Integrand size = 22, antiderivative size = 24 \[ \int \frac {-1+x^2}{\left (1+x^2\right ) \sqrt {1+x^4}} \, dx=-\frac {\arctan \left (\frac {\sqrt {2} x}{\sqrt {1+x^4}}\right )}{\sqrt {2}} \]
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Time = 0.02 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {1713, 209} \[ \int \frac {-1+x^2}{\left (1+x^2\right ) \sqrt {1+x^4}} \, dx=-\frac {\arctan \left (\frac {\sqrt {2} x}{\sqrt {x^4+1}}\right )}{\sqrt {2}} \]
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Rule 209
Rule 1713
Rubi steps \begin{align*} \text {integral}& = -\text {Subst}\left (\int \frac {1}{1+2 x^2} \, dx,x,\frac {x}{\sqrt {1+x^4}}\right ) \\ & = -\frac {\arctan \left (\frac {\sqrt {2} x}{\sqrt {1+x^4}}\right )}{\sqrt {2}} \\ \end{align*}
Time = 0.34 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {-1+x^2}{\left (1+x^2\right ) \sqrt {1+x^4}} \, dx=-\frac {\arctan \left (\frac {\sqrt {2} x}{\sqrt {1+x^4}}\right )}{\sqrt {2}} \]
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Time = 2.96 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.79
method | result | size |
default | \(-\frac {\arctan \left (\frac {\sqrt {2}\, x}{\sqrt {x^{4}+1}}\right ) \sqrt {2}}{2}\) | \(19\) |
pseudoelliptic | \(-\frac {\arctan \left (\frac {\sqrt {2}\, x}{\sqrt {x^{4}+1}}\right ) \sqrt {2}}{2}\) | \(19\) |
elliptic | \(\frac {\arctan \left (\frac {\sqrt {2}\, \sqrt {x^{4}+1}}{2 x}\right ) \sqrt {2}}{2}\) | \(22\) |
trager | \(\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+2\right ) \ln \left (\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+2\right ) x +\sqrt {x^{4}+1}}{x^{2}+1}\right )}{2}\) | \(34\) |
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none
Time = 0.27 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.75 \[ \int \frac {-1+x^2}{\left (1+x^2\right ) \sqrt {1+x^4}} \, dx=-\frac {1}{2} \, \sqrt {2} \arctan \left (\frac {\sqrt {2} x}{\sqrt {x^{4} + 1}}\right ) \]
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\[ \int \frac {-1+x^2}{\left (1+x^2\right ) \sqrt {1+x^4}} \, dx=\int \frac {\left (x - 1\right ) \left (x + 1\right )}{\left (x^{2} + 1\right ) \sqrt {x^{4} + 1}}\, dx \]
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\[ \int \frac {-1+x^2}{\left (1+x^2\right ) \sqrt {1+x^4}} \, dx=\int { \frac {x^{2} - 1}{\sqrt {x^{4} + 1} {\left (x^{2} + 1\right )}} \,d x } \]
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\[ \int \frac {-1+x^2}{\left (1+x^2\right ) \sqrt {1+x^4}} \, dx=\int { \frac {x^{2} - 1}{\sqrt {x^{4} + 1} {\left (x^{2} + 1\right )}} \,d x } \]
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Timed out. \[ \int \frac {-1+x^2}{\left (1+x^2\right ) \sqrt {1+x^4}} \, dx=\int \frac {x^2-1}{\left (x^2+1\right )\,\sqrt {x^4+1}} \,d x \]
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