Integrand size = 45, antiderivative size = 221 \[ \int \frac {(-4+3 x) \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{(-1+x) x} \, dx=-\frac {2 \sqrt [4]{a} \arctan \left (\frac {\sqrt [4]{c} \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{\sqrt [4]{a}}\right )}{\sqrt [4]{c}}+\frac {2 \sqrt [4]{b} \arctan \left (\frac {\sqrt [4]{d} \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{\sqrt [4]{b}}\right )}{\sqrt [4]{d}}-\frac {2 \sqrt [4]{a} \text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{\sqrt [4]{a}}\right )}{\sqrt [4]{c}}+\frac {2 \sqrt [4]{b} \text {arctanh}\left (\frac {\sqrt [4]{d} \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{\sqrt [4]{b}}\right )}{\sqrt [4]{d}} \]
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\[ \int \frac {(-4+3 x) \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{(-1+x) x} \, dx=\int \frac {(-4+3 x) \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{(-1+x) x} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\left (\sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}} \sqrt [4]{-c+c x+d x^4}\right ) \int \frac {(-4+3 x) \sqrt [4]{-a+a x+b x^4}}{(-1+x) x \sqrt [4]{-c+c x+d x^4}} \, dx}{\sqrt [4]{-a+a x+b x^4}} \\ & = \frac {\left (\sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}} \sqrt [4]{-c+c x+d x^4}\right ) \int \left (\frac {\sqrt [4]{-a+a x+b x^4}}{(1-x) \sqrt [4]{-c+c x+d x^4}}+\frac {4 \sqrt [4]{-a+a x+b x^4}}{x \sqrt [4]{-c+c x+d x^4}}\right ) \, dx}{\sqrt [4]{-a+a x+b x^4}} \\ & = \frac {\left (\sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}} \sqrt [4]{-c+c x+d x^4}\right ) \int \frac {\sqrt [4]{-a+a x+b x^4}}{(1-x) \sqrt [4]{-c+c x+d x^4}} \, dx}{\sqrt [4]{-a+a x+b x^4}}+\frac {\left (4 \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}} \sqrt [4]{-c+c x+d x^4}\right ) \int \frac {\sqrt [4]{-a+a x+b x^4}}{x \sqrt [4]{-c+c x+d x^4}} \, dx}{\sqrt [4]{-a+a x+b x^4}} \\ \end{align*}
Time = 4.04 (sec) , antiderivative size = 213, normalized size of antiderivative = 0.96 \[ \int \frac {(-4+3 x) \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{(-1+x) x} \, dx=-\frac {2 \sqrt [4]{a} \arctan \left (\frac {\sqrt [4]{c} \sqrt [4]{\frac {a (-1+x)+b x^4}{c (-1+x)+d x^4}}}{\sqrt [4]{a}}\right )}{\sqrt [4]{c}}+\frac {2 \sqrt [4]{b} \arctan \left (\frac {\sqrt [4]{d} \sqrt [4]{\frac {a (-1+x)+b x^4}{c (-1+x)+d x^4}}}{\sqrt [4]{b}}\right )}{\sqrt [4]{d}}-\frac {2 \sqrt [4]{a} \text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt [4]{\frac {a (-1+x)+b x^4}{c (-1+x)+d x^4}}}{\sqrt [4]{a}}\right )}{\sqrt [4]{c}}+\frac {2 \sqrt [4]{b} \text {arctanh}\left (\frac {\sqrt [4]{d} \sqrt [4]{\frac {a (-1+x)+b x^4}{c (-1+x)+d x^4}}}{\sqrt [4]{b}}\right )}{\sqrt [4]{d}} \]
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\[\int \frac {\left (-4+3 x \right ) \left (\frac {b \,x^{4}+a x -a}{d \,x^{4}+c x -c}\right )^{\frac {1}{4}}}{\left (-1+x \right ) x}d x\]
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Timed out. \[ \int \frac {(-4+3 x) \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{(-1+x) x} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {(-4+3 x) \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{(-1+x) x} \, dx=\text {Timed out} \]
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\[ \int \frac {(-4+3 x) \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{(-1+x) x} \, dx=\int { \frac {{\left (3 \, x - 4\right )} \left (\frac {b x^{4} + a x - a}{d x^{4} + c x - c}\right )^{\frac {1}{4}}}{{\left (x - 1\right )} x} \,d x } \]
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\[ \int \frac {(-4+3 x) \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{(-1+x) x} \, dx=\int { \frac {{\left (3 \, x - 4\right )} \left (\frac {b x^{4} + a x - a}{d x^{4} + c x - c}\right )^{\frac {1}{4}}}{{\left (x - 1\right )} x} \,d x } \]
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Timed out. \[ \int \frac {(-4+3 x) \sqrt [4]{\frac {-a+a x+b x^4}{-c+c x+d x^4}}}{(-1+x) x} \, dx=\int \frac {\left (3\,x-4\right )\,{\left (\frac {b\,x^4+a\,x-a}{d\,x^4+c\,x-c}\right )}^{1/4}}{x\,\left (x-1\right )} \,d x \]
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