Integrand size = 39, antiderivative size = 25 \[ \int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{4 x} \, dx=\frac {1}{4} \left (e^{3+e^4+2 e^{2/x} x}+3 x\right ) \]
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\[ \int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{4 x} \, dx=\int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{4 x} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {1}{4} \int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{x} \, dx \\ & = \frac {1}{4} \int \left (3+\frac {2 e^{3 \left (1+\frac {e^4}{3}\right )+\frac {2}{x}+2 e^{2/x} x} (-2+x)}{x}\right ) \, dx \\ & = \frac {3 x}{4}+\frac {1}{2} \int \frac {e^{3 \left (1+\frac {e^4}{3}\right )+\frac {2}{x}+2 e^{2/x} x} (-2+x)}{x} \, dx \\ & = \frac {3 x}{4}+\frac {1}{2} \int \left (e^{3 \left (1+\frac {e^4}{3}\right )+\frac {2}{x}+2 e^{2/x} x}-\frac {2 e^{3 \left (1+\frac {e^4}{3}\right )+\frac {2}{x}+2 e^{2/x} x}}{x}\right ) \, dx \\ & = \frac {3 x}{4}+\frac {1}{2} \int e^{3 \left (1+\frac {e^4}{3}\right )+\frac {2}{x}+2 e^{2/x} x} \, dx-\int \frac {e^{3 \left (1+\frac {e^4}{3}\right )+\frac {2}{x}+2 e^{2/x} x}}{x} \, dx \\ \end{align*}
Time = 0.21 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.08 \[ \int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{4 x} \, dx=\frac {1}{4} e^{3+e^4+2 e^{2/x} x}+\frac {3 x}{4} \]
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Time = 0.64 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.84
method | result | size |
norman | \(\frac {{\mathrm e}^{2 x \,{\mathrm e}^{\frac {2}{x}}+{\mathrm e}^{4}+3}}{4}+\frac {3 x}{4}\) | \(21\) |
risch | \(\frac {{\mathrm e}^{2 x \,{\mathrm e}^{\frac {2}{x}}+{\mathrm e}^{4}+3}}{4}+\frac {3 x}{4}\) | \(21\) |
parallelrisch | \(\frac {{\mathrm e}^{2 x \,{\mathrm e}^{\frac {2}{x}}+{\mathrm e}^{4}+3}}{4}+\frac {3 x}{4}\) | \(21\) |
parts | \(\frac {{\mathrm e}^{2 x \,{\mathrm e}^{\frac {2}{x}}+{\mathrm e}^{4}+3}}{4}+\frac {3 x}{4}\) | \(21\) |
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Leaf count of result is larger than twice the leaf count of optimal. 43 vs. \(2 (20) = 40\).
Time = 0.27 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.72 \[ \int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{4 x} \, dx=\frac {1}{4} \, {\left (3 \, x e^{\frac {2}{x}} + e^{\left (\frac {2 \, x^{2} e^{\frac {2}{x}} + x e^{4} + 3 \, x + 2}{x}\right )}\right )} e^{\left (-\frac {2}{x}\right )} \]
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Time = 0.13 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.80 \[ \int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{4 x} \, dx=\frac {3 x}{4} + \frac {e^{2 x e^{\frac {2}{x}} + 3 + e^{4}}}{4} \]
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Time = 0.34 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.80 \[ \int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{4 x} \, dx=\frac {3}{4} \, x + \frac {1}{4} \, e^{\left (2 \, x e^{\frac {2}{x}} + e^{4} + 3\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 43 vs. \(2 (20) = 40\).
Time = 0.28 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.72 \[ \int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{4 x} \, dx=\frac {1}{4} \, {\left (3 \, x e^{\frac {2}{x}} + e^{\left (\frac {2 \, x^{2} e^{\frac {2}{x}} + x e^{4} + 3 \, x + 2}{x}\right )}\right )} e^{\left (-\frac {2}{x}\right )} \]
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Time = 16.66 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.84 \[ \int \frac {3 x+e^{3+e^4+\frac {2}{x}+2 e^{2/x} x} (-4+2 x)}{4 x} \, dx=\frac {3\,x}{4}+\frac {{\mathrm {e}}^3\,{\mathrm {e}}^{{\mathrm {e}}^4}\,{\mathrm {e}}^{2\,x\,{\mathrm {e}}^{2/x}}}{4} \]
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