Integrand size = 56, antiderivative size = 23 \[ \int \frac {2+50 e^6 x^2+600 e^3 x^4+1350 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx=\log \left (3+25 x^2 \left (e^3+3 x^2\right )^2+2 \log (x)\right ) \]
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\[ \int \frac {2+50 e^6 x^2+600 e^3 x^4+1350 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx=\int \frac {2+50 e^6 x^2+600 e^3 x^4+1350 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {2 \left (1+25 e^6 x^2+300 e^3 x^4+675 x^6\right )}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx \\ & = 2 \int \frac {1+25 e^6 x^2+300 e^3 x^4+675 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx \\ & = 2 \int \left (\frac {1}{x \left (3+25 e^6 x^2+150 e^3 x^4+225 x^6+2 \log (x)\right )}+\frac {25 e^6 x}{3+25 e^6 x^2+150 e^3 x^4+225 x^6+2 \log (x)}+\frac {300 e^3 x^3}{3+25 e^6 x^2+150 e^3 x^4+225 x^6+2 \log (x)}+\frac {675 x^5}{3+25 e^6 x^2+150 e^3 x^4+225 x^6+2 \log (x)}\right ) \, dx \\ & = 2 \int \frac {1}{x \left (3+25 e^6 x^2+150 e^3 x^4+225 x^6+2 \log (x)\right )} \, dx+1350 \int \frac {x^5}{3+25 e^6 x^2+150 e^3 x^4+225 x^6+2 \log (x)} \, dx+\left (600 e^3\right ) \int \frac {x^3}{3+25 e^6 x^2+150 e^3 x^4+225 x^6+2 \log (x)} \, dx+\left (50 e^6\right ) \int \frac {x}{3+25 e^6 x^2+150 e^3 x^4+225 x^6+2 \log (x)} \, dx \\ \end{align*}
Time = 0.34 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.22 \[ \int \frac {2+50 e^6 x^2+600 e^3 x^4+1350 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx=\log \left (3+25 e^6 x^2+150 e^3 x^4+225 x^6+2 \log (x)\right ) \]
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Time = 0.27 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.09
method | result | size |
risch | \(\ln \left (\frac {225 x^{6}}{2}+75 x^{4} {\mathrm e}^{3}+\frac {25 x^{2} {\mathrm e}^{6}}{2}+\ln \left (x \right )+\frac {3}{2}\right )\) | \(25\) |
parallelrisch | \(\ln \left (x^{6}+\frac {2 x^{4} {\mathrm e}^{3}}{3}+\frac {x^{2} {\mathrm e}^{6}}{9}+\frac {2 \ln \left (x \right )}{225}+\frac {1}{75}\right )\) | \(27\) |
default | \(\ln \left (225 x^{6}+150 x^{4} {\mathrm e}^{3}+25 x^{2} {\mathrm e}^{6}+2 \ln \left (x \right )+3\right )\) | \(29\) |
norman | \(\ln \left (225 x^{6}+150 x^{4} {\mathrm e}^{3}+25 x^{2} {\mathrm e}^{6}+2 \ln \left (x \right )+3\right )\) | \(29\) |
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Time = 0.24 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.13 \[ \int \frac {2+50 e^6 x^2+600 e^3 x^4+1350 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx=\log \left (225 \, x^{6} + 150 \, x^{4} e^{3} + 25 \, x^{2} e^{6} + 2 \, \log \left (x\right ) + 3\right ) \]
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Time = 0.09 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.39 \[ \int \frac {2+50 e^6 x^2+600 e^3 x^4+1350 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx=\log {\left (\frac {225 x^{6}}{2} + 75 x^{4} e^{3} + \frac {25 x^{2} e^{6}}{2} + \log {\left (x \right )} + \frac {3}{2} \right )} \]
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Time = 0.20 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.04 \[ \int \frac {2+50 e^6 x^2+600 e^3 x^4+1350 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx=\log \left (\frac {225}{2} \, x^{6} + 75 \, x^{4} e^{3} + \frac {25}{2} \, x^{2} e^{6} + \log \left (x\right ) + \frac {3}{2}\right ) \]
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Time = 0.25 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.13 \[ \int \frac {2+50 e^6 x^2+600 e^3 x^4+1350 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx=\log \left (225 \, x^{6} + 150 \, x^{4} e^{3} + 25 \, x^{2} e^{6} + 2 \, \log \left (x\right ) + 3\right ) \]
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Time = 8.35 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.04 \[ \int \frac {2+50 e^6 x^2+600 e^3 x^4+1350 x^6}{3 x+25 e^6 x^3+150 e^3 x^5+225 x^7+2 x \log (x)} \, dx=\ln \left (\ln \left (x\right )+75\,x^4\,{\mathrm {e}}^3+\frac {25\,x^2\,{\mathrm {e}}^6}{2}+\frac {225\,x^6}{2}+\frac {3}{2}\right ) \]
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