Integrand size = 44, antiderivative size = 216 \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx=\frac {\sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [3]{a b+(-a-b) x+x^2}}{-2 a \sqrt [3]{d}+2 \sqrt [3]{d} x+\sqrt [3]{a b+(-a-b) x+x^2}}\right )}{\sqrt [3]{d}}+\frac {\log \left (a \sqrt [3]{d}-\sqrt [3]{d} x+\sqrt [3]{a b+(-a-b) x+x^2}\right )}{\sqrt [3]{d}}-\frac {\log \left (a^2 d^{2/3}-2 a d^{2/3} x+d^{2/3} x^2+\left (-a \sqrt [3]{d}+\sqrt [3]{d} x\right ) \sqrt [3]{a b+(-a-b) x+x^2}+\left (a b+(-a-b) x+x^2\right )^{2/3}\right )}{2 \sqrt [3]{d}} \]
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\[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx=\int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {a-2 b+x}{\sqrt [3]{a b+(-a-b) x+x^2} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx \\ \end{align*}
Time = 5.41 (sec) , antiderivative size = 175, normalized size of antiderivative = 0.81 \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx=\frac {\sqrt [3]{a-x} \sqrt [3]{b-x} \left (2 \sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [3]{b-x}}{-2 \sqrt [3]{d} (a-x)^{2/3}+\sqrt [3]{b-x}}\right )+2 \log \left (\sqrt [3]{d} (a-x)^{2/3}+\sqrt [3]{b-x}\right )-\log \left (d^{2/3} (a-x)^{4/3}-\sqrt [3]{d} (a-x)^{2/3} \sqrt [3]{b-x}+(b-x)^{2/3}\right )\right )}{2 \sqrt [3]{d} \sqrt [3]{(-a+x) (-b+x)}} \]
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\[\int \frac {a -2 b +x}{\left (\left (-a +x \right ) \left (-b +x \right )\right )^{\frac {1}{3}} \left (b +a^{2} d +\left (-2 a d -1\right ) x +d \,x^{2}\right )}d x\]
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Timed out. \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx=\int { \frac {a - 2 \, b + x}{{\left (a^{2} d + d x^{2} - {\left (2 \, a d + 1\right )} x + b\right )} \left ({\left (a - x\right )} {\left (b - x\right )}\right )^{\frac {1}{3}}} \,d x } \]
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\[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx=\int { \frac {a - 2 \, b + x}{{\left (a^{2} d + d x^{2} - {\left (2 \, a d + 1\right )} x + b\right )} \left ({\left (a - x\right )} {\left (b - x\right )}\right )^{\frac {1}{3}}} \,d x } \]
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Timed out. \[ \int \frac {a-2 b+x}{\sqrt [3]{(-a+x) (-b+x)} \left (b+a^2 d+(-1-2 a d) x+d x^2\right )} \, dx=\int \frac {a-2\,b+x}{{\left (\left (a-x\right )\,\left (b-x\right )\right )}^{1/3}\,\left (b-x\,\left (2\,a\,d+1\right )+a^2\,d+d\,x^2\right )} \,d x \]
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