Integrand size = 44, antiderivative size = 239 \[ \int \frac {-b^5+a^5 x^5}{\sqrt {b^2 x+a^2 x^3} \left (b^5+a^5 x^5\right )} \, dx=-\frac {\sqrt {2} \arctan \left (\frac {\sqrt {2} \sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}{b^2+a^2 x^2}\right )}{5 \sqrt {a} \sqrt {b}}-\frac {2 \sqrt {2 \left (1+\sqrt {5}\right )} \arctan \left (\frac {\sqrt {-\frac {1}{2}+\frac {\sqrt {5}}{2}} \sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}{b^2+a^2 x^2}\right )}{5 \sqrt {a} \sqrt {b}}-\frac {2 \sqrt {2 \left (-1+\sqrt {5}\right )} \text {arctanh}\left (\frac {\sqrt {\frac {1}{2}+\frac {\sqrt {5}}{2}} \sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}{b^2+a^2 x^2}\right )}{5 \sqrt {a} \sqrt {b}} \]
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\[ \int \frac {-b^5+a^5 x^5}{\sqrt {b^2 x+a^2 x^3} \left (b^5+a^5 x^5\right )} \, dx=\int \frac {-b^5+a^5 x^5}{\sqrt {b^2 x+a^2 x^3} \left (b^5+a^5 x^5\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\left (\sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \int \frac {-b^5+a^5 x^5}{\sqrt {x} \sqrt {b^2+a^2 x^2} \left (b^5+a^5 x^5\right )} \, dx}{\sqrt {b^2 x+a^2 x^3}} \\ & = \frac {\left (2 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {-b^5+a^5 x^{10}}{\sqrt {b^2+a^2 x^4} \left (b^5+a^5 x^{10}\right )} \, dx,x,\sqrt {x}\right )}{\sqrt {b^2 x+a^2 x^3}} \\ & = \frac {\left (2 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \left (\frac {1}{\sqrt {b^2+a^2 x^4}}-\frac {2 b^5}{\sqrt {b^2+a^2 x^4} \left (b^5+a^5 x^{10}\right )}\right ) \, dx,x,\sqrt {x}\right )}{\sqrt {b^2 x+a^2 x^3}} \\ & = \frac {\left (2 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b^2+a^2 x^4}} \, dx,x,\sqrt {x}\right )}{\sqrt {b^2 x+a^2 x^3}}-\frac {\left (4 b^5 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b^2+a^2 x^4} \left (b^5+a^5 x^{10}\right )} \, dx,x,\sqrt {x}\right )}{\sqrt {b^2 x+a^2 x^3}} \\ & = \frac {\sqrt {x} (b+a x) \sqrt {\frac {b^2+a^2 x^2}{(b+a x)^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {a} \sqrt {x}}{\sqrt {b}}\right ),\frac {1}{2}\right )}{\sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}-\frac {\left (4 b^5 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \left (\frac {1}{5 b^4 \left (b+a x^2\right ) \sqrt {b^2+a^2 x^4}}+\frac {4 b^3-3 a b^2 x^2+2 a^2 b x^4-a^3 x^6}{5 b^4 \sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )}\right ) \, dx,x,\sqrt {x}\right )}{\sqrt {b^2 x+a^2 x^3}} \\ & = \frac {\sqrt {x} (b+a x) \sqrt {\frac {b^2+a^2 x^2}{(b+a x)^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {a} \sqrt {x}}{\sqrt {b}}\right ),\frac {1}{2}\right )}{\sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}-\frac {\left (4 b \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{\left (b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}}-\frac {\left (4 b \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {4 b^3-3 a b^2 x^2+2 a^2 b x^4-a^3 x^6}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}} \\ & = \frac {\sqrt {x} (b+a x) \sqrt {\frac {b^2+a^2 x^2}{(b+a x)^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {a} \sqrt {x}}{\sqrt {b}}\right ),\frac {1}{2}\right )}{\sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}-\frac {\left (2 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b^2+a^2 x^4}} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}}-\frac {\left (2 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {b-a x^2}{\left (b+a x^2\right ) \sqrt {b^2+a^2 x^4}} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}}-\frac {\left (4 b \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \left (\frac {4 b^3}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )}-\frac {3 a b^2 x^2}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )}+\frac {2 a^2 b x^4}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )}-\frac {a^3 x^6}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )}\right ) \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}} \\ & = \frac {4 \sqrt {x} (b+a x) \sqrt {\frac {b^2+a^2 x^2}{(b+a x)^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {a} \sqrt {x}}{\sqrt {b}}\right ),\frac {1}{2}\right )}{5 \sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}-\frac {\left (2 b \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{b+2 a b^2 x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt {b^2+a^2 x^2}}\right )}{5 \sqrt {b^2 x+a^2 x^3}}+\frac {\left (4 a^3 b \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {x^6}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}}-\frac {\left (8 a^2 b^2 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {x^4}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}}+\frac {\left (12 a b^3 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}}-\frac {\left (16 b^4 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}} \\ & = -\frac {\sqrt {2} \sqrt {x} \sqrt {b^2+a^2 x^2} \arctan \left (\frac {\sqrt {2} \sqrt {a} \sqrt {b} \sqrt {x}}{\sqrt {b^2+a^2 x^2}}\right )}{5 \sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}+\frac {4 \sqrt {x} (b+a x) \sqrt {\frac {b^2+a^2 x^2}{(b+a x)^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {a} \sqrt {x}}{\sqrt {b}}\right ),\frac {1}{2}\right )}{5 \sqrt {a} \sqrt {b} \sqrt {b^2 x+a^2 x^3}}+\frac {\left (4 a^3 b \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {x^6}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}}-\frac {\left (8 a^2 b^2 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {x^4}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}}+\frac {\left (12 a b^3 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}}-\frac {\left (16 b^4 \sqrt {x} \sqrt {b^2+a^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b^2+a^2 x^4} \left (b^4-a b^3 x^2+a^2 b^2 x^4-a^3 b x^6+a^4 x^8\right )} \, dx,x,\sqrt {x}\right )}{5 \sqrt {b^2 x+a^2 x^3}} \\ \end{align*}
Time = 1.62 (sec) , antiderivative size = 214, normalized size of antiderivative = 0.90 \[ \int \frac {-b^5+a^5 x^5}{\sqrt {b^2 x+a^2 x^3} \left (b^5+a^5 x^5\right )} \, dx=-\frac {\sqrt {2} \sqrt {x} \sqrt {b^2+a^2 x^2} \left (\arctan \left (\frac {\sqrt {2} \sqrt {a} \sqrt {b} \sqrt {x}}{\sqrt {b^2+a^2 x^2}}\right )+2 \sqrt {1+\sqrt {5}} \arctan \left (\frac {\sqrt {\frac {1}{2} \left (-1+\sqrt {5}\right )} \sqrt {a} \sqrt {b} \sqrt {x}}{\sqrt {b^2+a^2 x^2}}\right )+2 \sqrt {-1+\sqrt {5}} \text {arctanh}\left (\frac {\sqrt {\frac {1}{2} \left (1+\sqrt {5}\right )} \sqrt {a} \sqrt {b} \sqrt {x}}{\sqrt {b^2+a^2 x^2}}\right )\right )}{5 \sqrt {a} \sqrt {b} \sqrt {x \left (b^2+a^2 x^2\right )}} \]
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Time = 1.82 (sec) , antiderivative size = 171, normalized size of antiderivative = 0.72
method | result | size |
default | \(\frac {8 \arctan \left (\frac {2 \sqrt {x \left (a^{2} x^{2}+b^{2}\right )}}{x \sqrt {-2 \sqrt {5}\, \sqrt {a^{2} b^{2}}-2 a b}}\right )}{5 \sqrt {-2 \sqrt {5}\, \sqrt {a^{2} b^{2}}-2 a b}}+\frac {8 \arctan \left (\frac {2 \sqrt {x \left (a^{2} x^{2}+b^{2}\right )}}{x \sqrt {2 \sqrt {5}\, \sqrt {a^{2} b^{2}}-2 a b}}\right )}{5 \sqrt {2 \sqrt {5}\, \sqrt {a^{2} b^{2}}-2 a b}}+\frac {\sqrt {2}\, \arctan \left (\frac {\sqrt {x \left (a^{2} x^{2}+b^{2}\right )}\, \sqrt {2}}{2 x \sqrt {a b}}\right )}{5 \sqrt {a b}}\) | \(171\) |
pseudoelliptic | \(\frac {8 \arctan \left (\frac {2 \sqrt {x \left (a^{2} x^{2}+b^{2}\right )}}{x \sqrt {-2 \sqrt {5}\, \sqrt {a^{2} b^{2}}-2 a b}}\right )}{5 \sqrt {-2 \sqrt {5}\, \sqrt {a^{2} b^{2}}-2 a b}}+\frac {8 \arctan \left (\frac {2 \sqrt {x \left (a^{2} x^{2}+b^{2}\right )}}{x \sqrt {2 \sqrt {5}\, \sqrt {a^{2} b^{2}}-2 a b}}\right )}{5 \sqrt {2 \sqrt {5}\, \sqrt {a^{2} b^{2}}-2 a b}}+\frac {\sqrt {2}\, \arctan \left (\frac {\sqrt {x \left (a^{2} x^{2}+b^{2}\right )}\, \sqrt {2}}{2 x \sqrt {a b}}\right )}{5 \sqrt {a b}}\) | \(171\) |
elliptic | \(\text {Expression too large to display}\) | \(2185\) |
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Leaf count of result is larger than twice the leaf count of optimal. 1003 vs. \(2 (177) = 354\).
Time = 0.46 (sec) , antiderivative size = 2091, normalized size of antiderivative = 8.75 \[ \int \frac {-b^5+a^5 x^5}{\sqrt {b^2 x+a^2 x^3} \left (b^5+a^5 x^5\right )} \, dx=\text {Too large to display} \]
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\[ \int \frac {-b^5+a^5 x^5}{\sqrt {b^2 x+a^2 x^3} \left (b^5+a^5 x^5\right )} \, dx=\int \frac {\left (a x - b\right ) \left (a^{4} x^{4} + a^{3} b x^{3} + a^{2} b^{2} x^{2} + a b^{3} x + b^{4}\right )}{\sqrt {x \left (a^{2} x^{2} + b^{2}\right )} \left (a x + b\right ) \left (a^{4} x^{4} - a^{3} b x^{3} + a^{2} b^{2} x^{2} - a b^{3} x + b^{4}\right )}\, dx \]
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\[ \int \frac {-b^5+a^5 x^5}{\sqrt {b^2 x+a^2 x^3} \left (b^5+a^5 x^5\right )} \, dx=\int { \frac {a^{5} x^{5} - b^{5}}{{\left (a^{5} x^{5} + b^{5}\right )} \sqrt {a^{2} x^{3} + b^{2} x}} \,d x } \]
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\[ \int \frac {-b^5+a^5 x^5}{\sqrt {b^2 x+a^2 x^3} \left (b^5+a^5 x^5\right )} \, dx=\int { \frac {a^{5} x^{5} - b^{5}}{{\left (a^{5} x^{5} + b^{5}\right )} \sqrt {a^{2} x^{3} + b^{2} x}} \,d x } \]
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Timed out. \[ \int \frac {-b^5+a^5 x^5}{\sqrt {b^2 x+a^2 x^3} \left (b^5+a^5 x^5\right )} \, dx=\text {Hanged} \]
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