Integrand size = 99, antiderivative size = 26 \[ \int \left (75 x^2+300 e^3 x^2+300 e^6 x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx=x \left (-e^{2 x}+5 \left (x+2 e^3 x+x \log (4)\right )\right )^2 \]
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Leaf count is larger than twice the leaf count of optimal. \(89\) vs. \(2(26)=52\).
Time = 0.09 (sec) , antiderivative size = 89, normalized size of antiderivative = 3.42, number of steps used = 23, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.061, Rules used = {6, 2207, 2225, 12, 30, 2227} \[ \int \left (75 x^2+300 e^3 x^2+300 e^6 x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx=25 x^3 \left (1+4 e^3+4 e^6+\log ^2(4)\right )+50 \left (1+2 e^3\right ) x^3 \log (4)-10 e^{2 x} x^2-10 e^{2 x+3} x^2 \left (2+\frac {\log (4)}{e^3}\right )-\frac {e^{4 x}}{4}+\frac {1}{4} e^{4 x} (4 x+1) \]
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Rule 6
Rule 12
Rule 30
Rule 2207
Rule 2225
Rule 2227
Rubi steps \begin{align*} \text {integral}& = \int \left (300 e^6 x^2+\left (75+300 e^3\right ) x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx \\ & = \int \left (\left (75+300 e^3+300 e^6\right ) x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx \\ & = \int \left (e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )+x^2 \left (75+300 e^3+300 e^6+75 \log ^2(4)\right )\right ) \, dx \\ & = 25 x^3 \left (1+4 e^3+4 e^6+\log ^2(4)\right )+\log (4) \int \left (150 x^2+300 e^3 x^2\right ) \, dx+\int e^{4 x} (1+4 x) \, dx+\int e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right ) \, dx \\ & = \frac {1}{4} e^{4 x} (1+4 x)+25 x^3 \left (1+4 e^3+4 e^6+\log ^2(4)\right )+\log (4) \int \left (150+300 e^3\right ) x^2 \, dx-\int e^{4 x} \, dx+\int \left (-20 e^{2 x} x-20 e^{2 x} x^2-40 e^{3+2 x} x (1+x) \left (1+\frac {\log (4)}{2 e^3}\right )\right ) \, dx \\ & = -\frac {e^{4 x}}{4}+\frac {1}{4} e^{4 x} (1+4 x)+25 x^3 \left (1+4 e^3+4 e^6+\log ^2(4)\right )-20 \int e^{2 x} x \, dx-20 \int e^{2 x} x^2 \, dx+\left (150 \left (1+2 e^3\right ) \log (4)\right ) \int x^2 \, dx-\left (20 \left (2+\frac {\log (4)}{e^3}\right )\right ) \int e^{3+2 x} x (1+x) \, dx \\ & = -\frac {e^{4 x}}{4}-10 e^{2 x} x-10 e^{2 x} x^2+\frac {1}{4} e^{4 x} (1+4 x)+50 \left (1+2 e^3\right ) x^3 \log (4)+25 x^3 \left (1+4 e^3+4 e^6+\log ^2(4)\right )+10 \int e^{2 x} \, dx+20 \int e^{2 x} x \, dx-\left (20 \left (2+\frac {\log (4)}{e^3}\right )\right ) \int \left (e^{3+2 x} x+e^{3+2 x} x^2\right ) \, dx \\ & = 5 e^{2 x}-\frac {e^{4 x}}{4}-10 e^{2 x} x^2+\frac {1}{4} e^{4 x} (1+4 x)+50 \left (1+2 e^3\right ) x^3 \log (4)+25 x^3 \left (1+4 e^3+4 e^6+\log ^2(4)\right )-10 \int e^{2 x} \, dx-\left (20 \left (2+\frac {\log (4)}{e^3}\right )\right ) \int e^{3+2 x} x \, dx-\left (20 \left (2+\frac {\log (4)}{e^3}\right )\right ) \int e^{3+2 x} x^2 \, dx \\ & = -\frac {e^{4 x}}{4}-10 e^{2 x} x^2+\frac {1}{4} e^{4 x} (1+4 x)+50 \left (1+2 e^3\right ) x^3 \log (4)-10 e^{3+2 x} x \left (2+\frac {\log (4)}{e^3}\right )-10 e^{3+2 x} x^2 \left (2+\frac {\log (4)}{e^3}\right )+25 x^3 \left (1+4 e^3+4 e^6+\log ^2(4)\right )+\left (10 \left (2+\frac {\log (4)}{e^3}\right )\right ) \int e^{3+2 x} \, dx+\left (20 \left (2+\frac {\log (4)}{e^3}\right )\right ) \int e^{3+2 x} x \, dx \\ & = -\frac {e^{4 x}}{4}-10 e^{2 x} x^2+\frac {1}{4} e^{4 x} (1+4 x)+50 \left (1+2 e^3\right ) x^3 \log (4)+5 e^{3+2 x} \left (2+\frac {\log (4)}{e^3}\right )-10 e^{3+2 x} x^2 \left (2+\frac {\log (4)}{e^3}\right )+25 x^3 \left (1+4 e^3+4 e^6+\log ^2(4)\right )-\left (10 \left (2+\frac {\log (4)}{e^3}\right )\right ) \int e^{3+2 x} \, dx \\ & = -\frac {e^{4 x}}{4}-10 e^{2 x} x^2+\frac {1}{4} e^{4 x} (1+4 x)+50 \left (1+2 e^3\right ) x^3 \log (4)-10 e^{3+2 x} x^2 \left (2+\frac {\log (4)}{e^3}\right )+25 x^3 \left (1+4 e^3+4 e^6+\log ^2(4)\right ) \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.88 \[ \int \left (75 x^2+300 e^3 x^2+300 e^6 x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx=x \left (e^{2 x}-10 e^3 x-5 x (1+\log (4))\right )^2 \]
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Leaf count of result is larger than twice the leaf count of optimal. \(59\) vs. \(2(24)=48\).
Time = 0.68 (sec) , antiderivative size = 60, normalized size of antiderivative = 2.31
method | result | size |
norman | \(x \,{\mathrm e}^{4 x}+\left (100 \ln \left (2\right )^{2}+200 \,{\mathrm e}^{3} \ln \left (2\right )+100 \,{\mathrm e}^{6}+100 \ln \left (2\right )+100 \,{\mathrm e}^{3}+25\right ) x^{3}+\left (-20 \ln \left (2\right )-20 \,{\mathrm e}^{3}-10\right ) x^{2} {\mathrm e}^{2 x}\) | \(60\) |
risch | \(x \,{\mathrm e}^{4 x}-10 \left (2 \ln \left (2\right )+2 \,{\mathrm e}^{3}+1\right ) x^{2} {\mathrm e}^{2 x}+100 x^{3} \ln \left (2\right )^{2}+200 \ln \left (2\right ) x^{3} {\mathrm e}^{3}+100 x^{3} \ln \left (2\right )+100 x^{3} {\mathrm e}^{6}+100 x^{3} {\mathrm e}^{3}+25 x^{3}\) | \(71\) |
derivativedivides | \(100 \ln \left (2\right ) x^{3} \left (2 \,{\mathrm e}^{3}+1\right )+25 x^{3}+100 x^{3} {\mathrm e}^{3}+100 x^{3} {\mathrm e}^{6}+100 x^{3} \ln \left (2\right )^{2}+x \,{\mathrm e}^{4 x}-10 \,{\mathrm e}^{2 x} x^{2}-20 x^{2} {\mathrm e}^{3} {\mathrm e}^{2 x}-20 \ln \left (2\right ) {\mathrm e}^{2 x} x^{2}\) | \(84\) |
default | \(100 \ln \left (2\right ) x^{3} \left (2 \,{\mathrm e}^{3}+1\right )+25 x^{3}+100 x^{3} {\mathrm e}^{3}+100 x^{3} {\mathrm e}^{6}+100 x^{3} \ln \left (2\right )^{2}+x \,{\mathrm e}^{4 x}-10 \,{\mathrm e}^{2 x} x^{2}-20 x^{2} {\mathrm e}^{3} {\mathrm e}^{2 x}-20 \ln \left (2\right ) {\mathrm e}^{2 x} x^{2}\) | \(84\) |
parallelrisch | \(100 x^{3} \ln \left (2\right )^{2}+200 \ln \left (2\right ) x^{3} {\mathrm e}^{3}-20 \ln \left (2\right ) {\mathrm e}^{2 x} x^{2}+100 x^{3} \ln \left (2\right )-20 x^{2} {\mathrm e}^{3} {\mathrm e}^{2 x}+100 x^{3} {\mathrm e}^{3}+100 x^{3} {\mathrm e}^{6}-10 \,{\mathrm e}^{2 x} x^{2}+25 x^{3}+x \,{\mathrm e}^{4 x}\) | \(87\) |
parts | \(100 x^{3} \ln \left (2\right )^{2}+200 \ln \left (2\right ) x^{3} {\mathrm e}^{3}-20 \ln \left (2\right ) {\mathrm e}^{2 x} x^{2}+100 x^{3} \ln \left (2\right )-20 x^{2} {\mathrm e}^{3} {\mathrm e}^{2 x}+100 x^{3} {\mathrm e}^{3}+100 x^{3} {\mathrm e}^{6}-10 \,{\mathrm e}^{2 x} x^{2}+25 x^{3}+x \,{\mathrm e}^{4 x}\) | \(87\) |
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Leaf count of result is larger than twice the leaf count of optimal. 74 vs. \(2 (24) = 48\).
Time = 0.26 (sec) , antiderivative size = 74, normalized size of antiderivative = 2.85 \[ \int \left (75 x^2+300 e^3 x^2+300 e^6 x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx=100 \, x^{3} \log \left (2\right )^{2} + 100 \, x^{3} e^{6} + 100 \, x^{3} e^{3} + 25 \, x^{3} + x e^{\left (4 \, x\right )} - 10 \, {\left (2 \, x^{2} e^{3} + 2 \, x^{2} \log \left (2\right ) + x^{2}\right )} e^{\left (2 \, x\right )} + 100 \, {\left (2 \, x^{3} e^{3} + x^{3}\right )} \log \left (2\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 70 vs. \(2 (24) = 48\).
Time = 0.13 (sec) , antiderivative size = 70, normalized size of antiderivative = 2.69 \[ \int \left (75 x^2+300 e^3 x^2+300 e^6 x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx=x^{3} \cdot \left (25 + 100 \log {\left (2 \right )}^{2} + 100 \log {\left (2 \right )} + 100 e^{3} + 200 e^{3} \log {\left (2 \right )} + 100 e^{6}\right ) + x e^{4 x} + \left (- 20 x^{2} e^{3} - 20 x^{2} \log {\left (2 \right )} - 10 x^{2}\right ) e^{2 x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 69 vs. \(2 (24) = 48\).
Time = 0.29 (sec) , antiderivative size = 69, normalized size of antiderivative = 2.65 \[ \int \left (75 x^2+300 e^3 x^2+300 e^6 x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx=100 \, x^{3} \log \left (2\right )^{2} + 100 \, x^{3} e^{6} + 100 \, x^{3} e^{3} - 10 \, x^{2} {\left (2 \, e^{3} + 2 \, \log \left (2\right ) + 1\right )} e^{\left (2 \, x\right )} + 25 \, x^{3} + x e^{\left (4 \, x\right )} + 100 \, {\left (2 \, x^{3} e^{3} + x^{3}\right )} \log \left (2\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 78 vs. \(2 (24) = 48\).
Time = 0.28 (sec) , antiderivative size = 78, normalized size of antiderivative = 3.00 \[ \int \left (75 x^2+300 e^3 x^2+300 e^6 x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx=100 \, x^{3} \log \left (2\right )^{2} + 100 \, x^{3} e^{6} + 100 \, x^{3} e^{3} + 25 \, x^{3} - 20 \, x^{2} e^{\left (2 \, x + 3\right )} + x e^{\left (4 \, x\right )} - 10 \, {\left (2 \, x^{2} \log \left (2\right ) + x^{2}\right )} e^{\left (2 \, x\right )} + 100 \, {\left (2 \, x^{3} e^{3} + x^{3}\right )} \log \left (2\right ) \]
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Time = 0.23 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.92 \[ \int \left (75 x^2+300 e^3 x^2+300 e^6 x^2+e^{4 x} (1+4 x)+\left (150 x^2+300 e^3 x^2\right ) \log (4)+75 x^2 \log ^2(4)+e^{2 x} \left (-20 x-20 x^2+e^3 \left (-40 x-40 x^2\right )+\left (-20 x-20 x^2\right ) \log (4)\right )\right ) \, dx=x\,{\left (5\,x-{\mathrm {e}}^{2\,x}+10\,x\,{\mathrm {e}}^3+10\,x\,\ln \left (2\right )\right )}^2 \]
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