Integrand size = 56, antiderivative size = 22 \[ \int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^3+x^2 \log (x)} \, dx=\frac {(-e+x) (-2 (2+2 x)+\log (x+\log (x)))}{x} \]
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\[ \int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^3+x^2 \log (x)} \, dx=\int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^3+x^2 \log (x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^2 (x+\log (x))} \, dx \\ & = \int \left (\frac {-e+(1-5 e) x+x^2-4 x^3-4 e \log (x)-4 x^2 \log (x)}{x^2 (x+\log (x))}+\frac {e \log (x+\log (x))}{x^2}\right ) \, dx \\ & = e \int \frac {\log (x+\log (x))}{x^2} \, dx+\int \frac {-e+(1-5 e) x+x^2-4 x^3-4 e \log (x)-4 x^2 \log (x)}{x^2 (x+\log (x))} \, dx \\ & = e \int \frac {\log (x+\log (x))}{x^2} \, dx+\int \left (-\frac {4 \left (e+x^2\right )}{x^2}-\frac {(e-x) (1+x)}{x^2 (x+\log (x))}\right ) \, dx \\ & = -\left (4 \int \frac {e+x^2}{x^2} \, dx\right )+e \int \frac {\log (x+\log (x))}{x^2} \, dx-\int \frac {(e-x) (1+x)}{x^2 (x+\log (x))} \, dx \\ & = -\left (4 \int \left (1+\frac {e}{x^2}\right ) \, dx\right )+e \int \frac {\log (x+\log (x))}{x^2} \, dx-\int \left (\frac {1}{-x-\log (x)}+\frac {e}{x^2 (x+\log (x))}+\frac {-1+e}{x (x+\log (x))}\right ) \, dx \\ & = \frac {4 e}{x}-4 x-(-1+e) \int \frac {1}{x (x+\log (x))} \, dx-e \int \frac {1}{x^2 (x+\log (x))} \, dx+e \int \frac {\log (x+\log (x))}{x^2} \, dx-\int \frac {1}{-x-\log (x)} \, dx \\ \end{align*}
Time = 0.27 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.18 \[ \int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^3+x^2 \log (x)} \, dx=\frac {4 e}{x}-4 x+\log (x+\log (x))-\frac {e \log (x+\log (x))}{x} \]
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Time = 0.37 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.45
method | result | size |
parallelrisch | \(-\frac {{\mathrm e} \ln \left (x +\ln \left (x \right )\right )-\ln \left (x +\ln \left (x \right )\right ) x +4 x^{2}-4 \,{\mathrm e}}{x}\) | \(32\) |
risch | \(-\frac {{\mathrm e} \ln \left (x +\ln \left (x \right )\right )}{x}+\frac {\ln \left (x +\ln \left (x \right )\right ) x -4 x^{2}+4 \,{\mathrm e}}{x}\) | \(35\) |
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Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.27 \[ \int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^3+x^2 \log (x)} \, dx=-\frac {4 \, x^{2} - {\left (x - e\right )} \log \left (x + \log \left (x\right )\right ) - 4 \, e}{x} \]
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Time = 0.17 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.23 \[ \int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^3+x^2 \log (x)} \, dx=- 4 x + \log {\left (x + \log {\left (x \right )} \right )} - \frac {e \log {\left (x + \log {\left (x \right )} \right )}}{x} + \frac {4 e}{x} \]
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Time = 0.20 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.27 \[ \int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^3+x^2 \log (x)} \, dx=-\frac {4 \, x^{2} - {\left (x - e\right )} \log \left (x + \log \left (x\right )\right ) - 4 \, e}{x} \]
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Time = 0.27 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.59 \[ \int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^3+x^2 \log (x)} \, dx=-\frac {4 \, x^{2} + e \log \left (x + \log \left (x\right )\right ) - x \log \left (-x - \log \left (x\right )\right ) - 4 \, e}{x} \]
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Time = 8.75 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.27 \[ \int \frac {e (-1-5 x)+x+x^2-4 x^3+\left (-4 e-4 x^2\right ) \log (x)+(e x+e \log (x)) \log (x+\log (x))}{x^3+x^2 \log (x)} \, dx=\ln \left (x+\ln \left (x\right )\right )-4\,x+\frac {4\,\mathrm {e}}{x}-\frac {\ln \left (x+\ln \left (x\right )\right )\,\mathrm {e}}{x} \]
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