Integrand size = 66, antiderivative size = 21 \[ \int \frac {-92-570 x-356 x^2+24 x^3+32 x^4+2 x^5+\left (8+52 x+44 x^2-4 x^3-4 x^4\right ) \log (x)}{x+3 x^2+3 x^3+x^4} \, dx=\left (-15-x-\frac {8 x}{x+x^2}+2 \log (x)\right )^2 \]
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Leaf count is larger than twice the leaf count of optimal. \(46\) vs. \(2(21)=42\).
Time = 0.28 (sec) , antiderivative size = 46, normalized size of antiderivative = 2.19, number of steps used = 16, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.152, Rules used = {6820, 12, 6874, 1864, 1634, 2404, 2332, 2338, 2351, 31} \[ \int \frac {-92-570 x-356 x^2+24 x^3+32 x^4+2 x^5+\left (8+52 x+44 x^2-4 x^3-4 x^4\right ) \log (x)}{x+3 x^2+3 x^3+x^4} \, dx=x^2+30 x+\frac {224}{x+1}+\frac {64}{(x+1)^2}+4 \log ^2(x)+\frac {32 x \log (x)}{x+1}-4 x \log (x)-92 \log (x) \]
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Rule 12
Rule 31
Rule 1634
Rule 1864
Rule 2332
Rule 2338
Rule 2351
Rule 2404
Rule 6820
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {2 \left (2+11 x-x^3\right ) \left (-23-16 x-x^2+2 (1+x) \log (x)\right )}{x (1+x)^3} \, dx \\ & = 2 \int \frac {\left (2+11 x-x^3\right ) \left (-23-16 x-x^2+2 (1+x) \log (x)\right )}{x (1+x)^3} \, dx \\ & = 2 \int \left (\frac {16 \left (-2-11 x+x^3\right )}{(1+x)^3}+\frac {23 \left (-2-11 x+x^3\right )}{x (1+x)^3}+\frac {x \left (-2-11 x+x^3\right )}{(1+x)^3}-\frac {2 \left (-2-11 x+x^3\right ) \log (x)}{x (1+x)^2}\right ) \, dx \\ & = 2 \int \frac {x \left (-2-11 x+x^3\right )}{(1+x)^3} \, dx-4 \int \frac {\left (-2-11 x+x^3\right ) \log (x)}{x (1+x)^2} \, dx+32 \int \frac {-2-11 x+x^3}{(1+x)^3} \, dx+46 \int \frac {-2-11 x+x^3}{x (1+x)^3} \, dx \\ & = 2 \int \left (-3+x-\frac {8}{(1+x)^3}+\frac {16}{(1+x)^2}-\frac {5}{1+x}\right ) \, dx-4 \int \left (\log (x)-\frac {2 \log (x)}{x}-\frac {8 \log (x)}{(1+x)^2}\right ) \, dx+32 \int \left (1+\frac {8}{(1+x)^3}-\frac {8}{(1+x)^2}-\frac {3}{1+x}\right ) \, dx+46 \int \left (-\frac {2}{x}-\frac {8}{(1+x)^3}+\frac {3}{1+x}\right ) \, dx \\ & = 26 x+x^2+\frac {64}{(1+x)^2}+\frac {224}{1+x}-92 \log (x)+32 \log (1+x)-4 \int \log (x) \, dx+8 \int \frac {\log (x)}{x} \, dx+32 \int \frac {\log (x)}{(1+x)^2} \, dx \\ & = 30 x+x^2+\frac {64}{(1+x)^2}+\frac {224}{1+x}-92 \log (x)-4 x \log (x)+\frac {32 x \log (x)}{1+x}+4 \log ^2(x)+32 \log (1+x)-32 \int \frac {1}{1+x} \, dx \\ & = 30 x+x^2+\frac {64}{(1+x)^2}+\frac {224}{1+x}-92 \log (x)-4 x \log (x)+\frac {32 x \log (x)}{1+x}+4 \log ^2(x) \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(48\) vs. \(2(21)=42\).
Time = 0.08 (sec) , antiderivative size = 48, normalized size of antiderivative = 2.29 \[ \int \frac {-92-570 x-356 x^2+24 x^3+32 x^4+2 x^5+\left (8+52 x+44 x^2-4 x^3-4 x^4\right ) \log (x)}{x+3 x^2+3 x^3+x^4} \, dx=2 \left (15 x+\frac {x^2}{2}+\frac {32}{(1+x)^2}+\frac {16 (7-\log (x))}{1+x}-30 \log (x)-2 x \log (x)+2 \log ^2(x)\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. \(46\) vs. \(2(21)=42\).
Time = 0.19 (sec) , antiderivative size = 47, normalized size of antiderivative = 2.24
method | result | size |
default | \(x^{2}+30 x -92 \ln \left (x \right )+\frac {64}{\left (1+x \right )^{2}}+\frac {224}{1+x}-4 x \ln \left (x \right )+4 \ln \left (x \right )^{2}+\frac {32 \ln \left (x \right ) x}{1+x}\) | \(47\) |
parts | \(x^{2}+30 x -92 \ln \left (x \right )+\frac {64}{\left (1+x \right )^{2}}+\frac {224}{1+x}-4 x \ln \left (x \right )+4 \ln \left (x \right )^{2}+\frac {32 \ln \left (x \right ) x}{1+x}\) | \(47\) |
norman | \(\frac {x^{4}-92 \ln \left (x \right )+132 x -156 x \ln \left (x \right )-68 x^{2} \ln \left (x \right )+32 x^{3}+4 \ln \left (x \right )^{2}+8 x \ln \left (x \right )^{2}+4 x^{2} \ln \left (x \right )^{2}-4 x^{3} \ln \left (x \right )+227}{\left (1+x \right )^{2}}\) | \(65\) |
risch | \(4 \ln \left (x \right )^{2}-\frac {4 \left (x^{2}+x +8\right ) \ln \left (x \right )}{1+x}-\frac {-x^{4}+60 x^{2} \ln \left (x \right )-32 x^{3}+120 x \ln \left (x \right )-61 x^{2}+60 \ln \left (x \right )-254 x -288}{\left (1+x \right )^{2}}\) | \(66\) |
parallelrisch | \(\frac {x^{4}-92 \ln \left (x \right )+132 x -156 x \ln \left (x \right )-68 x^{2} \ln \left (x \right )+32 x^{3}+4 \ln \left (x \right )^{2}+8 x \ln \left (x \right )^{2}+4 x^{2} \ln \left (x \right )^{2}-4 x^{3} \ln \left (x \right )+227}{x^{2}+2 x +1}\) | \(70\) |
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Leaf count of result is larger than twice the leaf count of optimal. 60 vs. \(2 (19) = 38\).
Time = 0.27 (sec) , antiderivative size = 60, normalized size of antiderivative = 2.86 \[ \int \frac {-92-570 x-356 x^2+24 x^3+32 x^4+2 x^5+\left (8+52 x+44 x^2-4 x^3-4 x^4\right ) \log (x)}{x+3 x^2+3 x^3+x^4} \, dx=\frac {x^{4} + 32 \, x^{3} + 4 \, {\left (x^{2} + 2 \, x + 1\right )} \log \left (x\right )^{2} + 61 \, x^{2} - 4 \, {\left (x^{3} + 17 \, x^{2} + 39 \, x + 23\right )} \log \left (x\right ) + 254 \, x + 288}{x^{2} + 2 \, x + 1} \]
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Leaf count of result is larger than twice the leaf count of optimal. 49 vs. \(2 (17) = 34\).
Time = 0.12 (sec) , antiderivative size = 49, normalized size of antiderivative = 2.33 \[ \int \frac {-92-570 x-356 x^2+24 x^3+32 x^4+2 x^5+\left (8+52 x+44 x^2-4 x^3-4 x^4\right ) \log (x)}{x+3 x^2+3 x^3+x^4} \, dx=x^{2} + 30 x + \frac {224 x + 288}{x^{2} + 2 x + 1} + 4 \log {\left (x \right )}^{2} - 60 \log {\left (x \right )} + \frac {\left (- 4 x^{2} - 4 x - 32\right ) \log {\left (x \right )}}{x + 1} \]
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Leaf count of result is larger than twice the leaf count of optimal. 137 vs. \(2 (19) = 38\).
Time = 0.26 (sec) , antiderivative size = 137, normalized size of antiderivative = 6.52 \[ \int \frac {-92-570 x-356 x^2+24 x^3+32 x^4+2 x^5+\left (8+52 x+44 x^2-4 x^3-4 x^4\right ) \log (x)}{x+3 x^2+3 x^3+x^4} \, dx=x^{2} + 26 \, x + \frac {8 \, x + 7}{x^{2} + 2 \, x + 1} - \frac {16 \, {\left (6 \, x + 5\right )}}{x^{2} + 2 \, x + 1} + \frac {12 \, {\left (4 \, x + 3\right )}}{x^{2} + 2 \, x + 1} - \frac {46 \, {\left (2 \, x + 3\right )}}{x^{2} + 2 \, x + 1} + \frac {178 \, {\left (2 \, x + 1\right )}}{x^{2} + 2 \, x + 1} + \frac {4 \, {\left ({\left (x + 1\right )} \log \left (x\right )^{2} + x^{2} - {\left (x^{2} + x + 8\right )} \log \left (x\right ) + x\right )}}{x + 1} + \frac {285}{x^{2} + 2 \, x + 1} - 60 \, \log \left (x\right ) \]
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\[ \int \frac {-92-570 x-356 x^2+24 x^3+32 x^4+2 x^5+\left (8+52 x+44 x^2-4 x^3-4 x^4\right ) \log (x)}{x+3 x^2+3 x^3+x^4} \, dx=\int { \frac {2 \, {\left (x^{5} + 16 \, x^{4} + 12 \, x^{3} - 178 \, x^{2} - 2 \, {\left (x^{4} + x^{3} - 11 \, x^{2} - 13 \, x - 2\right )} \log \left (x\right ) - 285 \, x - 46\right )}}{x^{4} + 3 \, x^{3} + 3 \, x^{2} + x} \,d x } \]
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Time = 16.01 (sec) , antiderivative size = 44, normalized size of antiderivative = 2.10 \[ \int \frac {-92-570 x-356 x^2+24 x^3+32 x^4+2 x^5+\left (8+52 x+44 x^2-4 x^3-4 x^4\right ) \log (x)}{x+3 x^2+3 x^3+x^4} \, dx=4\,{\ln \left (x\right )}^2-60\,\ln \left (x\right )-x\,\left (4\,\ln \left (x\right )-30\right )-\frac {32\,\ln \left (x\right )+x\,\left (32\,\ln \left (x\right )-224\right )-288}{{\left (x+1\right )}^2}+x^2 \]
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