Integrand size = 21, antiderivative size = 66 \[ \int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx=-\frac {2}{15} \sqrt {-1+x^2} \sqrt {x^2 \left (x+\sqrt {-1+x^2}\right )}+\frac {4 \left (-1+2 x^2\right ) \sqrt {x^2 \left (x+\sqrt {-1+x^2}\right )}}{15 x} \]
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\[ \int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx=\int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.97 \[ \int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx=\frac {2 x^3 \left (2-6 x^2+6 x^4-3 x \sqrt {-1+x^2}+6 x^3 \sqrt {-1+x^2}\right )}{15 \left (x^2 \left (x+\sqrt {-1+x^2}\right )\right )^{3/2}} \]
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\[\int \sqrt {x^{3}+x^{2} \sqrt {x^{2}-1}}d x\]
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none
Time = 0.28 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.59 \[ \int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx=\frac {2 \, \sqrt {x^{3} + \sqrt {x^{2} - 1} x^{2}} {\left (4 \, x^{2} - \sqrt {x^{2} - 1} x - 2\right )}}{15 \, x} \]
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\[ \int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx=\int \sqrt {x^{3} + x^{2} \sqrt {x^{2} - 1}}\, dx \]
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\[ \int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx=\int { \sqrt {x^{3} + \sqrt {x^{2} - 1} x^{2}} \,d x } \]
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\[ \int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx=\int { \sqrt {x^{3} + \sqrt {x^{2} - 1} x^{2}} \,d x } \]
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Timed out. \[ \int \sqrt {x^3+x^2 \sqrt {-1+x^2}} \, dx=\int \sqrt {x^2\,\sqrt {x^2-1}+x^3} \,d x \]
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