Integrand size = 15, antiderivative size = 35 \[ \int \frac {1}{x^8 \sqrt [4]{x^2+x^4}} \, dx=\frac {2 \left (x^2+x^4\right )^{3/4} \left (-77+84 x^2-96 x^4+128 x^6\right )}{1155 x^9} \]
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Leaf count is larger than twice the leaf count of optimal. \(73\) vs. \(2(35)=70\).
Time = 0.06 (sec) , antiderivative size = 73, normalized size of antiderivative = 2.09, number of steps used = 4, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {2041, 2039} \[ \int \frac {1}{x^8 \sqrt [4]{x^2+x^4}} \, dx=-\frac {2 \left (x^4+x^2\right )^{3/4}}{15 x^9}+\frac {8 \left (x^4+x^2\right )^{3/4}}{55 x^7}-\frac {64 \left (x^4+x^2\right )^{3/4}}{385 x^5}+\frac {256 \left (x^4+x^2\right )^{3/4}}{1155 x^3} \]
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Rule 2039
Rule 2041
Rubi steps \begin{align*} \text {integral}& = -\frac {2 \left (x^2+x^4\right )^{3/4}}{15 x^9}-\frac {4}{5} \int \frac {1}{x^6 \sqrt [4]{x^2+x^4}} \, dx \\ & = -\frac {2 \left (x^2+x^4\right )^{3/4}}{15 x^9}+\frac {8 \left (x^2+x^4\right )^{3/4}}{55 x^7}+\frac {32}{55} \int \frac {1}{x^4 \sqrt [4]{x^2+x^4}} \, dx \\ & = -\frac {2 \left (x^2+x^4\right )^{3/4}}{15 x^9}+\frac {8 \left (x^2+x^4\right )^{3/4}}{55 x^7}-\frac {64 \left (x^2+x^4\right )^{3/4}}{385 x^5}-\frac {128}{385} \int \frac {1}{x^2 \sqrt [4]{x^2+x^4}} \, dx \\ & = -\frac {2 \left (x^2+x^4\right )^{3/4}}{15 x^9}+\frac {8 \left (x^2+x^4\right )^{3/4}}{55 x^7}-\frac {64 \left (x^2+x^4\right )^{3/4}}{385 x^5}+\frac {256 \left (x^2+x^4\right )^{3/4}}{1155 x^3} \\ \end{align*}
Time = 1.40 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x^8 \sqrt [4]{x^2+x^4}} \, dx=\frac {2 \left (x^2+x^4\right )^{3/4} \left (-77+84 x^2-96 x^4+128 x^6\right )}{1155 x^9} \]
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Time = 0.92 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.86
method | result | size |
meijerg | \(-\frac {2 \left (-\frac {128}{77} x^{6}+\frac {96}{77} x^{4}-\frac {12}{11} x^{2}+1\right ) \left (x^{2}+1\right )^{\frac {3}{4}}}{15 x^{\frac {15}{2}}}\) | \(30\) |
trager | \(\frac {2 \left (x^{4}+x^{2}\right )^{\frac {3}{4}} \left (128 x^{6}-96 x^{4}+84 x^{2}-77\right )}{1155 x^{9}}\) | \(32\) |
pseudoelliptic | \(\frac {2 \left (x^{2} \left (x^{2}+1\right )\right )^{\frac {3}{4}} \left (128 x^{6}-96 x^{4}+84 x^{2}-77\right )}{1155 x^{9}}\) | \(34\) |
gosper | \(\frac {2 \left (x^{2}+1\right ) \left (128 x^{6}-96 x^{4}+84 x^{2}-77\right )}{1155 x^{7} \left (x^{4}+x^{2}\right )^{\frac {1}{4}}}\) | \(37\) |
risch | \(\frac {\frac {2}{165} x^{2}-\frac {2}{15}-\frac {8}{385} x^{4}+\frac {64}{1155} x^{6}+\frac {256}{1155} x^{8}}{x^{7} \left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{4}}}\) | \(39\) |
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Time = 0.23 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.89 \[ \int \frac {1}{x^8 \sqrt [4]{x^2+x^4}} \, dx=\frac {2 \, {\left (128 \, x^{6} - 96 \, x^{4} + 84 \, x^{2} - 77\right )} {\left (x^{4} + x^{2}\right )}^{\frac {3}{4}}}{1155 \, x^{9}} \]
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\[ \int \frac {1}{x^8 \sqrt [4]{x^2+x^4}} \, dx=\int \frac {1}{x^{8} \sqrt [4]{x^{2} \left (x^{2} + 1\right )}}\, dx \]
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Time = 0.28 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.03 \[ \int \frac {1}{x^8 \sqrt [4]{x^2+x^4}} \, dx=\frac {2 \, {\left (128 \, x^{9} + 32 \, x^{7} - 12 \, x^{5} + 7 \, x^{3} - 77 \, x\right )}}{1155 \, {\left (x^{2} + 1\right )}^{\frac {1}{4}} x^{\frac {17}{2}}} \]
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Time = 0.28 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.06 \[ \int \frac {1}{x^8 \sqrt [4]{x^2+x^4}} \, dx=-\frac {2}{15} \, {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {15}{4}} + \frac {6}{11} \, {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {11}{4}} - \frac {6}{7} \, {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {7}{4}} + \frac {2}{3} \, {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {3}{4}} \]
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Time = 5.51 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.63 \[ \int \frac {1}{x^8 \sqrt [4]{x^2+x^4}} \, dx=\frac {256\,{\left (x^4+x^2\right )}^{3/4}}{1155\,x^3}-\frac {64\,{\left (x^4+x^2\right )}^{3/4}}{385\,x^5}+\frac {8\,{\left (x^4+x^2\right )}^{3/4}}{55\,x^7}-\frac {2\,{\left (x^4+x^2\right )}^{3/4}}{15\,x^9} \]
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