Integrand size = 127, antiderivative size = 23 \[ \int \frac {e^{2+2 x} \left (216+180 x+36 x^2\right )+e^{3+3 x} \left (-24-36 x-18 x^2-3 x^3\right )}{1728+e^{1+x} \left (2592+2160 x+432 x^2\right )+e^{2+2 x} \left (1296+2160 x+1332 x^2+360 x^3+36 x^4\right )+e^{3+3 x} \left (216+540 x+558 x^2+305 x^3+93 x^4+15 x^5+x^6\right )} \, dx=\frac {3}{2 \left (3+x+\frac {12 e^{-1-x}}{2+x}\right )^2} \]
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\[ \int \frac {e^{2+2 x} \left (216+180 x+36 x^2\right )+e^{3+3 x} \left (-24-36 x-18 x^2-3 x^3\right )}{1728+e^{1+x} \left (2592+2160 x+432 x^2\right )+e^{2+2 x} \left (1296+2160 x+1332 x^2+360 x^3+36 x^4\right )+e^{3+3 x} \left (216+540 x+558 x^2+305 x^3+93 x^4+15 x^5+x^6\right )} \, dx=\int \frac {e^{2+2 x} \left (216+180 x+36 x^2\right )+e^{3+3 x} \left (-24-36 x-18 x^2-3 x^3\right )}{1728+e^{1+x} \left (2592+2160 x+432 x^2\right )+e^{2+2 x} \left (1296+2160 x+1332 x^2+360 x^3+36 x^4\right )+e^{3+3 x} \left (216+540 x+558 x^2+305 x^3+93 x^4+15 x^5+x^6\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {3 e^{2+2 x} (2+x) \left (-e^{1+x} (2+x)^2+12 (3+x)\right )}{\left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^3} \, dx \\ & = 3 \int \frac {e^{2+2 x} (2+x) \left (-e^{1+x} (2+x)^2+12 (3+x)\right )}{\left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^3} \, dx \\ & = 3 \int \left (-\frac {e^{2+2 x} (2+x)^2}{(3+x) \left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^2}+\frac {12 e^{2+2 x} \left (22+25 x+9 x^2+x^3\right )}{(3+x) \left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3}\right ) \, dx \\ & = -\left (3 \int \frac {e^{2+2 x} (2+x)^2}{(3+x) \left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^2} \, dx\right )+36 \int \frac {e^{2+2 x} \left (22+25 x+9 x^2+x^3\right )}{(3+x) \left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3} \, dx \\ & = -\left (3 \int \frac {e^{2+2 x} (2+x)^2}{(3+x) \left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^2} \, dx\right )+36 \int \frac {e^{2+2 x} \left (22+25 x+9 x^2+x^3\right )}{(3+x) \left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^3} \, dx \\ & = -\left (3 \int \left (\frac {e^{2+2 x}}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^2}+\frac {e^{2+2 x} x}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^2}+\frac {e^{2+2 x}}{(3+x) \left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^2}\right ) \, dx\right )+36 \int \left (\frac {7 e^{2+2 x}}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3}+\frac {6 e^{2+2 x} x}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3}+\frac {e^{2+2 x} x^2}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3}+\frac {e^{2+2 x}}{(3+x) \left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3}\right ) \, dx \\ & = -\left (3 \int \frac {e^{2+2 x}}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^2} \, dx\right )-3 \int \frac {e^{2+2 x} x}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^2} \, dx-3 \int \frac {e^{2+2 x}}{(3+x) \left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^2} \, dx+36 \int \frac {e^{2+2 x} x^2}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3} \, dx+36 \int \frac {e^{2+2 x}}{(3+x) \left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3} \, dx+216 \int \frac {e^{2+2 x} x}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3} \, dx+252 \int \frac {e^{2+2 x}}{\left (12+6 e^{1+x}+5 e^{1+x} x+e^{1+x} x^2\right )^3} \, dx \\ & = -\left (3 \int \frac {e^{2+2 x}}{\left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^2} \, dx\right )-3 \int \frac {e^{2+2 x} x}{\left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^2} \, dx-3 \int \frac {e^{2+2 x}}{(3+x) \left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^2} \, dx+36 \int \frac {e^{2+2 x} x^2}{\left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^3} \, dx+36 \int \frac {e^{2+2 x}}{(3+x) \left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^3} \, dx+216 \int \frac {e^{2+2 x} x}{\left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^3} \, dx+252 \int \frac {e^{2+2 x}}{\left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^3} \, dx \\ \end{align*}
Time = 11.86 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.48 \[ \int \frac {e^{2+2 x} \left (216+180 x+36 x^2\right )+e^{3+3 x} \left (-24-36 x-18 x^2-3 x^3\right )}{1728+e^{1+x} \left (2592+2160 x+432 x^2\right )+e^{2+2 x} \left (1296+2160 x+1332 x^2+360 x^3+36 x^4\right )+e^{3+3 x} \left (216+540 x+558 x^2+305 x^3+93 x^4+15 x^5+x^6\right )} \, dx=\frac {3 e^{2+2 x} (2+x)^2}{2 \left (12+e^{1+x} \left (6+5 x+x^2\right )\right )^2} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(41\) vs. \(2(20)=40\).
Time = 1.44 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.83
method | result | size |
risch | \(\frac {3 \left (x^{2}+4 x +4\right ) {\mathrm e}^{2+2 x}}{2 \left (x^{2} {\mathrm e}^{1+x}+5 x \,{\mathrm e}^{1+x}+6 \,{\mathrm e}^{1+x}+12\right )^{2}}\) | \(42\) |
norman | \(\frac {6 \,{\mathrm e}^{2+2 x}+6 x \,{\mathrm e}^{2+2 x}+\frac {3 x^{2} {\mathrm e}^{2+2 x}}{2}}{\left (x^{2} {\mathrm e}^{1+x}+5 x \,{\mathrm e}^{1+x}+6 \,{\mathrm e}^{1+x}+12\right )^{2}}\) | \(56\) |
parallelrisch | \(\frac {3 x^{2} {\mathrm e}^{2+2 x}+12 x \,{\mathrm e}^{2+2 x}+12 \,{\mathrm e}^{2+2 x}}{2 x^{4} {\mathrm e}^{2+2 x}+20 x^{3} {\mathrm e}^{2+2 x}+74 x^{2} {\mathrm e}^{2+2 x}+48 x^{2} {\mathrm e}^{1+x}+120 x \,{\mathrm e}^{2+2 x}+240 x \,{\mathrm e}^{1+x}+72 \,{\mathrm e}^{2+2 x}+288 \,{\mathrm e}^{1+x}+288}\) | \(107\) |
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Leaf count of result is larger than twice the leaf count of optimal. 59 vs. \(2 (20) = 40\).
Time = 0.26 (sec) , antiderivative size = 59, normalized size of antiderivative = 2.57 \[ \int \frac {e^{2+2 x} \left (216+180 x+36 x^2\right )+e^{3+3 x} \left (-24-36 x-18 x^2-3 x^3\right )}{1728+e^{1+x} \left (2592+2160 x+432 x^2\right )+e^{2+2 x} \left (1296+2160 x+1332 x^2+360 x^3+36 x^4\right )+e^{3+3 x} \left (216+540 x+558 x^2+305 x^3+93 x^4+15 x^5+x^6\right )} \, dx=\frac {3 \, {\left (x^{2} + 4 \, x + 4\right )} e^{\left (2 \, x + 2\right )}}{2 \, {\left ({\left (x^{4} + 10 \, x^{3} + 37 \, x^{2} + 60 \, x + 36\right )} e^{\left (2 \, x + 2\right )} + 24 \, {\left (x^{2} + 5 \, x + 6\right )} e^{\left (x + 1\right )} + 144\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 100 vs. \(2 (19) = 38\).
Time = 0.30 (sec) , antiderivative size = 100, normalized size of antiderivative = 4.35 \[ \int \frac {e^{2+2 x} \left (216+180 x+36 x^2\right )+e^{3+3 x} \left (-24-36 x-18 x^2-3 x^3\right )}{1728+e^{1+x} \left (2592+2160 x+432 x^2\right )+e^{2+2 x} \left (1296+2160 x+1332 x^2+360 x^3+36 x^4\right )+e^{3+3 x} \left (216+540 x+558 x^2+305 x^3+93 x^4+15 x^5+x^6\right )} \, dx=\frac {\left (- 36 x^{2} - 180 x - 216\right ) e^{x + 1} - 216}{144 x^{2} + 864 x + \left (24 x^{4} + 264 x^{3} + 1080 x^{2} + 1944 x + 1296\right ) e^{x + 1} + \left (x^{6} + 16 x^{5} + 106 x^{4} + 372 x^{3} + 729 x^{2} + 756 x + 324\right ) e^{2 x + 2} + 1296} + \frac {3}{2 x^{2} + 12 x + 18} \]
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Leaf count of result is larger than twice the leaf count of optimal. 81 vs. \(2 (20) = 40\).
Time = 0.28 (sec) , antiderivative size = 81, normalized size of antiderivative = 3.52 \[ \int \frac {e^{2+2 x} \left (216+180 x+36 x^2\right )+e^{3+3 x} \left (-24-36 x-18 x^2-3 x^3\right )}{1728+e^{1+x} \left (2592+2160 x+432 x^2\right )+e^{2+2 x} \left (1296+2160 x+1332 x^2+360 x^3+36 x^4\right )+e^{3+3 x} \left (216+540 x+558 x^2+305 x^3+93 x^4+15 x^5+x^6\right )} \, dx=\frac {3 \, {\left (x^{2} e^{2} + 4 \, x e^{2} + 4 \, e^{2}\right )} e^{\left (2 \, x\right )}}{2 \, {\left ({\left (x^{4} e^{2} + 10 \, x^{3} e^{2} + 37 \, x^{2} e^{2} + 60 \, x e^{2} + 36 \, e^{2}\right )} e^{\left (2 \, x\right )} + 24 \, {\left (x^{2} e + 5 \, x e + 6 \, e\right )} e^{x} + 144\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 105 vs. \(2 (20) = 40\).
Time = 0.31 (sec) , antiderivative size = 105, normalized size of antiderivative = 4.57 \[ \int \frac {e^{2+2 x} \left (216+180 x+36 x^2\right )+e^{3+3 x} \left (-24-36 x-18 x^2-3 x^3\right )}{1728+e^{1+x} \left (2592+2160 x+432 x^2\right )+e^{2+2 x} \left (1296+2160 x+1332 x^2+360 x^3+36 x^4\right )+e^{3+3 x} \left (216+540 x+558 x^2+305 x^3+93 x^4+15 x^5+x^6\right )} \, dx=\frac {3 \, {\left (x^{2} e^{\left (2 \, x + 2\right )} + 4 \, x e^{\left (2 \, x + 2\right )} + 4 \, e^{\left (2 \, x + 2\right )}\right )}}{2 \, {\left (x^{4} e^{\left (2 \, x + 2\right )} + 10 \, x^{3} e^{\left (2 \, x + 2\right )} + 37 \, x^{2} e^{\left (2 \, x + 2\right )} + 24 \, x^{2} e^{\left (x + 1\right )} + 60 \, x e^{\left (2 \, x + 2\right )} + 120 \, x e^{\left (x + 1\right )} + 36 \, e^{\left (2 \, x + 2\right )} + 144 \, e^{\left (x + 1\right )} + 144\right )}} \]
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Timed out. \[ \int \frac {e^{2+2 x} \left (216+180 x+36 x^2\right )+e^{3+3 x} \left (-24-36 x-18 x^2-3 x^3\right )}{1728+e^{1+x} \left (2592+2160 x+432 x^2\right )+e^{2+2 x} \left (1296+2160 x+1332 x^2+360 x^3+36 x^4\right )+e^{3+3 x} \left (216+540 x+558 x^2+305 x^3+93 x^4+15 x^5+x^6\right )} \, dx=\int \frac {{\mathrm {e}}^{2\,x+2}\,\left (36\,x^2+180\,x+216\right )-{\mathrm {e}}^{3\,x+3}\,\left (3\,x^3+18\,x^2+36\,x+24\right )}{{\mathrm {e}}^{x+1}\,\left (432\,x^2+2160\,x+2592\right )+{\mathrm {e}}^{2\,x+2}\,\left (36\,x^4+360\,x^3+1332\,x^2+2160\,x+1296\right )+{\mathrm {e}}^{3\,x+3}\,\left (x^6+15\,x^5+93\,x^4+305\,x^3+558\,x^2+540\,x+216\right )+1728} \,d x \]
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