Integrand size = 97, antiderivative size = 35 \[ \int \frac {3440-2592 x-872 x^2+1288 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8+\left (80+96 x-84 x^2+16 x^3\right ) \log (5)}{3600-2400 x-1040 x^2+1320 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8} \, dx=x-\frac {2-\log (5)}{(3-x) \left (5-\frac {1}{4} x \left (4 x-x^2\right )\right )} \]
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Leaf count is larger than twice the leaf count of optimal. \(1979\) vs. \(2(35)=70\).
Time = 8.36 (sec) , antiderivative size = 1979, normalized size of antiderivative = 56.54, number of steps used = 20, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {2099, 2126, 2106, 2104, 836, 814, 648, 632, 210, 642} \[ \int \frac {3440-2592 x-872 x^2+1288 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8+\left (80+96 x-84 x^2+16 x^3\right ) \log (5)}{3600-2400 x-1040 x^2+1320 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8} \, dx =\text {Too large to display} \]
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Rule 210
Rule 632
Rule 642
Rule 648
Rule 814
Rule 836
Rule 2099
Rule 2104
Rule 2106
Rule 2126
Rubi steps \begin{align*} \text {integral}& = \int \left (1+\frac {4 (-2+\log (5))}{11 (-3+x)^2}-\frac {4 \left (-20-36 x+3 x^2\right ) (-2+\log (5))}{11 \left (20-4 x^2+x^3\right )^2}-\frac {4 (2+x) (-2+\log (5))}{11 \left (20-4 x^2+x^3\right )}\right ) \, dx \\ & = x-\frac {4 (2-\log (5))}{11 (3-x)}+\frac {1}{11} (4 (2-\log (5))) \int \frac {-20-36 x+3 x^2}{\left (20-4 x^2+x^3\right )^2} \, dx+\frac {1}{11} (4 (2-\log (5))) \int \frac {2+x}{20-4 x^2+x^3} \, dx \\ & = x-\frac {4 (2-\log (5))}{11 (3-x)}-\frac {4 (2-\log (5))}{11 \left (20-4 x^2+x^3\right )}+\frac {1}{33} (4 (2-\log (5))) \int \frac {-60-84 x}{\left (20-4 x^2+x^3\right )^2} \, dx+\frac {1}{11} (4 (2-\log (5))) \text {Subst}\left (\int \frac {\frac {10}{3}+x}{\frac {412}{27}-\frac {16 x}{3}+x^3} \, dx,x,-\frac {4}{3}+x\right ) \\ & = x-\frac {4 (2-\log (5))}{11 (3-x)}-\frac {4 (2-\log (5))}{11 \left (20-4 x^2+x^3\right )}+\frac {1}{33} (4 (2-\log (5))) \text {Subst}\left (\int \frac {-172-84 x}{\left (\frac {412}{27}-\frac {16 x}{3}+x^3\right )^2} \, dx,x,-\frac {4}{3}+x\right )+\frac {1}{11} (4 (2-\log (5))) \text {Subst}\left (\int \frac {\frac {10}{3}+x}{\left (\frac {1}{3} \sqrt [3]{\frac {2}{103-3 \sqrt {1065}}} \left (8 \sqrt [3]{2}+\left (103-3 \sqrt {1065}\right )^{2/3}\right )+x\right ) \left (\frac {1}{9} \left (-16+\left (206-6 \sqrt {1065}\right )^{2/3}+\frac {128 \sqrt [3]{2}}{\left (103-3 \sqrt {1065}\right )^{2/3}}\right )-\frac {1}{3} \left (\sqrt [3]{206-6 \sqrt {1065}}+\frac {8\ 2^{2/3}}{\sqrt [3]{103-3 \sqrt {1065}}}\right ) x+x^2\right )} \, dx,x,-\frac {4}{3}+x\right ) \\ & = x-\frac {4 (2-\log (5))}{11 (3-x)}-\frac {4 (2-\log (5))}{11 \left (20-4 x^2+x^3\right )}+\frac {1}{33} (4 (2-\log (5))) \text {Subst}\left (\int \frac {-172-84 x}{\left (\frac {1}{3} \sqrt [3]{\frac {2}{103-3 \sqrt {1065}}} \left (8 \sqrt [3]{2}+\left (103-3 \sqrt {1065}\right )^{2/3}\right )+x\right )^2 \left (\frac {1}{9} \left (-16+\left (206-6 \sqrt {1065}\right )^{2/3}+\frac {128 \sqrt [3]{2}}{\left (103-3 \sqrt {1065}\right )^{2/3}}\right )-\frac {1}{3} \left (\sqrt [3]{206-6 \sqrt {1065}}+\frac {8\ 2^{2/3}}{\sqrt [3]{103-3 \sqrt {1065}}}\right ) x+x^2\right )^2} \, dx,x,-\frac {4}{3}+x\right )+\frac {1}{11} (4 (2-\log (5))) \text {Subst}\left (\int \left (\frac {9 \left (103-3 \sqrt {1065}\right )^{2/3} \left (-8 2^{2/3}+10 \sqrt [3]{103-3 \sqrt {1065}}-\sqrt [3]{2} \left (103-3 \sqrt {1065}\right )^{2/3}\right )}{2 \left (192 \sqrt [3]{2}+2^{2/3} \left (103-3 \sqrt {1065}\right )^{4/3}+\left (103-3 \sqrt {1065}\right )^{2/3} \left (24+\sqrt [3]{10097-309 \sqrt {1065}}\right )\right ) \left (8\ 2^{2/3}+\sqrt [3]{2} \left (103-3 \sqrt {1065}\right )^{2/3}+3 \sqrt [3]{103-3 \sqrt {1065}} x\right )}+\frac {9 \left (103-3 \sqrt {1065}\right )^{2/3} \left (4 \sqrt [3]{2} \left (547-15 \sqrt {1065}\right )-16 \left (103-3 \sqrt {1065}\right )^{2/3}+2^{2/3} \sqrt [3]{103-3 \sqrt {1065}} \left (263-3 \sqrt {1065}\right )+3 \left (8\ 2^{2/3} \sqrt [3]{103-3 \sqrt {1065}}-10 \left (103-3 \sqrt {1065}\right )^{2/3}+\sqrt [3]{2} \left (103-3 \sqrt {1065}\right )\right ) x\right )}{2 \left (192 \sqrt [3]{2}+2^{2/3} \left (103-3 \sqrt {1065}\right )^{4/3}+\left (103-3 \sqrt {1065}\right )^{2/3} \left (24+\sqrt [3]{10097-309 \sqrt {1065}}\right )\right ) \left (128 \sqrt [3]{2}-16 \left (103-3 \sqrt {1065}\right )^{2/3}+2^{2/3} \left (103-3 \sqrt {1065}\right )^{4/3}-3 \sqrt [3]{2} \left (103-3 \sqrt {1065}+8 \sqrt [3]{206-6 \sqrt {1065}}\right ) x+9 \left (103-3 \sqrt {1065}\right )^{2/3} x^2\right )}\right ) \, dx,x,-\frac {4}{3}+x\right ) \\ & = x-\frac {4 (2-\log (5))}{11 (3-x)}-\frac {18\ 2^{2/3} \left (103-3 \sqrt {1065}\right )^{5/3} \left (1420+\frac {\sqrt [3]{2} \left (1775-43 \sqrt {1065}+\left (355-7 \sqrt {1065}\right ) \sqrt [3]{206-6 \sqrt {1065}}\right ) (4-3 x)}{\left (103-3 \sqrt {1065}\right )^{2/3}}\right ) (2-\log (5))}{11 \left (329085-10097 \sqrt {1065}-4 \left (3195-103 \sqrt {1065}\right ) \sqrt [3]{206-6 \sqrt {1065}}\right ) \left (4-\sqrt [3]{206-6 \sqrt {1065}}-\frac {8\ 2^{2/3}}{\sqrt [3]{103-3 \sqrt {1065}}}-3 x\right ) \left (\sqrt [3]{15 \left (45+\sqrt {1065}\right )} \left (4+\sqrt [3]{206-6 \sqrt {1065}}\right )-2 \left (8+\sqrt [3]{206-6 \sqrt {1065}}+\frac {8\ 2^{2/3}}{\sqrt [3]{103-3 \sqrt {1065}}}\right ) x+6 x^2\right )}-\frac {4 (2-\log (5))}{11 \left (20-4 x^2+x^3\right )}-\frac {6 \sqrt [3]{2 \left (103-3 \sqrt {1065}\right )} \left (8 \sqrt [3]{2}-5\ 2^{2/3} \sqrt [3]{103-3 \sqrt {1065}}+\left (103-3 \sqrt {1065}\right )^{2/3}\right ) (2-\log (5)) \log \left (\sqrt [3]{2} \left (8 \sqrt [3]{2}+\left (103-3 \sqrt {1065}\right )^{2/3}\right )-\sqrt [3]{103-3 \sqrt {1065}} (4-3 x)\right )}{11 \left (192 \sqrt [3]{2}+2^{2/3} \left (103-3 \sqrt {1065}\right )^{4/3}+\left (103-3 \sqrt {1065}\right )^{2/3} \left (24+\sqrt [3]{10097-309 \sqrt {1065}}\right )\right )}+\frac {\left (\left (103-3 \sqrt {1065}\right )^{5/3} (2-\log (5))\right ) \text {Subst}\left (\int \frac {16 \left (355-\frac {16 \sqrt [3]{2} \left (29465-893 \sqrt {1065}\right )}{\left (103-3 \sqrt {1065}\right )^{5/3}}-\frac {2^{2/3} \left (160105-4877 \sqrt {1065}\right )}{\left (103-3 \sqrt {1065}\right )^{4/3}}\right )-\frac {24 \sqrt [3]{2} \left (1775-43 \sqrt {1065}+\left (355-7 \sqrt {1065}\right ) \sqrt [3]{206-6 \sqrt {1065}}\right ) x}{\left (103-3 \sqrt {1065}\right )^{2/3}}}{\left (\frac {1}{3} \sqrt [3]{\frac {2}{103-3 \sqrt {1065}}} \left (8 \sqrt [3]{2}+\left (103-3 \sqrt {1065}\right )^{2/3}\right )+x\right )^2 \left (\frac {1}{9} \left (-16+\left (206-6 \sqrt {1065}\right )^{2/3}+\frac {128 \sqrt [3]{2}}{\left (103-3 \sqrt {1065}\right )^{2/3}}\right )+\frac {1}{3} \left (-\sqrt [3]{206-6 \sqrt {1065}}-\frac {8\ 2^{2/3}}{\sqrt [3]{103-3 \sqrt {1065}}}\right ) x+x^2\right )} \, dx,x,-\frac {4}{3}+x\right )}{22 \sqrt [3]{2} \left (329085-10097 \sqrt {1065}-4 \left (3195-103 \sqrt {1065}\right ) \sqrt [3]{206-6 \sqrt {1065}}\right )}+\frac {\left (18 \left (103-3 \sqrt {1065}\right )^{2/3} (2-\log (5))\right ) \text {Subst}\left (\int \frac {4 \sqrt [3]{2} \left (547-15 \sqrt {1065}\right )-16 \left (103-3 \sqrt {1065}\right )^{2/3}+2^{2/3} \sqrt [3]{103-3 \sqrt {1065}} \left (263-3 \sqrt {1065}\right )+3 \left (8\ 2^{2/3} \sqrt [3]{103-3 \sqrt {1065}}-10 \left (103-3 \sqrt {1065}\right )^{2/3}+\sqrt [3]{2} \left (103-3 \sqrt {1065}\right )\right ) x}{128 \sqrt [3]{2}-16 \left (103-3 \sqrt {1065}\right )^{2/3}+2^{2/3} \left (103-3 \sqrt {1065}\right )^{4/3}-3 \sqrt [3]{2} \left (103-3 \sqrt {1065}+8 \sqrt [3]{206-6 \sqrt {1065}}\right ) x+9 \left (103-3 \sqrt {1065}\right )^{2/3} x^2} \, dx,x,-\frac {4}{3}+x\right )}{11 \left (192 \sqrt [3]{2}+2^{2/3} \left (103-3 \sqrt {1065}\right )^{4/3}+\left (103-3 \sqrt {1065}\right )^{2/3} \left (24+\sqrt [3]{10097-309 \sqrt {1065}}\right )\right )} \\ & = \text {Too large to display} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.03 \[ \int \frac {3440-2592 x-872 x^2+1288 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8+\left (80+96 x-84 x^2+16 x^3\right ) \log (5)}{3600-2400 x-1040 x^2+1320 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8} \, dx=x+\frac {4 (17182+229489 \log (5)-119040 \log (25))}{8591 \left (-60+20 x+12 x^2-7 x^3+x^4\right )} \]
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Time = 0.08 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.26
method | result | size |
norman | \(\frac {x^{5}-412-37 x^{3}+104 x^{2}+80 x -4 \ln \left (5\right )}{x^{4}-7 x^{3}+12 x^{2}+20 x -60}\) | \(44\) |
gosper | \(-\frac {-x^{5}+37 x^{3}-104 x^{2}+4 \ln \left (5\right )-80 x +412}{x^{4}-7 x^{3}+12 x^{2}+20 x -60}\) | \(47\) |
parallelrisch | \(-\frac {-x^{5}+37 x^{3}-104 x^{2}+4 \ln \left (5\right )-80 x +412}{x^{4}-7 x^{3}+12 x^{2}+20 x -60}\) | \(47\) |
risch | \(x -\frac {4 \ln \left (5\right )}{x^{4}-7 x^{3}+12 x^{2}+20 x -60}+\frac {8}{x^{4}-7 x^{3}+12 x^{2}+20 x -60}\) | \(49\) |
default | \(x -\frac {4 \left (\left (2-\ln \left (5\right )\right ) x^{2}+\left (\ln \left (5\right )-2\right ) x -6+3 \ln \left (5\right )\right )}{11 \left (x^{3}-4 x^{2}+20\right )}-\frac {\frac {4 \ln \left (5\right )}{11}-\frac {8}{11}}{-3+x}\) | \(52\) |
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Time = 0.24 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.37 \[ \int \frac {3440-2592 x-872 x^2+1288 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8+\left (80+96 x-84 x^2+16 x^3\right ) \log (5)}{3600-2400 x-1040 x^2+1320 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8} \, dx=\frac {x^{5} - 7 \, x^{4} + 12 \, x^{3} + 20 \, x^{2} - 60 \, x - 4 \, \log \left (5\right ) + 8}{x^{4} - 7 \, x^{3} + 12 \, x^{2} + 20 \, x - 60} \]
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Time = 0.75 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.74 \[ \int \frac {3440-2592 x-872 x^2+1288 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8+\left (80+96 x-84 x^2+16 x^3\right ) \log (5)}{3600-2400 x-1040 x^2+1320 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8} \, dx=x + \frac {8 - 4 \log {\left (5 \right )}}{x^{4} - 7 x^{3} + 12 x^{2} + 20 x - 60} \]
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Time = 0.21 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.80 \[ \int \frac {3440-2592 x-872 x^2+1288 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8+\left (80+96 x-84 x^2+16 x^3\right ) \log (5)}{3600-2400 x-1040 x^2+1320 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8} \, dx=x - \frac {4 \, {\left (\log \left (5\right ) - 2\right )}}{x^{4} - 7 \, x^{3} + 12 \, x^{2} + 20 \, x - 60} \]
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Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.80 \[ \int \frac {3440-2592 x-872 x^2+1288 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8+\left (80+96 x-84 x^2+16 x^3\right ) \log (5)}{3600-2400 x-1040 x^2+1320 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8} \, dx=x - \frac {4 \, {\left (\log \left (5\right ) - 2\right )}}{x^{4} - 7 \, x^{3} + 12 \, x^{2} + 20 \, x - 60} \]
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Time = 0.16 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.80 \[ \int \frac {3440-2592 x-872 x^2+1288 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8+\left (80+96 x-84 x^2+16 x^3\right ) \log (5)}{3600-2400 x-1040 x^2+1320 x^3-256 x^4-128 x^5+73 x^6-14 x^7+x^8} \, dx=x-\frac {\ln \left (625\right )-8}{x^4-7\,x^3+12\,x^2+20\,x-60} \]
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