Integrand size = 27, antiderivative size = 38 \[ \int \frac {-2+5 x^6}{x \sqrt {-1+x^6} \left (2+x^6\right )} \, dx=-\frac {1}{3} \arctan \left (\sqrt {-1+x^6}\right )+\frac {2 \arctan \left (\frac {\sqrt {-1+x^6}}{\sqrt {3}}\right )}{\sqrt {3}} \]
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Time = 0.03 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.148, Rules used = {587, 162, 65, 209} \[ \int \frac {-2+5 x^6}{x \sqrt {-1+x^6} \left (2+x^6\right )} \, dx=\frac {2 \arctan \left (\frac {\sqrt {x^6-1}}{\sqrt {3}}\right )}{\sqrt {3}}-\frac {1}{3} \arctan \left (\sqrt {x^6-1}\right ) \]
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Rule 65
Rule 162
Rule 209
Rule 587
Rubi steps \begin{align*} \text {integral}& = \frac {1}{6} \text {Subst}\left (\int \frac {-2+5 x}{\sqrt {-1+x} x (2+x)} \, dx,x,x^6\right ) \\ & = -\left (\frac {1}{6} \text {Subst}\left (\int \frac {1}{\sqrt {-1+x} x} \, dx,x,x^6\right )\right )+\text {Subst}\left (\int \frac {1}{\sqrt {-1+x} (2+x)} \, dx,x,x^6\right ) \\ & = -\left (\frac {1}{3} \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\sqrt {-1+x^6}\right )\right )+2 \text {Subst}\left (\int \frac {1}{3+x^2} \, dx,x,\sqrt {-1+x^6}\right ) \\ & = -\frac {1}{3} \arctan \left (\sqrt {-1+x^6}\right )+\frac {2 \arctan \left (\frac {\sqrt {-1+x^6}}{\sqrt {3}}\right )}{\sqrt {3}} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.00 \[ \int \frac {-2+5 x^6}{x \sqrt {-1+x^6} \left (2+x^6\right )} \, dx=-\frac {1}{3} \arctan \left (\sqrt {-1+x^6}\right )+\frac {2 \arctan \left (\frac {\sqrt {-1+x^6}}{\sqrt {3}}\right )}{\sqrt {3}} \]
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Time = 2.10 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.79
method | result | size |
pseudoelliptic | \(\frac {\arctan \left (\frac {1}{\sqrt {x^{6}-1}}\right )}{3}+\frac {2 \arctan \left (\frac {\sqrt {x^{6}-1}\, \sqrt {3}}{3}\right ) \sqrt {3}}{3}\) | \(30\) |
trager | \(\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (-\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )-\sqrt {x^{6}-1}}{x^{3}}\right )}{3}+\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+3\right ) \ln \left (-\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+3\right ) x^{6}-4 \operatorname {RootOf}\left (\textit {\_Z}^{2}+3\right )-6 \sqrt {x^{6}-1}}{x^{6}+2}\right )}{3}\) | \(78\) |
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Time = 0.26 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.76 \[ \int \frac {-2+5 x^6}{x \sqrt {-1+x^6} \left (2+x^6\right )} \, dx=\frac {2}{3} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} \sqrt {x^{6} - 1}\right ) - \frac {1}{3} \, \arctan \left (\sqrt {x^{6} - 1}\right ) \]
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Time = 9.39 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.95 \[ \int \frac {-2+5 x^6}{x \sqrt {-1+x^6} \left (2+x^6\right )} \, dx=\frac {2 \sqrt {3} \operatorname {atan}{\left (\frac {\sqrt {3} \sqrt {x^{6} - 1}}{3} \right )}}{3} - \frac {\operatorname {atan}{\left (\sqrt {x^{6} - 1} \right )}}{3} \]
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\[ \int \frac {-2+5 x^6}{x \sqrt {-1+x^6} \left (2+x^6\right )} \, dx=\int { \frac {5 \, x^{6} - 2}{{\left (x^{6} + 2\right )} \sqrt {x^{6} - 1} x} \,d x } \]
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Time = 0.27 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.76 \[ \int \frac {-2+5 x^6}{x \sqrt {-1+x^6} \left (2+x^6\right )} \, dx=\frac {2}{3} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} \sqrt {x^{6} - 1}\right ) - \frac {1}{3} \, \arctan \left (\sqrt {x^{6} - 1}\right ) \]
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Time = 5.20 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.76 \[ \int \frac {-2+5 x^6}{x \sqrt {-1+x^6} \left (2+x^6\right )} \, dx=\frac {2\,\sqrt {3}\,\mathrm {atan}\left (\frac {\sqrt {3}\,\sqrt {x^6-1}}{3}\right )}{3}-\frac {\mathrm {atan}\left (\sqrt {x^6-1}\right )}{3} \]
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