Integrand size = 38, antiderivative size = 44 \[ \int \frac {-3 x+2 x^2}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx=\frac {\text {arctanh}\left (\frac {\sqrt {2} x \sqrt {-2 x+2 x^2+3 x^4}}{-2+2 x+3 x^3}\right )}{\sqrt {2}} \]
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\[ \int \frac {-3 x+2 x^2}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx=\int \frac {-3 x+2 x^2}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {x (-3+2 x)}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx \\ & = \frac {\left (\sqrt {x} \sqrt {-2+2 x+3 x^3}\right ) \int \frac {\sqrt {x} (-3+2 x)}{\left (-2+2 x+x^3\right ) \sqrt {-2+2 x+3 x^3}} \, dx}{\sqrt {-2 x+2 x^2+3 x^4}} \\ & = \frac {\left (2 \sqrt {x} \sqrt {-2+2 x+3 x^3}\right ) \text {Subst}\left (\int \frac {x^2 \left (-3+2 x^2\right )}{\left (-2+2 x^2+x^6\right ) \sqrt {-2+2 x^2+3 x^6}} \, dx,x,\sqrt {x}\right )}{\sqrt {-2 x+2 x^2+3 x^4}} \\ & = \frac {\left (2 \sqrt {x} \sqrt {-2+2 x+3 x^3}\right ) \text {Subst}\left (\int \left (-\frac {3 x^2}{\left (-2+2 x^2+x^6\right ) \sqrt {-2+2 x^2+3 x^6}}+\frac {2 x^4}{\left (-2+2 x^2+x^6\right ) \sqrt {-2+2 x^2+3 x^6}}\right ) \, dx,x,\sqrt {x}\right )}{\sqrt {-2 x+2 x^2+3 x^4}} \\ & = \frac {\left (4 \sqrt {x} \sqrt {-2+2 x+3 x^3}\right ) \text {Subst}\left (\int \frac {x^4}{\left (-2+2 x^2+x^6\right ) \sqrt {-2+2 x^2+3 x^6}} \, dx,x,\sqrt {x}\right )}{\sqrt {-2 x+2 x^2+3 x^4}}-\frac {\left (6 \sqrt {x} \sqrt {-2+2 x+3 x^3}\right ) \text {Subst}\left (\int \frac {x^2}{\left (-2+2 x^2+x^6\right ) \sqrt {-2+2 x^2+3 x^6}} \, dx,x,\sqrt {x}\right )}{\sqrt {-2 x+2 x^2+3 x^4}} \\ \end{align*}
Time = 2.30 (sec) , antiderivative size = 62, normalized size of antiderivative = 1.41 \[ \int \frac {-3 x+2 x^2}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx=\frac {\sqrt {x} \sqrt {-2+2 x+3 x^3} \text {arctanh}\left (\frac {x^{3/2}}{\sqrt {-1+x+\frac {3 x^3}{2}}}\right )}{\sqrt {2} \sqrt {x \left (-2+2 x+3 x^3\right )}} \]
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Time = 5.13 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.70
method | result | size |
default | \(\frac {\sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {3 x^{4}+2 x^{2}-2 x}\, \sqrt {2}}{2 x^{2}}\right )}{2}\) | \(31\) |
pseudoelliptic | \(\frac {\sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {3 x^{4}+2 x^{2}-2 x}\, \sqrt {2}}{2 x^{2}}\right )}{2}\) | \(31\) |
trager | \(-\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}-2\right ) \ln \left (-\frac {-5 \operatorname {RootOf}\left (\textit {\_Z}^{2}-2\right ) x^{3}+4 x \sqrt {3 x^{4}+2 x^{2}-2 x}-2 \operatorname {RootOf}\left (\textit {\_Z}^{2}-2\right ) x +2 \operatorname {RootOf}\left (\textit {\_Z}^{2}-2\right )}{x^{3}+2 x -2}\right )}{4}\) | \(70\) |
elliptic | \(\text {Expression too large to display}\) | \(1659\) |
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Leaf count of result is larger than twice the leaf count of optimal. 93 vs. \(2 (39) = 78\).
Time = 0.30 (sec) , antiderivative size = 93, normalized size of antiderivative = 2.11 \[ \int \frac {-3 x+2 x^2}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx=\frac {1}{8} \, \sqrt {2} \log \left (-\frac {49 \, x^{6} + 36 \, x^{4} - 36 \, x^{3} + 4 \, \sqrt {2} {\left (5 \, x^{4} + 2 \, x^{2} - 2 \, x\right )} \sqrt {3 \, x^{4} + 2 \, x^{2} - 2 \, x} + 4 \, x^{2} - 8 \, x + 4}{x^{6} + 4 \, x^{4} - 4 \, x^{3} + 4 \, x^{2} - 8 \, x + 4}\right ) \]
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\[ \int \frac {-3 x+2 x^2}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx=\int \frac {x \left (2 x - 3\right )}{\sqrt {x \left (3 x^{3} + 2 x - 2\right )} \left (x^{3} + 2 x - 2\right )}\, dx \]
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\[ \int \frac {-3 x+2 x^2}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx=\int { \frac {2 \, x^{2} - 3 \, x}{\sqrt {3 \, x^{4} + 2 \, x^{2} - 2 \, x} {\left (x^{3} + 2 \, x - 2\right )}} \,d x } \]
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\[ \int \frac {-3 x+2 x^2}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx=\int { \frac {2 \, x^{2} - 3 \, x}{\sqrt {3 \, x^{4} + 2 \, x^{2} - 2 \, x} {\left (x^{3} + 2 \, x - 2\right )}} \,d x } \]
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Timed out. \[ \int \frac {-3 x+2 x^2}{\left (-2+2 x+x^3\right ) \sqrt {-2 x+2 x^2+3 x^4}} \, dx=-\int \frac {3\,x-2\,x^2}{\left (x^3+2\,x-2\right )\,\sqrt {3\,x^4+2\,x^2-2\,x}} \,d x \]
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