Integrand size = 40, antiderivative size = 219 \[ \int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx=\frac {\sqrt {a} x \sqrt {b+a^2 x^4} \left (28 a b x^2+16 a^3 x^6\right ) \sqrt {a x^2+\sqrt {b+a^2 x^4}}+\sqrt {a} x \left (9 b^2+36 a^2 b x^4+16 a^4 x^8\right ) \sqrt {a x^2+\sqrt {b+a^2 x^4}}}{48 a^{3/2} b+96 a^{7/2} x^4+96 a^{5/2} x^2 \sqrt {b+a^2 x^4}}-\frac {3 b^{3/2} \arctan \left (\frac {\sqrt {2} \sqrt {a} x \sqrt {a x^2+\sqrt {b+a^2 x^4}}}{\sqrt {b}}\right )}{16 \sqrt {2} a^{3/2}} \]
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\[ \int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx=\int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx \\ \end{align*}
Time = 0.36 (sec) , antiderivative size = 185, normalized size of antiderivative = 0.84 \[ \int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx=\frac {\frac {2 \sqrt {a} x \sqrt {a x^2+\sqrt {b+a^2 x^4}} \left (9 b^2+16 a^3 x^6 \left (a x^2+\sqrt {b+a^2 x^4}\right )+4 a b x^2 \left (9 a x^2+7 \sqrt {b+a^2 x^4}\right )\right )}{b+2 a x^2 \left (a x^2+\sqrt {b+a^2 x^4}\right )}-9 \sqrt {2} b^{3/2} \arctan \left (\frac {\sqrt {2} \sqrt {a} x \sqrt {a x^2+\sqrt {b+a^2 x^4}}}{\sqrt {b}}\right )}{96 a^{3/2}} \]
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\[\int x^{2} \sqrt {a^{2} x^{4}+b}\, \sqrt {a \,x^{2}+\sqrt {a^{2} x^{4}+b}}d x\]
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Time = 1.99 (sec) , antiderivative size = 319, normalized size of antiderivative = 1.46 \[ \int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx=\left [\frac {9 \, \sqrt {\frac {1}{2}} b \sqrt {-\frac {b}{a}} \log \left (4 \, a^{2} b x^{4} - 4 \, \sqrt {a^{2} x^{4} + b} a b x^{2} + b^{2} - 4 \, {\left (2 \, \sqrt {\frac {1}{2}} \sqrt {a^{2} x^{4} + b} a^{2} x^{3} \sqrt {-\frac {b}{a}} - \sqrt {\frac {1}{2}} {\left (2 \, a^{3} x^{5} + a b x\right )} \sqrt {-\frac {b}{a}}\right )} \sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}}\right ) - 2 \, {\left (2 \, a^{2} x^{5} - 10 \, \sqrt {a^{2} x^{4} + b} a x^{3} - 9 \, b x\right )} \sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}}}{96 \, a}, \frac {9 \, \sqrt {\frac {1}{2}} b \sqrt {\frac {b}{a}} \arctan \left (-\frac {{\left (\sqrt {\frac {1}{2}} a x^{2} \sqrt {\frac {b}{a}} - \sqrt {\frac {1}{2}} \sqrt {a^{2} x^{4} + b} \sqrt {\frac {b}{a}}\right )} \sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}}}{b x}\right ) - {\left (2 \, a^{2} x^{5} - 10 \, \sqrt {a^{2} x^{4} + b} a x^{3} - 9 \, b x\right )} \sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}}}{48 \, a}\right ] \]
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\[ \int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx=\int x^{2} \sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}} \sqrt {a^{2} x^{4} + b}\, dx \]
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\[ \int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx=\int { \sqrt {a^{2} x^{4} + b} \sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}} x^{2} \,d x } \]
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\[ \int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx=\int { \sqrt {a^{2} x^{4} + b} \sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}} x^{2} \,d x } \]
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Timed out. \[ \int x^2 \sqrt {b+a^2 x^4} \sqrt {a x^2+\sqrt {b+a^2 x^4}} \, dx=\int x^2\,\sqrt {\sqrt {a^2\,x^4+b}+a\,x^2}\,\sqrt {a^2\,x^4+b} \,d x \]
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