Integrand size = 30, antiderivative size = 67 \[ \int \frac {1}{\left (b+a^3 x^2\right ) \sqrt [3]{-b x^2+a^3 x^3}} \, dx=-\frac {\text {RootSum}\left [a^6+a^3 b-2 a^3 \text {$\#$1}^3+\text {$\#$1}^6\&,\frac {-\log (x)+\log \left (\sqrt [3]{-b x^2+a^3 x^3}-x \text {$\#$1}\right )}{\text {$\#$1}}\&\right ]}{2 b} \]
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Leaf count is larger than twice the leaf count of optimal. \(651\) vs. \(2(67)=134\).
Time = 0.17 (sec) , antiderivative size = 651, normalized size of antiderivative = 9.72, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {2081, 926, 93} \[ \int \frac {1}{\left (b+a^3 x^2\right ) \sqrt [3]{-b x^2+a^3 x^3}} \, dx=-\frac {\sqrt {3} x^{2/3} \sqrt [3]{a^3 x-b} \arctan \left (\frac {2 \sqrt [3]{a^3 x-b}}{\sqrt {3} \sqrt [3]{x} \sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}}}+\frac {1}{\sqrt {3}}\right )}{2 b \sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}} \sqrt [3]{a^3 x^3-b x^2}}-\frac {\sqrt {3} x^{2/3} \sqrt [3]{a^3 x-b} \arctan \left (\frac {2 \sqrt [3]{a^3 x-b}}{\sqrt {3} \sqrt [3]{x} \sqrt [3]{\sqrt {-a^3} \sqrt {b}+a^3}}+\frac {1}{\sqrt {3}}\right )}{2 b \sqrt [3]{\sqrt {-a^3} \sqrt {b}+a^3} \sqrt [3]{a^3 x^3-b x^2}}+\frac {x^{2/3} \sqrt [3]{a^3 x-b} \log \left (\sqrt {b}-\sqrt {-a^3} x\right )}{4 b \sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}} \sqrt [3]{a^3 x^3-b x^2}}+\frac {x^{2/3} \sqrt [3]{a^3 x-b} \log \left (\sqrt {-a^3} x+\sqrt {b}\right )}{4 b \sqrt [3]{\sqrt {-a^3} \sqrt {b}+a^3} \sqrt [3]{a^3 x^3-b x^2}}-\frac {3 x^{2/3} \sqrt [3]{a^3 x-b} \log \left (\frac {\sqrt [3]{a^3 x-b}}{\sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}}}-\sqrt [3]{x}\right )}{4 b \sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}} \sqrt [3]{a^3 x^3-b x^2}}-\frac {3 x^{2/3} \sqrt [3]{a^3 x-b} \log \left (\frac {\sqrt [3]{a^3 x-b}}{\sqrt [3]{\sqrt {-a^3} \sqrt {b}+a^3}}-\sqrt [3]{x}\right )}{4 b \sqrt [3]{\sqrt {-a^3} \sqrt {b}+a^3} \sqrt [3]{a^3 x^3-b x^2}} \]
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Rule 93
Rule 926
Rule 2081
Rubi steps \begin{align*} \text {integral}& = \frac {\left (x^{2/3} \sqrt [3]{-b+a^3 x}\right ) \int \frac {1}{x^{2/3} \sqrt [3]{-b+a^3 x} \left (b+a^3 x^2\right )} \, dx}{\sqrt [3]{-b x^2+a^3 x^3}} \\ & = \frac {\left (x^{2/3} \sqrt [3]{-b+a^3 x}\right ) \int \left (\frac {1}{2 \sqrt {b} x^{2/3} \sqrt [3]{-b+a^3 x} \left (\sqrt {b}-\sqrt {-a^3} x\right )}+\frac {1}{2 \sqrt {b} x^{2/3} \sqrt [3]{-b+a^3 x} \left (\sqrt {b}+\sqrt {-a^3} x\right )}\right ) \, dx}{\sqrt [3]{-b x^2+a^3 x^3}} \\ & = \frac {\left (x^{2/3} \sqrt [3]{-b+a^3 x}\right ) \int \frac {1}{x^{2/3} \sqrt [3]{-b+a^3 x} \left (\sqrt {b}-\sqrt {-a^3} x\right )} \, dx}{2 \sqrt {b} \sqrt [3]{-b x^2+a^3 x^3}}+\frac {\left (x^{2/3} \sqrt [3]{-b+a^3 x}\right ) \int \frac {1}{x^{2/3} \sqrt [3]{-b+a^3 x} \left (\sqrt {b}+\sqrt {-a^3} x\right )} \, dx}{2 \sqrt {b} \sqrt [3]{-b x^2+a^3 x^3}} \\ & = -\frac {\sqrt {3} x^{2/3} \sqrt [3]{-b+a^3 x} \arctan \left (\frac {1}{\sqrt {3}}+\frac {2 \sqrt [3]{-b+a^3 x}}{\sqrt {3} \sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}} \sqrt [3]{x}}\right )}{2 \sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}-\frac {\sqrt {3} x^{2/3} \sqrt [3]{-b+a^3 x} \arctan \left (\frac {1}{\sqrt {3}}+\frac {2 \sqrt [3]{-b+a^3 x}}{\sqrt {3} \sqrt [3]{a^3+\sqrt {-a^3} \sqrt {b}} \sqrt [3]{x}}\right )}{2 \sqrt [3]{a^3+\sqrt {-a^3} \sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}+\frac {x^{2/3} \sqrt [3]{-b+a^3 x} \log \left (\sqrt {b}-\sqrt {-a^3} x\right )}{4 \sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}+\frac {x^{2/3} \sqrt [3]{-b+a^3 x} \log \left (\sqrt {b}+\sqrt {-a^3} x\right )}{4 \sqrt [3]{a^3+\sqrt {-a^3} \sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}-\frac {3 x^{2/3} \sqrt [3]{-b+a^3 x} \log \left (-\sqrt [3]{x}+\frac {\sqrt [3]{-b+a^3 x}}{\sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}}}\right )}{4 \sqrt [3]{a^3-\sqrt {-a^3} \sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}-\frac {3 x^{2/3} \sqrt [3]{-b+a^3 x} \log \left (-\sqrt [3]{x}+\frac {\sqrt [3]{-b+a^3 x}}{\sqrt [3]{a^3+\sqrt {-a^3} \sqrt {b}}}\right )}{4 \sqrt [3]{a^3+\sqrt {-a^3} \sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.57 \[ \int \frac {1}{\left (b+a^3 x^2\right ) \sqrt [3]{-b x^2+a^3 x^3}} \, dx=-\frac {x^{2/3} \sqrt [3]{-b+a^3 x} \text {RootSum}\left [a^6+a^3 b-2 a^3 \text {$\#$1}^3+\text {$\#$1}^6\&,\frac {-\log \left (\sqrt [3]{x}\right )+\log \left (\sqrt [3]{-b+a^3 x}-\sqrt [3]{x} \text {$\#$1}\right )}{\text {$\#$1}}\&\right ]}{2 b \sqrt [3]{x^2 \left (-b+a^3 x\right )}} \]
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Time = 1.25 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.88
method | result | size |
pseudoelliptic | \(-\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{6}-2 a^{3} \textit {\_Z}^{3}+a^{6}+a^{3} b \right )}{\sum }\frac {\ln \left (\frac {-\textit {\_R} x +\left (x^{2} \left (a^{3} x -b \right )\right )^{\frac {1}{3}}}{x}\right )}{\textit {\_R}}}{2 b}\) | \(59\) |
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Result contains higher order function than in optimal. Order 3 vs. order 1.
Time = 0.30 (sec) , antiderivative size = 1372, normalized size of antiderivative = 20.48 \[ \int \frac {1}{\left (b+a^3 x^2\right ) \sqrt [3]{-b x^2+a^3 x^3}} \, dx=\text {Too large to display} \]
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Not integrable
Time = 0.86 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.36 \[ \int \frac {1}{\left (b+a^3 x^2\right ) \sqrt [3]{-b x^2+a^3 x^3}} \, dx=\int \frac {1}{\sqrt [3]{x^{2} \left (a^{3} x - b\right )} \left (a^{3} x^{2} + b\right )}\, dx \]
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Not integrable
Time = 0.22 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.45 \[ \int \frac {1}{\left (b+a^3 x^2\right ) \sqrt [3]{-b x^2+a^3 x^3}} \, dx=\int { \frac {1}{{\left (a^{3} x^{3} - b x^{2}\right )}^{\frac {1}{3}} {\left (a^{3} x^{2} + b\right )}} \,d x } \]
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Not integrable
Time = 0.55 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.45 \[ \int \frac {1}{\left (b+a^3 x^2\right ) \sqrt [3]{-b x^2+a^3 x^3}} \, dx=\int { \frac {1}{{\left (a^{3} x^{3} - b x^{2}\right )}^{\frac {1}{3}} {\left (a^{3} x^{2} + b\right )}} \,d x } \]
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Not integrable
Time = 0.00 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.45 \[ \int \frac {1}{\left (b+a^3 x^2\right ) \sqrt [3]{-b x^2+a^3 x^3}} \, dx=\int \frac {1}{\left (a^3\,x^2+b\right )\,{\left (a^3\,x^3-b\,x^2\right )}^{1/3}} \,d x \]
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