Integrand size = 74, antiderivative size = 19 \[ \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{\left (x^2-4 x^4+4 x^6\right ) \log ^2(x)} \, dx=e^{\frac {2+x}{\left (x-2 x^3\right ) \log (x)}} \]
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\[ \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{\left (x^2-4 x^4+4 x^6\right ) \log ^2(x)} \, dx=\int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{\left (x^2-4 x^4+4 x^6\right ) \log ^2(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{x^2 \left (1-4 x^2+4 x^4\right ) \log ^2(x)} \, dx \\ & = 4 \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{x^2 \left (-2+4 x^2\right )^2 \log ^2(x)} \, dx \\ & = 4 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{x^2 \left (2-4 x^2\right )^2 \log ^2(x)} \, dx \\ & = 4 \int \left (\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} (2+x)}{4 x^2 \left (-1+2 x^2\right ) \log ^2(x)}+\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} \left (-1+6 x^2+2 x^3\right )}{2 x^2 \left (-1+2 x^2\right )^2 \log (x)}\right ) \, dx \\ & = 2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} \left (-1+6 x^2+2 x^3\right )}{x^2 \left (-1+2 x^2\right )^2 \log (x)} \, dx+\int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} (2+x)}{x^2 \left (-1+2 x^2\right ) \log ^2(x)} \, dx \\ & = 2 \int \left (-\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log (x)}+\frac {2 e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} (2+x)}{\left (-1+2 x^2\right )^2 \log (x)}+\frac {2 e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (-1+2 x^2\right ) \log (x)}\right ) \, dx+\int \left (-\frac {2 e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log ^2(x)}-\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x \log ^2(x)}+\frac {2 e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} (2+x)}{\left (-1+2 x^2\right ) \log ^2(x)}\right ) \, dx \\ & = -\left (2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log ^2(x)} \, dx\right )+2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} (2+x)}{\left (-1+2 x^2\right ) \log ^2(x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log (x)} \, dx+4 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} (2+x)}{\left (-1+2 x^2\right )^2 \log (x)} \, dx+4 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (-1+2 x^2\right ) \log (x)} \, dx-\int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x \log ^2(x)} \, dx \\ & = 2 \int \left (\frac {2 e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (-1+2 x^2\right ) \log ^2(x)}+\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} x}{\left (-1+2 x^2\right ) \log ^2(x)}\right ) \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log ^2(x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log (x)} \, dx+4 \int \left (-\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{2 \left (1-\sqrt {2} x\right ) \log (x)}-\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{2 \left (1+\sqrt {2} x\right ) \log (x)}\right ) \, dx+4 \int \left (\frac {2 e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (-1+2 x^2\right )^2 \log (x)}+\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} x}{\left (-1+2 x^2\right )^2 \log (x)}\right ) \, dx-\int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x \log ^2(x)} \, dx \\ & = -\left (2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log ^2(x)} \, dx\right )+2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} x}{\left (-1+2 x^2\right ) \log ^2(x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log (x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1-\sqrt {2} x\right ) \log (x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1+\sqrt {2} x\right ) \log (x)} \, dx+4 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (-1+2 x^2\right ) \log ^2(x)} \, dx+4 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} x}{\left (-1+2 x^2\right )^2 \log (x)} \, dx+8 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (-1+2 x^2\right )^2 \log (x)} \, dx-\int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x \log ^2(x)} \, dx \\ & = 2 \int \left (-\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{2 \sqrt {2} \left (1-\sqrt {2} x\right ) \log ^2(x)}+\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{2 \sqrt {2} \left (1+\sqrt {2} x\right ) \log ^2(x)}\right ) \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log ^2(x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log (x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1-\sqrt {2} x\right ) \log (x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1+\sqrt {2} x\right ) \log (x)} \, dx+4 \int \left (-\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{2 \left (1-\sqrt {2} x\right ) \log ^2(x)}-\frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{2 \left (1+\sqrt {2} x\right ) \log ^2(x)}\right ) \, dx+4 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} x}{\left (-1+2 x^2\right )^2 \log (x)} \, dx+8 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (-1+2 x^2\right )^2 \log (x)} \, dx-\int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x \log ^2(x)} \, dx \\ & = -\left (2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log ^2(x)} \, dx\right )-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1-\sqrt {2} x\right ) \log ^2(x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1+\sqrt {2} x\right ) \log ^2(x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x^2 \log (x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1-\sqrt {2} x\right ) \log (x)} \, dx-2 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1+\sqrt {2} x\right ) \log (x)} \, dx+4 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}} x}{\left (-1+2 x^2\right )^2 \log (x)} \, dx+8 \int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (-1+2 x^2\right )^2 \log (x)} \, dx-\frac {\int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1-\sqrt {2} x\right ) \log ^2(x)} \, dx}{\sqrt {2}}+\frac {\int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{\left (1+\sqrt {2} x\right ) \log ^2(x)} \, dx}{\sqrt {2}}-\int \frac {e^{\frac {-2-x}{x \left (-1+2 x^2\right ) \log (x)}}}{x \log ^2(x)} \, dx \\ \end{align*}
Time = 3.78 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.05 \[ \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{\left (x^2-4 x^4+4 x^6\right ) \log ^2(x)} \, dx=e^{\frac {2+x}{x \log (x)-2 x^3 \log (x)}} \]
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Time = 4.16 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.21
method | result | size |
risch | \({\mathrm e}^{-\frac {2+x}{x \left (2 x^{2}-1\right ) \ln \left (x \right )}}\) | \(23\) |
parallelrisch | \({\mathrm e}^{-\frac {2+x}{x \left (2 x^{2}-1\right ) \ln \left (x \right )}}\) | \(23\) |
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Time = 0.25 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.11 \[ \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{\left (x^2-4 x^4+4 x^6\right ) \log ^2(x)} \, dx=e^{\left (-\frac {x + 2}{{\left (2 \, x^{3} - x\right )} \log \left (x\right )}\right )} \]
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Exception generated. \[ \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{\left (x^2-4 x^4+4 x^6\right ) \log ^2(x)} \, dx=\text {Exception raised: TypeError} \]
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Exception generated. \[ \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{\left (x^2-4 x^4+4 x^6\right ) \log ^2(x)} \, dx=\text {Exception raised: RuntimeError} \]
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Time = 0.28 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.95 \[ \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{\left (x^2-4 x^4+4 x^6\right ) \log ^2(x)} \, dx=e^{\left (-\frac {x}{2 \, x^{3} \log \left (x\right ) - x \log \left (x\right )} - \frac {2}{2 \, x^{3} \log \left (x\right ) - x \log \left (x\right )}\right )} \]
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Time = 8.97 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.68 \[ \int \frac {e^{\frac {-2-x}{\left (-x+2 x^3\right ) \log (x)}} \left (-2-x+4 x^2+2 x^3+\left (-2+12 x^2+4 x^3\right ) \log (x)\right )}{\left (x^2-4 x^4+4 x^6\right ) \log ^2(x)} \, dx={\mathrm {e}}^{\frac {1}{\ln \left (x\right )-2\,x^2\,\ln \left (x\right )}}\,{\mathrm {e}}^{-\frac {2}{2\,x^3\,\ln \left (x\right )-x\,\ln \left (x\right )}} \]
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