Integrand size = 150, antiderivative size = 30 \[ \int \frac {e^{-x^2} \left (e^{e^{e^{-x^2} x}} \left (e^{x^2} \left (-15+12 x+3 x^2\right )+e^{e^{-x^2} x} \left (-15 x+12 x^2+33 x^3-24 x^4-6 x^5\right )\right )+\left (\frac {-5+4 x+x^2}{x}\right )^{5 x/3} \left (e^{x^2} \left (25+5 x^2\right )+e^{x^2} \left (-25+20 x+5 x^2\right ) \log \left (\frac {-5+4 x+x^2}{x}\right )\right )\right )}{-15+12 x+3 x^2} \, dx=e^{e^{e^{-x^2} x}} x+\left (4-\frac {5}{x}+x\right )^{5 x/3} \]
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\[ \int \frac {e^{-x^2} \left (e^{e^{e^{-x^2} x}} \left (e^{x^2} \left (-15+12 x+3 x^2\right )+e^{e^{-x^2} x} \left (-15 x+12 x^2+33 x^3-24 x^4-6 x^5\right )\right )+\left (\frac {-5+4 x+x^2}{x}\right )^{5 x/3} \left (e^{x^2} \left (25+5 x^2\right )+e^{x^2} \left (-25+20 x+5 x^2\right ) \log \left (\frac {-5+4 x+x^2}{x}\right )\right )\right )}{-15+12 x+3 x^2} \, dx=\int \frac {e^{-x^2} \left (e^{e^{e^{-x^2} x}} \left (e^{x^2} \left (-15+12 x+3 x^2\right )+e^{e^{-x^2} x} \left (-15 x+12 x^2+33 x^3-24 x^4-6 x^5\right )\right )+\left (\frac {-5+4 x+x^2}{x}\right )^{5 x/3} \left (e^{x^2} \left (25+5 x^2\right )+e^{x^2} \left (-25+20 x+5 x^2\right ) \log \left (\frac {-5+4 x+x^2}{x}\right )\right )\right )}{-15+12 x+3 x^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (e^{e^{e^{-x^2} x}-x^2} \left (e^{x^2}+e^{e^{-x^2} x} \left (x-2 x^3\right )\right )+\frac {5 \left (4-\frac {5}{x}+x\right )^{5 x/3} \left (5+x^2+\left (-5+4 x+x^2\right ) \log \left (4-\frac {5}{x}+x\right )\right )}{3 \left (-5+4 x+x^2\right )}\right ) \, dx \\ & = \frac {5}{3} \int \frac {\left (4-\frac {5}{x}+x\right )^{5 x/3} \left (5+x^2+\left (-5+4 x+x^2\right ) \log \left (4-\frac {5}{x}+x\right )\right )}{-5+4 x+x^2} \, dx+\int e^{e^{e^{-x^2} x}-x^2} \left (e^{x^2}+e^{e^{-x^2} x} \left (x-2 x^3\right )\right ) \, dx \\ & = \frac {5}{3} \int \left (\frac {\left (4-\frac {5}{x}+x\right )^{5 x/3} \left (5+x^2\right )}{(-1+x) (5+x)}+\left (4-\frac {5}{x}+x\right )^{5 x/3} \log \left (4-\frac {5}{x}+x\right )\right ) \, dx+\int \left (e^{e^{e^{-x^2} x}}-e^{e^{e^{-x^2} x}+e^{-x^2} x-x^2} x \left (-1+2 x^2\right )\right ) \, dx \\ & = \frac {5}{3} \int \frac {\left (4-\frac {5}{x}+x\right )^{5 x/3} \left (5+x^2\right )}{(-1+x) (5+x)} \, dx+\frac {5}{3} \int \left (4-\frac {5}{x}+x\right )^{5 x/3} \log \left (4-\frac {5}{x}+x\right ) \, dx+\int e^{e^{e^{-x^2} x}} \, dx-\int e^{e^{e^{-x^2} x}+e^{-x^2} x-x^2} x \left (-1+2 x^2\right ) \, dx \\ & = \left (4-\frac {5}{x}+x\right )^{5 x/3}-\frac {5}{3} \int \left (1+\frac {5}{x^2}\right ) x \left (4-\frac {5}{x}+x\right )^{-1+\frac {5 x}{3}} \, dx+\frac {5}{3} \int \left (\left (4-\frac {5}{x}+x\right )^{5 x/3}+\frac {\left (4-\frac {5}{x}+x\right )^{5 x/3}}{-1+x}-\frac {5 \left (4-\frac {5}{x}+x\right )^{5 x/3}}{5+x}\right ) \, dx+\int e^{e^{e^{-x^2} x}} \, dx-\int \left (-e^{e^{e^{-x^2} x}+e^{-x^2} x-x^2} x+2 e^{e^{e^{-x^2} x}+e^{-x^2} x-x^2} x^3\right ) \, dx \\ & = \left (4-\frac {5}{x}+x\right )^{5 x/3}+\frac {5}{3} \int \left (4-\frac {5}{x}+x\right )^{5 x/3} \, dx+\frac {5}{3} \int \frac {\left (4-\frac {5}{x}+x\right )^{5 x/3}}{-1+x} \, dx-\frac {5}{3} \int \left (\frac {5 \left (4-\frac {5}{x}+x\right )^{-1+\frac {5 x}{3}}}{x}+x \left (4-\frac {5}{x}+x\right )^{-1+\frac {5 x}{3}}\right ) \, dx-2 \int e^{e^{e^{-x^2} x}+e^{-x^2} x-x^2} x^3 \, dx-\frac {25}{3} \int \frac {\left (4-\frac {5}{x}+x\right )^{5 x/3}}{5+x} \, dx+\int e^{e^{e^{-x^2} x}} \, dx+\int e^{e^{e^{-x^2} x}+e^{-x^2} x-x^2} x \, dx \\ & = \left (4-\frac {5}{x}+x\right )^{5 x/3}+\frac {5}{3} \int \left (4-\frac {5}{x}+x\right )^{5 x/3} \, dx+\frac {5}{3} \int \frac {\left (4-\frac {5}{x}+x\right )^{5 x/3}}{-1+x} \, dx-\frac {5}{3} \int x \left (4-\frac {5}{x}+x\right )^{-1+\frac {5 x}{3}} \, dx-2 \int e^{e^{e^{-x^2} x}+e^{-x^2} x-x^2} x^3 \, dx-\frac {25}{3} \int \frac {\left (4-\frac {5}{x}+x\right )^{5 x/3}}{5+x} \, dx-\frac {25}{3} \int \frac {\left (4-\frac {5}{x}+x\right )^{-1+\frac {5 x}{3}}}{x} \, dx+\int e^{e^{e^{-x^2} x}} \, dx+\int e^{e^{e^{-x^2} x}+e^{-x^2} x-x^2} x \, dx \\ \end{align*}
Time = 1.11 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00 \[ \int \frac {e^{-x^2} \left (e^{e^{e^{-x^2} x}} \left (e^{x^2} \left (-15+12 x+3 x^2\right )+e^{e^{-x^2} x} \left (-15 x+12 x^2+33 x^3-24 x^4-6 x^5\right )\right )+\left (\frac {-5+4 x+x^2}{x}\right )^{5 x/3} \left (e^{x^2} \left (25+5 x^2\right )+e^{x^2} \left (-25+20 x+5 x^2\right ) \log \left (\frac {-5+4 x+x^2}{x}\right )\right )\right )}{-15+12 x+3 x^2} \, dx=e^{e^{e^{-x^2} x}} x+\left (4-\frac {5}{x}+x\right )^{5 x/3} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.05 (sec) , antiderivative size = 108, normalized size of antiderivative = 3.60
\[x \,{\mathrm e}^{{\mathrm e}^{x \,{\mathrm e}^{-x^{2}}}}+x^{-\frac {5 x}{3}} \left (x^{2}+4 x -5\right )^{\frac {5 x}{3}} {\mathrm e}^{-\frac {5 i \pi \,\operatorname {csgn}\left (\frac {i \left (x^{2}+4 x -5\right )}{x}\right ) x \left (-\operatorname {csgn}\left (\frac {i \left (x^{2}+4 x -5\right )}{x}\right )+\operatorname {csgn}\left (i \left (x^{2}+4 x -5\right )\right )\right ) \left (-\operatorname {csgn}\left (\frac {i \left (x^{2}+4 x -5\right )}{x}\right )+\operatorname {csgn}\left (\frac {i}{x}\right )\right )}{6}}\]
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Time = 0.27 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.97 \[ \int \frac {e^{-x^2} \left (e^{e^{e^{-x^2} x}} \left (e^{x^2} \left (-15+12 x+3 x^2\right )+e^{e^{-x^2} x} \left (-15 x+12 x^2+33 x^3-24 x^4-6 x^5\right )\right )+\left (\frac {-5+4 x+x^2}{x}\right )^{5 x/3} \left (e^{x^2} \left (25+5 x^2\right )+e^{x^2} \left (-25+20 x+5 x^2\right ) \log \left (\frac {-5+4 x+x^2}{x}\right )\right )\right )}{-15+12 x+3 x^2} \, dx=x e^{\left (e^{\left (x e^{\left (-x^{2}\right )}\right )}\right )} + \left (\frac {x^{2} + 4 \, x - 5}{x}\right )^{\frac {5}{3} \, x} \]
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Timed out. \[ \int \frac {e^{-x^2} \left (e^{e^{e^{-x^2} x}} \left (e^{x^2} \left (-15+12 x+3 x^2\right )+e^{e^{-x^2} x} \left (-15 x+12 x^2+33 x^3-24 x^4-6 x^5\right )\right )+\left (\frac {-5+4 x+x^2}{x}\right )^{5 x/3} \left (e^{x^2} \left (25+5 x^2\right )+e^{x^2} \left (-25+20 x+5 x^2\right ) \log \left (\frac {-5+4 x+x^2}{x}\right )\right )\right )}{-15+12 x+3 x^2} \, dx=\text {Timed out} \]
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Time = 0.24 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.43 \[ \int \frac {e^{-x^2} \left (e^{e^{e^{-x^2} x}} \left (e^{x^2} \left (-15+12 x+3 x^2\right )+e^{e^{-x^2} x} \left (-15 x+12 x^2+33 x^3-24 x^4-6 x^5\right )\right )+\left (\frac {-5+4 x+x^2}{x}\right )^{5 x/3} \left (e^{x^2} \left (25+5 x^2\right )+e^{x^2} \left (-25+20 x+5 x^2\right ) \log \left (\frac {-5+4 x+x^2}{x}\right )\right )\right )}{-15+12 x+3 x^2} \, dx=\frac {x e^{\left (\frac {5}{3} \, x \log \left (x\right ) + e^{\left (x e^{\left (-x^{2}\right )}\right )}\right )} + e^{\left (\frac {5}{3} \, x \log \left (x + 5\right ) + \frac {5}{3} \, x \log \left (x - 1\right )\right )}}{x^{\frac {5}{3} \, x}} \]
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\[ \int \frac {e^{-x^2} \left (e^{e^{e^{-x^2} x}} \left (e^{x^2} \left (-15+12 x+3 x^2\right )+e^{e^{-x^2} x} \left (-15 x+12 x^2+33 x^3-24 x^4-6 x^5\right )\right )+\left (\frac {-5+4 x+x^2}{x}\right )^{5 x/3} \left (e^{x^2} \left (25+5 x^2\right )+e^{x^2} \left (-25+20 x+5 x^2\right ) \log \left (\frac {-5+4 x+x^2}{x}\right )\right )\right )}{-15+12 x+3 x^2} \, dx=\int { \frac {{\left (5 \, {\left ({\left (x^{2} + 4 \, x - 5\right )} e^{\left (x^{2}\right )} \log \left (\frac {x^{2} + 4 \, x - 5}{x}\right ) + {\left (x^{2} + 5\right )} e^{\left (x^{2}\right )}\right )} \left (\frac {x^{2} + 4 \, x - 5}{x}\right )^{\frac {5}{3} \, x} + 3 \, {\left ({\left (x^{2} + 4 \, x - 5\right )} e^{\left (x^{2}\right )} - {\left (2 \, x^{5} + 8 \, x^{4} - 11 \, x^{3} - 4 \, x^{2} + 5 \, x\right )} e^{\left (x e^{\left (-x^{2}\right )}\right )}\right )} e^{\left (e^{\left (x e^{\left (-x^{2}\right )}\right )}\right )}\right )} e^{\left (-x^{2}\right )}}{3 \, {\left (x^{2} + 4 \, x - 5\right )}} \,d x } \]
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Time = 9.71 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.83 \[ \int \frac {e^{-x^2} \left (e^{e^{e^{-x^2} x}} \left (e^{x^2} \left (-15+12 x+3 x^2\right )+e^{e^{-x^2} x} \left (-15 x+12 x^2+33 x^3-24 x^4-6 x^5\right )\right )+\left (\frac {-5+4 x+x^2}{x}\right )^{5 x/3} \left (e^{x^2} \left (25+5 x^2\right )+e^{x^2} \left (-25+20 x+5 x^2\right ) \log \left (\frac {-5+4 x+x^2}{x}\right )\right )\right )}{-15+12 x+3 x^2} \, dx=x\,{\mathrm {e}}^{{\mathrm {e}}^{x\,{\mathrm {e}}^{-x^2}}}+{\left (x-\frac {5}{x}+4\right )}^{\frac {5\,x}{3}} \]
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