Integrand size = 61, antiderivative size = 18 \[ \int \frac {e^{\frac {4+4 x^2+4 e^{78} x^2+x^4+e^{39} \left (8 x+4 x^3\right )}{x^2}} \left (-8+2 x^4+e^{39} \left (-8 x+4 x^3\right )\right )}{x^3} \, dx=-1+e^{\left (2 e^{39}+\frac {2}{x}+x\right )^2} \]
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Time = 0.43 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.06, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.049, Rules used = {6820, 12, 6838} \[ \int \frac {e^{\frac {4+4 x^2+4 e^{78} x^2+x^4+e^{39} \left (8 x+4 x^3\right )}{x^2}} \left (-8+2 x^4+e^{39} \left (-8 x+4 x^3\right )\right )}{x^3} \, dx=e^{\frac {\left (x^2+2 e^{39} x+2\right )^2}{x^2}} \]
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Rule 12
Rule 6820
Rule 6838
Rubi steps \begin{align*} \text {integral}& = \int \frac {2 e^{\frac {\left (2+2 e^{39} x+x^2\right )^2}{x^2}} \left (2-x^2\right ) \left (-2-2 e^{39} x-x^2\right )}{x^3} \, dx \\ & = 2 \int \frac {e^{\frac {\left (2+2 e^{39} x+x^2\right )^2}{x^2}} \left (2-x^2\right ) \left (-2-2 e^{39} x-x^2\right )}{x^3} \, dx \\ & = e^{\frac {\left (2+2 e^{39} x+x^2\right )^2}{x^2}} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.06 \[ \int \frac {e^{\frac {4+4 x^2+4 e^{78} x^2+x^4+e^{39} \left (8 x+4 x^3\right )}{x^2}} \left (-8+2 x^4+e^{39} \left (-8 x+4 x^3\right )\right )}{x^3} \, dx=e^{\frac {\left (2+2 e^{39} x+x^2\right )^2}{x^2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(34\) vs. \(2(16)=32\).
Time = 0.16 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.94
method | result | size |
risch | \({\mathrm e}^{\frac {4 \,{\mathrm e}^{39} x^{3}+x^{4}+4 x^{2} {\mathrm e}^{78}+8 \,{\mathrm e}^{39} x +4 x^{2}+4}{x^{2}}}\) | \(35\) |
gosper | \({\mathrm e}^{\frac {4 \,{\mathrm e}^{39} x^{3}+x^{4}+4 x^{2} {\mathrm e}^{78}+8 \,{\mathrm e}^{39} x +4 x^{2}+4}{x^{2}}}\) | \(37\) |
norman | \({\mathrm e}^{\frac {4 x^{2} {\mathrm e}^{78}+\left (4 x^{3}+8 x \right ) {\mathrm e}^{39}+x^{4}+4 x^{2}+4}{x^{2}}}\) | \(37\) |
parallelrisch | \({\mathrm e}^{\frac {4 x^{2} {\mathrm e}^{78}+\left (4 x^{3}+8 x \right ) {\mathrm e}^{39}+x^{4}+4 x^{2}+4}{x^{2}}}\) | \(37\) |
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Leaf count of result is larger than twice the leaf count of optimal. 33 vs. \(2 (16) = 32\).
Time = 0.25 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.83 \[ \int \frac {e^{\frac {4+4 x^2+4 e^{78} x^2+x^4+e^{39} \left (8 x+4 x^3\right )}{x^2}} \left (-8+2 x^4+e^{39} \left (-8 x+4 x^3\right )\right )}{x^3} \, dx=e^{\left (\frac {x^{4} + 4 \, x^{2} e^{78} + 4 \, x^{2} + 4 \, {\left (x^{3} + 2 \, x\right )} e^{39} + 4}{x^{2}}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 34 vs. \(2 (14) = 28\).
Time = 0.10 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.89 \[ \int \frac {e^{\frac {4+4 x^2+4 e^{78} x^2+x^4+e^{39} \left (8 x+4 x^3\right )}{x^2}} \left (-8+2 x^4+e^{39} \left (-8 x+4 x^3\right )\right )}{x^3} \, dx=e^{\frac {x^{4} + 4 x^{2} + 4 x^{2} e^{78} + \left (4 x^{3} + 8 x\right ) e^{39} + 4}{x^{2}}} \]
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none
Time = 0.63 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.50 \[ \int \frac {e^{\frac {4+4 x^2+4 e^{78} x^2+x^4+e^{39} \left (8 x+4 x^3\right )}{x^2}} \left (-8+2 x^4+e^{39} \left (-8 x+4 x^3\right )\right )}{x^3} \, dx=e^{\left (x^{2} + 4 \, x e^{39} + \frac {8 \, e^{39}}{x} + \frac {4}{x^{2}} + 4 \, e^{78} + 4\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 34 vs. \(2 (16) = 32\).
Time = 0.28 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.89 \[ \int \frac {e^{\frac {4+4 x^2+4 e^{78} x^2+x^4+e^{39} \left (8 x+4 x^3\right )}{x^2}} \left (-8+2 x^4+e^{39} \left (-8 x+4 x^3\right )\right )}{x^3} \, dx=e^{\left (\frac {x^{4} + 4 \, x^{3} e^{39} + 4 \, x^{2} e^{78} + 4 \, x^{2} + 8 \, x e^{39} + 4}{x^{2}}\right )} \]
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Time = 9.40 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.78 \[ \int \frac {e^{\frac {4+4 x^2+4 e^{78} x^2+x^4+e^{39} \left (8 x+4 x^3\right )}{x^2}} \left (-8+2 x^4+e^{39} \left (-8 x+4 x^3\right )\right )}{x^3} \, dx={\mathrm {e}}^{\frac {8\,{\mathrm {e}}^{39}}{x}}\,{\mathrm {e}}^{4\,{\mathrm {e}}^{78}}\,{\mathrm {e}}^{x^2}\,{\mathrm {e}}^4\,{\mathrm {e}}^{\frac {4}{x^2}}\,{\mathrm {e}}^{4\,x\,{\mathrm {e}}^{39}} \]
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