Integrand size = 53, antiderivative size = 26 \[ \int \frac {1}{25} \left (200 x-375 x^2+100 x^3+e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right )\right ) \, dx=x \left (4-4 \left (2+e^{\frac {e^5 x}{25}}\right )+x\right ) \left (-x+x^2\right ) \]
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Time = 0.14 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.69, number of steps used = 18, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.075, Rules used = {12, 2227, 2207, 2225} \[ \int \frac {1}{25} \left (200 x-375 x^2+100 x^3+e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right )\right ) \, dx=x^4-4 e^{\frac {e^5 x}{25}} x^3-5 x^3+4 e^{\frac {e^5 x}{25}} x^2+4 x^2 \]
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Rule 12
Rule 2207
Rule 2225
Rule 2227
Rubi steps \begin{align*} \text {integral}& = \frac {1}{25} \int \left (200 x-375 x^2+100 x^3+e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right )\right ) \, dx \\ & = 4 x^2-5 x^3+x^4+\frac {1}{25} \int e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right ) \, dx \\ & = 4 x^2-5 x^3+x^4+\frac {1}{25} \int \left (200 e^{\frac {e^5 x}{25}} x-300 e^{\frac {e^5 x}{25}} x^2-4 e^{5+\frac {e^5 x}{25}} (-1+x) x^2\right ) \, dx \\ & = 4 x^2-5 x^3+x^4-\frac {4}{25} \int e^{5+\frac {e^5 x}{25}} (-1+x) x^2 \, dx+8 \int e^{\frac {e^5 x}{25}} x \, dx-12 \int e^{\frac {e^5 x}{25}} x^2 \, dx \\ & = 200 e^{-5+\frac {e^5 x}{25}} x+4 x^2-300 e^{-5+\frac {e^5 x}{25}} x^2-5 x^3+x^4-\frac {4}{25} \int \left (-e^{5+\frac {e^5 x}{25}} x^2+e^{5+\frac {e^5 x}{25}} x^3\right ) \, dx-\frac {200 \int e^{\frac {e^5 x}{25}} \, dx}{e^5}+\frac {600 \int e^{\frac {e^5 x}{25}} x \, dx}{e^5} \\ & = -5000 e^{-10+\frac {e^5 x}{25}}+15000 e^{-10+\frac {e^5 x}{25}} x+200 e^{-5+\frac {e^5 x}{25}} x+4 x^2-300 e^{-5+\frac {e^5 x}{25}} x^2-5 x^3+x^4+\frac {4}{25} \int e^{5+\frac {e^5 x}{25}} x^2 \, dx-\frac {4}{25} \int e^{5+\frac {e^5 x}{25}} x^3 \, dx-\frac {15000 \int e^{\frac {e^5 x}{25}} \, dx}{e^{10}} \\ & = -375000 e^{-15+\frac {e^5 x}{25}}-5000 e^{-10+\frac {e^5 x}{25}}+15000 e^{-10+\frac {e^5 x}{25}} x+200 e^{-5+\frac {e^5 x}{25}} x+4 x^2+4 e^{\frac {e^5 x}{25}} x^2-300 e^{-5+\frac {e^5 x}{25}} x^2-5 x^3-4 e^{\frac {e^5 x}{25}} x^3+x^4-\frac {8 \int e^{5+\frac {e^5 x}{25}} x \, dx}{e^5}+\frac {12 \int e^{5+\frac {e^5 x}{25}} x^2 \, dx}{e^5} \\ & = -375000 e^{-15+\frac {e^5 x}{25}}-5000 e^{-10+\frac {e^5 x}{25}}+15000 e^{-10+\frac {e^5 x}{25}} x+4 x^2+4 e^{\frac {e^5 x}{25}} x^2-5 x^3-4 e^{\frac {e^5 x}{25}} x^3+x^4+\frac {200 \int e^{5+\frac {e^5 x}{25}} \, dx}{e^{10}}-\frac {600 \int e^{5+\frac {e^5 x}{25}} x \, dx}{e^{10}} \\ & = -375000 e^{-15+\frac {e^5 x}{25}}+4 x^2+4 e^{\frac {e^5 x}{25}} x^2-5 x^3-4 e^{\frac {e^5 x}{25}} x^3+x^4+\frac {15000 \int e^{5+\frac {e^5 x}{25}} \, dx}{e^{15}} \\ & = 4 x^2+4 e^{\frac {e^5 x}{25}} x^2-5 x^3-4 e^{\frac {e^5 x}{25}} x^3+x^4 \\ \end{align*}
Time = 0.54 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.85 \[ \int \frac {1}{25} \left (200 x-375 x^2+100 x^3+e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right )\right ) \, dx=(-1+x) x^2 \left (-4-4 e^{\frac {e^5 x}{25}}+x\right ) \]
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Time = 0.10 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.31
method | result | size |
risch | \(\frac {\left (-100 x^{3}+100 x^{2}\right ) {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}}{25}+x^{4}-5 x^{3}+4 x^{2}\) | \(34\) |
norman | \(x^{4}+4 x^{2}-5 x^{3}-4 x^{3} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}+4 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}\) | \(37\) |
parallelrisch | \(x^{4}+4 x^{2}-5 x^{3}-4 x^{3} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}+4 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}\) | \(37\) |
default | \({\mathrm e}^{-5} \left (5000 \,{\mathrm e}^{-5} \left (\frac {{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}-{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )-187500 \,{\mathrm e}^{-10} \left (\frac {{\mathrm e}^{10} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}}{625}-\frac {2 \,{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}+2 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )+2500 \,{\mathrm e}^{-5} \left (\frac {{\mathrm e}^{10} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}}{625}-\frac {2 \,{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}+2 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )-62500 \,{\mathrm e}^{-10} \left (\frac {{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{3} {\mathrm e}^{15}}{15625}-\frac {3 \,{\mathrm e}^{10} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}}{625}+\frac {6 \,{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}-6 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )\right )+4 x^{2}-5 x^{3}+x^{4}\) | \(185\) |
parts | \(2500 \,{\mathrm e}^{-5} \left ({\mathrm e}^{-5} \left (\frac {{\mathrm e}^{10} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}}{625}-\frac {2 \,{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}+2 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )+2 \,{\mathrm e}^{-5} \left (\frac {{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}-{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )-75 \,{\mathrm e}^{-10} \left (\frac {{\mathrm e}^{10} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}}{625}-\frac {2 \,{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}+2 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )-25 \,{\mathrm e}^{-10} \left (\frac {{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{3} {\mathrm e}^{15}}{15625}-\frac {3 \,{\mathrm e}^{10} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}}{625}+\frac {6 \,{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}-6 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )\right )+4 x^{2}-5 x^{3}+x^{4}\) | \(185\) |
derivativedivides | \({\mathrm e}^{-5} \left (5000 \,{\mathrm e}^{-5} \left (\frac {{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}-{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )-187500 \,{\mathrm e}^{-10} \left (\frac {{\mathrm e}^{10} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}}{625}-\frac {2 \,{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}+2 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )+2500 \,{\mathrm e}^{-5} \left (\frac {{\mathrm e}^{10} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}}{625}-\frac {2 \,{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}+2 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )-62500 \,{\mathrm e}^{-10} \left (\frac {{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{3} {\mathrm e}^{15}}{15625}-\frac {3 \,{\mathrm e}^{10} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x^{2}}{625}+\frac {6 \,{\mathrm e}^{5} {\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}} x}{25}-6 \,{\mathrm e}^{\frac {x \,{\mathrm e}^{5}}{25}}\right )+4 x^{2} {\mathrm e}^{5}-5 x^{3} {\mathrm e}^{5}+x^{4} {\mathrm e}^{5}\right )\) | \(191\) |
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Time = 0.24 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.19 \[ \int \frac {1}{25} \left (200 x-375 x^2+100 x^3+e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right )\right ) \, dx=x^{4} - 5 \, x^{3} + 4 \, x^{2} - 4 \, {\left (x^{3} - x^{2}\right )} e^{\left (\frac {1}{25} \, x e^{5}\right )} \]
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Time = 0.07 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.19 \[ \int \frac {1}{25} \left (200 x-375 x^2+100 x^3+e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right )\right ) \, dx=x^{4} - 5 x^{3} + 4 x^{2} + \left (- 4 x^{3} + 4 x^{2}\right ) e^{\frac {x e^{5}}{25}} \]
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Time = 0.22 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.19 \[ \int \frac {1}{25} \left (200 x-375 x^2+100 x^3+e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right )\right ) \, dx=x^{4} - 5 \, x^{3} + 4 \, x^{2} - 4 \, {\left (x^{3} - x^{2}\right )} e^{\left (\frac {1}{25} \, x e^{5}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 93 vs. \(2 (20) = 40\).
Time = 0.27 (sec) , antiderivative size = 93, normalized size of antiderivative = 3.58 \[ \int \frac {1}{25} \left (200 x-375 x^2+100 x^3+e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right )\right ) \, dx=x^{4} - 5 \, x^{3} + 4 \, x^{2} - 4 \, {\left (x^{3} e^{15} - x^{2} e^{15} - 75 \, x^{2} e^{10} + 50 \, x e^{10} + 3750 \, x e^{5} - 1250 \, e^{5} - 93750\right )} e^{\left (\frac {1}{25} \, x e^{5} - 15\right )} - 100 \, {\left (3 \, x^{2} e^{10} - 2 \, x e^{10} - 150 \, x e^{5} + 50 \, e^{5} + 3750\right )} e^{\left (\frac {1}{25} \, x e^{5} - 15\right )} \]
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Time = 0.08 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.81 \[ \int \frac {1}{25} \left (200 x-375 x^2+100 x^3+e^{\frac {e^5 x}{25}} \left (200 x-300 x^2+e^5 \left (4 x^2-4 x^3\right )\right )\right ) \, dx=-x^2\,\left (x-1\right )\,\left (4\,{\mathrm {e}}^{\frac {x\,{\mathrm {e}}^5}{25}}-x+4\right ) \]
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