Integrand size = 134, antiderivative size = 30 \[ \int \frac {-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )}{e^{2+2 e^x-2 x+2 e^2 \left (2 x-x^2\right )} x+x \log ^2(2)-2 x \log (2) \log (x)+x \log ^2(x)+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} (2 x \log (2)-2 x \log (x))} \, dx=\frac {1}{-e^{-1+e^x-(-2+x) \left (1+e^2 x\right )}-\log (2)+\log (x)} \]
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\[ \int \frac {-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )}{e^{2+2 e^x-2 x+2 e^2 \left (2 x-x^2\right )} x+x \log ^2(2)-2 x \log (2) \log (x)+x \log ^2(x)+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} (2 x \log (2)-2 x \log (x))} \, dx=\int \frac {-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )}{e^{2+2 e^x-2 x+2 e^2 \left (2 x-x^2\right )} x+x \log ^2(2)-2 x \log (2) \log (x)+x \log ^2(x)+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} (2 x \log (2)-2 x \log (x))} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{2 \left (1-2 e^2\right ) x+2 e^2 x^2} \left (-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )\right )}{x \left (e^{1+e^x}+e^{x+e^2 (-2+x) x} \log (2)-e^{x+e^2 (-2+x) x} \log (x)\right )^2} \, dx \\ & = \int \left (\exp \left (-1-e^x-x+2 \left (1-2 e^2\right ) x-e^2 (-2+x) x+2 e^2 x^2\right ) \left (-1+2 e^2+e^x-2 e^2 x\right )+\frac {\exp \left (-2 \left (1+e^x\right )+2 \left (1-2 e^2\right ) x+2 e^2 x^2\right ) \left (-1-e^x x \log (4)-4 e^2 x \log (2) \left (1-\frac {\log (4)}{e^2 \log (16)}\right )+e^2 x^2 \log (16)+2 e^x x \log (x)-2 \left (1-2 e^2\right ) x \log (x)-4 e^2 x^2 \log (x)\right )}{x}+\frac {\exp \left (-2-2 e^x+2 x+2 \left (1-2 e^2\right ) x+2 e^2 (-2+x) x+2 e^2 x^2\right ) \log ^2\left (\frac {x}{2}\right ) \left (-1-e^x x \log (2)+e^2 x^2 \log (4)+x \log (2) \left (1-\frac {e^2 \log (4)}{\log (2)}\right )+e^x x \log (x)-\left (1-2 e^2\right ) x \log (x)-2 e^2 x^2 \log (x)\right )}{x \left (e^{1+e^x}+e^{x+e^2 (-2+x) x} \log (2)-e^{x+e^2 (-2+x) x} \log (x)\right )^2}+\frac {\exp \left (-2-2 e^x+x+2 \left (1-2 e^2\right ) x+e^2 (-2+x) x+2 e^2 x^2\right ) (\log (2)-\log (x)) \left (2+e^x x \log (8)-e^2 x^2 \log (64)-x \log (8) \left (1-\frac {e^2 \log (64)}{\log (8)}\right )-3 e^x x \log (x)+3 \left (1-2 e^2\right ) x \log (x)+6 e^2 x^2 \log (x)\right )}{x \left (e^{1+e^x}+e^{x+e^2 (-2+x) x} \log (2)-e^{x+e^2 (-2+x) x} \log (x)\right )}\right ) \, dx \\ & = \int \exp \left (-1-e^x-x+2 \left (1-2 e^2\right ) x-e^2 (-2+x) x+2 e^2 x^2\right ) \left (-1+2 e^2+e^x-2 e^2 x\right ) \, dx+\int \frac {\exp \left (-2 \left (1+e^x\right )+2 \left (1-2 e^2\right ) x+2 e^2 x^2\right ) \left (-1-e^x x \log (4)-4 e^2 x \log (2) \left (1-\frac {\log (4)}{e^2 \log (16)}\right )+e^2 x^2 \log (16)+2 e^x x \log (x)-2 \left (1-2 e^2\right ) x \log (x)-4 e^2 x^2 \log (x)\right )}{x} \, dx+\int \frac {\exp \left (-2-2 e^x+2 x+2 \left (1-2 e^2\right ) x+2 e^2 (-2+x) x+2 e^2 x^2\right ) \log ^2\left (\frac {x}{2}\right ) \left (-1-e^x x \log (2)+e^2 x^2 \log (4)+x \log (2) \left (1-\frac {e^2 \log (4)}{\log (2)}\right )+e^x x \log (x)-\left (1-2 e^2\right ) x \log (x)-2 e^2 x^2 \log (x)\right )}{x \left (e^{1+e^x}+e^{x+e^2 (-2+x) x} \log (2)-e^{x+e^2 (-2+x) x} \log (x)\right )^2} \, dx+\int \frac {\exp \left (-2-2 e^x+x+2 \left (1-2 e^2\right ) x+e^2 (-2+x) x+2 e^2 x^2\right ) (\log (2)-\log (x)) \left (2+e^x x \log (8)-e^2 x^2 \log (64)-x \log (8) \left (1-\frac {e^2 \log (64)}{\log (8)}\right )-3 e^x x \log (x)+3 \left (1-2 e^2\right ) x \log (x)+6 e^2 x^2 \log (x)\right )}{x \left (e^{1+e^x}+e^{x+e^2 (-2+x) x} \log (2)-e^{x+e^2 (-2+x) x} \log (x)\right )} \, dx \\ & = -\frac {\exp \left (-2 \left (1+e^x\right )+2 \left (1-2 e^2\right ) x+2 e^2 x^2\right ) \left (e^x x \log (4)-e^2 x^2 \log (16)-\frac {4 x \log (2) \left (\log (4)-e^2 \log (16)\right )}{\log (16)}-2 e^x x \log (x)+2 \left (1-2 e^2\right ) x \log (x)+4 e^2 x^2 \log (x)\right )}{2 x \left (1-2 e^2-e^x+2 e^2 x\right )}+\int e^{-1-e^x+x+e^2 (-2+x) x} \left (-1+e^x-2 e^2 (-1+x)\right ) \, dx+\int \frac {e^{-2-2 e^x+4 x+4 e^2 (-2+x) x} \log ^2\left (\frac {x}{2}\right ) \left (-1+e^2 x^2 \log (4)+x \left (\log (2)-e^x \log (2)-e^2 \log (4)\right )-\left (1-e^x+2 e^2 (-1+x)\right ) x \log (x)\right )}{x \left (e^{1+e^x}+e^{x+e^2 (-2+x) x} \log (2)-e^{x+e^2 (-2+x) x} \log (x)\right )^2} \, dx+\int \frac {e^{-2-2 e^x+3 x+3 e^2 (-2+x) x} (\log (2)-\log (x)) \left (2-e^2 x^2 \log (64)+x \left (-\log (8)+e^x \log (8)+e^2 \log (64)\right )+3 \left (1-e^x+2 e^2 (-1+x)\right ) x \log (x)\right )}{x \left (e^{1+e^x}+e^{x+e^2 (-2+x) x} \log (2)-e^{x+e^2 (-2+x) x} \log (x)\right )} \, dx \\ & = \text {Too large to display} \\ \end{align*}
Time = 0.39 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.83 \[ \int \frac {-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )}{e^{2+2 e^x-2 x+2 e^2 \left (2 x-x^2\right )} x+x \log ^2(2)-2 x \log (2) \log (x)+x \log ^2(x)+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} (2 x \log (2)-2 x \log (x))} \, dx=-\frac {e^{e^2 x^2}}{e^{1+e^x-x+2 e^2 x}+e^{e^2 x^2} \log (2)-e^{e^2 x^2} \log (x)} \]
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Time = 0.63 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.07
method | result | size |
risch | \(-\frac {1}{\ln \left (2\right )-\ln \left (x \right )+{\mathrm e}^{-x^{2} {\mathrm e}^{2}+2 \,{\mathrm e}^{2} x +{\mathrm e}^{x}-x +1}}\) | \(32\) |
parallelrisch | \(-\frac {1}{\ln \left (2\right )-\ln \left (x \right )+{\mathrm e}^{{\mathrm e}^{x}+\left (-x^{2}+2 x \right ) {\mathrm e}^{2}-x +1}}\) | \(32\) |
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Time = 0.26 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00 \[ \int \frac {-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )}{e^{2+2 e^x-2 x+2 e^2 \left (2 x-x^2\right )} x+x \log ^2(2)-2 x \log (2) \log (x)+x \log ^2(x)+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} (2 x \log (2)-2 x \log (x))} \, dx=-\frac {1}{e^{\left (-{\left (x^{2} - 2 \, x\right )} e^{2} - x + e^{x} + 1\right )} + \log \left (2\right ) - \log \left (x\right )} \]
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Time = 0.14 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.90 \[ \int \frac {-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )}{e^{2+2 e^x-2 x+2 e^2 \left (2 x-x^2\right )} x+x \log ^2(2)-2 x \log (2) \log (x)+x \log ^2(x)+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} (2 x \log (2)-2 x \log (x))} \, dx=- \frac {1}{e^{- x + \left (- x^{2} + 2 x\right ) e^{2} + e^{x} + 1} - \log {\left (x \right )} + \log {\left (2 \right )}} \]
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Time = 0.44 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.37 \[ \int \frac {-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )}{e^{2+2 e^x-2 x+2 e^2 \left (2 x-x^2\right )} x+x \log ^2(2)-2 x \log (2) \log (x)+x \log ^2(x)+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} (2 x \log (2)-2 x \log (x))} \, dx=-\frac {e^{\left (x^{2} e^{2} + x\right )}}{{\left (\log \left (2\right ) - \log \left (x\right )\right )} e^{\left (x^{2} e^{2} + x\right )} + e^{\left (2 \, x e^{2} + e^{x} + 1\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1135 vs. \(2 (27) = 54\).
Time = 0.56 (sec) , antiderivative size = 1135, normalized size of antiderivative = 37.83 \[ \int \frac {-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )}{e^{2+2 e^x-2 x+2 e^2 \left (2 x-x^2\right )} x+x \log ^2(2)-2 x \log (2) \log (x)+x \log ^2(x)+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} (2 x \log (2)-2 x \log (x))} \, dx=\text {Too large to display} \]
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Timed out. \[ \int \frac {-1+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} \left (-x+e^x x+e^2 \left (2 x-2 x^2\right )\right )}{e^{2+2 e^x-2 x+2 e^2 \left (2 x-x^2\right )} x+x \log ^2(2)-2 x \log (2) \log (x)+x \log ^2(x)+e^{1+e^x-x+e^2 \left (2 x-x^2\right )} (2 x \log (2)-2 x \log (x))} \, dx=\int \frac {{\mathrm {e}}^{{\mathrm {e}}^x-x+{\mathrm {e}}^2\,\left (2\,x-x^2\right )+1}\,\left ({\mathrm {e}}^2\,\left (2\,x-2\,x^2\right )-x+x\,{\mathrm {e}}^x\right )-1}{x\,{\ln \left (x\right )}^2+{\mathrm {e}}^{{\mathrm {e}}^x-x+{\mathrm {e}}^2\,\left (2\,x-x^2\right )+1}\,\left (2\,x\,\ln \left (2\right )-2\,x\,\ln \left (x\right )\right )+x\,{\ln \left (2\right )}^2+x\,{\mathrm {e}}^{2\,{\mathrm {e}}^x-2\,x+2\,{\mathrm {e}}^2\,\left (2\,x-x^2\right )+2}-2\,x\,\ln \left (2\right )\,\ln \left (x\right )} \,d x \]
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