Integrand size = 28, antiderivative size = 65 \[ \int \frac {x^4}{\sqrt [4]{-b+a x^4} \left (-b+a x^8\right )} \, dx=\frac {1}{8} \text {RootSum}\left [a^2-a b-2 a \text {$\#$1}^4+\text {$\#$1}^8\&,\frac {-\log (x)+\log \left (\sqrt [4]{-b+a x^4}-x \text {$\#$1}\right )}{a \text {$\#$1}-\text {$\#$1}^5}\&\right ] \]
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Leaf count is larger than twice the leaf count of optimal. \(269\) vs. \(2(65)=130\).
Time = 0.18 (sec) , antiderivative size = 269, normalized size of antiderivative = 4.14, number of steps used = 10, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {1543, 385, 218, 212, 209} \[ \int \frac {x^4}{\sqrt [4]{-b+a x^4} \left (-b+a x^8\right )} \, dx=-\frac {\arctan \left (\frac {\sqrt [8]{a} x \sqrt [4]{\sqrt {a}-\sqrt {b}}}{\sqrt [4]{a x^4-b}}\right )}{4 a^{5/8} \sqrt {b} \sqrt [4]{\sqrt {a}-\sqrt {b}}}+\frac {\arctan \left (\frac {\sqrt [8]{a} x \sqrt [4]{\sqrt {a}+\sqrt {b}}}{\sqrt [4]{a x^4-b}}\right )}{4 a^{5/8} \sqrt {b} \sqrt [4]{\sqrt {a}+\sqrt {b}}}-\frac {\text {arctanh}\left (\frac {\sqrt [8]{a} x \sqrt [4]{\sqrt {a}-\sqrt {b}}}{\sqrt [4]{a x^4-b}}\right )}{4 a^{5/8} \sqrt {b} \sqrt [4]{\sqrt {a}-\sqrt {b}}}+\frac {\text {arctanh}\left (\frac {\sqrt [8]{a} x \sqrt [4]{\sqrt {a}+\sqrt {b}}}{\sqrt [4]{a x^4-b}}\right )}{4 a^{5/8} \sqrt {b} \sqrt [4]{\sqrt {a}+\sqrt {b}}} \]
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Rule 209
Rule 212
Rule 218
Rule 385
Rule 1543
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {1}{2 \sqrt {a} \left (\sqrt {b}-\sqrt {a} x^4\right ) \sqrt [4]{-b+a x^4}}+\frac {1}{2 \sqrt {a} \left (\sqrt {b}+\sqrt {a} x^4\right ) \sqrt [4]{-b+a x^4}}\right ) \, dx \\ & = -\frac {\int \frac {1}{\left (\sqrt {b}-\sqrt {a} x^4\right ) \sqrt [4]{-b+a x^4}} \, dx}{2 \sqrt {a}}+\frac {\int \frac {1}{\left (\sqrt {b}+\sqrt {a} x^4\right ) \sqrt [4]{-b+a x^4}} \, dx}{2 \sqrt {a}} \\ & = -\frac {\text {Subst}\left (\int \frac {1}{\sqrt {b}-\left (a \sqrt {b}-\sqrt {a} b\right ) x^4} \, dx,x,\frac {x}{\sqrt [4]{-b+a x^4}}\right )}{2 \sqrt {a}}+\frac {\text {Subst}\left (\int \frac {1}{\sqrt {b}-\left (a \sqrt {b}+\sqrt {a} b\right ) x^4} \, dx,x,\frac {x}{\sqrt [4]{-b+a x^4}}\right )}{2 \sqrt {a}} \\ & = -\frac {\text {Subst}\left (\int \frac {1}{1-\sqrt [4]{a} \sqrt {\sqrt {a}-\sqrt {b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{-b+a x^4}}\right )}{4 \sqrt {a} \sqrt {b}}-\frac {\text {Subst}\left (\int \frac {1}{1+\sqrt [4]{a} \sqrt {\sqrt {a}-\sqrt {b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{-b+a x^4}}\right )}{4 \sqrt {a} \sqrt {b}}+\frac {\text {Subst}\left (\int \frac {1}{1-\sqrt [4]{a} \sqrt {\sqrt {a}+\sqrt {b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{-b+a x^4}}\right )}{4 \sqrt {a} \sqrt {b}}+\frac {\text {Subst}\left (\int \frac {1}{1+\sqrt [4]{a} \sqrt {\sqrt {a}+\sqrt {b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{-b+a x^4}}\right )}{4 \sqrt {a} \sqrt {b}} \\ & = -\frac {\arctan \left (\frac {\sqrt [8]{a} \sqrt [4]{\sqrt {a}-\sqrt {b}} x}{\sqrt [4]{-b+a x^4}}\right )}{4 a^{5/8} \sqrt [4]{\sqrt {a}-\sqrt {b}} \sqrt {b}}+\frac {\arctan \left (\frac {\sqrt [8]{a} \sqrt [4]{\sqrt {a}+\sqrt {b}} x}{\sqrt [4]{-b+a x^4}}\right )}{4 a^{5/8} \sqrt [4]{\sqrt {a}+\sqrt {b}} \sqrt {b}}-\frac {\text {arctanh}\left (\frac {\sqrt [8]{a} \sqrt [4]{\sqrt {a}-\sqrt {b}} x}{\sqrt [4]{-b+a x^4}}\right )}{4 a^{5/8} \sqrt [4]{\sqrt {a}-\sqrt {b}} \sqrt {b}}+\frac {\text {arctanh}\left (\frac {\sqrt [8]{a} \sqrt [4]{\sqrt {a}+\sqrt {b}} x}{\sqrt [4]{-b+a x^4}}\right )}{4 a^{5/8} \sqrt [4]{\sqrt {a}+\sqrt {b}} \sqrt {b}} \\ \end{align*}
Time = 0.41 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.98 \[ \int \frac {x^4}{\sqrt [4]{-b+a x^4} \left (-b+a x^8\right )} \, dx=\frac {1}{8} \text {RootSum}\left [a^2-a b-2 a \text {$\#$1}^4+\text {$\#$1}^8\&,\frac {\log (x)-\log \left (\sqrt [4]{-b+a x^4}-x \text {$\#$1}\right )}{-a \text {$\#$1}+\text {$\#$1}^5}\&\right ] \]
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Time = 1.28 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.89
method | result | size |
pseudoelliptic | \(-\frac {\left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{8}-2 \textit {\_Z}^{4} a +a^{2}-a b \right )}{\sum }\frac {\ln \left (\frac {-\textit {\_R} x +\left (a \,x^{4}-b \right )^{\frac {1}{4}}}{x}\right )}{\textit {\_R} \left (\textit {\_R}^{4}-a \right )}\right )}{8}\) | \(58\) |
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Timed out. \[ \int \frac {x^4}{\sqrt [4]{-b+a x^4} \left (-b+a x^8\right )} \, dx=\text {Timed out} \]
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Not integrable
Time = 9.44 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.31 \[ \int \frac {x^4}{\sqrt [4]{-b+a x^4} \left (-b+a x^8\right )} \, dx=\int \frac {x^{4}}{\sqrt [4]{a x^{4} - b} \left (a x^{8} - b\right )}\, dx \]
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Not integrable
Time = 0.22 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.43 \[ \int \frac {x^4}{\sqrt [4]{-b+a x^4} \left (-b+a x^8\right )} \, dx=\int { \frac {x^{4}}{{\left (a x^{8} - b\right )} {\left (a x^{4} - b\right )}^{\frac {1}{4}}} \,d x } \]
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Not integrable
Time = 0.31 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.43 \[ \int \frac {x^4}{\sqrt [4]{-b+a x^4} \left (-b+a x^8\right )} \, dx=\int { \frac {x^{4}}{{\left (a x^{8} - b\right )} {\left (a x^{4} - b\right )}^{\frac {1}{4}}} \,d x } \]
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Not integrable
Time = 5.28 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.45 \[ \int \frac {x^4}{\sqrt [4]{-b+a x^4} \left (-b+a x^8\right )} \, dx=-\int \frac {x^4}{{\left (a\,x^4-b\right )}^{1/4}\,\left (b-a\,x^8\right )} \,d x \]
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