Integrand size = 30, antiderivative size = 214 \[ \int \frac {\left (-1+x^3\right )^{2/3} \left (8+2 x^3+x^6\right )}{x^6 \left (-2+x^3\right )} \, dx=\frac {\left (-1+x^3\right )^{2/3} \left (8+7 x^3\right )}{10 x^5}+\frac {\arctan \left (\frac {\sqrt {3} x}{x+2 \sqrt [3]{-1+x^3}}\right )}{\sqrt {3}}-\frac {2 \sqrt [3]{2} \arctan \left (\frac {\sqrt {3} x}{x+2 \sqrt [3]{2} \sqrt [3]{-1+x^3}}\right )}{\sqrt {3}}-\frac {1}{3} \log \left (-x+\sqrt [3]{-1+x^3}\right )+\frac {2}{3} \sqrt [3]{2} \log \left (-x+\sqrt [3]{2} \sqrt [3]{-1+x^3}\right )+\frac {1}{6} \log \left (x^2+x \sqrt [3]{-1+x^3}+\left (-1+x^3\right )^{2/3}\right )-\frac {1}{3} \sqrt [3]{2} \log \left (x^2+\sqrt [3]{2} x \sqrt [3]{-1+x^3}+2^{2/3} \left (-1+x^3\right )^{2/3}\right ) \]
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Time = 0.24 (sec) , antiderivative size = 185, normalized size of antiderivative = 0.86, number of steps used = 8, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {6857, 270, 283, 245, 399, 384} \[ \int \frac {\left (-1+x^3\right )^{2/3} \left (8+2 x^3+x^6\right )}{x^6 \left (-2+x^3\right )} \, dx=-\sqrt {3} \arctan \left (\frac {\frac {2 x}{\sqrt [3]{x^3-1}}+1}{\sqrt {3}}\right )+\frac {4 \arctan \left (\frac {\frac {2 x}{\sqrt [3]{x^3-1}}+1}{\sqrt {3}}\right )}{\sqrt {3}}-\frac {2 \sqrt [3]{2} \arctan \left (\frac {\frac {2^{2/3} x}{\sqrt [3]{x^3-1}}+1}{\sqrt {3}}\right )}{\sqrt {3}}-\frac {1}{3} \sqrt [3]{2} \log \left (x^3-2\right )+\sqrt [3]{2} \log \left (\frac {x}{\sqrt [3]{2}}-\sqrt [3]{x^3-1}\right )-\frac {1}{2} \log \left (\sqrt [3]{x^3-1}-x\right )-\frac {4 \left (x^3-1\right )^{5/3}}{5 x^5}+\frac {3 \left (x^3-1\right )^{2/3}}{2 x^2} \]
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Rule 245
Rule 270
Rule 283
Rule 384
Rule 399
Rule 6857
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {4 \left (-1+x^3\right )^{2/3}}{x^6}-\frac {3 \left (-1+x^3\right )^{2/3}}{x^3}+\frac {4 \left (-1+x^3\right )^{2/3}}{-2+x^3}\right ) \, dx \\ & = -\left (3 \int \frac {\left (-1+x^3\right )^{2/3}}{x^3} \, dx\right )-4 \int \frac {\left (-1+x^3\right )^{2/3}}{x^6} \, dx+4 \int \frac {\left (-1+x^3\right )^{2/3}}{-2+x^3} \, dx \\ & = \frac {3 \left (-1+x^3\right )^{2/3}}{2 x^2}-\frac {4 \left (-1+x^3\right )^{5/3}}{5 x^5}-3 \int \frac {1}{\sqrt [3]{-1+x^3}} \, dx+4 \int \frac {1}{\sqrt [3]{-1+x^3}} \, dx+4 \int \frac {1}{\left (-2+x^3\right ) \sqrt [3]{-1+x^3}} \, dx \\ & = \frac {3 \left (-1+x^3\right )^{2/3}}{2 x^2}-\frac {4 \left (-1+x^3\right )^{5/3}}{5 x^5}+\frac {4 \arctan \left (\frac {1+\frac {2 x}{\sqrt [3]{-1+x^3}}}{\sqrt {3}}\right )}{\sqrt {3}}-\sqrt {3} \arctan \left (\frac {1+\frac {2 x}{\sqrt [3]{-1+x^3}}}{\sqrt {3}}\right )-\frac {2 \sqrt [3]{2} \arctan \left (\frac {1+\frac {2^{2/3} x}{\sqrt [3]{-1+x^3}}}{\sqrt {3}}\right )}{\sqrt {3}}-\frac {1}{3} \sqrt [3]{2} \log \left (-2+x^3\right )+\sqrt [3]{2} \log \left (\frac {x}{\sqrt [3]{2}}-\sqrt [3]{-1+x^3}\right )-\frac {1}{2} \log \left (-x+\sqrt [3]{-1+x^3}\right ) \\ \end{align*}
Time = 0.41 (sec) , antiderivative size = 209, normalized size of antiderivative = 0.98 \[ \int \frac {\left (-1+x^3\right )^{2/3} \left (8+2 x^3+x^6\right )}{x^6 \left (-2+x^3\right )} \, dx=\frac {1}{30} \left (\frac {3 \left (-1+x^3\right )^{2/3} \left (8+7 x^3\right )}{x^5}+10 \sqrt {3} \arctan \left (\frac {\sqrt {3} x}{x+2 \sqrt [3]{-1+x^3}}\right )-20 \sqrt [3]{2} \sqrt {3} \arctan \left (\frac {\sqrt {3} x}{x+2 \sqrt [3]{2} \sqrt [3]{-1+x^3}}\right )-10 \log \left (-x+\sqrt [3]{-1+x^3}\right )+20 \sqrt [3]{2} \log \left (-x+\sqrt [3]{2} \sqrt [3]{-1+x^3}\right )+5 \log \left (x^2+x \sqrt [3]{-1+x^3}+\left (-1+x^3\right )^{2/3}\right )-10 \sqrt [3]{2} \log \left (x^2+\sqrt [3]{2} x \sqrt [3]{-1+x^3}+2^{2/3} \left (-1+x^3\right )^{2/3}\right )\right ) \]
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Time = 2.38 (sec) , antiderivative size = 222, normalized size of antiderivative = 1.04
method | result | size |
pseudoelliptic | \(\frac {20 \sqrt {3}\, 2^{\frac {1}{3}} \arctan \left (\frac {\sqrt {3}\, \left (x +2 \,2^{\frac {1}{3}} \left (x^{3}-1\right )^{\frac {1}{3}}\right )}{3 x}\right ) x^{5}-10 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (x +2 \left (x^{3}-1\right )^{\frac {1}{3}}\right )}{3 x}\right ) x^{5}+20 \,2^{\frac {1}{3}} x^{5} \ln \left (\frac {-2^{\frac {2}{3}} x +2 \left (x^{3}-1\right )^{\frac {1}{3}}}{x}\right )-10 \,2^{\frac {1}{3}} x^{5} \ln \left (\frac {2^{\frac {2}{3}} x \left (x^{3}-1\right )^{\frac {1}{3}}+2^{\frac {1}{3}} x^{2}+2 \left (x^{3}-1\right )^{\frac {2}{3}}}{x^{2}}\right )-10 \,2^{\frac {1}{3}} x^{5} \ln \left (2\right )-10 \ln \left (\frac {-x +\left (x^{3}-1\right )^{\frac {1}{3}}}{x}\right ) x^{5}+5 \ln \left (\frac {x^{2}+x \left (x^{3}-1\right )^{\frac {1}{3}}+\left (x^{3}-1\right )^{\frac {2}{3}}}{x^{2}}\right ) x^{5}+21 x^{3} \left (x^{3}-1\right )^{\frac {2}{3}}+24 \left (x^{3}-1\right )^{\frac {2}{3}}}{30 x^{5}}\) | \(222\) |
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Leaf count of result is larger than twice the leaf count of optimal. 360 vs. \(2 (165) = 330\).
Time = 14.28 (sec) , antiderivative size = 360, normalized size of antiderivative = 1.68 \[ \int \frac {\left (-1+x^3\right )^{2/3} \left (8+2 x^3+x^6\right )}{x^6 \left (-2+x^3\right )} \, dx=\frac {20 \, \sqrt {3} 2^{\frac {1}{3}} x^{5} \arctan \left (\frac {12 \, \sqrt {3} 2^{\frac {2}{3}} {\left (2 \, x^{7} - 5 \, x^{4} + 2 \, x\right )} {\left (x^{3} - 1\right )}^{\frac {2}{3}} + 6 \, \sqrt {3} 2^{\frac {1}{3}} {\left (19 \, x^{8} - 22 \, x^{5} + 4 \, x^{2}\right )} {\left (x^{3} - 1\right )}^{\frac {1}{3}} + \sqrt {3} {\left (91 \, x^{9} - 168 \, x^{6} + 84 \, x^{3} - 8\right )}}{3 \, {\left (53 \, x^{9} - 48 \, x^{6} - 12 \, x^{3} + 8\right )}}\right ) + 30 \, \sqrt {3} x^{5} \arctan \left (-\frac {25382 \, \sqrt {3} {\left (x^{3} - 1\right )}^{\frac {1}{3}} x^{2} - 13720 \, \sqrt {3} {\left (x^{3} - 1\right )}^{\frac {2}{3}} x + \sqrt {3} {\left (5831 \, x^{3} - 7200\right )}}{58653 \, x^{3} - 8000}\right ) + 20 \cdot 2^{\frac {1}{3}} x^{5} \log \left (-\frac {3 \cdot 2^{\frac {2}{3}} {\left (x^{3} - 1\right )}^{\frac {1}{3}} x^{2} - 6 \, {\left (x^{3} - 1\right )}^{\frac {2}{3}} x + 2^{\frac {1}{3}} {\left (x^{3} - 2\right )}}{x^{3} - 2}\right ) - 10 \cdot 2^{\frac {1}{3}} x^{5} \log \left (\frac {12 \cdot 2^{\frac {1}{3}} {\left (2 \, x^{4} - x\right )} {\left (x^{3} - 1\right )}^{\frac {2}{3}} + 2^{\frac {2}{3}} {\left (19 \, x^{6} - 22 \, x^{3} + 4\right )} + 6 \, {\left (5 \, x^{5} - 4 \, x^{2}\right )} {\left (x^{3} - 1\right )}^{\frac {1}{3}}}{x^{6} - 4 \, x^{3} + 4}\right ) - 15 \, x^{5} \log \left (-3 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}} x^{2} + 3 \, {\left (x^{3} - 1\right )}^{\frac {2}{3}} x + 1\right ) + 9 \, {\left (7 \, x^{3} + 8\right )} {\left (x^{3} - 1\right )}^{\frac {2}{3}}}{90 \, x^{5}} \]
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\[ \int \frac {\left (-1+x^3\right )^{2/3} \left (8+2 x^3+x^6\right )}{x^6 \left (-2+x^3\right )} \, dx=\int \frac {\left (\left (x - 1\right ) \left (x^{2} + x + 1\right )\right )^{\frac {2}{3}} \left (x^{6} + 2 x^{3} + 8\right )}{x^{6} \left (x^{3} - 2\right )}\, dx \]
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\[ \int \frac {\left (-1+x^3\right )^{2/3} \left (8+2 x^3+x^6\right )}{x^6 \left (-2+x^3\right )} \, dx=\int { \frac {{\left (x^{6} + 2 \, x^{3} + 8\right )} {\left (x^{3} - 1\right )}^{\frac {2}{3}}}{{\left (x^{3} - 2\right )} x^{6}} \,d x } \]
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\[ \int \frac {\left (-1+x^3\right )^{2/3} \left (8+2 x^3+x^6\right )}{x^6 \left (-2+x^3\right )} \, dx=\int { \frac {{\left (x^{6} + 2 \, x^{3} + 8\right )} {\left (x^{3} - 1\right )}^{\frac {2}{3}}}{{\left (x^{3} - 2\right )} x^{6}} \,d x } \]
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Timed out. \[ \int \frac {\left (-1+x^3\right )^{2/3} \left (8+2 x^3+x^6\right )}{x^6 \left (-2+x^3\right )} \, dx=\int \frac {{\left (x^3-1\right )}^{2/3}\,\left (x^6+2\,x^3+8\right )}{x^6\,\left (x^3-2\right )} \,d x \]
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