Integrand size = 49, antiderivative size = 337 \[ \int \frac {-x^2+\sqrt {1+2 x^2}+\left (1+2 x^2\right )^{5/2}}{x^2-x \left (1+2 x^2\right )^{3/2}} \, dx=-x^2+\frac {1}{2} \left (2+\sqrt {2}\right ) \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}\right )-2 \log \left (-2 x^2+\sqrt {2} x \sqrt {1+2 x^2}\right )+\frac {1}{2} \text {RootSum}\left [1+3 \text {$\#$1}^2-2 \sqrt {2} \text {$\#$1}^2+3 \text {$\#$1}^4+2 \sqrt {2} \text {$\#$1}^4+\text {$\#$1}^6\&,\frac {-\log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right )+4 \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}+2 \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}^3+4 \sqrt {2} \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}^3+\log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}^4+2 \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}^5}{3 \text {$\#$1}-2 \sqrt {2} \text {$\#$1}+6 \text {$\#$1}^3+4 \sqrt {2} \text {$\#$1}^3+3 \text {$\#$1}^5}\&\right ] \]
[Out]
Result contains complex when optimal does not.
Time = 1.63 (sec) , antiderivative size = 776, normalized size of antiderivative = 2.30, number of steps used = 112, number of rules used = 37, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.755, Rules used = {6874, 399, 221, 385, 212, 14, 455, 45, 1706, 214, 211, 1261, 648, 631, 210, 642, 1265, 787, 12, 427, 542, 537, 272, 715, 814, 209, 52, 65, 1183, 632, 713, 1141, 1175, 1178, 838, 721, 1108} \[ \int \frac {-x^2+\sqrt {1+2 x^2}+\left (1+2 x^2\right )^{5/2}}{x^2-x \left (1+2 x^2\right )^{3/2}} \, dx=-\frac {\text {arcsinh}\left (\sqrt {2} x\right )}{\sqrt {2}}-\left (\frac {2}{5}-\frac {3 i}{10}\right ) \arctan \left (\frac {(1+i) x}{\sqrt {2 x^2+1}}\right )+\frac {1}{5} \arctan \left (\sqrt {2 x^2+1}\right )-\frac {2}{5} \arctan \left (4 x^2+1\right )+\frac {1}{10} \sqrt {\frac {1}{2} \left (1+\sqrt {2}\right )} \arctan \left (\frac {\sqrt {1+\sqrt {2}}-2 \sqrt {2 x^2+1}}{\sqrt {\sqrt {2}-1}}\right )-\frac {3 \arctan \left (\frac {\sqrt {1+\sqrt {2}}-2 \sqrt {2 x^2+1}}{\sqrt {\sqrt {2}-1}}\right )}{20 \sqrt {\sqrt {2}-1}}-\frac {1}{10} \sqrt {\frac {1}{2} \left (1+\sqrt {2}\right )} \arctan \left (\frac {2 \sqrt {2 x^2+1}+\sqrt {1+\sqrt {2}}}{\sqrt {\sqrt {2}-1}}\right )+\frac {3 \arctan \left (\frac {2 \sqrt {2 x^2+1}+\sqrt {1+\sqrt {2}}}{\sqrt {\sqrt {2}-1}}\right )}{20 \sqrt {\sqrt {2}-1}}-\frac {\arctan (x)}{5}-\frac {1}{20} \sqrt {5 \sqrt {2}-1} \arctan \left (-2 \sqrt {2 \left (\sqrt {2}-1\right )} x-\sqrt {2}+1\right )+\frac {1}{20} \sqrt {5 \sqrt {2}-1} \arctan \left (2 \sqrt {2 \left (\sqrt {2}-1\right )} x-\sqrt {2}+1\right )+\frac {2}{5} \text {arctanh}\left (\frac {x}{\sqrt {2 x^2+1}}\right )-\left (\frac {3}{10}-\frac {2 i}{5}\right ) \text {arctanh}\left (\frac {(1+i) x}{\sqrt {2 x^2+1}}\right )-x^2+\frac {1}{5} \log \left (x^2+1\right )+\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (4 x^2-2 \sqrt {2 \left (\sqrt {2}-1\right )} x+\sqrt {2}\right )-\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (4 x^2+2 \sqrt {2 \left (\sqrt {2}-1\right )} x+\sqrt {2}\right )+\frac {\log \left (2 \left (2 x^2+1\right )-2 \sqrt {1+\sqrt {2}} \sqrt {2 x^2+1}+\sqrt {2}\right )}{20 \sqrt {2 \left (1+\sqrt {2}\right )}}+\frac {3 \log \left (2 \left (2 x^2+1\right )-2 \sqrt {1+\sqrt {2}} \sqrt {2 x^2+1}+\sqrt {2}\right )}{40 \sqrt {1+\sqrt {2}}}-\frac {\log \left (\sqrt {2} \left (2 x^2+1\right )+\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {2 x^2+1}+1\right )}{20 \sqrt {2 \left (1+\sqrt {2}\right )}}-\frac {3 \log \left (\sqrt {2} \left (2 x^2+1\right )+\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {2 x^2+1}+1\right )}{40 \sqrt {1+\sqrt {2}}}+\frac {3}{20} \log \left (8 x^4+4 x^2+1\right )-2 \log (x) \]
[In]
[Out]
Rule 12
Rule 14
Rule 45
Rule 52
Rule 65
Rule 209
Rule 210
Rule 211
Rule 212
Rule 214
Rule 221
Rule 272
Rule 385
Rule 399
Rule 427
Rule 455
Rule 537
Rule 542
Rule 631
Rule 632
Rule 642
Rule 648
Rule 713
Rule 715
Rule 721
Rule 787
Rule 814
Rule 838
Rule 1108
Rule 1141
Rule 1175
Rule 1178
Rule 1183
Rule 1261
Rule 1265
Rule 1706
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {\sqrt {1+2 x^2}}{x \left (-x+\sqrt {1+2 x^2}+2 x^2 \sqrt {1+2 x^2}\right )}-\frac {\left (1+2 x^2\right )^{5/2}}{x \left (-x+\sqrt {1+2 x^2}+2 x^2 \sqrt {1+2 x^2}\right )}-\frac {x}{x-\left (1+2 x^2\right )^{3/2}}\right ) \, dx \\ & = -\int \frac {\sqrt {1+2 x^2}}{x \left (-x+\sqrt {1+2 x^2}+2 x^2 \sqrt {1+2 x^2}\right )} \, dx-\int \frac {\left (1+2 x^2\right )^{5/2}}{x \left (-x+\sqrt {1+2 x^2}+2 x^2 \sqrt {1+2 x^2}\right )} \, dx-\int \frac {x}{x-\left (1+2 x^2\right )^{3/2}} \, dx \\ & = -\int \left (\frac {1}{5 \left (1+x^2\right )}+\frac {x \sqrt {1+2 x^2}}{5 \left (1+x^2\right )}+\frac {-1-8 x^2}{5 \left (1+4 x^2+8 x^4\right )}-\frac {6 x \sqrt {1+2 x^2}}{5 \left (1+4 x^2+8 x^4\right )}-\frac {8 x^3 \sqrt {1+2 x^2}}{5 \left (1+4 x^2+8 x^4\right )}\right ) \, dx-\int \left (\frac {\sqrt {1+2 x^2}}{5 \left (1+x^2\right )}+\frac {1+2 x^2}{x}+\frac {x \left (1+2 x^2\right )}{5 \left (1+x^2\right )}-\frac {4 \left (-1+2 x^2\right ) \sqrt {1+2 x^2}}{5 \left (1+4 x^2+8 x^4\right )}-\frac {16 x \left (1+2 x^2\right )}{5 \left (1+4 x^2+8 x^4\right )}-\frac {48 x^3 \left (1+2 x^2\right )}{5 \left (1+4 x^2+8 x^4\right )}\right ) \, dx-\int \left (\frac {\left (1+2 x^2\right )^{5/2}}{5 \left (1+x^2\right )}+\frac {\left (1+2 x^2\right )^3}{x}+\frac {x \left (1+2 x^2\right )^3}{5 \left (1+x^2\right )}-\frac {4 \left (-1+2 x^2\right ) \left (1+2 x^2\right )^{5/2}}{5 \left (1+4 x^2+8 x^4\right )}-\frac {16 x \left (1+2 x^2\right )^3}{5 \left (1+4 x^2+8 x^4\right )}-\frac {48 x^3 \left (1+2 x^2\right )^3}{5 \left (1+4 x^2+8 x^4\right )}\right ) \, dx \\ & = -\left (\frac {1}{5} \int \frac {1}{1+x^2} \, dx\right )-\frac {1}{5} \int \frac {\sqrt {1+2 x^2}}{1+x^2} \, dx-\frac {1}{5} \int \frac {x \sqrt {1+2 x^2}}{1+x^2} \, dx-\frac {1}{5} \int \frac {x \left (1+2 x^2\right )}{1+x^2} \, dx-\frac {1}{5} \int \frac {\left (1+2 x^2\right )^{5/2}}{1+x^2} \, dx-\frac {1}{5} \int \frac {x \left (1+2 x^2\right )^3}{1+x^2} \, dx-\frac {1}{5} \int \frac {-1-8 x^2}{1+4 x^2+8 x^4} \, dx+\frac {4}{5} \int \frac {\left (-1+2 x^2\right ) \sqrt {1+2 x^2}}{1+4 x^2+8 x^4} \, dx+\frac {4}{5} \int \frac {\left (-1+2 x^2\right ) \left (1+2 x^2\right )^{5/2}}{1+4 x^2+8 x^4} \, dx+\frac {6}{5} \int \frac {x \sqrt {1+2 x^2}}{1+4 x^2+8 x^4} \, dx+\frac {8}{5} \int \frac {x^3 \sqrt {1+2 x^2}}{1+4 x^2+8 x^4} \, dx+\frac {16}{5} \int \frac {x \left (1+2 x^2\right )}{1+4 x^2+8 x^4} \, dx+\frac {16}{5} \int \frac {x \left (1+2 x^2\right )^3}{1+4 x^2+8 x^4} \, dx+\frac {48}{5} \int \frac {x^3 \left (1+2 x^2\right )}{1+4 x^2+8 x^4} \, dx+\frac {48}{5} \int \frac {x^3 \left (1+2 x^2\right )^3}{1+4 x^2+8 x^4} \, dx-\int \frac {1+2 x^2}{x} \, dx-\int \frac {\left (1+2 x^2\right )^3}{x} \, dx \\ & = -\frac {1}{10} x \left (1+2 x^2\right )^{3/2}-\frac {\arctan (x)}{5}-\frac {1}{20} \int \frac {\left (2-2 x^2\right ) \sqrt {1+2 x^2}}{1+x^2} \, dx-\frac {1}{10} \text {Subst}\left (\int \frac {\sqrt {1+2 x}}{1+x} \, dx,x,x^2\right )-\frac {1}{10} \text {Subst}\left (\int \frac {1+2 x}{1+x} \, dx,x,x^2\right )-\frac {1}{10} \text {Subst}\left (\int \frac {(1+2 x)^3}{1+x} \, dx,x,x^2\right )+\frac {1}{5} \int \frac {1}{\left (1+x^2\right ) \sqrt {1+2 x^2}} \, dx-\frac {2}{5} \int \frac {1}{\sqrt {1+2 x^2}} \, dx-\frac {1}{2} \text {Subst}\left (\int \frac {(1+2 x)^3}{x} \, dx,x,x^2\right )+\frac {3}{5} \text {Subst}\left (\int \frac {\sqrt {1+2 x}}{1+4 x+8 x^2} \, dx,x,x^2\right )+\frac {4}{5} \int \left (\frac {(2+6 i) \sqrt {1+2 x^2}}{(4-4 i)+16 x^2}+\frac {(2-6 i) \sqrt {1+2 x^2}}{(4+4 i)+16 x^2}\right ) \, dx+\frac {4}{5} \int \left (\frac {(2+6 i) \left (1+2 x^2\right )^{5/2}}{(4-4 i)+16 x^2}+\frac {(2-6 i) \left (1+2 x^2\right )^{5/2}}{(4+4 i)+16 x^2}\right ) \, dx+\frac {4}{5} \text {Subst}\left (\int \frac {x \sqrt {1+2 x}}{1+4 x+8 x^2} \, dx,x,x^2\right )+\frac {8}{5} \text {Subst}\left (\int \frac {1+2 x}{1+4 x+8 x^2} \, dx,x,x^2\right )+\frac {8}{5} \text {Subst}\left (\int \frac {(1+2 x)^3}{1+4 x+8 x^2} \, dx,x,x^2\right )+\frac {24}{5} \text {Subst}\left (\int \frac {x (1+2 x)}{1+4 x+8 x^2} \, dx,x,x^2\right )+\frac {24}{5} \text {Subst}\left (\int \frac {x (1+2 x)^3}{1+4 x+8 x^2} \, dx,x,x^2\right )-\frac {\int \frac {-\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )}-\left (-1+2 \sqrt {2}\right ) x}{\frac {1}{2 \sqrt {2}}-\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )} x+x^2} \, dx}{20 \sqrt {-1+\sqrt {2}}}-\frac {\int \frac {-\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )}+\left (-1+2 \sqrt {2}\right ) x}{\frac {1}{2 \sqrt {2}}+\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )} x+x^2} \, dx}{20 \sqrt {-1+\sqrt {2}}}-\int \left (\frac {1}{x}+2 x\right ) \, dx \\ & = \frac {x^2}{5}+\frac {1}{20} x \sqrt {1+2 x^2}-\frac {1}{10} x \left (1+2 x^2\right )^{3/2}-\frac {1}{5} \sqrt {2} \text {arcsinh}\left (\sqrt {2} x\right )-\frac {\arctan (x)}{5}-\log (x)-\frac {1}{40} \int \frac {6+14 x^2}{\left (1+x^2\right ) \sqrt {1+2 x^2}} \, dx-\frac {1}{10} \text {Subst}\left (\int \left (2+\frac {1}{-1-x}\right ) \, dx,x,x^2\right )+\frac {1}{10} \text {Subst}\left (\int \frac {1}{(1+x) \sqrt {1+2 x}} \, dx,x,x^2\right )+\frac {1}{10} \text {Subst}\left (\int -\frac {2}{\sqrt {1+2 x} \left (1+4 x+8 x^2\right )} \, dx,x,x^2\right )-\frac {1}{10} \text {Subst}\left (\int \left (2+\frac {1}{-1-x}+4 x+8 x^2\right ) \, dx,x,x^2\right )+\frac {1}{5} \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {x}{\sqrt {1+2 x^2}}\right )+\frac {1}{5} \text {Subst}\left (\int \frac {4+16 x}{1+4 x+8 x^2} \, dx,x,x^2\right )-\frac {1}{2} \text {Subst}\left (\int \left (6+\frac {1}{x}+12 x+8 x^2\right ) \, dx,x,x^2\right )+\frac {3}{5} \text {Subst}\left (\int -\frac {2}{1+4 x+8 x^2} \, dx,x,x^2\right )+\frac {4}{5} \text {Subst}\left (\int \frac {1}{1+4 x+8 x^2} \, dx,x,x^2\right )+\frac {8}{5} \text {Subst}\left (\int \left (1+x+\frac {x}{1+4 x+8 x^2}\right ) \, dx,x,x^2\right )+\left (\frac {8}{5}-\frac {24 i}{5}\right ) \int \frac {\sqrt {1+2 x^2}}{(4+4 i)+16 x^2} \, dx+\left (\frac {8}{5}-\frac {24 i}{5}\right ) \int \frac {\left (1+2 x^2\right )^{5/2}}{(4+4 i)+16 x^2} \, dx+\left (\frac {8}{5}+\frac {24 i}{5}\right ) \int \frac {\sqrt {1+2 x^2}}{(4-4 i)+16 x^2} \, dx+\left (\frac {8}{5}+\frac {24 i}{5}\right ) \int \frac {\left (1+2 x^2\right )^{5/2}}{(4-4 i)+16 x^2} \, dx+\frac {12}{5} \text {Subst}\left (\int \frac {x^2}{4-8 x^2+8 x^4} \, dx,x,\sqrt {1+2 x^2}\right )+\frac {24}{5} \text {Subst}\left (\int \left (\frac {1}{8}+x+x^2-\frac {1+4 x}{8 \left (1+4 x+8 x^2\right )}\right ) \, dx,x,x^2\right )+\frac {1}{80} \left (4+\sqrt {2}\right ) \int \frac {1}{\frac {1}{2 \sqrt {2}}-\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )} x+x^2} \, dx+\frac {1}{80} \left (4+\sqrt {2}\right ) \int \frac {1}{\frac {1}{2 \sqrt {2}}+\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )} x+x^2} \, dx+\frac {1}{40} \sqrt {1+5 \sqrt {2}} \int \frac {-\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )}+2 x}{\frac {1}{2 \sqrt {2}}-\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )} x+x^2} \, dx-\frac {1}{40} \sqrt {1+5 \sqrt {2}} \int \frac {\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )}+2 x}{\frac {1}{2 \sqrt {2}}+\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )} x+x^2} \, dx \\ & = -x^2+\frac {1}{20} x \sqrt {1+2 x^2}-\frac {1}{5} \sqrt {2} \text {arcsinh}\left (\sqrt {2} x\right )-\frac {\arctan (x)}{5}+\frac {1}{5} \text {arctanh}\left (\frac {x}{\sqrt {1+2 x^2}}\right )-2 \log (x)+\frac {1}{5} \log \left (1+x^2\right )+\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )-\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )+\frac {1}{5} \log \left (1+4 x^2+8 x^4\right )+\left (-\frac {8}{5}-\frac {16 i}{5}\right ) \int \frac {1}{\sqrt {1+2 x^2} \left ((4+4 i)+16 x^2\right )} \, dx+\left (-\frac {8}{5}+\frac {16 i}{5}\right ) \int \frac {1}{\sqrt {1+2 x^2} \left ((4-4 i)+16 x^2\right )} \, dx+\left (\frac {1}{40}-\frac {3 i}{40}\right ) \int \frac {\sqrt {1+2 x^2} \left ((56-8 i)+(160-64 i) x^2\right )}{(4+4 i)+16 x^2} \, dx+\left (\frac {1}{40}+\frac {3 i}{40}\right ) \int \frac {\sqrt {1+2 x^2} \left ((56+8 i)+(160+64 i) x^2\right )}{(4-4 i)+16 x^2} \, dx+\frac {1}{10} \text {Subst}\left (\int \frac {1}{\frac {1}{2}+\frac {x^2}{2}} \, dx,x,\sqrt {1+2 x^2}\right )+\frac {1}{5} \int \frac {1}{\left (1+x^2\right ) \sqrt {1+2 x^2}} \, dx-\frac {1}{5} \text {Subst}\left (\int \frac {1}{\sqrt {1+2 x} \left (1+4 x+8 x^2\right )} \, dx,x,x^2\right )+\left (\frac {1}{5}-\frac {3 i}{5}\right ) \int \frac {1}{\sqrt {1+2 x^2}} \, dx+\left (\frac {1}{5}+\frac {3 i}{5}\right ) \int \frac {1}{\sqrt {1+2 x^2}} \, dx-\frac {7}{20} \int \frac {1}{\sqrt {1+2 x^2}} \, dx-\frac {2}{5} \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+4 x^2\right )-\frac {3}{5} \text {Subst}\left (\int \frac {1+4 x}{1+4 x+8 x^2} \, dx,x,x^2\right )-\frac {6}{5} \text {Subst}\left (\int \frac {1}{1+4 x+8 x^2} \, dx,x,x^2\right )-\frac {6}{5} \text {Subst}\left (\int \frac {\frac {1}{\sqrt {2}}-x^2}{4-8 x^2+8 x^4} \, dx,x,\sqrt {1+2 x^2}\right )+\frac {6}{5} \text {Subst}\left (\int \frac {\frac {1}{\sqrt {2}}+x^2}{4-8 x^2+8 x^4} \, dx,x,\sqrt {1+2 x^2}\right )+\frac {8}{5} \text {Subst}\left (\int \frac {x}{1+4 x+8 x^2} \, dx,x,x^2\right )-\frac {1}{40} \left (4+\sqrt {2}\right ) \text {Subst}\left (\int \frac {1}{\frac {1}{2} \left (-1-\sqrt {2}\right )-x^2} \, dx,x,-\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )}+2 x\right )-\frac {1}{40} \left (4+\sqrt {2}\right ) \text {Subst}\left (\int \frac {1}{\frac {1}{2} \left (-1-\sqrt {2}\right )-x^2} \, dx,x,\sqrt {\frac {1}{2} \left (-1+\sqrt {2}\right )}+2 x\right ) \\ & = -x^2+\frac {\text {arcsinh}\left (\sqrt {2} x\right )}{20 \sqrt {2}}-\frac {1}{5} \sqrt {2} \text {arcsinh}\left (\sqrt {2} x\right )-\frac {\arctan (x)}{5}-\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )+\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )+\frac {1}{5} \arctan \left (\sqrt {1+2 x^2}\right )+\frac {2}{5} \arctan \left (1+4 x^2\right )+\frac {1}{5} \text {arctanh}\left (\frac {x}{\sqrt {1+2 x^2}}\right )-2 \log (x)+\frac {1}{5} \log \left (1+x^2\right )+\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )-\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )+\frac {1}{20} \log \left (1+4 x^2+8 x^4\right )+\left (-\frac {8}{5}-\frac {16 i}{5}\right ) \text {Subst}\left (\int \frac {1}{(4+4 i)+(8-8 i) x^2} \, dx,x,\frac {x}{\sqrt {1+2 x^2}}\right )+\left (-\frac {8}{5}+\frac {16 i}{5}\right ) \text {Subst}\left (\int \frac {1}{(4-4 i)+(8+8 i) x^2} \, dx,x,\frac {x}{\sqrt {1+2 x^2}}\right )+\left (\frac {1}{1280}-\frac {3 i}{1280}\right ) \int \frac {(896-640 i)+(2560-3072 i) x^2}{\sqrt {1+2 x^2} \left ((4+4 i)+16 x^2\right )} \, dx+\left (\frac {1}{1280}+\frac {3 i}{1280}\right ) \int \frac {(896+640 i)+(2560+3072 i) x^2}{\sqrt {1+2 x^2} \left ((4-4 i)+16 x^2\right )} \, dx+\frac {3}{40} \text {Subst}\left (\int \frac {1}{\frac {1}{\sqrt {2}}-\sqrt {1+\sqrt {2}} x+x^2} \, dx,x,\sqrt {1+2 x^2}\right )+\frac {3}{40} \text {Subst}\left (\int \frac {1}{\frac {1}{\sqrt {2}}+\sqrt {1+\sqrt {2}} x+x^2} \, dx,x,\sqrt {1+2 x^2}\right )+\frac {1}{10} \text {Subst}\left (\int \frac {4+16 x}{1+4 x+8 x^2} \, dx,x,x^2\right )+\frac {1}{5} \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {x}{\sqrt {1+2 x^2}}\right )-\frac {2}{5} \text {Subst}\left (\int \frac {1}{1+4 x+8 x^2} \, dx,x,x^2\right )+\frac {3}{5} \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+4 x^2\right )-\frac {4}{5} \text {Subst}\left (\int \frac {1}{4-8 x^2+8 x^4} \, dx,x,\sqrt {1+2 x^2}\right )+\frac {3 \text {Subst}\left (\int \frac {\sqrt {1+\sqrt {2}}+2 x}{-\frac {1}{\sqrt {2}}-\sqrt {1+\sqrt {2}} x-x^2} \, dx,x,\sqrt {1+2 x^2}\right )}{40 \sqrt {1+\sqrt {2}}}+\frac {3 \text {Subst}\left (\int \frac {\sqrt {1+\sqrt {2}}-2 x}{-\frac {1}{\sqrt {2}}+\sqrt {1+\sqrt {2}} x-x^2} \, dx,x,\sqrt {1+2 x^2}\right )}{40 \sqrt {1+\sqrt {2}}} \\ & = -x^2+\frac {\text {arcsinh}\left (\sqrt {2} x\right )}{20 \sqrt {2}}-\frac {1}{5} \sqrt {2} \text {arcsinh}\left (\sqrt {2} x\right )-\frac {\arctan (x)}{5}-\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )+\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )-\left (\frac {1}{5}-\frac {2 i}{5}\right ) \arctan \left (\frac {(1+i) x}{\sqrt {1+2 x^2}}\right )+\frac {1}{5} \arctan \left (\sqrt {1+2 x^2}\right )-\frac {1}{5} \arctan \left (1+4 x^2\right )+\frac {2}{5} \text {arctanh}\left (\frac {x}{\sqrt {1+2 x^2}}\right )-\left (\frac {2}{5}-\frac {i}{5}\right ) \text {arctanh}\left (\frac {(1+i) x}{\sqrt {1+2 x^2}}\right )-2 \log (x)+\frac {1}{5} \log \left (1+x^2\right )+\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )-\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )+\frac {3}{20} \log \left (1+4 x^2+8 x^4\right )+\frac {3 \log \left (\sqrt {2}-2 \sqrt {1+\sqrt {2}} \sqrt {1+2 x^2}+2 \left (1+2 x^2\right )\right )}{40 \sqrt {1+\sqrt {2}}}-\frac {3 \log \left (1+\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {1+2 x^2}+\sqrt {2} \left (1+2 x^2\right )\right )}{40 \sqrt {1+\sqrt {2}}}+\left (-\frac {8}{5}-\frac {4 i}{5}\right ) \int \frac {1}{\sqrt {1+2 x^2} \left ((4-4 i)+16 x^2\right )} \, dx+\left (-\frac {8}{5}+\frac {4 i}{5}\right ) \int \frac {1}{\sqrt {1+2 x^2} \left ((4+4 i)+16 x^2\right )} \, dx+\left (-\frac {13}{40}-\frac {21 i}{40}\right ) \int \frac {1}{\sqrt {1+2 x^2}} \, dx+\left (-\frac {13}{40}+\frac {21 i}{40}\right ) \int \frac {1}{\sqrt {1+2 x^2}} \, dx-\frac {3}{20} \text {Subst}\left (\int \frac {1}{1-\sqrt {2}-x^2} \, dx,x,-\sqrt {1+\sqrt {2}}+2 \sqrt {1+2 x^2}\right )-\frac {3}{20} \text {Subst}\left (\int \frac {1}{1-\sqrt {2}-x^2} \, dx,x,\sqrt {1+\sqrt {2}}+2 \sqrt {1+2 x^2}\right )+\frac {1}{5} \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+4 x^2\right )-\frac {\text {Subst}\left (\int \frac {\sqrt {1+\sqrt {2}}-x}{\frac {1}{\sqrt {2}}-\sqrt {1+\sqrt {2}} x+x^2} \, dx,x,\sqrt {1+2 x^2}\right )}{10 \sqrt {2 \left (1+\sqrt {2}\right )}}-\frac {\text {Subst}\left (\int \frac {\sqrt {1+\sqrt {2}}+x}{\frac {1}{\sqrt {2}}+\sqrt {1+\sqrt {2}} x+x^2} \, dx,x,\sqrt {1+2 x^2}\right )}{10 \sqrt {2 \left (1+\sqrt {2}\right )}} \\ & = -x^2-\frac {3 \text {arcsinh}\left (\sqrt {2} x\right )}{5 \sqrt {2}}-\frac {1}{5} \sqrt {2} \text {arcsinh}\left (\sqrt {2} x\right )-\frac {\arctan (x)}{5}-\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )+\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )-\left (\frac {1}{5}-\frac {2 i}{5}\right ) \arctan \left (\frac {(1+i) x}{\sqrt {1+2 x^2}}\right )+\frac {1}{5} \arctan \left (\sqrt {1+2 x^2}\right )-\frac {2}{5} \arctan \left (1+4 x^2\right )-\frac {3 \arctan \left (\frac {\sqrt {1+\sqrt {2}}-2 \sqrt {1+2 x^2}}{\sqrt {-1+\sqrt {2}}}\right )}{20 \sqrt {-1+\sqrt {2}}}+\frac {3 \arctan \left (\frac {\sqrt {1+\sqrt {2}}+2 \sqrt {1+2 x^2}}{\sqrt {-1+\sqrt {2}}}\right )}{20 \sqrt {-1+\sqrt {2}}}+\frac {2}{5} \text {arctanh}\left (\frac {x}{\sqrt {1+2 x^2}}\right )-\left (\frac {2}{5}-\frac {i}{5}\right ) \text {arctanh}\left (\frac {(1+i) x}{\sqrt {1+2 x^2}}\right )-2 \log (x)+\frac {1}{5} \log \left (1+x^2\right )+\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )-\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )+\frac {3}{20} \log \left (1+4 x^2+8 x^4\right )+\frac {3 \log \left (\sqrt {2}-2 \sqrt {1+\sqrt {2}} \sqrt {1+2 x^2}+2 \left (1+2 x^2\right )\right )}{40 \sqrt {1+\sqrt {2}}}-\frac {3 \log \left (1+\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {1+2 x^2}+\sqrt {2} \left (1+2 x^2\right )\right )}{40 \sqrt {1+\sqrt {2}}}+\left (-\frac {8}{5}-\frac {4 i}{5}\right ) \text {Subst}\left (\int \frac {1}{(4-4 i)+(8+8 i) x^2} \, dx,x,\frac {x}{\sqrt {1+2 x^2}}\right )+\left (-\frac {8}{5}+\frac {4 i}{5}\right ) \text {Subst}\left (\int \frac {1}{(4+4 i)+(8-8 i) x^2} \, dx,x,\frac {x}{\sqrt {1+2 x^2}}\right )-\frac {\text {Subst}\left (\int \frac {1}{\frac {1}{\sqrt {2}}-\sqrt {1+\sqrt {2}} x+x^2} \, dx,x,\sqrt {1+2 x^2}\right )}{20 \sqrt {2}}-\frac {\text {Subst}\left (\int \frac {1}{\frac {1}{\sqrt {2}}+\sqrt {1+\sqrt {2}} x+x^2} \, dx,x,\sqrt {1+2 x^2}\right )}{20 \sqrt {2}}+\frac {\text {Subst}\left (\int \frac {-\sqrt {1+\sqrt {2}}+2 x}{\frac {1}{\sqrt {2}}-\sqrt {1+\sqrt {2}} x+x^2} \, dx,x,\sqrt {1+2 x^2}\right )}{20 \sqrt {2 \left (1+\sqrt {2}\right )}}-\frac {\text {Subst}\left (\int \frac {\sqrt {1+\sqrt {2}}+2 x}{\frac {1}{\sqrt {2}}+\sqrt {1+\sqrt {2}} x+x^2} \, dx,x,\sqrt {1+2 x^2}\right )}{20 \sqrt {2 \left (1+\sqrt {2}\right )}} \\ & = -x^2-\frac {3 \text {arcsinh}\left (\sqrt {2} x\right )}{5 \sqrt {2}}-\frac {1}{5} \sqrt {2} \text {arcsinh}\left (\sqrt {2} x\right )-\frac {\arctan (x)}{5}-\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )+\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )-\left (\frac {2}{5}-\frac {3 i}{10}\right ) \arctan \left (\frac {(1+i) x}{\sqrt {1+2 x^2}}\right )+\frac {1}{5} \arctan \left (\sqrt {1+2 x^2}\right )-\frac {2}{5} \arctan \left (1+4 x^2\right )-\frac {3 \arctan \left (\frac {\sqrt {1+\sqrt {2}}-2 \sqrt {1+2 x^2}}{\sqrt {-1+\sqrt {2}}}\right )}{20 \sqrt {-1+\sqrt {2}}}+\frac {3 \arctan \left (\frac {\sqrt {1+\sqrt {2}}+2 \sqrt {1+2 x^2}}{\sqrt {-1+\sqrt {2}}}\right )}{20 \sqrt {-1+\sqrt {2}}}+\frac {2}{5} \text {arctanh}\left (\frac {x}{\sqrt {1+2 x^2}}\right )-\left (\frac {3}{10}-\frac {2 i}{5}\right ) \text {arctanh}\left (\frac {(1+i) x}{\sqrt {1+2 x^2}}\right )-2 \log (x)+\frac {1}{5} \log \left (1+x^2\right )+\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )-\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )+\frac {3}{20} \log \left (1+4 x^2+8 x^4\right )+\frac {3 \log \left (\sqrt {2}-2 \sqrt {1+\sqrt {2}} \sqrt {1+2 x^2}+2 \left (1+2 x^2\right )\right )}{40 \sqrt {1+\sqrt {2}}}+\frac {\log \left (\sqrt {2}-2 \sqrt {1+\sqrt {2}} \sqrt {1+2 x^2}+2 \left (1+2 x^2\right )\right )}{20 \sqrt {2 \left (1+\sqrt {2}\right )}}-\frac {3 \log \left (1+\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {1+2 x^2}+\sqrt {2} \left (1+2 x^2\right )\right )}{40 \sqrt {1+\sqrt {2}}}-\frac {\log \left (1+\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {1+2 x^2}+\sqrt {2} \left (1+2 x^2\right )\right )}{20 \sqrt {2 \left (1+\sqrt {2}\right )}}+\frac {\text {Subst}\left (\int \frac {1}{1-\sqrt {2}-x^2} \, dx,x,-\sqrt {1+\sqrt {2}}+2 \sqrt {1+2 x^2}\right )}{10 \sqrt {2}}+\frac {\text {Subst}\left (\int \frac {1}{1-\sqrt {2}-x^2} \, dx,x,\sqrt {1+\sqrt {2}}+2 \sqrt {1+2 x^2}\right )}{10 \sqrt {2}} \\ & = -x^2-\frac {3 \text {arcsinh}\left (\sqrt {2} x\right )}{5 \sqrt {2}}-\frac {1}{5} \sqrt {2} \text {arcsinh}\left (\sqrt {2} x\right )-\frac {\arctan (x)}{5}-\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )+\frac {1}{20} \sqrt {-1+5 \sqrt {2}} \arctan \left (1-\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x\right )-\left (\frac {2}{5}-\frac {3 i}{10}\right ) \arctan \left (\frac {(1+i) x}{\sqrt {1+2 x^2}}\right )+\frac {1}{5} \arctan \left (\sqrt {1+2 x^2}\right )-\frac {2}{5} \arctan \left (1+4 x^2\right )-\frac {3 \arctan \left (\frac {\sqrt {1+\sqrt {2}}-2 \sqrt {1+2 x^2}}{\sqrt {-1+\sqrt {2}}}\right )}{20 \sqrt {-1+\sqrt {2}}}+\frac {\arctan \left (\frac {\sqrt {1+\sqrt {2}}-2 \sqrt {1+2 x^2}}{\sqrt {-1+\sqrt {2}}}\right )}{10 \sqrt {2 \left (-1+\sqrt {2}\right )}}+\frac {3 \arctan \left (\frac {\sqrt {1+\sqrt {2}}+2 \sqrt {1+2 x^2}}{\sqrt {-1+\sqrt {2}}}\right )}{20 \sqrt {-1+\sqrt {2}}}-\frac {\arctan \left (\frac {\sqrt {1+\sqrt {2}}+2 \sqrt {1+2 x^2}}{\sqrt {-1+\sqrt {2}}}\right )}{10 \sqrt {2 \left (-1+\sqrt {2}\right )}}+\frac {2}{5} \text {arctanh}\left (\frac {x}{\sqrt {1+2 x^2}}\right )-\left (\frac {3}{10}-\frac {2 i}{5}\right ) \text {arctanh}\left (\frac {(1+i) x}{\sqrt {1+2 x^2}}\right )-2 \log (x)+\frac {1}{5} \log \left (1+x^2\right )+\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}-2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )-\frac {1}{40} \sqrt {1+5 \sqrt {2}} \log \left (\sqrt {2}+2 \sqrt {2 \left (-1+\sqrt {2}\right )} x+4 x^2\right )+\frac {3}{20} \log \left (1+4 x^2+8 x^4\right )+\frac {3 \log \left (\sqrt {2}-2 \sqrt {1+\sqrt {2}} \sqrt {1+2 x^2}+2 \left (1+2 x^2\right )\right )}{40 \sqrt {1+\sqrt {2}}}+\frac {\log \left (\sqrt {2}-2 \sqrt {1+\sqrt {2}} \sqrt {1+2 x^2}+2 \left (1+2 x^2\right )\right )}{20 \sqrt {2 \left (1+\sqrt {2}\right )}}-\frac {3 \log \left (1+\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {1+2 x^2}+\sqrt {2} \left (1+2 x^2\right )\right )}{40 \sqrt {1+\sqrt {2}}}-\frac {\log \left (1+\sqrt {2 \left (1+\sqrt {2}\right )} \sqrt {1+2 x^2}+\sqrt {2} \left (1+2 x^2\right )\right )}{20 \sqrt {2 \left (1+\sqrt {2}\right )}} \\ \end{align*}
Time = 0.79 (sec) , antiderivative size = 327, normalized size of antiderivative = 0.97 \[ \int \frac {-x^2+\sqrt {1+2 x^2}+\left (1+2 x^2\right )^{5/2}}{x^2-x \left (1+2 x^2\right )^{3/2}} \, dx=-x^2+\left (1+\frac {1}{\sqrt {2}}\right ) \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}\right )-2 \log \left (x \left (-2 x+\sqrt {2+4 x^2}\right )\right )+\frac {1}{2} \text {RootSum}\left [1+3 \text {$\#$1}^2-2 \sqrt {2} \text {$\#$1}^2+3 \text {$\#$1}^4+2 \sqrt {2} \text {$\#$1}^4+\text {$\#$1}^6\&,\frac {-\log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right )+4 \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}+2 \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}^3+4 \sqrt {2} \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}^3+\log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}^4+2 \log \left (-\sqrt {2} x+\sqrt {1+2 x^2}-\text {$\#$1}\right ) \text {$\#$1}^5}{3 \text {$\#$1}-2 \sqrt {2} \text {$\#$1}+6 \text {$\#$1}^3+4 \sqrt {2} \text {$\#$1}^3+3 \text {$\#$1}^5}\&\right ] \]
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Timed out.
hanged
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Result contains higher order function than in optimal. Order 3 vs. order 1.
Time = 1.08 (sec) , antiderivative size = 2052, normalized size of antiderivative = 6.09 \[ \int \frac {-x^2+\sqrt {1+2 x^2}+\left (1+2 x^2\right )^{5/2}}{x^2-x \left (1+2 x^2\right )^{3/2}} \, dx=\text {Too large to display} \]
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Not integrable
Time = 102.66 (sec) , antiderivative size = 177, normalized size of antiderivative = 0.53 \[ \int \frac {-x^2+\sqrt {1+2 x^2}+\left (1+2 x^2\right )^{5/2}}{x^2-x \left (1+2 x^2\right )^{3/2}} \, dx=- \int \left (- \frac {x^{2}}{2 x^{3} \sqrt {2 x^{2} + 1} - x^{2} + x \sqrt {2 x^{2} + 1}}\right )\, dx - \int \frac {2 \sqrt {2 x^{2} + 1}}{2 x^{3} \sqrt {2 x^{2} + 1} - x^{2} + x \sqrt {2 x^{2} + 1}}\, dx - \int \frac {4 x^{2} \sqrt {2 x^{2} + 1}}{2 x^{3} \sqrt {2 x^{2} + 1} - x^{2} + x \sqrt {2 x^{2} + 1}}\, dx - \int \frac {4 x^{4} \sqrt {2 x^{2} + 1}}{2 x^{3} \sqrt {2 x^{2} + 1} - x^{2} + x \sqrt {2 x^{2} + 1}}\, dx \]
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Not integrable
Time = 0.26 (sec) , antiderivative size = 243, normalized size of antiderivative = 0.72 \[ \int \frac {-x^2+\sqrt {1+2 x^2}+\left (1+2 x^2\right )^{5/2}}{x^2-x \left (1+2 x^2\right )^{3/2}} \, dx=\int { -\frac {{\left (2 \, x^{2} + 1\right )}^{\frac {5}{2}} - x^{2} + \sqrt {2 \, x^{2} + 1}}{{\left (2 \, x^{2} + 1\right )}^{\frac {3}{2}} x - x^{2}} \,d x } \]
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Result contains higher order function than in optimal. Order 3 vs. order 1.
Time = 1.02 (sec) , antiderivative size = 929, normalized size of antiderivative = 2.76 \[ \int \frac {-x^2+\sqrt {1+2 x^2}+\left (1+2 x^2\right )^{5/2}}{x^2-x \left (1+2 x^2\right )^{3/2}} \, dx=\text {Too large to display} \]
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Time = 7.76 (sec) , antiderivative size = 540, normalized size of antiderivative = 1.60 \[ \int \frac {-x^2+\sqrt {1+2 x^2}+\left (1+2 x^2\right )^{5/2}}{x^2-x \left (1+2 x^2\right )^{3/2}} \, dx=\text {Too large to display} \]
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