} - 5 \, x^{2} + 5 \, x - 2\right )}} \]
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\[ \int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx=\int \frac {1}{\left (- \left (x - 1\right )^{2} \cdot \left (2 x^{2} + x + 2\right )\right )^{\frac {3}{2}} \left (x + 1\right )}\, dx \]
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\[ \int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx=\int { \frac {1}{{\left (-2 \, x^{4} + 3 \, x^{3} - 2 \, x^{2} + 3 \, x - 2\right )}^{\frac {3}{2}} {\left (x + 1\right )}} \,d x } \]
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\[ \int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx=\int { \frac {1}{{\left (-2 \, x^{4} + 3 \, x^{3} - 2 \, x^{2} + 3 \, x - 2\right )}^{\frac {3}{2}} {\left (x + 1\right )}} \,d x } \]
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Timed out. \[ \int \frac {1}{(1+x) \left (-2+3 x-2 x^2+3 x^3-2 x^4\right )^{3/2}} \, dx=\int \frac {1}{\left (x+1\right )\,{\left (-2\,x^4+3\,x^3-2\,x^2+3\,x-2\right )}^{3/2}} \,d x \]
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