Integrand size = 60, antiderivative size = 191 \[ \int \frac {\left (-q+2 p x^3\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (b x^3+a \left (q+p x^3\right )^3\right )}{x^6} \, dx=\frac {\sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (6 a q^4-4 a p q^3 x^2+15 b q x^3+24 a p q^3 x^3-16 a p^2 q^2 x^4-8 a p^2 q^2 x^5+15 b p x^6+36 a p^2 q^2 x^6-4 a p^3 q x^8+24 a p^3 q x^9+6 a p^4 x^{12}\right )}{30 x^5}+b p q \log (x)-b p q \log \left (q+p x^3+\sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6}\right ) \]
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\[ \int \frac {\left (-q+2 p x^3\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (b x^3+a \left (q+p x^3\right )^3\right )}{x^6} \, dx=\int \frac {\left (-q+2 p x^3\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (b x^3+a \left (q+p x^3\right )^3\right )}{x^6} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (p \left (2 b+3 a p q^2\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6}-\frac {a q^4 \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6}}{x^6}-\frac {q \left (b+a p q^2\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6}}{x^3}+5 a p^3 q x^3 \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6}+2 a p^4 x^6 \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6}\right ) \, dx \\ & = \left (2 a p^4\right ) \int x^6 \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \, dx+\left (5 a p^3 q\right ) \int x^3 \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \, dx-\left (a q^4\right ) \int \frac {\sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6}}{x^6} \, dx-\left (q \left (b+a p q^2\right )\right ) \int \frac {\sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6}}{x^3} \, dx+\left (p \left (2 b+3 a p q^2\right )\right ) \int \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \, dx \\ \end{align*}
Time = 0.44 (sec) , antiderivative size = 157, normalized size of antiderivative = 0.82 \[ \int \frac {\left (-q+2 p x^3\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (b x^3+a \left (q+p x^3\right )^3\right )}{x^6} \, dx=\frac {\sqrt {q^2+2 p q (-1+x) x^2+p^2 x^6} \left (15 b x^3 \left (q+p x^3\right )+2 a \left (3 q^4+3 p^4 x^{12}+2 p q^3 x^2 (-1+6 x)+2 p^3 q x^8 (-1+6 x)+2 p^2 q^2 x^4 \left (-4-2 x+9 x^2\right )\right )\right )}{30 x^5}+b p q \log (x)-b p q \log \left (q+p x^3+\sqrt {q^2+2 p q (-1+x) x^2+p^2 x^6}\right ) \]
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Time = 0.25 (sec) , antiderivative size = 178, normalized size of antiderivative = 0.93
method | result | size |
pseudoelliptic | \(\frac {\left (6 a \,p^{4} x^{12}+24 a \,p^{3} q \,x^{9}-4 a \,p^{3} q \,x^{8}+\left (36 q^{2} a \,p^{2}+15 b p \right ) x^{6}-8 a \,p^{2} q^{2} x^{5}-16 a \,p^{2} q^{2} x^{4}+\left (24 a \,q^{3} p +15 q b \right ) x^{3}-4 a p \,q^{3} x^{2}+6 a \,q^{4}\right ) \sqrt {p^{2} x^{6}+2 p q \,x^{2} \left (-1+x \right )+q^{2}}-30 b p q \ln \left (\frac {q +p \,x^{3}+\sqrt {p^{2} x^{6}+2 p q \,x^{2} \left (-1+x \right )+q^{2}}}{x}\right ) x^{5}}{30 x^{5}}\) | \(178\) |
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Time = 9.31 (sec) , antiderivative size = 188, normalized size of antiderivative = 0.98 \[ \int \frac {\left (-q+2 p x^3\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (b x^3+a \left (q+p x^3\right )^3\right )}{x^6} \, dx=-\frac {30 \, b p q x^{5} \log \left (\frac {p x^{3} + q + \sqrt {p^{2} x^{6} + 2 \, p q x^{3} - 2 \, p q x^{2} + q^{2}}}{x}\right ) - {\left (6 \, a p^{4} x^{12} + 24 \, a p^{3} q x^{9} - 4 \, a p^{3} q x^{8} - 8 \, a p^{2} q^{2} x^{5} - 16 \, a p^{2} q^{2} x^{4} - 4 \, a p q^{3} x^{2} + 3 \, {\left (12 \, a p^{2} q^{2} + 5 \, b p\right )} x^{6} + 6 \, a q^{4} + 3 \, {\left (8 \, a p q^{3} + 5 \, b q\right )} x^{3}\right )} \sqrt {p^{2} x^{6} + 2 \, p q x^{3} - 2 \, p q x^{2} + q^{2}}}{30 \, x^{5}} \]
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\[ \int \frac {\left (-q+2 p x^3\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (b x^3+a \left (q+p x^3\right )^3\right )}{x^6} \, dx=\int \frac {\left (2 p x^{3} - q\right ) \sqrt {p^{2} x^{6} + 2 p q x^{3} - 2 p q x^{2} + q^{2}} \left (a p^{3} x^{9} + 3 a p^{2} q x^{6} + 3 a p q^{2} x^{3} + a q^{3} + b x^{3}\right )}{x^{6}}\, dx \]
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\[ \int \frac {\left (-q+2 p x^3\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (b x^3+a \left (q+p x^3\right )^3\right )}{x^6} \, dx=\int { \frac {\sqrt {p^{2} x^{6} + 2 \, p q x^{3} - 2 \, p q x^{2} + q^{2}} {\left ({\left (p x^{3} + q\right )}^{3} a + b x^{3}\right )} {\left (2 \, p x^{3} - q\right )}}{x^{6}} \,d x } \]
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\[ \int \frac {\left (-q+2 p x^3\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (b x^3+a \left (q+p x^3\right )^3\right )}{x^6} \, dx=\int { \frac {\sqrt {p^{2} x^{6} + 2 \, p q x^{3} - 2 \, p q x^{2} + q^{2}} {\left ({\left (p x^{3} + q\right )}^{3} a + b x^{3}\right )} {\left (2 \, p x^{3} - q\right )}}{x^{6}} \,d x } \]
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Timed out. \[ \int \frac {\left (-q+2 p x^3\right ) \sqrt {q^2-2 p q x^2+2 p q x^3+p^2 x^6} \left (b x^3+a \left (q+p x^3\right )^3\right )}{x^6} \, dx=-\int \frac {\left (q-2\,p\,x^3\right )\,\left (a\,{\left (p\,x^3+q\right )}^3+b\,x^3\right )\,\sqrt {p^2\,x^6+2\,p\,q\,x^3-2\,p\,q\,x^2+q^2}}{x^6} \,d x \]
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