Integrand size = 103, antiderivative size = 267 \[ \int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c+d q^2+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx=\frac {\arctan \left (\frac {b \sqrt [4]{c}+a \sqrt [4]{c} x}{b \sqrt [4]{c}+a \sqrt [4]{c} x-\sqrt {2} \sqrt [4]{d} \sqrt {q+p x^3}}\right )}{\sqrt {2} c^{3/4} \sqrt [4]{d}}-\frac {\arctan \left (\frac {b \sqrt [4]{c}+a \sqrt [4]{c} x}{b \sqrt [4]{c}+a \sqrt [4]{c} x+\sqrt {2} \sqrt [4]{d} \sqrt {q+p x^3}}\right )}{\sqrt {2} c^{3/4} \sqrt [4]{d}}+\frac {\text {arctanh}\left (\frac {\left (\sqrt {2} b \sqrt [4]{c} \sqrt [4]{d}+\sqrt {2} a \sqrt [4]{c} \sqrt [4]{d} x\right ) \sqrt {q+p x^3}}{b^2 \sqrt {c}+\sqrt {d} q+2 a b \sqrt {c} x+a^2 \sqrt {c} x^2+\sqrt {d} p x^3}\right )}{\sqrt {2} c^{3/4} \sqrt [4]{d}} \]
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\[ \int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c+d q^2+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx=\int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c+d q^2+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c \left (1+\frac {d q^2}{b^4 c}\right )+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx \\ & = \int \left (\frac {2 a b^2 q}{\sqrt {q+p x^3} \left (-b^4 c \left (1+\frac {d q^2}{b^4 c}\right )-4 a b^3 c x-6 a^2 b^2 c x^2-4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3-a^4 c x^4-d p^2 x^6\right )}+\frac {4 a^2 b q x}{\sqrt {q+p x^3} \left (-b^4 c \left (1+\frac {d q^2}{b^4 c}\right )-4 a b^3 c x-6 a^2 b^2 c x^2-4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3-a^4 c x^4-d p^2 x^6\right )}+\frac {2 a^3 \left (1-\frac {3 b^3 p}{2 a^3 q}\right ) q x^2}{\sqrt {q+p x^3} \left (-b^4 c \left (1+\frac {d q^2}{b^4 c}\right )-4 a b^3 c x-6 a^2 b^2 c x^2-4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3-a^4 c x^4-d p^2 x^6\right )}+\frac {7 a b^2 p x^3}{\sqrt {q+p x^3} \left (b^4 c \left (1+\frac {d q^2}{b^4 c}\right )+4 a b^3 c x+6 a^2 b^2 c x^2+4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3+a^4 c x^4+d p^2 x^6\right )}+\frac {5 a^2 b p x^4}{\sqrt {q+p x^3} \left (b^4 c \left (1+\frac {d q^2}{b^4 c}\right )+4 a b^3 c x+6 a^2 b^2 c x^2+4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3+a^4 c x^4+d p^2 x^6\right )}+\frac {a^3 p x^5}{\sqrt {q+p x^3} \left (b^4 c \left (1+\frac {d q^2}{b^4 c}\right )+4 a b^3 c x+6 a^2 b^2 c x^2+4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3+a^4 c x^4+d p^2 x^6\right )}\right ) \, dx \\ & = \left (a^3 p\right ) \int \frac {x^5}{\sqrt {q+p x^3} \left (b^4 c \left (1+\frac {d q^2}{b^4 c}\right )+4 a b^3 c x+6 a^2 b^2 c x^2+4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx+\left (5 a^2 b p\right ) \int \frac {x^4}{\sqrt {q+p x^3} \left (b^4 c \left (1+\frac {d q^2}{b^4 c}\right )+4 a b^3 c x+6 a^2 b^2 c x^2+4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx+\left (7 a b^2 p\right ) \int \frac {x^3}{\sqrt {q+p x^3} \left (b^4 c \left (1+\frac {d q^2}{b^4 c}\right )+4 a b^3 c x+6 a^2 b^2 c x^2+4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx+\left (4 a^2 b q\right ) \int \frac {x}{\sqrt {q+p x^3} \left (-b^4 c \left (1+\frac {d q^2}{b^4 c}\right )-4 a b^3 c x-6 a^2 b^2 c x^2-4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3-a^4 c x^4-d p^2 x^6\right )} \, dx+\left (2 a b^2 q\right ) \int \frac {1}{\sqrt {q+p x^3} \left (-b^4 c \left (1+\frac {d q^2}{b^4 c}\right )-4 a b^3 c x-6 a^2 b^2 c x^2-4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3-a^4 c x^4-d p^2 x^6\right )} \, dx+\left (-3 b^3 p+2 a^3 q\right ) \int \frac {x^2}{\sqrt {q+p x^3} \left (-b^4 c \left (1+\frac {d q^2}{b^4 c}\right )-4 a b^3 c x-6 a^2 b^2 c x^2-4 a^3 b c \left (1+\frac {d p q}{2 a^3 b c}\right ) x^3-a^4 c x^4-d p^2 x^6\right )} \, dx \\ & = \left (a^3 p\right ) \int \frac {x^5}{\sqrt {q+p x^3} \left (b^4 c+4 a b^3 c x+6 a^2 b^2 c x^2+4 a^3 b c x^3+a^4 c x^4+d \left (q+p x^3\right )^2\right )} \, dx+\left (5 a^2 b p\right ) \int \frac {x^4}{\sqrt {q+p x^3} \left (b^4 c+4 a b^3 c x+6 a^2 b^2 c x^2+4 a^3 b c x^3+a^4 c x^4+d \left (q+p x^3\right )^2\right )} \, dx+\left (7 a b^2 p\right ) \int \frac {x^3}{\sqrt {q+p x^3} \left (b^4 c+4 a b^3 c x+6 a^2 b^2 c x^2+4 a^3 b c x^3+a^4 c x^4+d \left (q+p x^3\right )^2\right )} \, dx+\left (4 a^2 b q\right ) \int \frac {x}{\sqrt {q+p x^3} \left (-b^4 c-4 a b^3 c x-6 a^2 b^2 c x^2-4 a^3 b c x^3-a^4 c x^4-d \left (q+p x^3\right )^2\right )} \, dx+\left (2 a b^2 q\right ) \int \frac {1}{\sqrt {q+p x^3} \left (-b^4 c-4 a b^3 c x-6 a^2 b^2 c x^2-4 a^3 b c x^3-a^4 c x^4-d \left (q+p x^3\right )^2\right )} \, dx+\left (-3 b^3 p+2 a^3 q\right ) \int \frac {x^2}{\sqrt {q+p x^3} \left (-b^4 c-4 a b^3 c x-6 a^2 b^2 c x^2-4 a^3 b c x^3-a^4 c x^4-d \left (q+p x^3\right )^2\right )} \, dx \\ \end{align*}
Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
Time = 16.87 (sec) , antiderivative size = 52633, normalized size of antiderivative = 197.13 \[ \int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c+d q^2+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx=\text {Result too large to show} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 2.63 (sec) , antiderivative size = 7274, normalized size of antiderivative = 27.24
method | result | size |
default | \(\text {Expression too large to display}\) | \(7274\) |
elliptic | \(\text {Expression too large to display}\) | \(7274\) |
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Timed out. \[ \int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c+d q^2+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c+d q^2+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx=\int \frac {\left (a x + b\right )^{2} \left (a p x^{3} - 2 a q + 3 b p x^{2}\right )}{\sqrt {p x^{3} + q} \left (a^{4} c x^{4} + 4 a^{3} b c x^{3} + 6 a^{2} b^{2} c x^{2} + 4 a b^{3} c x + b^{4} c + d p^{2} x^{6} + 2 d p q x^{3} + d q^{2}\right )}\, dx \]
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\[ \int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c+d q^2+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx=\int { \frac {{\left (a p x^{3} + 3 \, b p x^{2} - 2 \, a q\right )} {\left (a x + b\right )}^{2}}{{\left (a^{4} c x^{4} + d p^{2} x^{6} + 6 \, a^{2} b^{2} c x^{2} + 4 \, a b^{3} c x + b^{4} c + 2 \, {\left (2 \, a^{3} b c + d p q\right )} x^{3} + d q^{2}\right )} \sqrt {p x^{3} + q}} \,d x } \]
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Timed out. \[ \int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c+d q^2+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {(b+a x)^2 \left (-2 a q+3 b p x^2+a p x^3\right )}{\sqrt {q+p x^3} \left (b^4 c+d q^2+4 a b^3 c x+6 a^2 b^2 c x^2+\left (4 a^3 b c+2 d p q\right ) x^3+a^4 c x^4+d p^2 x^6\right )} \, dx=\text {Hanged} \]
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