\(\int \frac {1}{x^{13} \sqrt {-1+x^6}} \, dx\) [490]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [C] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 13, antiderivative size = 38 \[ \int \frac {1}{x^{13} \sqrt {-1+x^6}} \, dx=\frac {\sqrt {-1+x^6} \left (2+3 x^6\right )}{24 x^{12}}+\frac {1}{8} \arctan \left (\sqrt {-1+x^6}\right ) \]

[Out]

1/24*(x^6-1)^(1/2)*(3*x^6+2)/x^12+1/8*arctan((x^6-1)^(1/2))

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.24, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {272, 44, 65, 209} \[ \int \frac {1}{x^{13} \sqrt {-1+x^6}} \, dx=\frac {1}{8} \arctan \left (\sqrt {x^6-1}\right )+\frac {\sqrt {x^6-1}}{8 x^6}+\frac {\sqrt {x^6-1}}{12 x^{12}} \]

[In]

Int[1/(x^13*Sqrt[-1 + x^6]),x]

[Out]

Sqrt[-1 + x^6]/(12*x^12) + Sqrt[-1 + x^6]/(8*x^6) + ArcTan[Sqrt[-1 + x^6]]/8

Rule 44

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n + 1
)/((b*c - a*d)*(m + 1))), x] - Dist[d*((m + n + 2)/((b*c - a*d)*(m + 1))), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, -1] &&  !IntegerQ[n] && LtQ[n, 0]

Rule 65

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 209

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*ArcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /;
 FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 272

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps \begin{align*} \text {integral}& = \frac {1}{6} \text {Subst}\left (\int \frac {1}{\sqrt {-1+x} x^3} \, dx,x,x^6\right ) \\ & = \frac {\sqrt {-1+x^6}}{12 x^{12}}+\frac {1}{8} \text {Subst}\left (\int \frac {1}{\sqrt {-1+x} x^2} \, dx,x,x^6\right ) \\ & = \frac {\sqrt {-1+x^6}}{12 x^{12}}+\frac {\sqrt {-1+x^6}}{8 x^6}+\frac {1}{16} \text {Subst}\left (\int \frac {1}{\sqrt {-1+x} x} \, dx,x,x^6\right ) \\ & = \frac {\sqrt {-1+x^6}}{12 x^{12}}+\frac {\sqrt {-1+x^6}}{8 x^6}+\frac {1}{8} \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\sqrt {-1+x^6}\right ) \\ & = \frac {\sqrt {-1+x^6}}{12 x^{12}}+\frac {\sqrt {-1+x^6}}{8 x^6}+\frac {1}{8} \arctan \left (\sqrt {-1+x^6}\right ) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.03 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x^{13} \sqrt {-1+x^6}} \, dx=\frac {\sqrt {-1+x^6} \left (2+3 x^6\right )}{24 x^{12}}+\frac {1}{8} \arctan \left (\sqrt {-1+x^6}\right ) \]

[In]

Integrate[1/(x^13*Sqrt[-1 + x^6]),x]

[Out]

(Sqrt[-1 + x^6]*(2 + 3*x^6))/(24*x^12) + ArcTan[Sqrt[-1 + x^6]]/8

Maple [A] (verified)

Time = 1.32 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.08

method result size
pseudoelliptic \(\frac {-3 \arctan \left (\frac {1}{\sqrt {x^{6}-1}}\right ) x^{12}+3 \sqrt {x^{6}-1}\, x^{6}+2 \sqrt {x^{6}-1}}{24 x^{12}}\) \(41\)
trager \(\frac {\sqrt {x^{6}-1}\, \left (3 x^{6}+2\right )}{24 x^{12}}-\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (\frac {-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )+\sqrt {x^{6}-1}}{x^{3}}\right )}{8}\) \(50\)
risch \(\frac {3 x^{12}-x^{6}-2}{24 x^{12} \sqrt {x^{6}-1}}+\frac {\sqrt {-\operatorname {signum}\left (x^{6}-1\right )}\, \left (-2 \sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {-x^{6}+1}}{2}\right )+\left (-2 \ln \left (2\right )+6 \ln \left (x \right )+i \pi \right ) \sqrt {\pi }\right )}{16 \sqrt {\pi }\, \sqrt {\operatorname {signum}\left (x^{6}-1\right )}}\) \(86\)
meijerg \(\frac {\sqrt {-\operatorname {signum}\left (x^{6}-1\right )}\, \left (\frac {\sqrt {\pi }\, \left (-7 x^{12}+8 x^{6}+8\right )}{16 x^{12}}-\frac {\sqrt {\pi }\, \left (12 x^{6}+8\right ) \sqrt {-x^{6}+1}}{16 x^{12}}-\frac {3 \sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {-x^{6}+1}}{2}\right )}{4}+\frac {3 \left (\frac {7}{6}-2 \ln \left (2\right )+6 \ln \left (x \right )+i \pi \right ) \sqrt {\pi }}{8}-\frac {\sqrt {\pi }}{2 x^{12}}-\frac {\sqrt {\pi }}{2 x^{6}}\right )}{6 \sqrt {\pi }\, \sqrt {\operatorname {signum}\left (x^{6}-1\right )}}\) \(123\)

[In]

int(1/x^13/(x^6-1)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/24*(-3*arctan(1/(x^6-1)^(1/2))*x^12+3*(x^6-1)^(1/2)*x^6+2*(x^6-1)^(1/2))/x^12

Fricas [A] (verification not implemented)

none

Time = 0.24 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.89 \[ \int \frac {1}{x^{13} \sqrt {-1+x^6}} \, dx=\frac {3 \, x^{12} \arctan \left (\sqrt {x^{6} - 1}\right ) + {\left (3 \, x^{6} + 2\right )} \sqrt {x^{6} - 1}}{24 \, x^{12}} \]

[In]

integrate(1/x^13/(x^6-1)^(1/2),x, algorithm="fricas")

[Out]

1/24*(3*x^12*arctan(sqrt(x^6 - 1)) + (3*x^6 + 2)*sqrt(x^6 - 1))/x^12

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 2.20 (sec) , antiderivative size = 124, normalized size of antiderivative = 3.26 \[ \int \frac {1}{x^{13} \sqrt {-1+x^6}} \, dx=\begin {cases} \frac {i \operatorname {acosh}{\left (\frac {1}{x^{3}} \right )}}{8} - \frac {i}{8 x^{3} \sqrt {-1 + \frac {1}{x^{6}}}} + \frac {i}{24 x^{9} \sqrt {-1 + \frac {1}{x^{6}}}} + \frac {i}{12 x^{15} \sqrt {-1 + \frac {1}{x^{6}}}} & \text {for}\: \frac {1}{\left |{x^{6}}\right |} > 1 \\- \frac {\operatorname {asin}{\left (\frac {1}{x^{3}} \right )}}{8} + \frac {1}{8 x^{3} \sqrt {1 - \frac {1}{x^{6}}}} - \frac {1}{24 x^{9} \sqrt {1 - \frac {1}{x^{6}}}} - \frac {1}{12 x^{15} \sqrt {1 - \frac {1}{x^{6}}}} & \text {otherwise} \end {cases} \]

[In]

integrate(1/x**13/(x**6-1)**(1/2),x)

[Out]

Piecewise((I*acosh(x**(-3))/8 - I/(8*x**3*sqrt(-1 + x**(-6))) + I/(24*x**9*sqrt(-1 + x**(-6))) + I/(12*x**15*s
qrt(-1 + x**(-6))), 1/Abs(x**6) > 1), (-asin(x**(-3))/8 + 1/(8*x**3*sqrt(1 - 1/x**6)) - 1/(24*x**9*sqrt(1 - 1/
x**6)) - 1/(12*x**15*sqrt(1 - 1/x**6)), True))

Maxima [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.26 \[ \int \frac {1}{x^{13} \sqrt {-1+x^6}} \, dx=\frac {3 \, {\left (x^{6} - 1\right )}^{\frac {3}{2}} + 5 \, \sqrt {x^{6} - 1}}{24 \, {\left (2 \, x^{6} + {\left (x^{6} - 1\right )}^{2} - 1\right )}} + \frac {1}{8} \, \arctan \left (\sqrt {x^{6} - 1}\right ) \]

[In]

integrate(1/x^13/(x^6-1)^(1/2),x, algorithm="maxima")

[Out]

1/24*(3*(x^6 - 1)^(3/2) + 5*sqrt(x^6 - 1))/(2*x^6 + (x^6 - 1)^2 - 1) + 1/8*arctan(sqrt(x^6 - 1))

Giac [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.92 \[ \int \frac {1}{x^{13} \sqrt {-1+x^6}} \, dx=\frac {3 \, {\left (x^{6} - 1\right )}^{\frac {3}{2}} + 5 \, \sqrt {x^{6} - 1}}{24 \, x^{12}} + \frac {1}{8} \, \arctan \left (\sqrt {x^{6} - 1}\right ) \]

[In]

integrate(1/x^13/(x^6-1)^(1/2),x, algorithm="giac")

[Out]

1/24*(3*(x^6 - 1)^(3/2) + 5*sqrt(x^6 - 1))/x^12 + 1/8*arctan(sqrt(x^6 - 1))

Mupad [B] (verification not implemented)

Time = 5.15 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.92 \[ \int \frac {1}{x^{13} \sqrt {-1+x^6}} \, dx=\frac {\mathrm {atan}\left (\sqrt {x^6-1}\right )}{8}+\frac {\sqrt {x^6-1}}{8\,x^6}+\frac {\sqrt {x^6-1}}{12\,x^{12}} \]

[In]

int(1/(x^13*(x^6 - 1)^(1/2)),x)

[Out]

atan((x^6 - 1)^(1/2))/8 + (x^6 - 1)^(1/2)/(8*x^6) + (x^6 - 1)^(1/2)/(12*x^12)