Integrand size = 7, antiderivative size = 14 \[ \int \left (-25-2 e^2\right ) \, dx=25 (2-x)-2 e^2 x \]
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Time = 0.00 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.71, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {8} \[ \int \left (-25-2 e^2\right ) \, dx=-\left (\left (25+2 e^2\right ) x\right ) \]
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Rule 8
Rubi steps \begin{align*} \text {integral}& = -\left (\left (25+2 e^2\right ) x\right ) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.71 \[ \int \left (-25-2 e^2\right ) \, dx=-25 x-2 e^2 x \]
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Time = 0.02 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.71
method | result | size |
risch | \(-2 \,{\mathrm e}^{2} x -25 x\) | \(10\) |
default | \(x \left (-2 \,{\mathrm e}^{2}-25\right )\) | \(11\) |
norman | \(x \left (-2 \,{\mathrm e}^{2}-25\right )\) | \(11\) |
parallelrisch | \(x \left (-2 \,{\mathrm e}^{2}-25\right )\) | \(11\) |
parts | \(-2 \,{\mathrm e}^{2} x -25 x\) | \(12\) |
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none
Time = 0.25 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.64 \[ \int \left (-25-2 e^2\right ) \, dx=-2 \, x e^{2} - 25 \, x \]
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Time = 0.02 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.57 \[ \int \left (-25-2 e^2\right ) \, dx=x \left (-25 - 2 e^{2}\right ) \]
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none
Time = 0.19 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.64 \[ \int \left (-25-2 e^2\right ) \, dx=-x {\left (2 \, e^{2} + 25\right )} \]
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none
Time = 0.28 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.64 \[ \int \left (-25-2 e^2\right ) \, dx=-x {\left (2 \, e^{2} + 25\right )} \]
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Time = 0.00 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.64 \[ \int \left (-25-2 e^2\right ) \, dx=-x\,\left (2\,{\mathrm {e}}^2+25\right ) \]
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