Integrand size = 97, antiderivative size = 29 \[ \int \frac {-40-10 x-e^8 x+e^4 \left (-30 x-10 x^2\right )+\left (-30 x-2 e^4 x-10 x^2\right ) \log (x)-x \log ^2(x)}{3 e^8 x+e^4 \left (120 x+30 x^2\right )+\left (120 x+6 e^4 x+30 x^2\right ) \log (x)+3 x \log ^2(x)} \, dx=\frac {1}{3} \left (-5-x+\log \left (-2-\frac {4 (5+5 (3+x))}{e^4+\log (x)}\right )\right ) \]
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Time = 0.42 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.10, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.072, Rules used = {6, 6820, 12, 6874, 2339, 29, 6816} \[ \int \frac {-40-10 x-e^8 x+e^4 \left (-30 x-10 x^2\right )+\left (-30 x-2 e^4 x-10 x^2\right ) \log (x)-x \log ^2(x)}{3 e^8 x+e^4 \left (120 x+30 x^2\right )+\left (120 x+6 e^4 x+30 x^2\right ) \log (x)+3 x \log ^2(x)} \, dx=-\frac {x}{3}-\frac {1}{3} \log \left (\log (x)+e^4\right )+\frac {1}{3} \log \left (10 x+\log (x)+e^4+40\right ) \]
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Rule 6
Rule 12
Rule 29
Rule 2339
Rule 6816
Rule 6820
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {-40+\left (-10-e^8\right ) x+e^4 \left (-30 x-10 x^2\right )+\left (-30 x-2 e^4 x-10 x^2\right ) \log (x)-x \log ^2(x)}{3 e^8 x+e^4 \left (120 x+30 x^2\right )+\left (120 x+6 e^4 x+30 x^2\right ) \log (x)+3 x \log ^2(x)} \, dx \\ & = \int \frac {-40-\left (10+30 e^4+e^8\right ) x-10 e^4 x^2-2 x \left (e^4+5 (3+x)\right ) \log (x)-x \log ^2(x)}{3 x \left (e^4+\log (x)\right ) \left (e^4+10 (4+x)+\log (x)\right )} \, dx \\ & = \frac {1}{3} \int \frac {-40-\left (10+30 e^4+e^8\right ) x-10 e^4 x^2-2 x \left (e^4+5 (3+x)\right ) \log (x)-x \log ^2(x)}{x \left (e^4+\log (x)\right ) \left (e^4+10 (4+x)+\log (x)\right )} \, dx \\ & = \frac {1}{3} \int \left (-1-\frac {1}{x \left (e^4+\log (x)\right )}+\frac {1+10 x}{x \left (40 \left (1+\frac {e^4}{40}\right )+10 x+\log (x)\right )}\right ) \, dx \\ & = -\frac {x}{3}-\frac {1}{3} \int \frac {1}{x \left (e^4+\log (x)\right )} \, dx+\frac {1}{3} \int \frac {1+10 x}{x \left (40 \left (1+\frac {e^4}{40}\right )+10 x+\log (x)\right )} \, dx \\ & = -\frac {x}{3}+\frac {1}{3} \log \left (40+e^4+10 x+\log (x)\right )-\frac {1}{3} \text {Subst}\left (\int \frac {1}{x} \, dx,x,e^4+\log (x)\right ) \\ & = -\frac {x}{3}-\frac {1}{3} \log \left (e^4+\log (x)\right )+\frac {1}{3} \log \left (40+e^4+10 x+\log (x)\right ) \\ \end{align*}
Time = 0.27 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97 \[ \int \frac {-40-10 x-e^8 x+e^4 \left (-30 x-10 x^2\right )+\left (-30 x-2 e^4 x-10 x^2\right ) \log (x)-x \log ^2(x)}{3 e^8 x+e^4 \left (120 x+30 x^2\right )+\left (120 x+6 e^4 x+30 x^2\right ) \log (x)+3 x \log ^2(x)} \, dx=\frac {1}{3} \left (-x-\log \left (e^4+\log (x)\right )+\log \left (40+e^4+10 x+\log (x)\right )\right ) \]
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Time = 0.44 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.86
method | result | size |
default | \(-\frac {x}{3}+\frac {\ln \left ({\mathrm e}^{4}+\ln \left (x \right )+10 x +40\right )}{3}-\frac {\ln \left ({\mathrm e}^{4}+\ln \left (x \right )\right )}{3}\) | \(25\) |
norman | \(-\frac {x}{3}+\frac {\ln \left ({\mathrm e}^{4}+\ln \left (x \right )+10 x +40\right )}{3}-\frac {\ln \left ({\mathrm e}^{4}+\ln \left (x \right )\right )}{3}\) | \(25\) |
risch | \(-\frac {x}{3}+\frac {\ln \left ({\mathrm e}^{4}+\ln \left (x \right )+10 x +40\right )}{3}-\frac {\ln \left ({\mathrm e}^{4}+\ln \left (x \right )\right )}{3}\) | \(25\) |
parallelrisch | \(-\frac {x}{3}-\frac {\ln \left ({\mathrm e}^{4}+\ln \left (x \right )\right )}{3}+\frac {\ln \left (\frac {{\mathrm e}^{4}}{10}+x +\frac {\ln \left (x \right )}{10}+4\right )}{3}\) | \(27\) |
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Time = 0.27 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.83 \[ \int \frac {-40-10 x-e^8 x+e^4 \left (-30 x-10 x^2\right )+\left (-30 x-2 e^4 x-10 x^2\right ) \log (x)-x \log ^2(x)}{3 e^8 x+e^4 \left (120 x+30 x^2\right )+\left (120 x+6 e^4 x+30 x^2\right ) \log (x)+3 x \log ^2(x)} \, dx=-\frac {1}{3} \, x + \frac {1}{3} \, \log \left (10 \, x + e^{4} + \log \left (x\right ) + 40\right ) - \frac {1}{3} \, \log \left (e^{4} + \log \left (x\right )\right ) \]
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Time = 0.16 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.93 \[ \int \frac {-40-10 x-e^8 x+e^4 \left (-30 x-10 x^2\right )+\left (-30 x-2 e^4 x-10 x^2\right ) \log (x)-x \log ^2(x)}{3 e^8 x+e^4 \left (120 x+30 x^2\right )+\left (120 x+6 e^4 x+30 x^2\right ) \log (x)+3 x \log ^2(x)} \, dx=- \frac {x}{3} - \frac {\log {\left (\log {\left (x \right )} + e^{4} \right )}}{3} + \frac {\log {\left (10 x + \log {\left (x \right )} + 40 + e^{4} \right )}}{3} \]
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Time = 0.23 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.83 \[ \int \frac {-40-10 x-e^8 x+e^4 \left (-30 x-10 x^2\right )+\left (-30 x-2 e^4 x-10 x^2\right ) \log (x)-x \log ^2(x)}{3 e^8 x+e^4 \left (120 x+30 x^2\right )+\left (120 x+6 e^4 x+30 x^2\right ) \log (x)+3 x \log ^2(x)} \, dx=-\frac {1}{3} \, x + \frac {1}{3} \, \log \left (10 \, x + e^{4} + \log \left (x\right ) + 40\right ) - \frac {1}{3} \, \log \left (e^{4} + \log \left (x\right )\right ) \]
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Time = 0.32 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97 \[ \int \frac {-40-10 x-e^8 x+e^4 \left (-30 x-10 x^2\right )+\left (-30 x-2 e^4 x-10 x^2\right ) \log (x)-x \log ^2(x)}{3 e^8 x+e^4 \left (120 x+30 x^2\right )+\left (120 x+6 e^4 x+30 x^2\right ) \log (x)+3 x \log ^2(x)} \, dx=-\frac {1}{3} \, x + \frac {1}{3} \, \log \left (-10 \, x - e^{4} - \log \left (x\right ) - 40\right ) - \frac {1}{3} \, \log \left (e^{4} + \log \left (x\right )\right ) \]
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Timed out. \[ \int \frac {-40-10 x-e^8 x+e^4 \left (-30 x-10 x^2\right )+\left (-30 x-2 e^4 x-10 x^2\right ) \log (x)-x \log ^2(x)}{3 e^8 x+e^4 \left (120 x+30 x^2\right )+\left (120 x+6 e^4 x+30 x^2\right ) \log (x)+3 x \log ^2(x)} \, dx=\int -\frac {x\,{\ln \left (x\right )}^2+\left (30\,x+2\,x\,{\mathrm {e}}^4+10\,x^2\right )\,\ln \left (x\right )+10\,x+{\mathrm {e}}^4\,\left (10\,x^2+30\,x\right )+x\,{\mathrm {e}}^8+40}{3\,x\,{\ln \left (x\right )}^2+\left (120\,x+6\,x\,{\mathrm {e}}^4+30\,x^2\right )\,\ln \left (x\right )+{\mathrm {e}}^4\,\left (30\,x^2+120\,x\right )+3\,x\,{\mathrm {e}}^8} \,d x \]
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