Integrand size = 26, antiderivative size = 28 \[ \int \frac {\left (3+x^2\right ) \left (1+x^2+x^3\right )}{x^6 \sqrt [4]{x+x^3}} \, dx=-\frac {4 \left (x+x^3\right )^{3/4} \left (3+3 x^2+7 x^3\right )}{21 x^6} \]
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Time = 0.24 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.75, number of steps used = 21, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {2077, 2050, 2036, 371, 2057} \[ \int \frac {\left (3+x^2\right ) \left (1+x^2+x^3\right )}{x^6 \sqrt [4]{x+x^3}} \, dx=-\frac {4 \left (x^3+x\right )^{3/4}}{3 x^3}-\frac {4 \left (x^3+x\right )^{3/4}}{7 x^6}-\frac {4 \left (x^3+x\right )^{3/4}}{7 x^4} \]
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Rule 371
Rule 2036
Rule 2050
Rule 2057
Rule 2077
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {3}{x^6 \sqrt [4]{x+x^3}}+\frac {4}{x^4 \sqrt [4]{x+x^3}}+\frac {3}{x^3 \sqrt [4]{x+x^3}}+\frac {1}{x^2 \sqrt [4]{x+x^3}}+\frac {1}{x \sqrt [4]{x+x^3}}\right ) \, dx \\ & = 3 \int \frac {1}{x^6 \sqrt [4]{x+x^3}} \, dx+3 \int \frac {1}{x^3 \sqrt [4]{x+x^3}} \, dx+4 \int \frac {1}{x^4 \sqrt [4]{x+x^3}} \, dx+\int \frac {1}{x^2 \sqrt [4]{x+x^3}} \, dx+\int \frac {1}{x \sqrt [4]{x+x^3}} \, dx \\ & = -\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}-\frac {16 \left (x+x^3\right )^{3/4}}{13 x^4}-\frac {4 \left (x+x^3\right )^{3/4}}{3 x^3}-\frac {4 \left (x+x^3\right )^{3/4}}{5 x^2}-\frac {4 \left (x+x^3\right )^{3/4}}{x}+\frac {1}{5} \int \frac {1}{\sqrt [4]{x+x^3}} \, dx-\frac {15}{7} \int \frac {1}{x^4 \sqrt [4]{x+x^3}} \, dx-\frac {28}{13} \int \frac {1}{x^2 \sqrt [4]{x+x^3}} \, dx+5 \int \frac {x}{\sqrt [4]{x+x^3}} \, dx-\int \frac {1}{x \sqrt [4]{x+x^3}} \, dx \\ & = -\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}-\frac {4 \left (x+x^3\right )^{3/4}}{7 x^4}-\frac {4 \left (x+x^3\right )^{3/4}}{3 x^3}+\frac {12 \left (x+x^3\right )^{3/4}}{13 x^2}-\frac {28}{65} \int \frac {1}{\sqrt [4]{x+x^3}} \, dx+\frac {15}{13} \int \frac {1}{x^2 \sqrt [4]{x+x^3}} \, dx-5 \int \frac {x}{\sqrt [4]{x+x^3}} \, dx+\frac {\left (\sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {1}{\sqrt [4]{x} \sqrt [4]{1+x^2}} \, dx}{5 \sqrt [4]{x+x^3}}+\frac {\left (5 \sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {x^{3/4}}{\sqrt [4]{1+x^2}} \, dx}{\sqrt [4]{x+x^3}} \\ & = -\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}-\frac {4 \left (x+x^3\right )^{3/4}}{7 x^4}-\frac {4 \left (x+x^3\right )^{3/4}}{3 x^3}+\frac {4 x \sqrt [4]{1+x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {3}{8},\frac {11}{8},-x^2\right )}{15 \sqrt [4]{x+x^3}}+\frac {20 x^2 \sqrt [4]{1+x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {7}{8},\frac {15}{8},-x^2\right )}{7 \sqrt [4]{x+x^3}}+\frac {3}{13} \int \frac {1}{\sqrt [4]{x+x^3}} \, dx-\frac {\left (28 \sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {1}{\sqrt [4]{x} \sqrt [4]{1+x^2}} \, dx}{65 \sqrt [4]{x+x^3}}-\frac {\left (5 \sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {x^{3/4}}{\sqrt [4]{1+x^2}} \, dx}{\sqrt [4]{x+x^3}} \\ & = -\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}-\frac {4 \left (x+x^3\right )^{3/4}}{7 x^4}-\frac {4 \left (x+x^3\right )^{3/4}}{3 x^3}-\frac {4 x \sqrt [4]{1+x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {3}{8},\frac {11}{8},-x^2\right )}{13 \sqrt [4]{x+x^3}}+\frac {\left (3 \sqrt [4]{x} \sqrt [4]{1+x^2}\right ) \int \frac {1}{\sqrt [4]{x} \sqrt [4]{1+x^2}} \, dx}{13 \sqrt [4]{x+x^3}} \\ & = -\frac {4 \left (x+x^3\right )^{3/4}}{7 x^6}-\frac {4 \left (x+x^3\right )^{3/4}}{7 x^4}-\frac {4 \left (x+x^3\right )^{3/4}}{3 x^3} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 2 in optimal.
Time = 10.09 (sec) , antiderivative size = 124, normalized size of antiderivative = 4.43 \[ \int \frac {\left (3+x^2\right ) \left (1+x^2+x^3\right )}{x^6 \sqrt [4]{x+x^3}} \, dx=-\frac {4 \sqrt [4]{1+x^2} \left (195 \operatorname {Hypergeometric2F1}\left (-\frac {21}{8},\frac {1}{4},-\frac {13}{8},-x^2\right )+7 x^2 \left (60 \operatorname {Hypergeometric2F1}\left (-\frac {13}{8},\frac {1}{4},-\frac {5}{8},-x^2\right )+13 x \left (5 \operatorname {Hypergeometric2F1}\left (-\frac {9}{8},\frac {1}{4},-\frac {1}{8},-x^2\right )+3 x \left (\operatorname {Hypergeometric2F1}\left (-\frac {5}{8},\frac {1}{4},\frac {3}{8},-x^2\right )+5 x \operatorname {Hypergeometric2F1}\left (-\frac {1}{8},\frac {1}{4},\frac {7}{8},-x^2\right )\right )\right )\right )\right )}{1365 x^5 \sqrt [4]{x+x^3}} \]
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Time = 0.83 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.89
method | result | size |
trager | \(-\frac {4 \left (x^{3}+x \right )^{\frac {3}{4}} \left (7 x^{3}+3 x^{2}+3\right )}{21 x^{6}}\) | \(25\) |
gosper | \(-\frac {4 \left (x^{2}+1\right ) \left (7 x^{3}+3 x^{2}+3\right )}{21 x^{5} \left (x^{3}+x \right )^{\frac {1}{4}}}\) | \(30\) |
risch | \(-\frac {4 \left (7 x^{5}+3 x^{4}+7 x^{3}+6 x^{2}+3\right )}{21 x^{5} {\left (\left (x^{2}+1\right ) x \right )}^{\frac {1}{4}}}\) | \(37\) |
meijerg | \(-\frac {4 \operatorname {hypergeom}\left (\left [-\frac {21}{8}, \frac {1}{4}\right ], \left [-\frac {13}{8}\right ], -x^{2}\right )}{7 x^{\frac {21}{4}}}-\frac {4 \operatorname {hypergeom}\left (\left [-\frac {9}{8}, \frac {1}{4}\right ], \left [-\frac {1}{8}\right ], -x^{2}\right )}{3 x^{\frac {9}{4}}}-\frac {16 \operatorname {hypergeom}\left (\left [-\frac {13}{8}, \frac {1}{4}\right ], \left [-\frac {5}{8}\right ], -x^{2}\right )}{13 x^{\frac {13}{4}}}-\frac {4 \operatorname {hypergeom}\left (\left [-\frac {1}{8}, \frac {1}{4}\right ], \left [\frac {7}{8}\right ], -x^{2}\right )}{x^{\frac {1}{4}}}-\frac {4 \operatorname {hypergeom}\left (\left [-\frac {5}{8}, \frac {1}{4}\right ], \left [\frac {3}{8}\right ], -x^{2}\right )}{5 x^{\frac {5}{4}}}\) | \(82\) |
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Time = 0.24 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.86 \[ \int \frac {\left (3+x^2\right ) \left (1+x^2+x^3\right )}{x^6 \sqrt [4]{x+x^3}} \, dx=-\frac {4 \, {\left (7 \, x^{3} + 3 \, x^{2} + 3\right )} {\left (x^{3} + x\right )}^{\frac {3}{4}}}{21 \, x^{6}} \]
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\[ \int \frac {\left (3+x^2\right ) \left (1+x^2+x^3\right )}{x^6 \sqrt [4]{x+x^3}} \, dx=\int \frac {\left (x^{2} + 3\right ) \left (x^{3} + x^{2} + 1\right )}{x^{6} \sqrt [4]{x \left (x^{2} + 1\right )}}\, dx \]
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\[ \int \frac {\left (3+x^2\right ) \left (1+x^2+x^3\right )}{x^6 \sqrt [4]{x+x^3}} \, dx=\int { \frac {{\left (x^{3} + x^{2} + 1\right )} {\left (x^{2} + 3\right )}}{{\left (x^{3} + x\right )}^{\frac {1}{4}} x^{6}} \,d x } \]
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Time = 0.28 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.82 \[ \int \frac {\left (3+x^2\right ) \left (1+x^2+x^3\right )}{x^6 \sqrt [4]{x+x^3}} \, dx=-\frac {4}{7} \, {\left (\frac {1}{x} + \frac {1}{x^{3}}\right )}^{\frac {7}{4}} - \frac {4}{3} \, {\left (\frac {1}{x} + \frac {1}{x^{3}}\right )}^{\frac {3}{4}} \]
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Time = 5.05 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.39 \[ \int \frac {\left (3+x^2\right ) \left (1+x^2+x^3\right )}{x^6 \sqrt [4]{x+x^3}} \, dx=-\frac {12\,{\left (x^3+x\right )}^{3/4}+12\,x^2\,{\left (x^3+x\right )}^{3/4}+28\,x^3\,{\left (x^3+x\right )}^{3/4}}{21\,x^6} \]
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