Integrand size = 28, antiderivative size = 35 \[ \int \frac {1+2 x}{\sqrt {-4-3 x-2 x^2+2 x^3+x^4}} \, dx=\log \left (-3+2 x+2 x^2+2 \sqrt {-4-3 x-2 x^2+2 x^3+x^4}\right ) \]
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Time = 0.03 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.11, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {1694, 12, 1121, 635, 212} \[ \int \frac {1+2 x}{\sqrt {-4-3 x-2 x^2+2 x^3+x^4}} \, dx=-\text {arctanh}\left (\frac {7-4 \left (x+\frac {1}{2}\right )^2}{\sqrt {16 \left (x+\frac {1}{2}\right )^4-56 \left (x+\frac {1}{2}\right )^2-51}}\right ) \]
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Rule 12
Rule 212
Rule 635
Rule 1121
Rule 1694
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {8 x}{\sqrt {-51-56 x^2+16 x^4}} \, dx,x,\frac {1}{2}+x\right ) \\ & = 8 \text {Subst}\left (\int \frac {x}{\sqrt {-51-56 x^2+16 x^4}} \, dx,x,\frac {1}{2}+x\right ) \\ & = 4 \text {Subst}\left (\int \frac {1}{\sqrt {-51-56 x+16 x^2}} \, dx,x,\left (\frac {1}{2}+x\right )^2\right ) \\ & = 8 \text {Subst}\left (\int \frac {1}{64-x^2} \, dx,x,\frac {8 \left (-7+4 \left (\frac {1}{2}+x\right )^2\right )}{\sqrt {-51-56 \left (\frac {1}{2}+x\right )^2+(1+2 x)^4}}\right ) \\ & = -\text {arctanh}\left (\frac {7-(1+2 x)^2}{\sqrt {-51-14 (1+2 x)^2+(1+2 x)^4}}\right ) \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.06 \[ \int \frac {1+2 x}{\sqrt {-4-3 x-2 x^2+2 x^3+x^4}} \, dx=-\log \left (3-2 x-2 x^2+2 \sqrt {-4-3 x-2 x^2+2 x^3+x^4}\right ) \]
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Time = 2.98 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.97
method | result | size |
default | \(\ln \left (-3+2 x +2 x^{2}+2 \sqrt {x^{4}+2 x^{3}-2 x^{2}-3 x -4}\right )\) | \(34\) |
pseudoelliptic | \(\ln \left (-3+2 x +2 x^{2}+2 \sqrt {x^{4}+2 x^{3}-2 x^{2}-3 x -4}\right )\) | \(34\) |
trager | \(-\ln \left (-2 x^{2}+2 \sqrt {x^{4}+2 x^{3}-2 x^{2}-3 x -4}-2 x +3\right )\) | \(36\) |
elliptic | \(\text {Expression too large to display}\) | \(782\) |
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none
Time = 0.27 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.94 \[ \int \frac {1+2 x}{\sqrt {-4-3 x-2 x^2+2 x^3+x^4}} \, dx=\log \left (2 \, x^{2} + 2 \, x + 2 \, \sqrt {x^{4} + 2 \, x^{3} - 2 \, x^{2} - 3 \, x - 4} - 3\right ) \]
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\[ \int \frac {1+2 x}{\sqrt {-4-3 x-2 x^2+2 x^3+x^4}} \, dx=\int \frac {2 x + 1}{\sqrt {\left (x^{2} + x - 4\right ) \left (x^{2} + x + 1\right )}}\, dx \]
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\[ \int \frac {1+2 x}{\sqrt {-4-3 x-2 x^2+2 x^3+x^4}} \, dx=\int { \frac {2 \, x + 1}{\sqrt {x^{4} + 2 \, x^{3} - 2 \, x^{2} - 3 \, x - 4}} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 67 vs. \(2 (33) = 66\).
Time = 0.29 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.91 \[ \int \frac {1+2 x}{\sqrt {-4-3 x-2 x^2+2 x^3+x^4}} \, dx=\frac {1}{4} \, \sqrt {{\left (x^{2} + x\right )}^{2} - 3 \, x^{2} - 3 \, x - 4} {\left (2 \, x^{2} + 2 \, x - 3\right )} + \frac {25}{8} \, \log \left ({\left | -2 \, x^{2} - 2 \, x + 2 \, \sqrt {{\left (x^{2} + x\right )}^{2} - 3 \, x^{2} - 3 \, x - 4} + 3 \right |}\right ) \]
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Timed out. \[ \int \frac {1+2 x}{\sqrt {-4-3 x-2 x^2+2 x^3+x^4}} \, dx=\int \frac {2\,x+1}{\sqrt {x^4+2\,x^3-2\,x^2-3\,x-4}} \,d x \]
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