Integrand size = 29, antiderivative size = 18 \[ \int \frac {1}{3} e^{\frac {1}{3} (3+3 x-\log (x))} (3+(2+3 x) \log (x)) \, dx=e^{x+\frac {1}{3} (3-\log (x))} x \log (x) \]
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Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.32 (sec) , antiderivative size = 175, normalized size of antiderivative = 9.72, number of steps used = 16, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.345, Rules used = {12, 2306, 6820, 6874, 2250, 2258, 2634, 15, 14, 6696} \[ \int \frac {1}{3} e^{\frac {1}{3} (3+3 x-\log (x))} (3+(2+3 x) \log (x)) \, dx=-\frac {9}{25} e x^{5/3} \, _2F_2\left (\frac {5}{3},\frac {5}{3};\frac {8}{3},\frac {8}{3};x\right )-\frac {3}{2} e x^{2/3} \, _2F_2\left (\frac {2}{3},\frac {2}{3};\frac {5}{3},\frac {5}{3};x\right )-\frac {e x^{2/3} \Gamma \left (\frac {2}{3},-x\right )}{(-x)^{2/3}}-\frac {3 e x^{2/3} \operatorname {Gamma}\left (\frac {5}{3}\right ) \log \left (\sqrt [3]{x}\right )}{(-x)^{2/3}}+\frac {2 e x^{2/3} \operatorname {Gamma}\left (\frac {2}{3}\right ) \log \left (\sqrt [3]{x}\right )}{(-x)^{2/3}}-\frac {e x^{5/3} \log (x) \Gamma \left (\frac {5}{3},-x\right )}{(-x)^{5/3}}-\frac {2 e x^{2/3} \log (x) \Gamma \left (\frac {2}{3},-x\right )}{3 (-x)^{2/3}} \]
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Rule 12
Rule 14
Rule 15
Rule 2250
Rule 2258
Rule 2306
Rule 2634
Rule 6696
Rule 6820
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \int e^{\frac {1}{3} (3+3 x-\log (x))} (3+(2+3 x) \log (x)) \, dx \\ & = \frac {1}{3} \int \frac {e^{\frac {1}{3} (3+3 x)} (3+(2+3 x) \log (x))}{\sqrt [3]{x}} \, dx \\ & = \frac {1}{3} \int \frac {e^{1+x} (3+(2+3 x) \log (x))}{\sqrt [3]{x}} \, dx \\ & = \text {Subst}\left (\int e^{1+x^3} x \left (3+\left (2+3 x^3\right ) \log \left (x^3\right )\right ) \, dx,x,\sqrt [3]{x}\right ) \\ & = \text {Subst}\left (\int \left (3 e^{1+x^3} x+e^{1+x^3} x \left (2+3 x^3\right ) \log \left (x^3\right )\right ) \, dx,x,\sqrt [3]{x}\right ) \\ & = 3 \text {Subst}\left (\int e^{1+x^3} x \, dx,x,\sqrt [3]{x}\right )+\text {Subst}\left (\int e^{1+x^3} x \left (2+3 x^3\right ) \log \left (x^3\right ) \, dx,x,\sqrt [3]{x}\right ) \\ & = -\frac {e x^{2/3} \Gamma \left (\frac {2}{3},-x\right )}{(-x)^{2/3}}-\frac {2 e x^{2/3} \Gamma \left (\frac {2}{3},-x\right ) \log (x)}{3 (-x)^{2/3}}-\frac {e x^{5/3} \Gamma \left (\frac {5}{3},-x\right ) \log (x)}{(-x)^{5/3}}-\text {Subst}\left (\int \frac {e x \left (-2 \Gamma \left (\frac {2}{3},-x^3\right )+3 \Gamma \left (\frac {5}{3},-x^3\right )\right )}{\left (-x^3\right )^{2/3}} \, dx,x,\sqrt [3]{x}\right ) \\ & = -\frac {e x^{2/3} \Gamma \left (\frac {2}{3},-x\right )}{(-x)^{2/3}}-\frac {2 e x^{2/3} \Gamma \left (\frac {2}{3},-x\right ) \log (x)}{3 (-x)^{2/3}}-\frac {e x^{5/3} \Gamma \left (\frac {5}{3},-x\right ) \log (x)}{(-x)^{5/3}}-e \text {Subst}\left (\int \frac {x \left (-2 \Gamma \left (\frac {2}{3},-x^3\right )+3 \Gamma \left (\frac {5}{3},-x^3\right )\right )}{\left (-x^3\right )^{2/3}} \, dx,x,\sqrt [3]{x}\right ) \\ & = -\frac {e x^{2/3} \Gamma \left (\frac {2}{3},-x\right )}{(-x)^{2/3}}-\frac {2 e x^{2/3} \Gamma \left (\frac {2}{3},-x\right ) \log (x)}{3 (-x)^{2/3}}-\frac {e x^{5/3} \Gamma \left (\frac {5}{3},-x\right ) \log (x)}{(-x)^{5/3}}-\frac {\left (e x^{2/3}\right ) \text {Subst}\left (\int \frac {-2 \Gamma \left (\frac {2}{3},-x^3\right )+3 \Gamma \left (\frac {5}{3},-x^3\right )}{x} \, dx,x,\sqrt [3]{x}\right )}{(-x)^{2/3}} \\ & = -\frac {e x^{2/3} \Gamma \left (\frac {2}{3},-x\right )}{(-x)^{2/3}}-\frac {2 e x^{2/3} \Gamma \left (\frac {2}{3},-x\right ) \log (x)}{3 (-x)^{2/3}}-\frac {e x^{5/3} \Gamma \left (\frac {5}{3},-x\right ) \log (x)}{(-x)^{5/3}}-\frac {\left (e x^{2/3}\right ) \text {Subst}\left (\int \left (-\frac {2 \Gamma \left (\frac {2}{3},-x^3\right )}{x}+\frac {3 \Gamma \left (\frac {5}{3},-x^3\right )}{x}\right ) \, dx,x,\sqrt [3]{x}\right )}{(-x)^{2/3}} \\ & = -\frac {e x^{2/3} \Gamma \left (\frac {2}{3},-x\right )}{(-x)^{2/3}}-\frac {2 e x^{2/3} \Gamma \left (\frac {2}{3},-x\right ) \log (x)}{3 (-x)^{2/3}}-\frac {e x^{5/3} \Gamma \left (\frac {5}{3},-x\right ) \log (x)}{(-x)^{5/3}}+\frac {\left (2 e x^{2/3}\right ) \text {Subst}\left (\int \frac {\Gamma \left (\frac {2}{3},-x^3\right )}{x} \, dx,x,\sqrt [3]{x}\right )}{(-x)^{2/3}}-\frac {\left (3 e x^{2/3}\right ) \text {Subst}\left (\int \frac {\Gamma \left (\frac {5}{3},-x^3\right )}{x} \, dx,x,\sqrt [3]{x}\right )}{(-x)^{2/3}} \\ & = -\frac {e x^{2/3} \Gamma \left (\frac {2}{3},-x\right )}{(-x)^{2/3}}-\frac {2 e x^{2/3} \Gamma \left (\frac {2}{3},-x\right ) \log (x)}{3 (-x)^{2/3}}-\frac {e x^{5/3} \Gamma \left (\frac {5}{3},-x\right ) \log (x)}{(-x)^{5/3}}+\frac {\left (2 e x^{2/3}\right ) \text {Subst}\left (\int \frac {\Gamma \left (\frac {2}{3},-x\right )}{x} \, dx,x,x\right )}{3 (-x)^{2/3}}-\frac {\left (e x^{2/3}\right ) \text {Subst}\left (\int \frac {\Gamma \left (\frac {5}{3},-x\right )}{x} \, dx,x,x\right )}{(-x)^{2/3}} \\ & = -\frac {e x^{2/3} \Gamma \left (\frac {2}{3},-x\right )}{(-x)^{2/3}}-\frac {3}{2} e x^{2/3} \, _2F_2\left (\frac {2}{3},\frac {2}{3};\frac {5}{3},\frac {5}{3};x\right )-\frac {9}{25} e x^{5/3} \, _2F_2\left (\frac {5}{3},\frac {5}{3};\frac {8}{3},\frac {8}{3};x\right )+\frac {2 e x^{2/3} \operatorname {Gamma}\left (\frac {2}{3}\right ) \log (x)}{3 (-x)^{2/3}}-\frac {e x^{2/3} \operatorname {Gamma}\left (\frac {5}{3}\right ) \log (x)}{(-x)^{2/3}}-\frac {2 e x^{2/3} \Gamma \left (\frac {2}{3},-x\right ) \log (x)}{3 (-x)^{2/3}}-\frac {e x^{5/3} \Gamma \left (\frac {5}{3},-x\right ) \log (x)}{(-x)^{5/3}} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.72 \[ \int \frac {1}{3} e^{\frac {1}{3} (3+3 x-\log (x))} (3+(2+3 x) \log (x)) \, dx=e^{1+x} x^{2/3} \log (x) \]
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Time = 0.21 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.61
method | result | size |
default | \(x^{\frac {2}{3}} {\mathrm e}^{1+x} \ln \left (x \right )\) | \(11\) |
risch | \(x^{\frac {2}{3}} {\mathrm e}^{1+x} \ln \left (x \right )\) | \(11\) |
norman | \(x \,{\mathrm e}^{-\frac {\ln \left (x \right )}{3}+x +1} \ln \left (x \right )\) | \(13\) |
parallelrisch | \(x \,{\mathrm e}^{-\frac {\ln \left (x \right )}{3}+x +1} \ln \left (x \right )\) | \(13\) |
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Time = 0.23 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.67 \[ \int \frac {1}{3} e^{\frac {1}{3} (3+3 x-\log (x))} (3+(2+3 x) \log (x)) \, dx=x e^{\left (x - \frac {1}{3} \, \log \left (x\right ) + 1\right )} \log \left (x\right ) \]
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Timed out. \[ \int \frac {1}{3} e^{\frac {1}{3} (3+3 x-\log (x))} (3+(2+3 x) \log (x)) \, dx=\text {Timed out} \]
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\[ \int \frac {1}{3} e^{\frac {1}{3} (3+3 x-\log (x))} (3+(2+3 x) \log (x)) \, dx=\int { \frac {1}{3} \, {\left ({\left (3 \, x + 2\right )} \log \left (x\right ) + 3\right )} e^{\left (x - \frac {1}{3} \, \log \left (x\right ) + 1\right )} \,d x } \]
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\[ \int \frac {1}{3} e^{\frac {1}{3} (3+3 x-\log (x))} (3+(2+3 x) \log (x)) \, dx=\int { \frac {1}{3} \, {\left ({\left (3 \, x + 2\right )} \log \left (x\right ) + 3\right )} e^{\left (x - \frac {1}{3} \, \log \left (x\right ) + 1\right )} \,d x } \]
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Time = 8.46 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.56 \[ \int \frac {1}{3} e^{\frac {1}{3} (3+3 x-\log (x))} (3+(2+3 x) \log (x)) \, dx=x^{2/3}\,\mathrm {e}\,{\mathrm {e}}^x\,\ln \left (x\right ) \]
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