Integrand size = 28, antiderivative size = 38 \[ \int \frac {\left (-1+x^5\right )^{3/4} \left (4+x^5\right ) \left (-1-x^4+x^5\right )}{x^{12}} \, dx=\frac {4 \left (-1+x^5\right )^{3/4} \left (7+11 x^4-14 x^5-11 x^9+7 x^{10}\right )}{77 x^{11}} \]
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Leaf count is larger than twice the leaf count of optimal. \(88\) vs. \(2(38)=76\).
Time = 0.13 (sec) , antiderivative size = 88, normalized size of antiderivative = 2.32, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {1834, 1839, 1849, 1600, 460} \[ \int \frac {\left (-1+x^5\right )^{3/4} \left (4+x^5\right ) \left (-1-x^4+x^5\right )}{x^{12}} \, dx=\frac {15 \left (x^5-1\right )^{3/4}}{11 x}-\frac {5 \left (x^5-1\right )^{3/4}}{22 x^6}-\frac {15 \left (x^5-1\right )^{3/4}}{14 x^2}+\frac {1}{154} \left (x^5-1\right )^{3/4} \left (\frac {56}{x^{11}}+\frac {88}{x^7}-\frac {77}{x^6}+\frac {77}{x^2}-\frac {154}{x}\right ) \]
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Rule 460
Rule 1600
Rule 1834
Rule 1839
Rule 1849
Rubi steps \begin{align*} \text {integral}& = \frac {1}{154} \left (\frac {56}{x^{11}}+\frac {88}{x^7}-\frac {77}{x^6}+\frac {77}{x^2}-\frac {154}{x}\right ) \left (-1+x^5\right )^{3/4}-\frac {15}{4} \int \frac {\frac {4}{11}+\frac {4 x^4}{7}-\frac {x^5}{2}+\frac {x^9}{2}-x^{10}}{x^7 \sqrt [4]{-1+x^5}} \, dx \\ & = \frac {1}{154} \left (\frac {56}{x^{11}}+\frac {88}{x^7}-\frac {77}{x^6}+\frac {77}{x^2}-\frac {154}{x}\right ) \left (-1+x^5\right )^{3/4}-\frac {5 \left (-1+x^5\right )^{3/4}}{22 x^6}-\frac {5}{16} \int \frac {\frac {48 x^3}{7}-\frac {48 x^4}{11}+6 x^8-12 x^9}{x^6 \sqrt [4]{-1+x^5}} \, dx \\ & = \frac {1}{154} \left (\frac {56}{x^{11}}+\frac {88}{x^7}-\frac {77}{x^6}+\frac {77}{x^2}-\frac {154}{x}\right ) \left (-1+x^5\right )^{3/4}-\frac {5 \left (-1+x^5\right )^{3/4}}{22 x^6}-\frac {5}{16} \int \frac {\frac {48 x^2}{7}-\frac {48 x^3}{11}+6 x^7-12 x^8}{x^5 \sqrt [4]{-1+x^5}} \, dx \\ & = \frac {1}{154} \left (\frac {56}{x^{11}}+\frac {88}{x^7}-\frac {77}{x^6}+\frac {77}{x^2}-\frac {154}{x}\right ) \left (-1+x^5\right )^{3/4}-\frac {5 \left (-1+x^5\right )^{3/4}}{22 x^6}-\frac {5}{16} \int \frac {\frac {48 x}{7}-\frac {48 x^2}{11}+6 x^6-12 x^7}{x^4 \sqrt [4]{-1+x^5}} \, dx \\ & = \frac {1}{154} \left (\frac {56}{x^{11}}+\frac {88}{x^7}-\frac {77}{x^6}+\frac {77}{x^2}-\frac {154}{x}\right ) \left (-1+x^5\right )^{3/4}-\frac {5 \left (-1+x^5\right )^{3/4}}{22 x^6}-\frac {5}{16} \int \frac {\frac {48}{7}-\frac {48 x}{11}+6 x^5-12 x^6}{x^3 \sqrt [4]{-1+x^5}} \, dx \\ & = \frac {1}{154} \left (\frac {56}{x^{11}}+\frac {88}{x^7}-\frac {77}{x^6}+\frac {77}{x^2}-\frac {154}{x}\right ) \left (-1+x^5\right )^{3/4}-\frac {5 \left (-1+x^5\right )^{3/4}}{22 x^6}-\frac {15 \left (-1+x^5\right )^{3/4}}{14 x^2}-\frac {5}{64} \int \frac {-\frac {192}{11}-48 x^5}{x^2 \sqrt [4]{-1+x^5}} \, dx \\ & = \frac {1}{154} \left (\frac {56}{x^{11}}+\frac {88}{x^7}-\frac {77}{x^6}+\frac {77}{x^2}-\frac {154}{x}\right ) \left (-1+x^5\right )^{3/4}-\frac {5 \left (-1+x^5\right )^{3/4}}{22 x^6}-\frac {15 \left (-1+x^5\right )^{3/4}}{14 x^2}+\frac {15 \left (-1+x^5\right )^{3/4}}{11 x} \\ \end{align*}
Time = 1.88 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.74 \[ \int \frac {\left (-1+x^5\right )^{3/4} \left (4+x^5\right ) \left (-1-x^4+x^5\right )}{x^{12}} \, dx=\frac {4 \left (-1+x^5\right )^{7/4} \left (-7-11 x^4+7 x^5\right )}{77 x^{11}} \]
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Time = 1.01 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.66
method | result | size |
pseudoelliptic | \(\frac {4 \left (x^{5}-1\right )^{\frac {7}{4}} \left (7 x^{5}-11 x^{4}-7\right )}{77 x^{11}}\) | \(25\) |
trager | \(\frac {4 \left (x^{5}-1\right )^{\frac {3}{4}} \left (7 x^{10}-11 x^{9}-14 x^{5}+11 x^{4}+7\right )}{77 x^{11}}\) | \(35\) |
gosper | \(\frac {4 \left (x^{5}-1\right )^{\frac {3}{4}} \left (7 x^{5}-11 x^{4}-7\right ) \left (x -1\right ) \left (x^{4}+x^{3}+x^{2}+x +1\right )}{77 x^{11}}\) | \(40\) |
risch | \(\frac {\frac {4}{11} x^{15}-\frac {12}{11} x^{10}+\frac {12}{11} x^{5}-\frac {4}{11}-\frac {4}{7} x^{14}+\frac {8}{7} x^{9}-\frac {4}{7} x^{4}}{x^{11} \left (x^{5}-1\right )^{\frac {1}{4}}}\) | \(45\) |
meijerg | \(-\frac {\operatorname {signum}\left (x^{5}-1\right )^{\frac {3}{4}} \operatorname {hypergeom}\left (\left [-\frac {3}{4}, -\frac {1}{5}\right ], \left [\frac {4}{5}\right ], x^{5}\right )}{{\left (-\operatorname {signum}\left (x^{5}-1\right )\right )}^{\frac {3}{4}} x}+\frac {\operatorname {signum}\left (x^{5}-1\right )^{\frac {3}{4}} \operatorname {hypergeom}\left (\left [-\frac {3}{4}, -\frac {2}{5}\right ], \left [\frac {3}{5}\right ], x^{5}\right )}{2 {\left (-\operatorname {signum}\left (x^{5}-1\right )\right )}^{\frac {3}{4}} x^{2}}-\frac {\operatorname {signum}\left (x^{5}-1\right )^{\frac {3}{4}} \operatorname {hypergeom}\left (\left [-\frac {6}{5}, -\frac {3}{4}\right ], \left [-\frac {1}{5}\right ], x^{5}\right )}{2 {\left (-\operatorname {signum}\left (x^{5}-1\right )\right )}^{\frac {3}{4}} x^{6}}+\frac {4 \operatorname {signum}\left (x^{5}-1\right )^{\frac {3}{4}} \operatorname {hypergeom}\left (\left [-\frac {7}{5}, -\frac {3}{4}\right ], \left [-\frac {2}{5}\right ], x^{5}\right )}{7 {\left (-\operatorname {signum}\left (x^{5}-1\right )\right )}^{\frac {3}{4}} x^{7}}+\frac {4 \operatorname {signum}\left (x^{5}-1\right )^{\frac {3}{4}} \operatorname {hypergeom}\left (\left [-\frac {11}{5}, -\frac {3}{4}\right ], \left [-\frac {6}{5}\right ], x^{5}\right )}{11 {\left (-\operatorname {signum}\left (x^{5}-1\right )\right )}^{\frac {3}{4}} x^{11}}\) | \(162\) |
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Time = 0.26 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.89 \[ \int \frac {\left (-1+x^5\right )^{3/4} \left (4+x^5\right ) \left (-1-x^4+x^5\right )}{x^{12}} \, dx=\frac {4 \, {\left (7 \, x^{10} - 11 \, x^{9} - 14 \, x^{5} + 11 \, x^{4} + 7\right )} {\left (x^{5} - 1\right )}^{\frac {3}{4}}}{77 \, x^{11}} \]
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Result contains complex when optimal does not.
Time = 3.18 (sec) , antiderivative size = 199, normalized size of antiderivative = 5.24 \[ \int \frac {\left (-1+x^5\right )^{3/4} \left (4+x^5\right ) \left (-1-x^4+x^5\right )}{x^{12}} \, dx=- \frac {e^{- \frac {i \pi }{4}} \Gamma \left (- \frac {1}{5}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {3}{4}, - \frac {1}{5} \\ \frac {4}{5} \end {matrix}\middle | {x^{5}} \right )}}{5 x \Gamma \left (\frac {4}{5}\right )} + \frac {e^{- \frac {i \pi }{4}} \Gamma \left (- \frac {2}{5}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {3}{4}, - \frac {2}{5} \\ \frac {3}{5} \end {matrix}\middle | {x^{5}} \right )}}{5 x^{2} \Gamma \left (\frac {3}{5}\right )} - \frac {3 e^{- \frac {i \pi }{4}} \Gamma \left (- \frac {6}{5}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {6}{5}, - \frac {3}{4} \\ - \frac {1}{5} \end {matrix}\middle | {x^{5}} \right )}}{5 x^{6} \Gamma \left (- \frac {1}{5}\right )} + \frac {4 e^{- \frac {i \pi }{4}} \Gamma \left (- \frac {7}{5}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {7}{5}, - \frac {3}{4} \\ - \frac {2}{5} \end {matrix}\middle | {x^{5}} \right )}}{5 x^{7} \Gamma \left (- \frac {2}{5}\right )} + \frac {4 e^{- \frac {i \pi }{4}} \Gamma \left (- \frac {11}{5}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {11}{5}, - \frac {3}{4} \\ - \frac {6}{5} \end {matrix}\middle | {x^{5}} \right )}}{5 x^{11} \Gamma \left (- \frac {6}{5}\right )} \]
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Time = 0.32 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.21 \[ \int \frac {\left (-1+x^5\right )^{3/4} \left (4+x^5\right ) \left (-1-x^4+x^5\right )}{x^{12}} \, dx=\frac {4 \, {\left (7 \, x^{10} - 11 \, x^{9} - 14 \, x^{5} + 11 \, x^{4} + 7\right )} {\left (x^{4} + x^{3} + x^{2} + x + 1\right )}^{\frac {3}{4}} {\left (x - 1\right )}^{\frac {3}{4}}}{77 \, x^{11}} \]
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\[ \int \frac {\left (-1+x^5\right )^{3/4} \left (4+x^5\right ) \left (-1-x^4+x^5\right )}{x^{12}} \, dx=\int { \frac {{\left (x^{5} - x^{4} - 1\right )} {\left (x^{5} + 4\right )} {\left (x^{5} - 1\right )}^{\frac {3}{4}}}{x^{12}} \,d x } \]
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Time = 5.42 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.61 \[ \int \frac {\left (-1+x^5\right )^{3/4} \left (4+x^5\right ) \left (-1-x^4+x^5\right )}{x^{12}} \, dx=\frac {4\,{\left (x^5-1\right )}^{3/4}}{11\,x}-\frac {4\,{\left (x^5-1\right )}^{3/4}}{7\,x^2}-\frac {8\,{\left (x^5-1\right )}^{3/4}}{11\,x^6}+\frac {4\,{\left (x^5-1\right )}^{3/4}}{7\,x^7}+\frac {4\,{\left (x^5-1\right )}^{3/4}}{11\,x^{11}} \]
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