Integrand size = 23, antiderivative size = 48 \[ \int \frac {(-1+x) \sqrt [4]{x^3+x^4}}{x (1+x)} \, dx=\sqrt [4]{x^3+x^4}+\frac {7}{2} \arctan \left (\frac {x}{\sqrt [4]{x^3+x^4}}\right )-\frac {7}{2} \text {arctanh}\left (\frac {x}{\sqrt [4]{x^3+x^4}}\right ) \]
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Time = 0.09 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.96, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.304, Rules used = {2081, 81, 65, 338, 304, 209, 212} \[ \int \frac {(-1+x) \sqrt [4]{x^3+x^4}}{x (1+x)} \, dx=\frac {7 \sqrt [4]{x^4+x^3} \arctan \left (\frac {\sqrt [4]{x}}{\sqrt [4]{x+1}}\right )}{2 x^{3/4} \sqrt [4]{x+1}}-\frac {7 \sqrt [4]{x^4+x^3} \text {arctanh}\left (\frac {\sqrt [4]{x}}{\sqrt [4]{x+1}}\right )}{2 x^{3/4} \sqrt [4]{x+1}}+\sqrt [4]{x^4+x^3} \]
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Rule 65
Rule 81
Rule 209
Rule 212
Rule 304
Rule 338
Rule 2081
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt [4]{x^3+x^4} \int \frac {-1+x}{\sqrt [4]{x} (1+x)^{3/4}} \, dx}{x^{3/4} \sqrt [4]{1+x}} \\ & = \sqrt [4]{x^3+x^4}-\frac {\left (7 \sqrt [4]{x^3+x^4}\right ) \int \frac {1}{\sqrt [4]{x} (1+x)^{3/4}} \, dx}{4 x^{3/4} \sqrt [4]{1+x}} \\ & = \sqrt [4]{x^3+x^4}-\frac {\left (7 \sqrt [4]{x^3+x^4}\right ) \text {Subst}\left (\int \frac {x^2}{\left (1+x^4\right )^{3/4}} \, dx,x,\sqrt [4]{x}\right )}{x^{3/4} \sqrt [4]{1+x}} \\ & = \sqrt [4]{x^3+x^4}-\frac {\left (7 \sqrt [4]{x^3+x^4}\right ) \text {Subst}\left (\int \frac {x^2}{1-x^4} \, dx,x,\frac {\sqrt [4]{x}}{\sqrt [4]{1+x}}\right )}{x^{3/4} \sqrt [4]{1+x}} \\ & = \sqrt [4]{x^3+x^4}-\frac {\left (7 \sqrt [4]{x^3+x^4}\right ) \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {\sqrt [4]{x}}{\sqrt [4]{1+x}}\right )}{2 x^{3/4} \sqrt [4]{1+x}}+\frac {\left (7 \sqrt [4]{x^3+x^4}\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt [4]{x}}{\sqrt [4]{1+x}}\right )}{2 x^{3/4} \sqrt [4]{1+x}} \\ & = \sqrt [4]{x^3+x^4}+\frac {7 \sqrt [4]{x^3+x^4} \arctan \left (\frac {\sqrt [4]{x}}{\sqrt [4]{1+x}}\right )}{2 x^{3/4} \sqrt [4]{1+x}}-\frac {7 \sqrt [4]{x^3+x^4} \text {arctanh}\left (\frac {\sqrt [4]{x}}{\sqrt [4]{1+x}}\right )}{2 x^{3/4} \sqrt [4]{1+x}} \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.52 \[ \int \frac {(-1+x) \sqrt [4]{x^3+x^4}}{x (1+x)} \, dx=\frac {x^{9/4} \left (2 x^{3/4} (1+x)+7 (1+x)^{3/4} \arctan \left (\sqrt [4]{\frac {x}{1+x}}\right )-7 (1+x)^{3/4} \text {arctanh}\left (\sqrt [4]{\frac {x}{1+x}}\right )\right )}{2 \left (x^3 (1+x)\right )^{3/4}} \]
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Result contains higher order function than in optimal. Order 5 vs. order 3.
Time = 2.22 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.62
method | result | size |
meijerg | \(-\frac {4 x^{\frac {3}{4}} \operatorname {hypergeom}\left (\left [\frac {3}{4}, \frac {3}{4}\right ], \left [\frac {7}{4}\right ], -x \right )}{3}+\frac {4 x^{\frac {7}{4}} \operatorname {hypergeom}\left (\left [\frac {3}{4}, \frac {7}{4}\right ], \left [\frac {11}{4}\right ], -x \right )}{7}\) | \(30\) |
pseudoelliptic | \(\left (x^{3} \left (1+x \right )\right )^{\frac {1}{4}}+\frac {7 \ln \left (\frac {\left (x^{3} \left (1+x \right )\right )^{\frac {1}{4}}-x}{x}\right )}{4}-\frac {7 \arctan \left (\frac {\left (x^{3} \left (1+x \right )\right )^{\frac {1}{4}}}{x}\right )}{2}-\frac {7 \ln \left (\frac {\left (x^{3} \left (1+x \right )\right )^{\frac {1}{4}}+x}{x}\right )}{4}\) | \(65\) |
trager | \(\left (x^{4}+x^{3}\right )^{\frac {1}{4}}-\frac {7 \ln \left (\frac {2 \left (x^{4}+x^{3}\right )^{\frac {3}{4}}+2 \sqrt {x^{4}+x^{3}}\, x +2 \left (x^{4}+x^{3}\right )^{\frac {1}{4}} x^{2}+2 x^{3}+x^{2}}{x^{2}}\right )}{4}-\frac {7 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (\frac {2 \sqrt {x^{4}+x^{3}}\, \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x -2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{3}+2 \left (x^{4}+x^{3}\right )^{\frac {3}{4}}-2 \left (x^{4}+x^{3}\right )^{\frac {1}{4}} x^{2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{2}}{x^{2}}\right )}{4}\) | \(143\) |
risch | \(\left (x^{3} \left (1+x \right )\right )^{\frac {1}{4}}+\frac {\left (-\frac {7 \ln \left (\frac {2 \left (x^{4}+3 x^{3}+3 x^{2}+x \right )^{\frac {3}{4}}+2 \sqrt {x^{4}+3 x^{3}+3 x^{2}+x}\, x +2 \left (x^{4}+3 x^{3}+3 x^{2}+x \right )^{\frac {1}{4}} x^{2}+2 x^{3}+2 \sqrt {x^{4}+3 x^{3}+3 x^{2}+x}+4 \left (x^{4}+3 x^{3}+3 x^{2}+x \right )^{\frac {1}{4}} x +5 x^{2}+2 \left (x^{4}+3 x^{3}+3 x^{2}+x \right )^{\frac {1}{4}}+4 x +1}{\left (1+x \right )^{2}}\right )}{4}-\frac {7 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (-\frac {2 \sqrt {x^{4}+3 x^{3}+3 x^{2}+x}\, \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x -2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{3}+2 \sqrt {x^{4}+3 x^{3}+3 x^{2}+x}\, \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )-5 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{2}-2 \left (x^{4}+3 x^{3}+3 x^{2}+x \right )^{\frac {3}{4}}+2 \left (x^{4}+3 x^{3}+3 x^{2}+x \right )^{\frac {1}{4}} x^{2}-4 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x +4 \left (x^{4}+3 x^{3}+3 x^{2}+x \right )^{\frac {1}{4}} x -\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )+2 \left (x^{4}+3 x^{3}+3 x^{2}+x \right )^{\frac {1}{4}}}{\left (1+x \right )^{2}}\right )}{4}\right ) \left (x^{3} \left (1+x \right )\right )^{\frac {1}{4}} \left (\left (1+x \right )^{3} x \right )^{\frac {1}{4}}}{x \left (1+x \right )}\) | \(369\) |
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Time = 0.26 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.35 \[ \int \frac {(-1+x) \sqrt [4]{x^3+x^4}}{x (1+x)} \, dx={\left (x^{4} + x^{3}\right )}^{\frac {1}{4}} - \frac {7}{2} \, \arctan \left (\frac {{\left (x^{4} + x^{3}\right )}^{\frac {1}{4}}}{x}\right ) - \frac {7}{4} \, \log \left (\frac {x + {\left (x^{4} + x^{3}\right )}^{\frac {1}{4}}}{x}\right ) + \frac {7}{4} \, \log \left (-\frac {x - {\left (x^{4} + x^{3}\right )}^{\frac {1}{4}}}{x}\right ) \]
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\[ \int \frac {(-1+x) \sqrt [4]{x^3+x^4}}{x (1+x)} \, dx=\int \frac {\sqrt [4]{x^{3} \left (x + 1\right )} \left (x - 1\right )}{x \left (x + 1\right )}\, dx \]
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\[ \int \frac {(-1+x) \sqrt [4]{x^3+x^4}}{x (1+x)} \, dx=\int { \frac {{\left (x^{4} + x^{3}\right )}^{\frac {1}{4}} {\left (x - 1\right )}}{{\left (x + 1\right )} x} \,d x } \]
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Time = 0.28 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.94 \[ \int \frac {(-1+x) \sqrt [4]{x^3+x^4}}{x (1+x)} \, dx=x {\left (\frac {1}{x} + 1\right )}^{\frac {1}{4}} - \frac {7}{2} \, \arctan \left ({\left (\frac {1}{x} + 1\right )}^{\frac {1}{4}}\right ) - \frac {7}{4} \, \log \left ({\left (\frac {1}{x} + 1\right )}^{\frac {1}{4}} + 1\right ) + \frac {7}{4} \, \log \left ({\left | {\left (\frac {1}{x} + 1\right )}^{\frac {1}{4}} - 1 \right |}\right ) \]
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Timed out. \[ \int \frac {(-1+x) \sqrt [4]{x^3+x^4}}{x (1+x)} \, dx=\int \frac {{\left (x^4+x^3\right )}^{1/4}\,\left (x-1\right )}{x\,\left (x+1\right )} \,d x \]
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