Integrand size = 96, antiderivative size = 317 \[ \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx=\frac {\sqrt {3} \arctan \left (\frac {\sqrt {3} a^2 \sqrt [3]{d}-2 \sqrt {3} a \sqrt [3]{d} x+\sqrt {3} \sqrt [3]{d} x^2}{a^2 \sqrt [3]{d}-2 a \sqrt [3]{d} x+\sqrt [3]{d} x^2+2 \sqrt [3]{a b+(-a-b) x+x^2}}\right )}{d^{2/3}}+\frac {\log \left (a^3 \sqrt [3]{d}-2 a^2 \sqrt [3]{d} x+a \sqrt [3]{d} x^2-a \sqrt [3]{a b+(-a-b) x+x^2}\right )}{d^{2/3}}-\frac {\log \left (a^6 d^{2/3}-4 a^5 d^{2/3} x+6 a^4 d^{2/3} x^2-4 a^3 d^{2/3} x^3+a^2 d^{2/3} x^4+a^2 \left (a b+(-a-b) x+x^2\right )^{2/3}+\sqrt [3]{a b+(-a-b) x+x^2} \left (a^4 \sqrt [3]{d}-2 a^3 \sqrt [3]{d} x+a^2 \sqrt [3]{d} x^2\right )\right )}{2 d^{2/3}} \]
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\[ \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx=\int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{\left (a b+(-a-b) x+x^2\right )^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx \\ & = \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx \\ & = \int \frac {(-a+5 b-4 x) (a-x)^3}{((a-x) (b-x))^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx \\ & = \int \frac {(-a+5 b-4 x) (a-x)^3}{\left (a b+(-a-b) x+x^2\right )^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx \\ & = \int \frac {(-a+5 b-4 x) (a-x)^3}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx \\ & = \int \left (\frac {a^4 \left (1-\frac {5 b}{a}\right )}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (-b \left (1-\frac {a^5 d}{b}\right )+\left (1-5 a^4 d\right ) x+10 a^3 d x^2-10 a^2 d x^3+5 a d x^4-d x^5\right )}+\frac {a^3 \left (1+\frac {15 b}{a}\right ) x}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (-b \left (1-\frac {a^5 d}{b}\right )+\left (1-5 a^4 d\right ) x+10 a^3 d x^2-10 a^2 d x^3+5 a d x^4-d x^5\right )}+\frac {11 a \left (1+\frac {5 b}{11 a}\right ) x^3}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (-b \left (1-\frac {a^5 d}{b}\right )+\left (1-5 a^4 d\right ) x+10 a^3 d x^2-10 a^2 d x^3+5 a d x^4-d x^5\right )}+\frac {9 a^2 \left (1+\frac {5 b}{3 a}\right ) x^2}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )}+\frac {4 x^4}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )}\right ) \, dx \\ & = 4 \int \frac {x^4}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx+\left (a^3 (a-5 b)\right ) \int \frac {1}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (-b \left (1-\frac {a^5 d}{b}\right )+\left (1-5 a^4 d\right ) x+10 a^3 d x^2-10 a^2 d x^3+5 a d x^4-d x^5\right )} \, dx+(3 a (3 a+5 b)) \int \frac {x^2}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx+(11 a+5 b) \int \frac {x^3}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (-b \left (1-\frac {a^5 d}{b}\right )+\left (1-5 a^4 d\right ) x+10 a^3 d x^2-10 a^2 d x^3+5 a d x^4-d x^5\right )} \, dx+\left (a^2 (a+15 b)\right ) \int \frac {x}{\left (a b-(a+b) x+x^2\right )^{2/3} \left (-b \left (1-\frac {a^5 d}{b}\right )+\left (1-5 a^4 d\right ) x+10 a^3 d x^2-10 a^2 d x^3+5 a d x^4-d x^5\right )} \, dx \\ \end{align*}
\[ \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx=\int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx \]
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\[\int \frac {\left (a -5 b +4 x \right ) \left (-a^{3}+3 a^{2} x -3 a \,x^{2}+x^{3}\right )}{\left (\left (-a +x \right ) \left (-b +x \right )\right )^{\frac {2}{3}} \left (b -a^{5} d -\left (-5 a^{4} d +1\right ) x -10 a^{3} d \,x^{2}+10 a^{2} d \,x^{3}-5 a d \,x^{4}+d \,x^{5}\right )}d x\]
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Timed out. \[ \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx=\int \frac {\left (- a + x\right )^{3} \left (a - 5 b + 4 x\right )}{\left (\left (- a + x\right ) \left (- b + x\right )\right )^{\frac {2}{3}} \left (- a^{5} d + 5 a^{4} d x - 10 a^{3} d x^{2} + 10 a^{2} d x^{3} - 5 a d x^{4} + b + d x^{5} - x\right )}\, dx \]
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\[ \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx=\int { \frac {{\left (a^{3} - 3 \, a^{2} x + 3 \, a x^{2} - x^{3}\right )} {\left (a - 5 \, b + 4 \, x\right )}}{{\left (a^{5} d + 10 \, a^{3} d x^{2} - 10 \, a^{2} d x^{3} + 5 \, a d x^{4} - d x^{5} - {\left (5 \, a^{4} d - 1\right )} x - b\right )} \left ({\left (a - x\right )} {\left (b - x\right )}\right )^{\frac {2}{3}}} \,d x } \]
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\[ \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx=\int { \frac {{\left (a^{3} - 3 \, a^{2} x + 3 \, a x^{2} - x^{3}\right )} {\left (a - 5 \, b + 4 \, x\right )}}{{\left (a^{5} d + 10 \, a^{3} d x^{2} - 10 \, a^{2} d x^{3} + 5 \, a d x^{4} - d x^{5} - {\left (5 \, a^{4} d - 1\right )} x - b\right )} \left ({\left (a - x\right )} {\left (b - x\right )}\right )^{\frac {2}{3}}} \,d x } \]
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Timed out. \[ \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx=\int -\frac {\left (a-5\,b+4\,x\right )\,\left (a^3-3\,a^2\,x+3\,a\,x^2-x^3\right )}{{\left (\left (a-x\right )\,\left (b-x\right )\right )}^{2/3}\,\left (b-a^5\,d+d\,x^5+x\,\left (5\,a^4\,d-1\right )+10\,a^2\,d\,x^3-10\,a^3\,d\,x^2-5\,a\,d\,x^4\right )} \,d x \]
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