Integrand size = 24, antiderivative size = 288 \[ \int \frac {1+x^6}{\sqrt [3]{x^2+x^4} \left (-1+x^6\right )} \, dx=-\frac {\arctan \left (\frac {\sqrt {3} x}{-x+2 \sqrt [3]{x^2+x^4}}\right )}{\sqrt {3}}-\frac {\arctan \left (\frac {\sqrt {3} x}{x+2 \sqrt [3]{x^2+x^4}}\right )}{\sqrt {3}}-\frac {\arctan \left (\frac {\sqrt {3} x}{-x+2^{2/3} \sqrt [3]{x^2+x^4}}\right )}{2 \sqrt [3]{2} \sqrt {3}}-\frac {\arctan \left (\frac {\sqrt {3} x}{x+2^{2/3} \sqrt [3]{x^2+x^4}}\right )}{2 \sqrt [3]{2} \sqrt {3}}-\frac {2}{3} \text {arctanh}\left (\frac {x}{\sqrt [3]{x^2+x^4}}\right )-\frac {\text {arctanh}\left (\frac {\sqrt [3]{2} x}{\sqrt [3]{x^2+x^4}}\right )}{3 \sqrt [3]{2}}-\frac {1}{3} \text {arctanh}\left (\frac {x^2+\left (x^2+x^4\right )^{2/3}}{x \sqrt [3]{x^2+x^4}}\right )-\frac {\text {arctanh}\left (\frac {\sqrt [3]{2} x^2+\frac {\left (x^2+x^4\right )^{2/3}}{\sqrt [3]{2}}}{x \sqrt [3]{x^2+x^4}}\right )}{6 \sqrt [3]{2}} \]
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\[ \int \frac {1+x^6}{\sqrt [3]{x^2+x^4} \left (-1+x^6\right )} \, dx=\int \frac {1+x^6}{\sqrt [3]{x^2+x^4} \left (-1+x^6\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\left (x^{2/3} \sqrt [3]{1+x^2}\right ) \int \frac {1+x^6}{x^{2/3} \sqrt [3]{1+x^2} \left (-1+x^6\right )} \, dx}{\sqrt [3]{x^2+x^4}} \\ & = \frac {\left (x^{2/3} \sqrt [3]{1+x^2}\right ) \int \frac {\left (1+x^2\right )^{2/3} \left (1-x^2+x^4\right )}{x^{2/3} \left (-1+x^6\right )} \, dx}{\sqrt [3]{x^2+x^4}} \\ & = \frac {\left (3 x^{2/3} \sqrt [3]{1+x^2}\right ) \text {Subst}\left (\int \frac {\left (1+x^6\right )^{2/3} \left (1-x^6+x^{12}\right )}{-1+x^{18}} \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{x^2+x^4}} \\ & = \frac {\left (3 x^{2/3} \sqrt [3]{1+x^2}\right ) \text {Subst}\left (\int \left (-\frac {\left (1+x^6\right )^{2/3}}{18 (1-x)}-\frac {\left (1+x^6\right )^{2/3}}{18 (1+x)}-\frac {\left (1+\sqrt [3]{-1}+(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1-\sqrt [9]{-1} x\right )}-\frac {\left (1+\sqrt [3]{-1}+(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1+\sqrt [9]{-1} x\right )}-\frac {\left (1-\sqrt [3]{-1}-(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1-(-1)^{2/9} x\right )}-\frac {\left (1-\sqrt [3]{-1}-(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1+(-1)^{2/9} x\right )}-\frac {\left (1+x^6\right )^{2/3}}{18 \left (1-\sqrt [3]{-1} x\right )}-\frac {\left (1+x^6\right )^{2/3}}{18 \left (1+\sqrt [3]{-1} x\right )}-\frac {\left (1+\sqrt [3]{-1}+(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1-(-1)^{4/9} x\right )}-\frac {\left (1+\sqrt [3]{-1}+(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1+(-1)^{4/9} x\right )}-\frac {\left (1-\sqrt [3]{-1}-(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1-(-1)^{5/9} x\right )}-\frac {\left (1-\sqrt [3]{-1}-(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1+(-1)^{5/9} x\right )}-\frac {\left (1+x^6\right )^{2/3}}{18 \left (1-(-1)^{2/3} x\right )}-\frac {\left (1+x^6\right )^{2/3}}{18 \left (1+(-1)^{2/3} x\right )}-\frac {\left (1+\sqrt [3]{-1}+(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1-(-1)^{7/9} x\right )}-\frac {\left (1+\sqrt [3]{-1}+(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1+(-1)^{7/9} x\right )}-\frac {\left (1-\sqrt [3]{-1}-(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1-(-1)^{8/9} x\right )}-\frac {\left (1-\sqrt [3]{-1}-(-1)^{2/3}\right ) \left (1+x^6\right )^{2/3}}{18 \left (1+(-1)^{8/9} x\right )}\right ) \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{x^2+x^4}} \\ & = \text {Too large to display} \\ \end{align*}
Time = 0.95 (sec) , antiderivative size = 333, normalized size of antiderivative = 1.16 \[ \int \frac {1+x^6}{\sqrt [3]{x^2+x^4} \left (-1+x^6\right )} \, dx=-\frac {x^{2/3} \sqrt [3]{1+x^2} \left (-4 \sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [3]{x}}{\sqrt [3]{x}-2 \sqrt [3]{1+x^2}}\right )+4 \sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [3]{x}}{\sqrt [3]{x}+2 \sqrt [3]{1+x^2}}\right )+2^{2/3} \sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [3]{x}}{-\sqrt [3]{x}+2^{2/3} \sqrt [3]{1+x^2}}\right )+2^{2/3} \sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt [3]{x}}{\sqrt [3]{x}+2^{2/3} \sqrt [3]{1+x^2}}\right )+8 \text {arctanh}\left (\frac {\sqrt [3]{x}}{\sqrt [3]{1+x^2}}\right )+2\ 2^{2/3} \text {arctanh}\left (\frac {\sqrt [3]{2} \sqrt [3]{x}}{\sqrt [3]{1+x^2}}\right )+4 \text {arctanh}\left (\frac {\sqrt [3]{x} \sqrt [3]{1+x^2}}{x^{2/3}+\left (1+x^2\right )^{2/3}}\right )+2^{2/3} \text {arctanh}\left (\frac {2^{2/3} \sqrt [3]{x} \sqrt [3]{1+x^2}}{2 x^{2/3}+\sqrt [3]{2} \left (1+x^2\right )^{2/3}}\right )\right )}{12 \sqrt [3]{x^2+x^4}} \]
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Time = 35.54 (sec) , antiderivative size = 388, normalized size of antiderivative = 1.35
method | result | size |
pseudoelliptic | \(\frac {\ln \left (\frac {\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {2}{3}}-\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}} x +x^{2}}{x^{2}}\right )}{6}-\frac {\sqrt {3}\, \arctan \left (\frac {\left (-2 \left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}}+x \right ) \sqrt {3}}{3 x}\right )}{3}-\frac {\ln \left (\frac {\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {2}{3}}+\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}} x +x^{2}}{x^{2}}\right )}{6}+\frac {\sqrt {3}\, \arctan \left (\frac {\left (2 \left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}}+x \right ) \sqrt {3}}{3 x}\right )}{3}+\frac {2^{\frac {2}{3}} \ln \left (\frac {-2^{\frac {1}{3}} x +\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}}}{x}\right )}{12}-\frac {2^{\frac {2}{3}} \ln \left (\frac {2^{\frac {2}{3}} x^{2}+2^{\frac {1}{3}} \left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}} x +\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {2}{3}}}{x^{2}}\right )}{24}+\frac {\sqrt {3}\, 2^{\frac {2}{3}} \arctan \left (\frac {\sqrt {3}\, \left (\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}} 2^{\frac {2}{3}}+x \right )}{3 x}\right )}{12}-\frac {\ln \left (\frac {\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}}+x}{x}\right )}{3}+\frac {\ln \left (\frac {\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}}-x}{x}\right )}{3}-\frac {2^{\frac {2}{3}} \ln \left (\frac {2^{\frac {1}{3}} x +\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}}}{x}\right )}{12}+\frac {2^{\frac {2}{3}} \ln \left (\frac {2^{\frac {2}{3}} x^{2}-2^{\frac {1}{3}} \left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}} x +\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {2}{3}}}{x^{2}}\right )}{24}-\frac {\sqrt {3}\, 2^{\frac {2}{3}} \arctan \left (\frac {\sqrt {3}\, \left (-\left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{3}} 2^{\frac {2}{3}}+x \right )}{3 x}\right )}{12}\) | \(388\) |
trager | \(\text {Expression too large to display}\) | \(5994\) |
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Leaf count of result is larger than twice the leaf count of optimal. 456 vs. \(2 (223) = 446\).
Time = 1.75 (sec) , antiderivative size = 456, normalized size of antiderivative = 1.58 \[ \int \frac {1+x^6}{\sqrt [3]{x^2+x^4} \left (-1+x^6\right )} \, dx=\frac {1}{12} \, \sqrt {6} 2^{\frac {1}{6}} \left (-1\right )^{\frac {1}{3}} \arctan \left (\frac {2^{\frac {1}{6}} {\left (4 \, \sqrt {6} 2^{\frac {2}{3}} \left (-1\right )^{\frac {2}{3}} {\left (x^{4} + x^{2}\right )}^{\frac {2}{3}} {\left (x^{2} + 2 \, x + 1\right )} + 8 \, \sqrt {6} \left (-1\right )^{\frac {1}{3}} {\left (x^{4} + x^{2}\right )}^{\frac {1}{3}} {\left (x^{3} - 2 \, x^{2} + x\right )} - \sqrt {6} 2^{\frac {1}{3}} {\left (x^{5} - 8 \, x^{4} - 2 \, x^{3} - 8 \, x^{2} + x\right )}\right )}}{6 \, {\left (x^{5} + 8 \, x^{4} - 2 \, x^{3} + 8 \, x^{2} + x\right )}}\right ) + \frac {1}{12} \cdot 2^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} \log \left (-\frac {4 \cdot 2^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} {\left (x^{4} + x^{2}\right )}^{\frac {1}{3}} x - 2^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} {\left (x^{3} + 2 \, x^{2} + x\right )} + 4 \, {\left (x^{4} + x^{2}\right )}^{\frac {2}{3}}}{x^{3} - 2 \, x^{2} + x}\right ) - \frac {1}{24} \cdot 2^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} \log \left (\frac {2^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} {\left (x^{3} - 2 \, x^{2} + x\right )} + 2 \cdot 2^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} {\left (x^{4} + x^{2}\right )}^{\frac {2}{3}} + 4 \, {\left (x^{4} + x^{2}\right )}^{\frac {1}{3}} x}{x^{3} - 2 \, x^{2} + x}\right ) - \frac {1}{3} \, \sqrt {3} \arctan \left (\frac {4 \, \sqrt {3} {\left (x^{4} + x^{2}\right )}^{\frac {2}{3}} {\left (x^{2} + x + 1\right )} - 4 \, \sqrt {3} {\left (x^{4} + x^{2}\right )}^{\frac {1}{3}} {\left (x^{3} - x^{2} + x\right )} - \sqrt {3} {\left (x^{5} - 4 \, x^{4} + x^{3} - 4 \, x^{2} + x\right )}}{3 \, {\left (x^{5} + 4 \, x^{4} + x^{3} + 4 \, x^{2} + x\right )}}\right ) + \frac {1}{3} \, \log \left (\frac {x^{3} - x^{2} + 2 \, {\left (x^{4} + x^{2}\right )}^{\frac {1}{3}} x + x - 2 \, {\left (x^{4} + x^{2}\right )}^{\frac {2}{3}}}{x^{3} + x^{2} + x}\right ) + \frac {1}{6} \, \log \left (\frac {x^{3} - x^{2} + 2 \, {\left (x^{4} + x^{2}\right )}^{\frac {1}{3}} x + x - 2 \, {\left (x^{4} + x^{2}\right )}^{\frac {2}{3}}}{x^{3} - x^{2} + x}\right ) \]
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\[ \int \frac {1+x^6}{\sqrt [3]{x^2+x^4} \left (-1+x^6\right )} \, dx=\int \frac {\left (x^{2} + 1\right ) \left (x^{4} - x^{2} + 1\right )}{\sqrt [3]{x^{2} \left (x^{2} + 1\right )} \left (x - 1\right ) \left (x + 1\right ) \left (x^{2} - x + 1\right ) \left (x^{2} + x + 1\right )}\, dx \]
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\[ \int \frac {1+x^6}{\sqrt [3]{x^2+x^4} \left (-1+x^6\right )} \, dx=\int { \frac {x^{6} + 1}{{\left (x^{6} - 1\right )} {\left (x^{4} + x^{2}\right )}^{\frac {1}{3}}} \,d x } \]
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\[ \int \frac {1+x^6}{\sqrt [3]{x^2+x^4} \left (-1+x^6\right )} \, dx=\int { \frac {x^{6} + 1}{{\left (x^{6} - 1\right )} {\left (x^{4} + x^{2}\right )}^{\frac {1}{3}}} \,d x } \]
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Timed out. \[ \int \frac {1+x^6}{\sqrt [3]{x^2+x^4} \left (-1+x^6\right )} \, dx=\int \frac {x^6+1}{{\left (x^4+x^2\right )}^{1/3}\,\left (x^6-1\right )} \,d x \]
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