Integrand size = 53, antiderivative size = 29 \[ \int \frac {4-6 e+e^4+x^2+e^x x^2}{-4 x-e^4 x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx=\log \left (e^x-\frac {4+e^4-x-x^2-e (6+x)}{x}\right ) \]
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\[ \int \frac {4-6 e+e^4+x^2+e^x x^2}{-4 x-e^4 x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx=\int \frac {4-6 e+e^4+x^2+e^x x^2}{-4 x-e^4 x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {4-6 e+e^4+x^2+e^x x^2}{\left (-4-e^4\right ) x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx \\ & = \int \frac {4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )+x^2+e^x x^2}{\left (-4-e^4\right ) x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx \\ & = \int \left (1+\frac {-4+6 e-e^4-\left (4-6 e+e^4\right ) x+e x^2+x^3}{x \left (4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2\right )}\right ) \, dx \\ & = x+\int \frac {-4+6 e-e^4-\left (4-6 e+e^4\right ) x+e x^2+x^3}{x \left (4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2\right )} \, dx \\ & = x+\int \left (\frac {6 e \left (1-\frac {4+e^4}{6 e}\right )}{4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2}+\frac {-4+6 e-e^4}{x \left (4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2\right )}+\frac {e x}{4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2}+\frac {x^2}{4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2}\right ) \, dx \\ & = x+e \int \frac {x}{4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2} \, dx+\left (-4+6 e-e^4\right ) \int \frac {1}{4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2} \, dx+\left (-4+6 e-e^4\right ) \int \frac {1}{x \left (4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2\right )} \, dx+\int \frac {x^2}{4 \left (1+\frac {1}{4} e \left (-6+e^3\right )\right )-e^x x-(1+e) x-x^2} \, dx \\ \end{align*}
Time = 3.69 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.10 \[ \int \frac {4-6 e+e^4+x^2+e^x x^2}{-4 x-e^4 x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx=-\log (x)+\log \left (4-6 e+e^4-x-e x-e^x x-x^2\right ) \]
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Time = 0.07 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00
method | result | size |
parallelrisch | \(-\ln \left (x \right )+\ln \left (x \,{\mathrm e}+x^{2}+{\mathrm e}^{x} x +6 \,{\mathrm e}-{\mathrm e}^{4}+x -4\right )\) | \(29\) |
risch | \(\ln \left ({\mathrm e}^{x}-\frac {{\mathrm e}^{4}-x \,{\mathrm e}-x^{2}-6 \,{\mathrm e}-x +4}{x}\right )\) | \(31\) |
norman | \(-\ln \left (x \right )+\ln \left (-x \,{\mathrm e}-{\mathrm e}^{x} x -x^{2}+{\mathrm e}^{4}-6 \,{\mathrm e}-x +4\right )\) | \(33\) |
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Time = 0.26 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.86 \[ \int \frac {4-6 e+e^4+x^2+e^x x^2}{-4 x-e^4 x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx=\log \left (\frac {x^{2} + {\left (x + 6\right )} e + x e^{x} + x - e^{4} - 4}{x}\right ) \]
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Time = 0.12 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.90 \[ \int \frac {4-6 e+e^4+x^2+e^x x^2}{-4 x-e^4 x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx=\log {\left (e^{x} + \frac {x^{2} + x + e x - e^{4} - 4 + 6 e}{x} \right )} \]
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Time = 0.22 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97 \[ \int \frac {4-6 e+e^4+x^2+e^x x^2}{-4 x-e^4 x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx=\log \left (\frac {x^{2} + x {\left (e + 1\right )} + x e^{x} - e^{4} + 6 \, e - 4}{x}\right ) \]
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Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97 \[ \int \frac {4-6 e+e^4+x^2+e^x x^2}{-4 x-e^4 x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx=\log \left (x^{2} + x e + x e^{x} + x - e^{4} + 6 \, e - 4\right ) - \log \left (x\right ) \]
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Time = 9.35 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97 \[ \int \frac {4-6 e+e^4+x^2+e^x x^2}{-4 x-e^4 x+x^2+e^x x^2+x^3+e \left (6 x+x^2\right )} \, dx=\ln \left (x+6\,\mathrm {e}-{\mathrm {e}}^4+x\,\mathrm {e}+x\,{\mathrm {e}}^x+x^2-4\right )-\ln \left (x\right ) \]
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