Integrand size = 76, antiderivative size = 26 \[ \int \frac {125-125 \log \left (\frac {x}{e}\right )+(-175+250 x) \log ^2\left (\frac {x}{e}\right )}{150 x^2+\left (420 x^2-300 x^3\right ) \log \left (\frac {x}{e}\right )+\left (294 x^2-420 x^3+150 x^4\right ) \log ^2\left (\frac {x}{e}\right )} \, dx=\frac {5}{2 x \left (\frac {21}{5}-3 x+\frac {3}{\log \left (\frac {x}{e}\right )}\right )} \]
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\[ \int \frac {125-125 \log \left (\frac {x}{e}\right )+(-175+250 x) \log ^2\left (\frac {x}{e}\right )}{150 x^2+\left (420 x^2-300 x^3\right ) \log \left (\frac {x}{e}\right )+\left (294 x^2-420 x^3+150 x^4\right ) \log ^2\left (\frac {x}{e}\right )} \, dx=\int \frac {125-125 \log \left (\frac {x}{e}\right )+(-175+250 x) \log ^2\left (\frac {x}{e}\right )}{150 x^2+\left (420 x^2-300 x^3\right ) \log \left (\frac {x}{e}\right )+\left (294 x^2-420 x^3+150 x^4\right ) \log ^2\left (\frac {x}{e}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {25 \left (3+10 x+(9-20 x) \log (x)+(-7+10 x) \log ^2(x)\right )}{6 x^2 (2-5 x+(-7+5 x) \log (x))^2} \, dx \\ & = \frac {25}{6} \int \frac {3+10 x+(9-20 x) \log (x)+(-7+10 x) \log ^2(x)}{x^2 (2-5 x+(-7+5 x) \log (x))^2} \, dx \\ & = \frac {25}{6} \int \left (\frac {-7+10 x}{x^2 (-7+5 x)^2}+\frac {5 \left (49-45 x+25 x^2\right )}{x^2 (-7+5 x)^2 (2-5 x-7 \log (x)+5 x \log (x))^2}+\frac {5 (-7+15 x)}{x^2 (-7+5 x)^2 (2-5 x-7 \log (x)+5 x \log (x))}\right ) \, dx \\ & = \frac {25}{6} \int \frac {-7+10 x}{x^2 (-7+5 x)^2} \, dx+\frac {125}{6} \int \frac {49-45 x+25 x^2}{x^2 (-7+5 x)^2 (2-5 x-7 \log (x)+5 x \log (x))^2} \, dx+\frac {125}{6} \int \frac {-7+15 x}{x^2 (-7+5 x)^2 (2-5 x-7 \log (x)+5 x \log (x))} \, dx \\ & = \frac {25}{6 (7-5 x) x}+\frac {125}{6} \int \left (\frac {1}{x^2 (2-5 x-7 \log (x)+5 x \log (x))^2}+\frac {25}{49 x (2-5 x-7 \log (x)+5 x \log (x))^2}+\frac {125}{7 (-7+5 x)^2 (2-5 x-7 \log (x)+5 x \log (x))^2}-\frac {125}{49 (-7+5 x) (2-5 x-7 \log (x)+5 x \log (x))^2}\right ) \, dx+\frac {125}{6} \int \left (-\frac {1}{7 x^2 (2-5 x-7 \log (x)+5 x \log (x))}+\frac {5}{49 x (2-5 x-7 \log (x)+5 x \log (x))}+\frac {50}{7 (-7+5 x)^2 (2-5 x-7 \log (x)+5 x \log (x))}-\frac {25}{49 (-7+5 x) (2-5 x-7 \log (x)+5 x \log (x))}\right ) \, dx \\ & = \frac {25}{6 (7-5 x) x}+\frac {625}{294} \int \frac {1}{x (2-5 x-7 \log (x)+5 x \log (x))} \, dx-\frac {125}{42} \int \frac {1}{x^2 (2-5 x-7 \log (x)+5 x \log (x))} \, dx+\frac {3125}{294} \int \frac {1}{x (2-5 x-7 \log (x)+5 x \log (x))^2} \, dx-\frac {3125}{294} \int \frac {1}{(-7+5 x) (2-5 x-7 \log (x)+5 x \log (x))} \, dx+\frac {125}{6} \int \frac {1}{x^2 (2-5 x-7 \log (x)+5 x \log (x))^2} \, dx-\frac {15625}{294} \int \frac {1}{(-7+5 x) (2-5 x-7 \log (x)+5 x \log (x))^2} \, dx+\frac {3125}{21} \int \frac {1}{(-7+5 x)^2 (2-5 x-7 \log (x)+5 x \log (x))} \, dx+\frac {15625}{42} \int \frac {1}{(-7+5 x)^2 (2-5 x-7 \log (x)+5 x \log (x))^2} \, dx \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.08 \[ \int \frac {125-125 \log \left (\frac {x}{e}\right )+(-175+250 x) \log ^2\left (\frac {x}{e}\right )}{150 x^2+\left (420 x^2-300 x^3\right ) \log \left (\frac {x}{e}\right )+\left (294 x^2-420 x^3+150 x^4\right ) \log ^2\left (\frac {x}{e}\right )} \, dx=\frac {25 (1-\log (x))}{6 x (2-5 x+(-7+5 x) \log (x))} \]
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Time = 0.21 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.08
method | result | size |
default | \(\frac {\frac {25}{6}-\frac {25 \ln \left (x \right )}{6}}{x \left (5 x \ln \left (x \right )-5 x -7 \ln \left (x \right )+2\right )}\) | \(28\) |
norman | \(-\frac {25 \ln \left ({\mathrm e}^{-1} x \right )}{6 \left (5 \ln \left ({\mathrm e}^{-1} x \right ) x -7 \ln \left ({\mathrm e}^{-1} x \right )-5\right ) x}\) | \(36\) |
parallelrisch | \(-\frac {25 \ln \left ({\mathrm e}^{-1} x \right )}{6 \left (5 \ln \left ({\mathrm e}^{-1} x \right ) x -7 \ln \left ({\mathrm e}^{-1} x \right )-5\right ) x}\) | \(36\) |
risch | \(-\frac {25}{6 x \left (5 x -7\right )}-\frac {125}{6 x \left (5 x -7\right ) \left (5 \ln \left ({\mathrm e}^{-1} x \right ) x -7 \ln \left ({\mathrm e}^{-1} x \right )-5\right )}\) | \(45\) |
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Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.08 \[ \int \frac {125-125 \log \left (\frac {x}{e}\right )+(-175+250 x) \log ^2\left (\frac {x}{e}\right )}{150 x^2+\left (420 x^2-300 x^3\right ) \log \left (\frac {x}{e}\right )+\left (294 x^2-420 x^3+150 x^4\right ) \log ^2\left (\frac {x}{e}\right )} \, dx=-\frac {25 \, \log \left (x e^{\left (-1\right )}\right )}{6 \, {\left ({\left (5 \, x^{2} - 7 \, x\right )} \log \left (x e^{\left (-1\right )}\right ) - 5 \, x\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 41 vs. \(2 (19) = 38\).
Time = 0.11 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.58 \[ \int \frac {125-125 \log \left (\frac {x}{e}\right )+(-175+250 x) \log ^2\left (\frac {x}{e}\right )}{150 x^2+\left (420 x^2-300 x^3\right ) \log \left (\frac {x}{e}\right )+\left (294 x^2-420 x^3+150 x^4\right ) \log ^2\left (\frac {x}{e}\right )} \, dx=- \frac {125}{- 150 x^{2} + 210 x + \left (150 x^{3} - 420 x^{2} + 294 x\right ) \log {\left (\frac {x}{e} \right )}} - \frac {25}{30 x^{2} - 42 x} \]
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Time = 0.22 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.15 \[ \int \frac {125-125 \log \left (\frac {x}{e}\right )+(-175+250 x) \log ^2\left (\frac {x}{e}\right )}{150 x^2+\left (420 x^2-300 x^3\right ) \log \left (\frac {x}{e}\right )+\left (294 x^2-420 x^3+150 x^4\right ) \log ^2\left (\frac {x}{e}\right )} \, dx=\frac {25 \, {\left (\log \left (x\right ) - 1\right )}}{6 \, {\left (5 \, x^{2} - {\left (5 \, x^{2} - 7 \, x\right )} \log \left (x\right ) - 2 \, x\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 52 vs. \(2 (21) = 42\).
Time = 0.28 (sec) , antiderivative size = 52, normalized size of antiderivative = 2.00 \[ \int \frac {125-125 \log \left (\frac {x}{e}\right )+(-175+250 x) \log ^2\left (\frac {x}{e}\right )}{150 x^2+\left (420 x^2-300 x^3\right ) \log \left (\frac {x}{e}\right )+\left (294 x^2-420 x^3+150 x^4\right ) \log ^2\left (\frac {x}{e}\right )} \, dx=-\frac {125}{6 \, {\left (25 \, x^{3} \log \left (x\right ) - 25 \, x^{3} - 70 \, x^{2} \log \left (x\right ) + 45 \, x^{2} + 49 \, x \log \left (x\right ) - 14 \, x\right )}} - \frac {125}{42 \, {\left (5 \, x - 7\right )}} + \frac {25}{42 \, x} \]
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Timed out. \[ \int \frac {125-125 \log \left (\frac {x}{e}\right )+(-175+250 x) \log ^2\left (\frac {x}{e}\right )}{150 x^2+\left (420 x^2-300 x^3\right ) \log \left (\frac {x}{e}\right )+\left (294 x^2-420 x^3+150 x^4\right ) \log ^2\left (\frac {x}{e}\right )} \, dx=\int \frac {\left (250\,x-175\right )\,{\ln \left (x\,{\mathrm {e}}^{-1}\right )}^2-125\,\ln \left (x\,{\mathrm {e}}^{-1}\right )+125}{{\ln \left (x\,{\mathrm {e}}^{-1}\right )}^2\,\left (150\,x^4-420\,x^3+294\,x^2\right )+\ln \left (x\,{\mathrm {e}}^{-1}\right )\,\left (420\,x^2-300\,x^3\right )+150\,x^2} \,d x \]
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