Integrand size = 46, antiderivative size = 207 \[ \int \frac {x^7 (-4 a+3 x)}{\left (x^2 (-a+x)\right )^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx=-\frac {\sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [6]{d} x^2}{\sqrt [6]{d} x^2-2 \sqrt [3]{-a x^2+x^3}}\right )}{2 d^{5/6}}+\frac {\sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [6]{d} x^2}{\sqrt [6]{d} x^2+2 \sqrt [3]{-a x^2+x^3}}\right )}{2 d^{5/6}}+\frac {\text {arctanh}\left (\frac {\sqrt [6]{d} \left (-a x^2+x^3\right )^{2/3}}{a-x}\right )}{d^{5/6}}-\frac {\text {arctanh}\left (\frac {\sqrt [6]{d} x^4+\frac {\left (-a x^2+x^3\right )^{2/3}}{\sqrt [6]{d}}}{x^2 \sqrt [3]{-a x^2+x^3}}\right )}{2 d^{5/6}} \]
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\[ \int \frac {x^7 (-4 a+3 x)}{\left (x^2 (-a+x)\right )^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx=\int \frac {x^7 (-4 a+3 x)}{\left (x^2 (-a+x)\right )^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\left (x^{4/3} (-a+x)^{2/3}\right ) \int \frac {x^{17/3} (-4 a+3 x)}{(-a+x)^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx}{\left (x^2 (-a+x)\right )^{2/3}} \\ & = \frac {\left (3 x^{4/3} (-a+x)^{2/3}\right ) \text {Subst}\left (\int \frac {x^{19} \left (-4 a+3 x^3\right )}{\left (-a+x^3\right )^{2/3} \left (-a^2+2 a x^3-x^6+d x^{24}\right )} \, dx,x,\sqrt [3]{x}\right )}{\left (x^2 (-a+x)\right )^{2/3}} \\ & = \frac {\left (3 x^{4/3} (-a+x)^{2/3}\right ) \text {Subst}\left (\int \left (\frac {4 a x^{19}}{\left (-a+x^3\right )^{2/3} \left (a^2-2 a x^3+x^6-d x^{24}\right )}+\frac {3 x^{22}}{\left (-a+x^3\right )^{2/3} \left (-a^2+2 a x^3-x^6+d x^{24}\right )}\right ) \, dx,x,\sqrt [3]{x}\right )}{\left (x^2 (-a+x)\right )^{2/3}} \\ & = \frac {\left (9 x^{4/3} (-a+x)^{2/3}\right ) \text {Subst}\left (\int \frac {x^{22}}{\left (-a+x^3\right )^{2/3} \left (-a^2+2 a x^3-x^6+d x^{24}\right )} \, dx,x,\sqrt [3]{x}\right )}{\left (x^2 (-a+x)\right )^{2/3}}+\frac {\left (12 a x^{4/3} (-a+x)^{2/3}\right ) \text {Subst}\left (\int \frac {x^{19}}{\left (-a+x^3\right )^{2/3} \left (a^2-2 a x^3+x^6-d x^{24}\right )} \, dx,x,\sqrt [3]{x}\right )}{\left (x^2 (-a+x)\right )^{2/3}} \\ \end{align*}
Time = 0.30 (sec) , antiderivative size = 175, normalized size of antiderivative = 0.85 \[ \int \frac {x^7 (-4 a+3 x)}{\left (x^2 (-a+x)\right )^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx=\frac {x^{4/3} (-a+x)^{2/3} \left (\sqrt {3} \left (\arctan \left (\frac {1-\frac {2 \sqrt [3]{-a+x}}{\sqrt [6]{d} x^{4/3}}}{\sqrt {3}}\right )-\arctan \left (\frac {1+\frac {2 \sqrt [3]{-a+x}}{\sqrt [6]{d} x^{4/3}}}{\sqrt {3}}\right )\right )-2 \text {arctanh}\left (\frac {\sqrt [3]{-a+x}}{\sqrt [6]{d} x^{4/3}}\right )-\text {arctanh}\left (\frac {\sqrt [6]{d} x^{4/3} \sqrt [3]{-a+x}}{\sqrt [3]{d} x^{8/3}+(-a+x)^{2/3}}\right )\right )}{2 d^{5/6} \left (x^2 (-a+x)\right )^{2/3}} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.25 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.42
method | result | size |
pseudoelliptic | \(-\frac {a^{5} \left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{24}-6 \textit {\_Z}^{21}+15 \textit {\_Z}^{18}-20 \textit {\_Z}^{15}+15 \textit {\_Z}^{12}-6 \textit {\_Z}^{9}-a^{6} d +\textit {\_Z}^{6}\right )}{\sum }\frac {\ln \left (\frac {-\textit {\_R} x +\left (-x^{2} \left (a -x \right )\right )^{\frac {1}{3}}}{x}\right )}{\left (\textit {\_R} -1\right )^{5} \left (\textit {\_R}^{2}+\textit {\_R} +1\right )^{5} \textit {\_R}^{5}}\right )}{2}\) | \(87\) |
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Time = 0.29 (sec) , antiderivative size = 288, normalized size of antiderivative = 1.39 \[ \int \frac {x^7 (-4 a+3 x)}{\left (x^2 (-a+x)\right )^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx=-\frac {1}{4} \, {\left (\sqrt {-3} + 1\right )} \frac {1}{d^{5}}^{\frac {1}{6}} \log \left (-\frac {{\left (\sqrt {-3} d x^{2} + d x^{2}\right )} \frac {1}{d^{5}}^{\frac {1}{6}} + 2 \, {\left (-a x^{2} + x^{3}\right )}^{\frac {1}{3}}}{2 \, x^{2}}\right ) + \frac {1}{4} \, {\left (\sqrt {-3} + 1\right )} \frac {1}{d^{5}}^{\frac {1}{6}} \log \left (\frac {{\left (\sqrt {-3} d x^{2} + d x^{2}\right )} \frac {1}{d^{5}}^{\frac {1}{6}} - 2 \, {\left (-a x^{2} + x^{3}\right )}^{\frac {1}{3}}}{2 \, x^{2}}\right ) - \frac {1}{4} \, {\left (\sqrt {-3} - 1\right )} \frac {1}{d^{5}}^{\frac {1}{6}} \log \left (-\frac {{\left (\sqrt {-3} d x^{2} - d x^{2}\right )} \frac {1}{d^{5}}^{\frac {1}{6}} + 2 \, {\left (-a x^{2} + x^{3}\right )}^{\frac {1}{3}}}{2 \, x^{2}}\right ) + \frac {1}{4} \, {\left (\sqrt {-3} - 1\right )} \frac {1}{d^{5}}^{\frac {1}{6}} \log \left (\frac {{\left (\sqrt {-3} d x^{2} - d x^{2}\right )} \frac {1}{d^{5}}^{\frac {1}{6}} - 2 \, {\left (-a x^{2} + x^{3}\right )}^{\frac {1}{3}}}{2 \, x^{2}}\right ) - \frac {1}{2} \, \frac {1}{d^{5}}^{\frac {1}{6}} \log \left (-\frac {d \frac {1}{d^{5}}^{\frac {1}{6}} x^{2} + {\left (-a x^{2} + x^{3}\right )}^{\frac {1}{3}}}{x^{2}}\right ) + \frac {1}{2} \, \frac {1}{d^{5}}^{\frac {1}{6}} \log \left (\frac {d \frac {1}{d^{5}}^{\frac {1}{6}} x^{2} - {\left (-a x^{2} + x^{3}\right )}^{\frac {1}{3}}}{x^{2}}\right ) \]
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\[ \int \frac {x^7 (-4 a+3 x)}{\left (x^2 (-a+x)\right )^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx=\int \frac {x^{7} \left (- 4 a + 3 x\right )}{\left (x^{2} \left (- a + x\right )\right )^{\frac {2}{3}} \left (- a^{2} + 2 a x + d x^{8} - x^{2}\right )}\, dx \]
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\[ \int \frac {x^7 (-4 a+3 x)}{\left (x^2 (-a+x)\right )^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx=\int { -\frac {{\left (4 \, a - 3 \, x\right )} x^{7}}{{\left (d x^{8} - a^{2} + 2 \, a x - x^{2}\right )} \left (-{\left (a - x\right )} x^{2}\right )^{\frac {2}{3}}} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 399 vs. \(2 (161) = 322\).
Time = 0.50 (sec) , antiderivative size = 399, normalized size of antiderivative = 1.93 \[ \int \frac {x^7 (-4 a+3 x)}{\left (x^2 (-a+x)\right )^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx=\frac {1}{2} \, \sqrt {3} \frac {1}{d^{5}}^{\frac {1}{6}} \arctan \left (\frac {\sqrt {3} {\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} - \sqrt {3} a d^{\frac {1}{6}} - \sqrt {3} {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}}}{{\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} + a d^{\frac {1}{6}} - {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}}}\right ) + \frac {1}{2} \, \sqrt {3} \frac {1}{d^{5}}^{\frac {1}{6}} \arctan \left (-\frac {\sqrt {3} {\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} + \sqrt {3} a d^{\frac {1}{6}} - \sqrt {3} {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}}}{{\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} - a d^{\frac {1}{6}} - {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}}}\right ) + \frac {1}{4} \, \frac {1}{d^{5}}^{\frac {1}{6}} \log \left ({\left (\sqrt {3} {\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} + \sqrt {3} a d^{\frac {1}{6}} - \sqrt {3} {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}}\right )}^{2} + {\left ({\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} - a d^{\frac {1}{6}} - {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}}\right )}^{2}\right ) - \frac {1}{4} \, \frac {1}{d^{5}}^{\frac {1}{6}} \log \left ({\left (\sqrt {3} {\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} - \sqrt {3} a d^{\frac {1}{6}} - \sqrt {3} {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}}\right )}^{2} + {\left ({\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} + a d^{\frac {1}{6}} - {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}}\right )}^{2}\right ) + \frac {1}{2} \, \frac {1}{d^{5}}^{\frac {1}{6}} \log \left ({\left | {\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} + a d^{\frac {1}{6}} - {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}} \right |}\right ) - \frac {1}{2} \, \frac {1}{d^{5}}^{\frac {1}{6}} \log \left ({\left | {\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} - a d^{\frac {1}{6}} - {\left (-\frac {a}{x} + 1\right )}^{\frac {1}{3}} \right |}\right ) \]
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Timed out. \[ \int \frac {x^7 (-4 a+3 x)}{\left (x^2 (-a+x)\right )^{2/3} \left (-a^2+2 a x-x^2+d x^8\right )} \, dx=\int -\frac {x^7\,\left (4\,a-3\,x\right )}{{\left (-x^2\,\left (a-x\right )\right )}^{2/3}\,\left (-a^2+2\,a\,x+d\,x^8-x^2\right )} \,d x \]
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