Integrand size = 100, antiderivative size = 21 \[ \int \frac {282-48 x+2 x^2+\left (-24 x+26 x^2-2 x^3+\left (24 x-26 x^2+2 x^3\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {1-2 x+x^2}{x^2}\right )\right )}{x-x^2+\left (-x+x^2\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )} \, dx=\left (-3+(12-x)^2\right ) \log \left (-1+\log \left (\left (-1+\frac {1}{x}\right )^2\right )\right ) \]
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\[ \int \frac {282-48 x+2 x^2+\left (-24 x+26 x^2-2 x^3+\left (24 x-26 x^2+2 x^3\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {1-2 x+x^2}{x^2}\right )\right )}{x-x^2+\left (-x+x^2\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )} \, dx=\int \frac {282-48 x+2 x^2+\left (-24 x+26 x^2-2 x^3+\left (24 x-26 x^2+2 x^3\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {1-2 x+x^2}{x^2}\right )\right )}{x-x^2+\left (-x+x^2\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {2 \left (141-24 x+x^2+x \left (12-13 x+x^2\right ) \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )\right )}{(1-x) x \left (1-\log \left (\frac {(-1+x)^2}{x^2}\right )\right )} \, dx \\ & = 2 \int \frac {141-24 x+x^2+x \left (12-13 x+x^2\right ) \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )}{(1-x) x \left (1-\log \left (\frac {(-1+x)^2}{x^2}\right )\right )} \, dx \\ & = 2 \int \left (\frac {141-24 x+x^2}{(-1+x) x \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )}+(-12+x) \log \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )\right ) \, dx \\ & = 2 \int \frac {141-24 x+x^2}{(-1+x) x \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )} \, dx+2 \int (-12+x) \log \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right ) \, dx \\ & = 2 \int \left (\frac {1}{-1+\log \left (\frac {(-1+x)^2}{x^2}\right )}+\frac {118}{(-1+x) \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )}-\frac {141}{x \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )}\right ) \, dx+2 \int \left (-12 \log \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )+x \log \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )\right ) \, dx \\ & = 2 \int \frac {1}{-1+\log \left (\frac {(-1+x)^2}{x^2}\right )} \, dx+2 \int x \log \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right ) \, dx-24 \int \log \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right ) \, dx+236 \int \frac {1}{(-1+x) \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )} \, dx-282 \int \frac {1}{x \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )} \, dx \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(43\) vs. \(2(21)=42\).
Time = 0.22 (sec) , antiderivative size = 43, normalized size of antiderivative = 2.05 \[ \int \frac {282-48 x+2 x^2+\left (-24 x+26 x^2-2 x^3+\left (24 x-26 x^2+2 x^3\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {1-2 x+x^2}{x^2}\right )\right )}{x-x^2+\left (-x+x^2\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )} \, dx=2 \left (\frac {141}{2} \log \left (1-\log \left (\frac {(-1+x)^2}{x^2}\right )\right )+\frac {1}{2} (-24+x) x \log \left (-1+\log \left (\frac {(-1+x)^2}{x^2}\right )\right )\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. \(58\) vs. \(2(21)=42\).
Time = 1.65 (sec) , antiderivative size = 59, normalized size of antiderivative = 2.81
method | result | size |
parallelrisch | \(\ln \left (\ln \left (\frac {x^{2}-2 x +1}{x^{2}}\right )-1\right ) x^{2}-24 \ln \left (\ln \left (\frac {x^{2}-2 x +1}{x^{2}}\right )-1\right ) x +141 \ln \left (\ln \left (\frac {x^{2}-2 x +1}{x^{2}}\right )-1\right )\) | \(59\) |
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Time = 0.25 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.19 \[ \int \frac {282-48 x+2 x^2+\left (-24 x+26 x^2-2 x^3+\left (24 x-26 x^2+2 x^3\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {1-2 x+x^2}{x^2}\right )\right )}{x-x^2+\left (-x+x^2\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )} \, dx={\left (x^{2} - 24 \, x + 141\right )} \log \left (\log \left (\frac {x^{2} - 2 \, x + 1}{x^{2}}\right ) - 1\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 46 vs. \(2 (17) = 34\).
Time = 0.37 (sec) , antiderivative size = 46, normalized size of antiderivative = 2.19 \[ \int \frac {282-48 x+2 x^2+\left (-24 x+26 x^2-2 x^3+\left (24 x-26 x^2+2 x^3\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {1-2 x+x^2}{x^2}\right )\right )}{x-x^2+\left (-x+x^2\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )} \, dx=\left (x^{2} - 24 x + \frac {23}{6}\right ) \log {\left (\log {\left (\frac {x^{2} - 2 x + 1}{x^{2}} \right )} - 1 \right )} + \frac {823 \log {\left (\log {\left (\frac {x^{2} - 2 x + 1}{x^{2}} \right )} - 1 \right )}}{6} \]
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Time = 0.25 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.67 \[ \int \frac {282-48 x+2 x^2+\left (-24 x+26 x^2-2 x^3+\left (24 x-26 x^2+2 x^3\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {1-2 x+x^2}{x^2}\right )\right )}{x-x^2+\left (-x+x^2\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )} \, dx={\left (x^{2} - 24 \, x\right )} \log \left (2 \, \log \left (x - 1\right ) - 2 \, \log \left (x\right ) - 1\right ) + 141 \, \log \left (\log \left (x - 1\right ) - \log \left (x\right ) - \frac {1}{2}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 45 vs. \(2 (19) = 38\).
Time = 0.62 (sec) , antiderivative size = 45, normalized size of antiderivative = 2.14 \[ \int \frac {282-48 x+2 x^2+\left (-24 x+26 x^2-2 x^3+\left (24 x-26 x^2+2 x^3\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {1-2 x+x^2}{x^2}\right )\right )}{x-x^2+\left (-x+x^2\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )} \, dx={\left (x^{2} - 24 \, x\right )} \log \left (\log \left (\frac {x^{2} - 2 \, x + 1}{x^{2}}\right ) - 1\right ) + 141 \, \log \left (\log \left (x^{2} - 2 \, x + 1\right ) - \log \left (x^{2}\right ) - 1\right ) \]
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Time = 15.85 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.19 \[ \int \frac {282-48 x+2 x^2+\left (-24 x+26 x^2-2 x^3+\left (24 x-26 x^2+2 x^3\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )\right ) \log \left (-1+\log \left (\frac {1-2 x+x^2}{x^2}\right )\right )}{x-x^2+\left (-x+x^2\right ) \log \left (\frac {1-2 x+x^2}{x^2}\right )} \, dx=\ln \left (\ln \left (\frac {x^2-2\,x+1}{x^2}\right )-1\right )\,\left (x^2-24\,x+141\right ) \]
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