Integrand size = 43, antiderivative size = 58 \[ \int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx=2^{3/4} \arctan \left (\frac {x \sqrt [4]{-b x+a x^5}}{\sqrt [4]{2}}\right )-2^{3/4} \text {arctanh}\left (\frac {x \sqrt [4]{-b x+a x^5}}{\sqrt [4]{2}}\right ) \]
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\[ \int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx=\int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\left (\sqrt [4]{x} \sqrt [4]{-b+a x^4}\right ) \int \frac {x^{11/4} \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b+a x^4} \left (-2-b x^5+a x^9\right )} \, dx}{\sqrt [4]{-b x+a x^5}} \\ & = \frac {\left (4 \sqrt [4]{x} \sqrt [4]{-b+a x^4}\right ) \text {Subst}\left (\int \frac {x^{14} \left (-5 b+9 a x^{16}\right )}{\sqrt [4]{-b+a x^{16}} \left (-2-b x^{20}+a x^{36}\right )} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{-b x+a x^5}} \\ & = \frac {\left (4 \sqrt [4]{x} \sqrt [4]{-b+a x^4}\right ) \text {Subst}\left (\int \left (\frac {5 b x^{14}}{\sqrt [4]{-b+a x^{16}} \left (2+b x^{20}-a x^{36}\right )}+\frac {9 a x^{30}}{\sqrt [4]{-b+a x^{16}} \left (-2-b x^{20}+a x^{36}\right )}\right ) \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{-b x+a x^5}} \\ & = \frac {\left (36 a \sqrt [4]{x} \sqrt [4]{-b+a x^4}\right ) \text {Subst}\left (\int \frac {x^{30}}{\sqrt [4]{-b+a x^{16}} \left (-2-b x^{20}+a x^{36}\right )} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{-b x+a x^5}}+\frac {\left (20 b \sqrt [4]{x} \sqrt [4]{-b+a x^4}\right ) \text {Subst}\left (\int \frac {x^{14}}{\sqrt [4]{-b+a x^{16}} \left (2+b x^{20}-a x^{36}\right )} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{-b x+a x^5}} \\ \end{align*}
\[ \int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx=\int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx \]
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\[\int \frac {x^{3} \left (9 a \,x^{4}-5 b \right )}{\left (a \,x^{5}-b x \right )^{\frac {1}{4}} \left (a \,x^{9}-b \,x^{5}-2\right )}d x\]
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Timed out. \[ \int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx=\int \frac {x^{3} \cdot \left (9 a x^{4} - 5 b\right )}{\sqrt [4]{x \left (a x^{4} - b\right )} \left (a x^{9} - b x^{5} - 2\right )}\, dx \]
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\[ \int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx=\int { \frac {{\left (9 \, a x^{4} - 5 \, b\right )} x^{3}}{{\left (a x^{9} - b x^{5} - 2\right )} {\left (a x^{5} - b x\right )}^{\frac {1}{4}}} \,d x } \]
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\[ \int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx=\int { \frac {{\left (9 \, a x^{4} - 5 \, b\right )} x^{3}}{{\left (a x^{9} - b x^{5} - 2\right )} {\left (a x^{5} - b x\right )}^{\frac {1}{4}}} \,d x } \]
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Timed out. \[ \int \frac {x^3 \left (-5 b+9 a x^4\right )}{\sqrt [4]{-b x+a x^5} \left (-2-b x^5+a x^9\right )} \, dx=\int \frac {x^3\,\left (5\,b-9\,a\,x^4\right )}{{\left (a\,x^5-b\,x\right )}^{1/4}\,\left (-a\,x^9+b\,x^5+2\right )} \,d x \]
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