Integrand size = 73, antiderivative size = 21 \[ \int \frac {e^{-2+e^{x+x^2}-6 x+x^2} \left (1-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )+\left (-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )\right ) \log (x)\right )}{x} \, dx=e^{-2+e^{x+x^2}+(-6+x) x} (1+\log (x)) \]
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Leaf count is larger than twice the leaf count of optimal. \(95\) vs. \(2(21)=42\).
Time = 0.61 (sec) , antiderivative size = 95, normalized size of antiderivative = 4.52, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.014, Rules used = {2326} \[ \int \frac {e^{-2+e^{x+x^2}-6 x+x^2} \left (1-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )+\left (-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )\right ) \log (x)\right )}{x} \, dx=\frac {e^{x^2+e^{x^2+x}-6 x-2} \left (-2 x^2-e^{x^2+x} \left (2 x^2+x\right )+\left (-2 x^2-e^{x^2+x} \left (2 x^2+x\right )+6 x\right ) \log (x)+6 x\right )}{x \left (-e^{x^2+x} (2 x+1)-2 x+6\right )} \]
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Rule 2326
Rubi steps \begin{align*} \text {integral}& = \frac {e^{-2+e^{x+x^2}-6 x+x^2} \left (6 x-2 x^2-e^{x+x^2} \left (x+2 x^2\right )+\left (6 x-2 x^2-e^{x+x^2} \left (x+2 x^2\right )\right ) \log (x)\right )}{x \left (6-2 x-e^{x+x^2} (1+2 x)\right )} \\ \end{align*}
Time = 0.43 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.05 \[ \int \frac {e^{-2+e^{x+x^2}-6 x+x^2} \left (1-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )+\left (-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )\right ) \log (x)\right )}{x} \, dx=e^{-2+e^{x+x^2}-6 x+x^2} (1+\log (x)) \]
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Time = 0.14 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00
method | result | size |
risch | \(\left (\ln \left (x \right )+1\right ) {\mathrm e}^{{\mathrm e}^{\left (1+x \right ) x}+x^{2}-6 x -2}\) | \(21\) |
parallelrisch | \(\ln \left (x \right ) {\mathrm e}^{{\mathrm e}^{x^{2}+x}+x^{2}-6 x -2}+{\mathrm e}^{{\mathrm e}^{x^{2}+x}+x^{2}-6 x -2}\) | \(35\) |
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Time = 0.28 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.95 \[ \int \frac {e^{-2+e^{x+x^2}-6 x+x^2} \left (1-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )+\left (-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )\right ) \log (x)\right )}{x} \, dx={\left (\log \left (x\right ) + 1\right )} e^{\left (x^{2} - 6 \, x + e^{\left (x^{2} + x\right )} - 2\right )} \]
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Time = 129.13 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.95 \[ \int \frac {e^{-2+e^{x+x^2}-6 x+x^2} \left (1-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )+\left (-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )\right ) \log (x)\right )}{x} \, dx=\left (\log {\left (x \right )} + 1\right ) e^{x^{2} - 6 x + e^{x^{2} + x} - 2} \]
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Time = 0.28 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.95 \[ \int \frac {e^{-2+e^{x+x^2}-6 x+x^2} \left (1-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )+\left (-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )\right ) \log (x)\right )}{x} \, dx={\left (\log \left (x\right ) + 1\right )} e^{\left (x^{2} - 6 \, x + e^{\left (x^{2} + x\right )} - 2\right )} \]
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\[ \int \frac {e^{-2+e^{x+x^2}-6 x+x^2} \left (1-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )+\left (-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )\right ) \log (x)\right )}{x} \, dx=\int { \frac {{\left (2 \, x^{2} + {\left (2 \, x^{2} + x\right )} e^{\left (x^{2} + x\right )} + {\left (2 \, x^{2} + {\left (2 \, x^{2} + x\right )} e^{\left (x^{2} + x\right )} - 6 \, x\right )} \log \left (x\right ) - 6 \, x + 1\right )} e^{\left (x^{2} - 6 \, x + e^{\left (x^{2} + x\right )} - 2\right )}}{x} \,d x } \]
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Time = 17.50 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.10 \[ \int \frac {e^{-2+e^{x+x^2}-6 x+x^2} \left (1-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )+\left (-6 x+2 x^2+e^{x+x^2} \left (x+2 x^2\right )\right ) \log (x)\right )}{x} \, dx={\mathrm {e}}^{-6\,x}\,{\mathrm {e}}^{x^2}\,{\mathrm {e}}^{-2}\,{\mathrm {e}}^{{\mathrm {e}}^{x^2}\,{\mathrm {e}}^x}\,\left (\ln \left (x\right )+1\right ) \]
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