Integrand size = 30, antiderivative size = 24 \[ \int \frac {2+3 x^5}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx=-\frac {2 \text {arctanh}\left (\frac {\sqrt {a} x}{\sqrt {-1+x^5}}\right )}{\sqrt {a}} \]
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\[ \int \frac {2+3 x^5}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx=\int \frac {2+3 x^5}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {3}{\sqrt {-1+x^5}}+\frac {5+3 a x^2}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )}\right ) \, dx \\ & = 3 \int \frac {1}{\sqrt {-1+x^5}} \, dx+\int \frac {5+3 a x^2}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx \\ & = \frac {\left (3 \sqrt {1-x^5}\right ) \int \frac {1}{\sqrt {1-x^5}} \, dx}{\sqrt {-1+x^5}}+\int \left (-\frac {5}{\left (1+a x^2-x^5\right ) \sqrt {-1+x^5}}-\frac {3 a x^2}{\left (1+a x^2-x^5\right ) \sqrt {-1+x^5}}\right ) \, dx \\ & = \frac {3 x \sqrt {1-x^5} \operatorname {Hypergeometric2F1}\left (\frac {1}{5},\frac {1}{2},\frac {6}{5},x^5\right )}{\sqrt {-1+x^5}}-5 \int \frac {1}{\left (1+a x^2-x^5\right ) \sqrt {-1+x^5}} \, dx-(3 a) \int \frac {x^2}{\left (1+a x^2-x^5\right ) \sqrt {-1+x^5}} \, dx \\ \end{align*}
Time = 3.90 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {2+3 x^5}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx=-\frac {2 \text {arctanh}\left (\frac {\sqrt {a} x}{\sqrt {-1+x^5}}\right )}{\sqrt {a}} \]
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Time = 0.90 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.88
method | result | size |
pseudoelliptic | \(-\frac {2 \,\operatorname {arctanh}\left (\frac {\sqrt {x^{5}-1}}{x \sqrt {a}}\right )}{\sqrt {a}}\) | \(21\) |
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Leaf count of result is larger than twice the leaf count of optimal. 46 vs. \(2 (18) = 36\).
Time = 0.28 (sec) , antiderivative size = 138, normalized size of antiderivative = 5.75 \[ \int \frac {2+3 x^5}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx=\left [\frac {\log \left (\frac {x^{10} + 6 \, a x^{7} + a^{2} x^{4} - 2 \, x^{5} - 6 \, a x^{2} - 4 \, {\left (x^{6} + a x^{3} - x\right )} \sqrt {x^{5} - 1} \sqrt {a} + 1}{x^{10} - 2 \, a x^{7} + a^{2} x^{4} - 2 \, x^{5} + 2 \, a x^{2} + 1}\right )}{2 \, \sqrt {a}}, \frac {\sqrt {-a} \arctan \left (\frac {{\left (x^{5} + a x^{2} - 1\right )} \sqrt {x^{5} - 1} \sqrt {-a}}{2 \, {\left (a x^{6} - a x\right )}}\right )}{a}\right ] \]
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\[ \int \frac {2+3 x^5}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx=\int \frac {3 x^{5} + 2}{\sqrt {\left (x - 1\right ) \left (x^{4} + x^{3} + x^{2} + x + 1\right )} \left (- a x^{2} + x^{5} - 1\right )}\, dx \]
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\[ \int \frac {2+3 x^5}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx=\int { \frac {3 \, x^{5} + 2}{{\left (x^{5} - a x^{2} - 1\right )} \sqrt {x^{5} - 1}} \,d x } \]
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\[ \int \frac {2+3 x^5}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx=\int { \frac {3 \, x^{5} + 2}{{\left (x^{5} - a x^{2} - 1\right )} \sqrt {x^{5} - 1}} \,d x } \]
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Time = 6.01 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.83 \[ \int \frac {2+3 x^5}{\sqrt {-1+x^5} \left (-1-a x^2+x^5\right )} \, dx=\frac {\ln \left (\frac {a\,x^2+x^5-2\,\sqrt {a}\,x\,\sqrt {x^5-1}-1}{-4\,x^5+4\,a\,x^2+4}\right )}{\sqrt {a}} \]
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